Two cities,a and are mapped on the coordinate plane. How far apart are they from each other?

Answer:

[tex]\frac{20}{40} \ and \ \frac{4}{8} \ is \ equivalent[/tex]

Step-by-step explanation:

1.

[tex]\frac{2}{3} \ and \ \frac{12}{9} \\\\\frac{2}{3} \ and \ \frac{4}{3}\\\\Not \ equivalent[/tex]

2.

[tex]\frac{20}{40} \ and \ \frac{45}{55}\\\\\frac{1}{2} \ and \ \frac{9}{11}\\\\Not\ equivalent[/tex]

3.

[tex]\frac{20}{40} \ and \ \frac{4}{8}\\\\\frac{1}{2} \ and \ \frac{1}{2} \\\\Equivalent[/tex]

4.

[tex]\frac{5}{5} \ and \ \frac{25}{50} \\\\\frac{1}{1} \ and \ \frac{1}{2} \\\\not \ equivalent[/tex]

Answer:

-2x³ - 14x² + 7x - 4

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

(3x³ - 2x² + 4x - 8) - (5x³ + 12x² - 3x - 4)

Step 2: Simplify

Answer:

Step-by-step explanation:

By applying cosine rule in the given triangle,

c² = a² + b²-2abcosC

c² = (5.6)² + (10.7)² - 2(5.6)(10.7)cos(109.3°)

c² = 185.46

c = 13.6 km

By applying sine rule in the given triangle ABC,

[tex]\frac{\text{sin}A}{a}= \frac{\text{sin}B}{b}= \frac{\text{sin}C}{c}[/tex]

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

[tex]\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(B) = [tex]\frac{10.7\times \text{sin}(109.30)}{13.6}[/tex]

         = 0.7425

B = [tex]\text{sin}^{-1}(0.7425)[/tex]

B = 48.0°

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(A) = [tex]\frac{[\text{sin}(109.3)]\times (5.6)}{13.6}[/tex]

         = 0.3886

A = [tex]\text{sin}^{-1}(0.3886)[/tex]

A = 22.9°

Answers:

=============================================

Explanation:

The angle theta is between pi and 3pi/2, excluding both endpoints.

This places theta in the third quadrant (Q3) between 180 degrees and 270 degrees. The third quadrant is in the southwest.

Plot point A at the origin. 12 units to the left of this point, will be point B. So B is at (-12,0). Then five units lower is point C at (-12,-5). Refer to the diagram below. Notice how triangle ABC is a right triangle.

The angle theta will be the angle BAC, or simply angle A.

Since cos(theta) = -12/13, this indicates that

AB = -12 = adjacent

AC = 13 = hypotenuse

Technically, AB is should be positive, but I'm making it negative so that we can then say

cos(angle) = adjacent/hypotenuse

cos(theta) = AB/AC

cos(theta) = -12/13

------------------

If you apply the pythagorean theorem, you should find that BC = 5, which I'll  make negative since we're below the x axis. Then we can say

sin(theta) = opposite/hypotenuse

sin(theta) = BC/AC

sin(theta) = -5/13

------------------

If you divide sine over cosine, then you'll get 5/12. The 13's cancel out. This is the value of tangent.

Or you could say

tan(theta) = opposite/adjacent

tan(theta) = BC/AB

tan(theta) = (-5)/(-12)

tan(theta) = 5/12

------------------

To find csc, aka cosecant, you apply the reciprocal to sine

sin = -5/13 which means csc = -13/5

sec, or secant, is the reciprocal of cosine

cos = -12/13 leads to sec = -13/12

and finally cotangent (cot) is the reciprocal of tangent

tan = 5/12 leads to cot = 12/5

------------------

Note: everything but tan and cot is negative in Q3.

