Answer:
71.6°
Step-by-step explanation:
The angle can be found from the dot product of PQ and PR.
PQ·PR = |PQ|×|PR|×cos(α)
where α is the angle between the two segments.
cos(α) = (Q -P)·(R -P)/(|Q -P|×|R -P|)
= ((0, 1, 0) -(1, 0, 0))·((0, 0, 2) -(1, 0, 0))/(|Q -P|×|R -P|)
= (-1, 1, 0)·(-1, 0, 2)/(√(((-1)² +1²)((-1²) +2²)) = (1+0+0)/√10
α = arccos(1/√10) ≈ 71.6°
The angle at P is about 71.6°.
_____
Additional comment
The side lengths of the triangle are √2, √5, √5. As we have seen, the angle at P is bounded by the sides of length √2 and √5. The law of cosines can also be used to arrive at the angle between these sides.
Which of these is a ratio table?
A
1
2.
3
o ono
WON
B.
5
6
7
A
1
2
3
chAUD
B
4
5
7
WN
B
A
1
2
3
COA
4
9
А
1
2
3
B
2.
4
6
ANUD
INI
Answer:
The last one
Step-by-step explanation:
A ratio table means that each number in the first column is multiplied by the same number to get the answer in the 2nd column
- z > 8 equivalent inequality
Answer: z < -8
Step-by-step explanation:
Since z is negative, divide both sides by -1, which leaves you with z > -8.
Multiplying or dividing an inequality by a negative number flips the sign, thus the answer is z < 8.
Correct me if I am incorrect.
Approximately what portion of the beaker is filled?
A. 1/2
B. 1/4 C.3/4
Answer:
B. [tex]\frac{1}{4}[/tex]
Step-by-step explanation:
The whole beaker is 1. If you measure the beaker, you will notice you can fill up the beaker to the brim (whole, which is 1) if you use the current amount 4 times, and four times is [tex]\frac{1}{4}[/tex].
Share and Show
MATH
BOARD
Model the product on the grid. Record the product.
1. 3 X 13 =
2. 5 >
Find the product.
Using the grid model, the product of 3 and 13 is 39
Product refers to the result of multiplying two or more numbers or quantities together. It is a fundamental operation in arithmetic and algebra. When multiplying two numbers, the product is obtained by adding together a number of copies of one of the numbers, equal to the value of the other number.
Given, two numbers 3 and 9, and a grid.
To determine the product of 3 and 13 just count all the grids covered in 3 rows up to 13 columns or adding 3 for 13 times will result in 39.
Count the grids covered in a red box attached in the image below.
3+3+3+3+3+3+3+3+3+3+3+3+3=39
So, the product of 3 and 13 is 39.
Learn more about mathematical operation, here:
https://brainly.com/question/29635854
#SPJ6
130 is what percent of 70?
Answer:
91%
Step-by-step explanation:
hopes this helps
Answer:
185.71%
Step-by-step explanation:
130 / 70 = 1.857142857
(1.857142857)(100) = 185.71%
Alvin is 9 years older than Elga. The sum of their ages is 81. What is Elga's age?
Answer:
elga is 32 and alvin is 49
24. Solve for x: 3x - 2(x - 4) = 5(2x + 4) -3
x=-1
3x-2x+8=10x+20-3
x+8=10x+17
-9x=9
x=-1
Answer:
[tex]x=-1[/tex]
Step-by-step explanation:
[tex]x-2\left(x-4\right)=5\left(2x+4\right)-3[/tex]
[tex]-2\left(x-4\right)\\\mathrm{Distribute}\\-2x+8[/tex]
[tex]3x-2x+8=5\left(2x+4\right)-3[/tex]
[tex]\mathrm{Combine\: like\: terms}[/tex]
[tex]x+8=5\left(2x+4\right)-3[/tex]
[tex]\left(2x+4\right)-3\\\mathrm{Distribute}\\10x+20-3\\10x+17[/tex]
[tex]x+8=10x+17[/tex]
[tex]\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}[/tex]
[tex]x+8-8=10x+17-8[/tex]
[tex]x=10x+9[/tex]
[tex]\mathrm{Subtract\:}10x\mathrm{\:from\:both\:sides}[/tex]
[tex]x-10x=10x+9-10x[/tex]
[tex]-9x=9[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}-9[/tex]
[tex]\frac{-9x}{-9}=\frac{9}{-9}[/tex]
[tex]\bold{x=-1}[/tex]
Which equation matches the graph?
Answer:
i think 4x+3y = -24 is answer
At the restaurant, Gordon packed 8 orders with 4 items per order
in the morning. In the afternoon, he packed 6 orders with 7 items
per order.
Answer:
what is the question?
