Answer:
The amount of potential energy is increasing when they jump on the board. The amount of potential energy is decreasing and the amount of kinetic energy is increasing when they are falling towards the water. The point of maximum kinetic energy is right before they splash into the water. The point of maximum potential energy is when they jump the highest into the air.
Explanation:
The points of maximum potential energy when they jump highest into the air, their potential energy is at its highest.
What is potential energy?Potential energy develops in systems where the configuration, or relative position of the pieces, determines the amount of the forces they exert on one another. Potential energy directly proportional to height of object higher the object higher the potential energy with respect to same reference point.
When they jump onto the board, potential energy is building. When they are descending toward the sea, their potential energy is dwindling and their kinetic energy is rising. Just before they splash into the water is when they have the most kinetic energy. When they jump highest into the air, their potential energy is at its highest.
Potential energy is highest at its highest point of jump.
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Help please it’s urgent
Answer:
Explanation:
The circuit is incomplete since it is a series circuit
what is kinetic energy
Answer:
energy which a body possesses by virtue of being in motion.
Explanation:
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How do you support adolescent development?
Answer:
Adolescent Development
Adolescence is the period of transition between childhood and adulthood. Children who are entering adolescence are going through many changes. This article offers advice for adolescents and parents to negotiate these changes.
Answer:
How do you support adolescent development?
Explanation:
Parents are a key support for teens during this time of growth and reflection. Be aware of the stages of emotional development, and provide clear guidance at each phase. Acknowledge when to give space and independence to teens. Help guide teens to feel good about themselves.
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I have snap chat if you need it.
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Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?
ANSWER correctly please!!!
A. Being flexible
B. Focusing on the good
C. Maintaining balance
D. Seeking help when needed
Answer:
Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?
Answer
A
Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer, so he is exercising the self-care strategy of being flexible that is in Option A.
What is the significance of "flexible"?Being flexible is an important self-care strategy, as it allows individuals to adjust to and cope with change such as in Andre's case, he had his heart set on being a basketball player, but when that didn't work out, he chose to be flexible and open to new possibilities, worked hard, and also Being flexible can help reduce stress and improve well-being because it allows someone to approach situations with a more positive and open mindset.
Hence, Andre is exercising the self-care strategy of being flexible, which is in Option A, as he didn't make the basketball team as a player this year.
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an Alaskan rescue plane traveling 59 m/s drops a package of emergency rations from w height of 168 m to a stranded party of explorers.
the accelerating of gravity is 9.8 m/s^2.
where does the package strike the ground relative to the point directly below where it was released? answer units of m
A framed picture hangs from two cords attached to the ceiling. Which shows the correct free body diagram of the hanging picture?
Answer: the answer is in the picture
Explanation:
Answer:
C
Explanation:
i did the test and got 100 :)
A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-
kilometer radius of its warehouse. What was the magnitude of its average acceleration?
Answer: The Answer is A 1.2 x 10−2 m/s2
The average acceleration of the delivery drone as it slowed down was -0.012 m/s².
What is average acceleration?The average acceleration is defined as the average rate of change of velocity with respect to time. Mathematically -
a = Δv/Δt
Given is a delivery drone that uniformly slows down from 45 m/s to 23 m/s in a straight line over a 30-minute duration.
We can write -
[u] = 45 m/s
[v] = 23 m/s
Δt = 30 min = 30 x 60 = 1800 sec
We can write the average acceleration as -
a = Δv/Δt
a = (23 - 45)/1800
a = - 0.012 m/s²
Therefore, the average acceleration of the delivery drone as it slowed down was -0.012 m/s².
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A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram above.
The student records observations of how much force it takes to hold the horseshoe magnet in place at each distance. Observations
• 20 cm: no force required
• 10 cm: small force required; easy to hold in place
• 5 cm: large force required; very difficult to hold in place
What do the student's observations demonstrate?
A. The electromagnet's magnetic field becomes stronger as more magnetic material is added to it.
B. The electromagnet's magnetic field is stronger as more turns are added to the wire on the nail.
C. The electromagnet's magnetic field becomes stronger as a small amount of strength is added to the system by the battery.
D. The electromagnet's magnetic field is stronger close to it than far from it.
The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.
Answer:
D. The electromagnet's magnetic field is stronger close to it than far from it.
Please see the image
Answer:
i think it is 89
what is digital vernier calliper
Answer:
a precision instrument for taking extremely precise measurements. It's the newest advancement in caliper technology.
Explanation:
A 3520 kg truck moving north at
18.5 m/s makes an INELASTIC
collision with an 1480 kg car
moving east. After colliding, they
have a velocity of 13.6 m/s at
72.6°. What was the initial velocity
of the car?
