The variance of the scores on a skill evaluation test is 143,641 with a mean of 1517 points. If 343 tests are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 36 points

Answer:

2x + 3y -3=0

Step-by-step explanation:

The given equation of the line is ,

[tex]\implies 2x - 3y = 13 [/tex]

Now convert it into slope intercept form to get the slope , we get ,

[tex]\implies 3y = 2x - 13 \\\\\implies y =\dfrac{2}{3}x -\dfrac{13}{2}[/tex]

Therefore the slope is ,

[tex]\implies m = \dfrac{2}{3} [/tex]

We know that the product of slope of perpendicular lines is -1 . Therefore the slope of the perpendicular line will be ,

[tex]\implies m_{perpendicular}= -\dfrac{2}{3} [/tex]

Now one of the point is (-6,5) .On Using point slope form , we have ,

[tex]\implies y-y_1 = m( x - x_1) \\\\\implies y - 5 = -\dfrac{2}{3}( x + 6 ) \\\\\implies 3y - 15 = -2x -12

\\\\\implies 2x + 3y -15+12=0 \\\\\implies \underline{\underline{ 2x + 3y -3=0 }}[/tex]

Answer:

y = - [tex]\frac{3}{2}[/tex]x - 4

Step-by-step explanation:

2x – 3y = 13

3y = 2x + 13

y = [tex]\frac{2}{3}[/tex]x + [tex]\frac{13}{3}[/tex]

slope = 2/3

negative reciprocal = -3/2

y = -3/2x + b

(-6, 5)

5 = (-3/2)(-6) + b

5 = 9 + b

b = -4

y = -3/2x - 4

Hello,

there are 5 differents sums:

16,18,20,22,24.

-------------------------------------------------------

Dim i As Integer, j As Integer, k As Integer, l As Integer, u As Integer, v As Integer, nb As Integer

Dim mat(4, 4) As Integer

nb = 0

For i = 1 To 4

   For j = 1 To 4

       If j <> i Then

           For k = 1 To 4

               If k <> j And k <> i Then

                   l = 10 - k - j - i

                   If l > 0 And l < 5 And l <> i And l <> j And l <> k Then

                       mat(1, 1) = i

                       mat(1, 2) = j

                       mat(1, 3) = k

                       mat(1, 4) = l

                       For u = 2 To 4

                           For v = 1 To 4 - u + 1

                               mat(u, v) = mat(u - 1, v) + mat(u - 1, v + 1)

                           Next v

                       Next u

                       'Call visu(mat())

                       nb = nb + 1

                       Print nb,

                       mat(4, 1)

                   End If

               End If

           Next k

       End If

   Next j

Next i

End

Sub visu (m() As Integer)

   Dim i As Integer, j As Integer

   For i = 1 To 4

       For j = 1 To 4 - i + 1

           Print m(i, j);

       Next j

       Print

   Next i

End Sub

This is one single number. The number is slightly larger than 163 thousand.

====================================================

Explanation:

Consider four slots labeled A,B,C,D

We have....

There's a countdown going on (46,45,44,43) when filling up the slots. This countdown is because we cannot reselect any specific person for multiple slots at the same time.

If order mattered, then we'd have 46*45*44*43 = 3,916,440 permutations possible.

However, order doesn't matter. For any group of 4 people, there are 4! = 4*3*2*1 = 24 ways to arrange them. So we must divide the previous result over 24 to get (3,916,440)/24 = 163,185

This means there are 163,185 different combinations and this is the number of possible samples of size 4 from a population of 46 people. The order of any sample doesn't matter.

Answer:

bottom graph

Step-by-step explanation:

f(x) = |3q-6|

because you have absolute value there are 2 possibilities

y= +(3q-6) and y= -(3q-6)

to find where the graph intersects the x-axis make y=0 because there the y coordinate is 0, so we have...

3q-6 =0 and -3q+6 =0

3q= 6 and -3q =-6

q=2 and q=2

the bottom graph has the intersection with x-axis only at 2, so is the correct one

9514 1404 393

Answer:

  bottom graph shown

Step-by-step explanation:

It can be helpful to rearrange the equation to either of the equivalent forms ...

  f(x) = |3(x -2)|

or ...

  f(x) = 3|x -2|

_____

The first of these forms represents a horizontal compression of the absolute value function by a factor of 3, then a right-shift by 2 units. This matches the bottom graph shown.

__

The second of these forms represents a horizontal right-shift by 2 units, and a vertical expansion by a factor of 3. This matches the bottom graph shown.

__

The attached graph shows the function given here along with the absolute value parent function.

_____

Additional comment

The transformations we're usually interested in are ...

g(x) = k·f(x) . . . . vertically scaled (stretched) by a factor of k

g(x) = f(kx) . . . . .horizontally compressed by a factor of k

g(x) = f(x) +k . . . shifted up by k units

g(x) = f(x -k) . . . . shifted right by k units

In many cases, as here, horizontal scaling and vertical scaling are indistinguishable as to which caused a given effect.