Answer:

False because $296=$296

Answer:

[tex] \large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{✽ \: m \: \angle \: RQP = m \: \angle \: RQH + m \: \angle \: HQP}}[/tex]

[tex] \large{ \tt{⇾ \: 152 \degree = \: m \: \angle \: \: RQH + 95 \degree}}[/tex]

[tex] \large{ \tt{⇾ \: 152 \degree - 95 \degree = m \: \angle \: RQH}}[/tex]

[tex] \boxed{ \large{ \tt{⇾ \: 57 \degree = m \: \angle \: RQH}}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

15:35

Step-by-step explanation:

50-35=Girls

50-35=15

Step-by-step explanation:

I am sorry question samajh Nahin a Raha question dijiye

Answer:

20

Step-by-step explanation:

6 + 2 = 8

8 + 3 = 11

11 + 4 =15

15 + 5 =20

Answer:

20

Step-by-step explanation:

the pattern is increase the number by one more than the increase before. so 6,8=2 greater

8-11=3 greater. 11-15=4 greater. so, 15+5=20 (with this answer being 5 greater continuing the pattern.)

Answer:

The speed in terms of kilometers per hour is 0.666 km / h.

Step-by-step explanation:

Given that the good construction slithers 3/9 kilometers in 3/6 hours, to determine what is it's speed in terms of kilometers per hour, the following calculation must be performed:

3/9 = 0.333 km

3/6 = 0.5 hours

0.666 km / h

Therefore, the speed in terms of kilometers per hour is 0.666 km / h.

Answer:

22=4

Step-by-step explanation:

0977-=ytb

Answer:

33

Step-by-step explanation:

45 - + 14 is 45 - 14 is 33

Answer:

7 brown M&Ms.

Step-by-step explanation:

This question is not complete, but I will assume that the final question is how many brown M&Ms will be in this package.

0.14 × 52 is our equation.

The answer is 7.28. We cannot have .28 of a brown M&M in a package (unless you count the broken ones) so there will be, on average, 7 brown M&Ms in a package.

(again, the question is incomplete, so this may not be the answer)

Answer:

distance = 11

Step-by-step explanation:

distance = [tex]\sqrt{[3-(-8)]^{2} +(4-4)^{2}}[/tex]

             = [tex]\sqrt{11^{2} }[/tex]

             = 11

Answer:

[tex]\frac{851}{1000}[/tex]

Step-by-step explanation:

First, we can simply multiply that number by 1000, and divide again by 1000 to get a base fraction:

[tex].851\\\\= \frac{1000}{1000} \times .851\\\\= \frac{1000 \times .851}{1000}\\\\= \frac{851}{1000}[/tex]

851 is a secondary prime, having only two factors, both of which are prime.  Those factors are 23 and 37, neither of which is a factor of 1000, so this is already in simplest form.

Answer:

7.3

Step-by-step explanation:

When you round, you look at the number to the right of which you are rounding to.

1 decimal place would be the tenths place.

7.263

So we would look at the 6, in the hundredths place.

6 is larger than 5, so 2 would be bumped up to 3.

7.3.

I hope this helps!

Answer:

7.3

Step-by-step explanation:

rounding up from 7.263 is 7.3

Answer:

52mtrs

Step-by-step explanation:

if length is 56meeters and the width is 4meeters less then 56 -4 = 52 so width is 52mtrs

Answer:

The measure of the smallest angle is 30º

Step-by-step explanation:

Let the angles be:

[tex]x \to[/tex] the first angle (the smallest)

[tex]y \to[/tex] the second angle

[tex]z \to[/tex] the third angle

So, we have:

[tex]y = 2x[/tex]

[tex]z=x + 60[/tex]

Required

Find x

The angles in a triangle is:

[tex]x + y +z = 180[/tex]

Substitute values for y and z

[tex]x + 2x +x + 60 = 180[/tex]

[tex]4x + 60 = 180[/tex]

Collect like terms

[tex]4x = 180-60[/tex]

[tex]4x = 120[/tex]

Divide by 4

[tex]x = 30[/tex]

Answer:

The resistance is 484 ohm.