Answer: 13.7 m/s
Explanation:
[tex]$$Mass of $T r u c k$$ \ \left(m_{T}\right)=3520\mathrm{kg}[/tex]
[tex]V_{T_{y}}=18.5 \mathrm{~m} / \mathrm{s} \\&V_{\text {Tix }}=0 \mathrm{~m} / \mathrm{s}[/tex]
[tex]\mathrm{Mass \ of \ car \ (m_c) = 1480 \ kg}[/tex]
[tex]V_{c i x}=\text { ? ; } V_{c i y}=0 \mathrm{~m} / \mathrm{s}[/tex]
[tex]Final \ velocity $\left(V_{f}\right)=13.6 \mathrm{~m} / \mathrm{s} \ \ \theta=72.6$[/tex]
[tex]v_{f x}=v_{f} \cos \theta=(13.6) \cos 72.6=4.067 \mathrm{~m} / \mathrm{s}[/tex]
[tex]\mathrm {Using \ the \ conservation \ of \ momentum \ along\ the \ $x$-axis}[/tex]
[tex]\begin{aligned}m_{T} v_{T i x}+m_{c} v_{c_{i x}} &=\left(m_{T}+m_{c}\right) v_{f x} \\0+(1480) V_{c_{i x}} &=(3520+1480)(4.067) \\(1480) v_{c i x} &=20335 \\V_{c i x} &=13.7 \mathrm{~m} / \mathrm{sec}\end{aligned}[/tex]
Answer:
13.7 m/s
Explanation:
Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are horizontal. While he is pushing the package, it moves in a straight line with constant 0.6 m/s speed. Please ignore air-resistance and make sure to justify your answers to the questions below.
a) (10 points) Write down as much information as you can about the main horizontal forces exerted on the package (names, directions, and if enough information is given, numerical values).
b) (10 points) Write down as much information as you can about the main vertical forces exerted on the package (names, directions, and whenever possible, if enough information is given, numerical values).
c) (5 points) How far did the package move during 3 seconds of pushing? Explain
d) (5 points) What was the package’s acceleration during that time? Explain
2
a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.
b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
c. The package moves 1.8 m
d. The package's acceleration is 0 m/s²
a. The horizontal forcesThe push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a
Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.
Also, a frictional force also acts to oppose the motion of the package.
Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.
Let
F = push force and f = frictional forceSo, F - f = 0
F = f
= 150 N
So, the frictional force is 150 N and opposite to the push.
So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.
b Vertical forces on package
The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.
The direction of the weight is downwards while the direction of the normal force is upwards.
Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.
Let W = weight of package = mg where m = mass of package = 50 kg and g = acceleration due to gravity = 9.8 m/s² and N = normal forceSo, the net force N - W = 0
N = W
= mg
= 50 kg × 9.8 m/s²
= 490 N
So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
c. Distance package moves
The package moves 1.8 m
Since distance, d = vt where
v = velocity = 0.6 m/s and t = time = 3 sSo, d = vt
= 0.6 m/s × 3 s
= 1.8 m
So, the package moves 1.8 m
d. The package's acceleration
The package's acceleration is 0 m/s²
Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where
m = mass of package and a = acceleration of packageSince F = 0,
ma = 0
a = 0
So, the package's acceleration is 0 m/s²
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students in a lab are doing experiments involving the motion of objects. they pull an object across a table and use a detector to measure the acceleration of the object for the entire time they pull it. The graph shows the data from the detector, with four segments labeled
Based on the acceleration-time graph, the segments of the motion in which the object experience a net force are both 1 and 3.
What is Newton's Second Law of Motion?Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.
How to calculate the net force.Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:
[tex]F=ma =\frac{m(v\;-\;u)}{t}[/tex]
Where:
m is the mass.t is the time.u is the initial velocity.u is the final velocity.a is the acceleration.Note: Mass represents the conversion factor between net force and acceleration on an acceleration-time graph.
Based on the acceleration-time graph, the segments of the motion in which there is a net force acting on the object are both 1 and 3 while it experienced constant acceleration at segment 2 and 4.
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Suppose a radio signal travels from Earth and through space at a speed of 3.0 × 108 m/s. How far into space did the signal travel during the first 33.3 minutes?
For a radio signal that travels from Earth and through space at a speed of 3.0 × 108 m/s, The distance into space the signal traveled during the first 33.3 minutes is mathematically given as
d=647352m
How far into space did the signal travel during the first 33.3 minutes?Generally, the equation for the distance is mathematically given as
d=v*t
Where
t=33.3min
t=33.3*60
t=1998sec
Therefore
d=3.0 × 108 m/s *1998sec
d=647352m
In conclusion, distance is
d=647352m
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Match each description with the correct graph
Answer: 1. B, 2. A, 3. C, 4. D
Answer:
1 = B
2 = A
3 = C
4 = D
I hope this helps
The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 and kinetic=0.3. Assume both blocks are attached together. Determine if the block system will slide down or not.