Step-by-step explanation:
Make x the subject of the formula
t=
[tex] \sqrt{2(x - ut) \div a}[/tex]
[tex]t = \sqrt \frac{ {2(x - ut)} }{a} \\ = > t = \sqrt{ \frac{2x - 2ut}{a} } \\ = > {t}^{2} = \frac{2x - 2ut}{a} \\ = > a {t}^{2} = 2x - 2ut \\ = > \frac{ { - at}^{2} }{2ut} = 2x \\ = > \frac{ - at}{2u} = 2x \\ = > \frac{ - at}{2u \times 2} = x \\ = > \frac{ - at}{4u} = x[/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
The triangles shown bellow must be congruent?
True or False?
find the difderence of 3/4 and 1/28
Answer:
5/7
Step-by-step explanation:
3/4-1/28
21/28-1/28
20/28
simplify
5/7
A ball is thrown vertically upward with an initial velocity of 80 feet per second. The distance s (in feet) of the ball from the ground after t seconds is
if we can assume the ball is being thrown from the ground upwards, then we can say that the inital height of it is 0, whilst its initial velocity is 80 ft/s, thus
[tex]~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&80\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&0\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+80t+0\implies h(t)=-16t^2+80t[/tex]
The function v(t) is the velocity in m/sec of a particle moving along the x-axis. Use analytic methods to do each of the following: (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particle's displacement for the given time interval. If s(0) = 3, what is the particle's final position? (c) Find the total distance traveled by the particle. v(t) = 5 (sint)^2(cost); 0 ≤ t ≤ 2π
Answer:
(a) The particle is moving to the right in the interval [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].
(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].
(c) The total distance traveled by the particle is 9.67 (2 d.p.)
Step-by-step explanation:
(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).
Situation 1: When the particle stops.
[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].
Situation 2: When the particle moves to the right.
[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]
Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .
*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.
Situation 3: When the particle moves to the left.
[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]
Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].
(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.
[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]
To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where
[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].
[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]
Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].
The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].
(c)
[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]
[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]
[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].
The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].
Share £30 in the ratio 1:5 between Tim and Sam
what is the slope of the line?
Answer:
1/2
Step-by-step explanation:
We can use the slope formula to find the slope
m = ( y2-y1)/(x2-x1)
We have two points on the line
(-1,3) and ( 1,4)
m = ( 4-3)/(1 - -1)
= (4-3)/(1+1)
= 1/2
Answer:
Start where the line meets a point. Then go up and over until it meets another.
The answer is 1/2
So go up one and over two. Then other problems such as this one should be pretty straight forward
Convert the following fraction to a decimal.
40x^-4 y^6
________
10x^-5 y^5
Answer:
[tex]4xy[/tex]
Step-by-step explanation:[tex](40/10) *(x^-^4/x^-^5) * (y^6/y^5) \\=4*x*y=4xy[/tex]
Lucy borrowed $73,250 to purchase a home. The bank offered her an APR of 3.15% for a term length of 20 years. Excel calculates the monthly payment to be $411.77. If she were to pay only the minimum payment for the lifetime of the loan, how much will Lucy be paying in interest?
Amount Lucy will be paying in interest will be $38,596.2
Using the compound amount formula to get the amount after she will pay back after 20 years expressed as:
[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]
A is the amount after 20 yearsr is the rate = 3.15% = 0.0315time in years = 20 yearsn is the compounding time = 12 (monthly)P is the amount borrowed = $73,250Substitute the parameters into the formula;
[tex]A=73,250(1+\frac{0.0315}{12} )^{20(12)}\\A= $73,250 (1.8761)\\A= \$137,421.49[/tex]
If Excel calculates the monthly payment to be $411.77, the amount paid for 20 years will be $411.77 * 240months = $98,824.8
Amount Lucy will be paying interest will be $137,421- $98,824.8 = $38,596.2
Learn more on compound interest here: https://brainly.com/question/24924853
Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours Kayla finally caught up. Find Jose's speed.
========================================================
Explanation:
x = Jose's speed in mph
x+35 = Kayla's speed since she drives 35 mph faster than Jose
Jose gets a 2.1 hour head start and it takes Kayla 1.2 hours to reach him. So this means Jose has been driving for 2.1+1.2 = 3.3 hours when Kayla reaches him. The distance he travels is
distance = rate*time
d = r*t
d = x*3.3
d = 3.3x
while Kayla's distance equation is
d = r*t
d = (x+35)*1.2
d = 1.2x+42
Since Kayla meets up with Jose at the 1.2 hour mark, this means the two distances they travel is the same. Set their distance expressions equal to one another. Solve for x.
3.3x = 1.2x+42
3.3x-1.2x = 42
2.1x = 42
x = 42/(2.1)
x = 20
Jose's speed is 20 mph, while Kayla's speed is x+35 = 20+35 = 55 mph.