Step-by-step explanation:

An incandescent lamp has the following data inscribed on its bulb. U= 220 V and P = 100 W. Knowing the relations U = R. i and P = U. i , it can be stated that the value of the resistance R of the lamp during operation is, in omhs:

P = 100 W

V = 220 V

Let the current is I.

P = V I

100 = 220 I

I = 0.45 A

Now,

V = I R

220 = 0.45 x R

R = 484 ohm

The resistance is 484 ohm.

Answer:

total pencil = 5 orange pencils + 8 yellow pencils + 4 green pencils

= 17 pencils

P (g n y) = 4/17 + 8/17

= 0.706

Step-by-step explanation:

1. first find the total number of pencils

2. since there is a replacement the demoinator remains the same

3. find the probability of each green and yellow

4. add the two probability

Answer:

(f • g) (x) = [tex]x^{3}[/tex] - 3[tex]x^{2}[/tex] - 16x - 12

Step-by-step explanation:

(x-6)([tex]x^{2}[/tex] + 3x + 2)

[tex]x^{3}[/tex] + 3[tex]x^{2}[/tex] + 2x - 6[tex]x^{2}[/tex] - 18x -12

[tex]x^{3}[/tex] - 3[tex]x^{2}[/tex] - 16x - 12

Answer:

z = ±  0.772193214

Step-by-step explanation:

Hence, the critical value for a [tex]88[/tex]% confidence level is [tex]z=1.56[/tex].

What is the standard deviation?

Standard deviation is the degree of dispersion or the scatter of the data points relative to its mean, in descriptive statistics.

It tells how the values are spread across the data sample and it is the measure of the variation of the data points from the mean.

Here given that,

For a confidence level of  [tex]88[/tex]%, find the critical value for a normally distributed variable.

Let us assume that the standard normal distribution having a mean is [tex]0[/tex] and the standard deviation is [tex]1[/tex].

As the significance level is [tex]1[/tex] - confidence interval

Confidence interval is [tex]\frac{80}{100}=0.88[/tex]

i.e., [tex]1-0.88=0.12[/tex]

For the two sided confidence interval the confidence level is [tex]0.44[/tex].

Now, the standard normal probability table the critical value for the  [tex]88[/tex]% confidence level is [tex]1.56[/tex].

Hence, the critical value for a [tex]88[/tex]% confidence level is [tex]z=1.56[/tex].

To know more about the standard deviation

https://brainly.com/question/13905583

#SPJ5

Answer:

As for metric prefixes, "hecto" means hundred and "centi" means hundredth.  

So, converting .53 hectograms to centigrams requires multiplying it by 10,000.

So, .53 hectograms * 10,000 equals 5,300 centigrams.

Source http://www.1728.org/convprfx.htm

Step-by-step explanation:

Answer:

(a): The conditional pmf of Y when X = 1

[tex]p_{Y|X}(0|1) = 0.2353[/tex]

[tex]p_{Y|X}(1|1) = 0.5882[/tex]

[tex]p_{Y|X}(2|1) = 0.1765[/tex]

(b): The conditional pmf of Y when X = 2

[tex]p_{Y|X}(0|2) = 0.0962[/tex]

[tex]p_{Y|X}(1|2) = 0.2692[/tex]

[tex]p_{Y|X}(2|2) = 0.6346[/tex]

(c): From (b) calculate P(Y<=1 | X =2)

[tex]P(Y\le1 | X =2) = 0.3654[/tex]

(d): The conditional pmf of X when Y = 2

[tex]p_{X|Y}(0|2) = 0.025[/tex]

[tex]p_{X|Y}(1|2) = 0.150[/tex]

[tex]p_{X|Y}(2|2) = 0.825[/tex]

Step-by-step explanation:

Given

The above table

Solving (a): The conditional pmf of Y when X = 1

This implies that we calculate

[tex]p_{Y|X}(0|1), p_{Y|X}(1|1), p_{Y|X}(2|1)[/tex]

So, we have:

[tex]p_{Y|X}(0|1) = \frac{p(y = 0\ n\ x = 1)}{p(x = 1)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{Y|X}(0|1) = \frac{0.08}{0.08+0.20+0.06}[/tex]