Coefficient of static friction = 0.5Coefficient of Kinetic friction = 0.3Angular velocity = 500 RPMsThe Radius of the System
Let R be the radius of cylinder
[tex]m_a + m_b = 4 + 3 = 7kg[/tex]
The angular velocity is 500 RPMs
[tex]\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R[/tex]
The normal force
[tex]f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm[/tex]
Since the radius is very little for two block to execute circular motion so system will slide down.
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Now imagine everyone in the group hug starts moving away from each other what effect do you think that would have on your temperature
temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.
What is Temperature?Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).
Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.
As opposed to extensive characteristics, like mass or volume, temperature is referred to as an intense property—one that is independent of the quantity of matter being considered—along with pressure, density, and other comparable properties.
Therefore, temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.
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An object is swung in a horizontal circle on a length of string
that is 0.93 m long. Its acceleration is 26.36 m/s? What is the
time it takes the object to complete one horizontal circle?
Answer: either 3.20s or 1.18s
Explanation:
The GPE for a 45 KG person at the top of a 2m slide
Answer:
22.5 J
Explanation:
GPE=wxh- 45kg divided by 2m= 22.5
Which of the following is a poor conductor?
metal
Quarters
Ob
O
Od
C
wood
iron
8. When are children MOST likely to begin using words to express meaning?
1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his trip
take?
Answer:
His trip took 5.78 seconds
Explanation:
23.7m divided by 4.1m/s = 5.78048780488
A pulley in the form of a uniform disk)
with mass 63 kg and a radius 20 cm is at-
tached to the ceiling in a uniform gravita-
tional field and rotates with no friction about
its pivot. The masses are connected by a
massless inextensible cord and T1, T2, and T3
are magnitudes of the tensions.
T3
20 cm
T2
63 kg
1
39 kg
T1
3.8 m
15 kg
2
What is the magnitude of the tension T?
The acceleration due to gravity is 9.8 m/s?.
Assume up is positive.
Answer in units of N.
For a pulley in the form of a uniform disk with a mass of 63 kg and a radius of 20 cm, the magnitude of the tension T is mathematically given as
T1=292.4N
What is the magnitude of the tension T?For 20kg
T1=196+20a
For
33kg
T2=323.4-33a
Generally, the simultaneous equation is mathematically given as
T2-T1=(323.4-33a)-(196+20a)
Hence
127.4-53.a
a=1.67m/s^2
T1=196+20(1.67)
T1=292.4N
In conclusion, the magnitude of the tension T
T1=292.4N
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A well substantiated explanation, or, a group of common ideas intended to
explain something. *
O Inference
Theory
Hypothesis
Inertia
Explain how the movement of the Moon around the Earth c langes we see at night?
Answer: We can see the moon at night because the earth spins in a circle wall it is going around the sun so when the sun go down and the moon comes up the suns light will go over the top of earth and hite the moon the all the light that is hite the moon will bounce off it and the moon it a light color and light shins off lighter colored thing and it will have a little proportion of that light will come and hite earth make the moon very easy to see at night and the most light hits the moon when if it a full moon and is the most brite.
I Hope This Helped!
HELP PLEASE!!!!!!!!!
Answer:
2.00×[tex]10^{8}[/tex]
Explanation:
3×[tex]10^{8}[/tex]/1.5
=2.00×[tex]10^{8}[/tex]
there is a rusted nut we have a two spanners each of i 15 cm and 20 CM respectively which spanner is suitable to open the nut and why
20cm spanner is suitable to open this nut , Because we feel easy to apply force at the end of spanner to rusted nut. It means that as the perpendicular distance between force and axis of rotation increase the magnitude of moment also increase.
I think the Answer will helps you.....
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11. Differentiate between refraction of light and dispersion of light.
Answer:
Refraction refers to any bending of waves due to a change in speed. In the case of light being refracted by a prism, dispersion means that the higher the frequency light bends more. In short, Refraction is the bending of light and Dispersion is the frequency dependece of this behaviour.
Is the moon always showing up at the same time?
Answer:
the moon showing up at same time as what
Explanation:
???
IP A tow rope, parallel to the water, pulls a water skier directly behind the boat with constant velocity for a distance of 75 m before the skier falls. The tension in the rope is 100 N.
Is the work done on the skier by the rope positive, negative, or zero?
Explain.
Calculate the work done by the rope on the skier.
The work is done against the skier, we call it negative work, and the magnitude of the work done on the skier by the rope is 7500 J.
Work done on the skier
The work done on the skier by the rope is in opposte direction of the water skier which caused the water skier to fall after some given period of time. Since the work is done against the skier, we call it negative work.
The magnitude of the work done on the skier by the rope is calculated as follows;
W = Fd
where;
F is the applied force on the rope
d is the distance moved by the skier
W = 100 x 75
W = 7500 J
Thus, the magnitude of the work done on the skier by the rope is 7500 J.
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