Jose's fairly slow speed is probably due to a number of factors such as heavy traffic, icy roads, or poor visibility. Kayla probably got a bit of a break with more favorable conditions.
Since Jose travels at 20 mph and does so for 3.3 hours, he travels d = r*t = 20*3.3 = 66 miles. Kayla travels d = r*t = 55*1.2 = 66 miles as well. We get the same number each time to help confirm the answer.
3. What is the exact area of triangle ABC? Use special right triangles to help find the base of the triangle. Show your work.
The exact area of triangle ABC is 93.51 cm².
The given parameters;
Height of the triangle, h = 18 cmThe base of the triangle is calculated by using trigonometry ratio as follows;
[tex]tan (30) = \frac{b}{18} \\\\[/tex]
where;
b is the base of the triangle ABC[tex]b = 18 \times tan(30)\\\\b = 10.39 \ cm[/tex]
The area of the triangle ABC with the calculated base and given height is calculated as follows;
[tex]A = \frac{1}{2} \times base \times height\\\\A = \frac{1}{2} \times 10.39 \times 18\\\\A = 93.51 \ cm^2[/tex]
Thus, the exact area of triangle ABC is 93.51 cm².
Learn more about area of a triangle here: https://brainly.com/question/23945265
The Levine family has 10 gallons of gas in the car. The car uses 1 5/8 of a gallon each hour. How long can they drive on 10 gallons of gas?
Answer:
6.15
Step-by-step explanation:
10 gallons is 80/8
1 5/8= 13/8
80 divided by 13 is 6.15384615385 but rounded 6.15
6.15 hours
if its not that then keep rounding to 6.2 or 6hrs
3.
In parallelogram ABCD, M
m
Answer:
Please send a picture or explain properly
Which graph shows a linear equation?
Answer:
The bottom right is a linear equation.
Step-by-step explanation:
Answer:
right side down one
Step-by-step explanation:
as you know linear means supplementary having 180 °
Pls help ASAP
Give the domain and range
Answer:
D: {-2, 0, 2}
R: {-1, 1, 3
Which of the following word phrases describe the expression y + 3?
A.three less than y
B.the sum of y and 3
C.the product of y and 3
D.three more than y
A triangle has sides measuring 7 centimeters and 13 centimeters that form an angle measuring 44°. Which of these is CLOSEST to the length of the third side of the triangle? A) 8.1 centimeters B) 8.7 centimeters C) 9.3 centimeters D) 9.9 centimeters
Answer:
9.3 centimeters
Step-by-step explanation:
Martin, his 2 brothers, and his 5 sisters want to fairly share 3 bottles of water. How
much water will Martin get?
Answer:
3/8 bottle
Step-by-step explanation:
Fractions are just division.
Martin + 2sisters + 5bros
= 8 people
3bottles ÷ 8people
= 3/8 bottles per person
Martin is a person, so he gets 3/8 of a bottle, if they all share equally.
Using proportions, it is found that Martin will get 0.375 of a bottle.
This question is solved by proportions, using a rule of three.Martin, his 2 brothers and 5 sisters combine to represent 8 people, which will share 3 bottles equally. How much will Martin, which is one person, get?The rule of three is:
1 person - x bottles
8 people - 3 bottles
Applying cross multiplication:
[tex]8x = 3[/tex]
[tex]x = \frac{3}{8}[/tex]
[tex]x = 0.375[/tex]
Martin will get 0.375 of a bottle.
To learn more about proportions, you can take a look at https://brainly.com/question/24372153
Help again please ?? I have 5 more that needs to be answer also ..
a manufacturer has the following quality control check at the end of a production line. if at least 8 of 10 randomly picked articles meet all specifications, the whole shipment is approved. if in reality, 85% of a particular shipment meets all specifications, what is the probability that the shipment will make it through the control check?
Using the binomial distribution, it is found that there is a 0.8202 = 82.02% probability that the shipment will make it through the control check.
For each article, there are only two possible outcomes, either it meets the specifications, or it does not. The probability of an article meeting the specifications is independent of any other article, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.In this problem:
10 articles are picked, hence [tex]n = 10[/tex].85% of the articles meets all specifications, hence [tex]p = 0.85[/tex]The probability is:
[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]
Then:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 8) = C_{10,8}.(0.85)^{8}.(0.15)^{2} = 0.2759[/tex]
[tex]P(X = 9) = C_{10,9}.(0.85)^{9}.(0.15)^{1} = 0.3474[/tex]
[tex]P(X = 10) = C_{10,10}.(0.85)^{10}.(0.15)^{0} = 0.1969[/tex]
[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.2759 + 0.3474 + 0.1969 = 0.8202[/tex]
0.8202 = 82.02% probability that the shipment will make it through the control check.
For more on the binomial distribution, you can check https://brainly.com/question/24863377