[tex]p_{Y|X}(0|1) = \frac{0.08}{0.34}[/tex]

[tex]p_{Y|X}(0|1) = 0.2353[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{Y|X}(1|1) = \frac{0.20}{0.34}[/tex]

[tex]p_{Y|X}(1|1) = 0.5882[/tex]

[tex]p_{Y|X}(2|1) = \frac{0.06}{0.34}[/tex]

[tex]p_{Y|X}(2|1) = 0.1765[/tex]

Solving (b): The conditional pmf of Y when X = 2

This implies that we calculate

[tex]p_{Y|X}(0|2), p_{Y|X}(1|2), p_{Y|X}(2|2)[/tex]

So, we have:

[tex]p_{Y|X}(0|2) = \frac{p(y = 0\ n\ x = 2)}{p(x = 2)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{Y|X}(0|2) = \frac{0.05}{0.05+0.14+0.33}[/tex]

[tex]p_{Y|X}(0|2) = \frac{0.05}{0.52}[/tex]

[tex]p_{Y|X}(0|2) = 0.0962[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{Y|X}(1|2) = \frac{0.14}{0.52}[/tex]

[tex]p_{Y|X}(1|2) = 0.2692[/tex]

[tex]p_{Y|X}(2|2) = \frac{0.33}{0.52}[/tex]

[tex]p_{Y|X}(2|2) = 0.6346[/tex]

Solving (c): From (b) calculate P(Y<=1 | X =2)

To do this, where Y = 0 or 1

So, we have:

[tex]P(Y\le1 | X =2) = P_{Y|X}(0|2) + P_{Y|X}(1|2)[/tex]

[tex]P(Y\le1 | X =2) = 0.0962 + 0.2692[/tex]

[tex]P(Y\le1 | X =2) = 0.3654[/tex]

Solving (d): The conditional pmf of X when Y = 2

This implies that we calculate

[tex]p_{X|Y}(0|2), p_{X|Y}(1|2), p_{X|Y}(2|2)[/tex]

So, we have:

[tex]p_{X|Y}(0|2) = \frac{p(x = 0\ n\ y = 2)}{p(y = 2)}[/tex]

Reading the data from the given table, the equation becomes

[tex]p_{X|Y}(0|2) = \frac{0.01}{0.01+0.06+0.33}[/tex]

[tex]p_{X|Y}(0|2) = \frac{0.01}{0.40}[/tex]

[tex]p_{X|Y}(0|2) = 0.025[/tex]

Using the format of the above formula for the rest, we have:

[tex]p_{X|Y}(1|2) = \frac{0.06}{0.40}[/tex]

[tex]p_{X|Y}(1|2) = 0.150[/tex]

[tex]p_{X|Y}(2|2) = \frac{0.33}{0.40}[/tex]

[tex]p_{X|Y}(2|2) = 0.825[/tex]

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that [tex]p = 0.3773[/tex]

Their schedule for November contains 12 games.

This means that [tex]n = 12[/tex]

Find the probability that the hockey team wins at least 3 games in November.

This is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034[/tex]

[tex]P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247[/tex]

[tex]P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824[/tex]

Then

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895[/tex]

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Answer:

false...

to be quadratic you need an "x^2" in the

function

(0,1)  might be 0^2 + 1

but then 1^2 + 1 = 2 than would be (1,2)  NOT (1,3)

Step-by-step explanation:

Answer:

D) y = –5x + 4x^2 + 2

Step-by-step explanation:

You can tell by the first number being positive or negative. To check use Desmo graphing calculator and enter your equation for next time.

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question:

We have to look at the standard error, which is:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

Answer:

D. No angle opposite the sides is given

Step-by-step explanation:

Given

See attachment for triangle

Required

Why the law of sines cannot be used

From the attached image of a triangle, we can see that all sides are given while none of the angles are given.

Since none of the angles are given, then law of sines doesn't apply