Answer:

[tex]14x cos(\frac{1}{15}x^{2})=14 \sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k+1}}{(2k)!15^{2k}}[/tex]

Step-by-step explanation:

In order to find this Maclaurin series, we can start by using a known Maclaurin series and modify it according to our function. A pretty regular Maclaurin series is the cos series, where:

[tex]cos(x)=\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{2k}}{(2k)!}[/tex]

So all we need to do is include the additional modifications to the series, for example, the angle of our current function is: [tex]\frac{1}{15}x^{2}[/tex] so for

[tex]cos(\frac{1}{15}x^{2})[/tex]

the modified series will look like this:

[tex]cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}(\frac{1}{15}x^{2})^{2k}}{(2k)!}[/tex]

So we can use some algebra to simplify the series:

[tex]cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}(\frac{1}{15^{2k}}x^{4k})}{(2k)!}[/tex]

which can be rewritten like this:

[tex]cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k}}{(2k)!15^{2k}}[/tex]

So finally, we can multiply a 14x to the series so we get:

[tex]14xcos(\frac{1}{15}x^{2})=14x\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k}}{(2k)!15^{2k}}[/tex]

We can input the x into the series by using power rules so we get:

[tex]14xcos(\frac{1}{15}x^{2})=14\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k+1}}{(2k)!15^{2k}}[/tex]

And that will be our answer.

Answer:

{-6,0,2,4}

Step-by-step explanation:

Answer:

ok so if she gets paid 372 we just multiply this by 4 since there's 4 weeks in a month then we multiply by 4 so

372*4*12=17856

now we just multiply 831.33 by 2 since she is paid semimonthly and we multiply by 12

831.33*2*12=19951.92

now we just subtract

19951.92-17856=2095.92

so she gets paid 2095.92 more dollars per year

Hope This Helps!!!

Answer:

74 inches

Step-by-step explanation:

1 foot is 12 inches, so 6 x 12 = 72, and just add the other 2 inches to get 74 inches.

Answer:

74 inches.

Step-by-step explanation:

Each foot has 12 inches, so multiply 6 by 12 to get 72 inches. Then add the remaining two inches to get a total of 74 inches.

Answer:

ab = 21

Step-by-step explanation:

[tex](a - b)^2 = (a^2 + b^2 ) - 2ab\\\\4^2 = 58 - 2ab\\\\16 - 58 = - 2ab\\\\- 42 = - 2ab\\\\ab = \frac{-42}{-2} = 21[/tex]

Step-by-step explanation:

Th value of ab is 21

Explanation is in the attachment

hope it is helpful to you ☺️

thank you for giving me a chance to answer your question

Answer:

I think the answer is 100 because nothing greater than 200 if its rounded hope this helped if not sorry

Answer:

The answer is 65

Step-by-step explanation:

Evaluate:

8x + 9

When x = 7

Use PEMDAS order of operations:

8x + 9

= 8(7) + 9

= 56 + 9

= 65

Hope this helps

Answer:

[tex]P = 8 + 2\sqrt{26}[/tex]

Step-by-step explanation:

Given

[tex]W = (-2, 4)[/tex]

[tex]X = (2, 4)[/tex]

[tex]Y = (1, -1)[/tex]

[tex]Z = (-3,-1)[/tex]

Required

The perimeter

First, calculate the distance between each point using:

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2[/tex]

So, we have:

[tex]WX = \sqrt{(-2- 2)^2 + (4-4)^2 } =4[/tex]

[tex]XY = \sqrt{(2- 1)^2 + (4--1)^2 } =\sqrt{26}[/tex]

[tex]YZ = \sqrt{(1- -3)^2 + (-1--1)^2 } =4[/tex]

[tex]ZW = \sqrt{(-3--2)^2 + (-1-4)^2 } =\sqrt{26}[/tex]

So, the perimeter (P) is:

[tex]P = 4 + \sqrt{26} + 4 + \sqrt{26}[/tex]

[tex]P = 8 + 2\sqrt{26}[/tex]

Answer:

its D.

Step-by-step explanation:

took test

Answer:

D

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

Answer:

B. angle with the greatest measure

opposite the largest angle

Step-by-step explanation:

how many layers of bricks are used ?

also, I assume, the thickness of bricks means actually their height when laid.

but still, I cannot answer that, as nothing indicates if there is only one layer of bricks or 2 or 3 or 4 or ...

Answer:

hey hi mate

Ur answer is

Step-by-step explanation:

u have to think

hope u like it

plz mark it as brainliest

tiene 40 años de edad

bond 40

jude 20

joh 30

40+20+30 = 90

Answer:

ii

Step-by-step explanation:

you have to look and read it it comes simple

Answer:

67. A

68. D

Step-by-step explanation:

I don't remember exactly the explanation, but I recommend you try to learn more about number lines sometime when you aren't under stress from schoolwork, because they're pretty simple questions to answer once you get a better understanding of them!

Answer:

The right answer is "0.3193".

Step-by-step explanation:

According to the question,

Mean,

[tex]\frac{1}{\lambda} = 13[/tex]

[tex]\lambda = \frac{1}{13}[/tex]

As we know,

The cumulative distributive function will be:

⇒ [tex]1-e^{-\lambda x}[/tex]

hence,

In the first 5 years, the probability of failure will be:

⇒ [tex]P(X<5)=1-e^{-\lambda\times 5}[/tex]

                    [tex]=1-e^{-(\frac{1}{13} )\times 5}[/tex]

                    [tex]=1-e^(-\frac{5}{13})[/tex]

                    [tex]=1-0.6807[/tex]

                    [tex]=0.3193[/tex]

Answer:

Purplemath

Introduces reflections in the x- and y-axes. ... To see how this works, take a look at the graph of h(x) = x2 + 2x – 3. ... The previous reflection was a reflection in the x-axis. ... f (x – b) shifts the function b units to the right.

Step-by-step explanation:

f(x) = 3 - 4x

f(1+a)= 3-4(1+a)

=3-4+4a

=4a-1

Answer:

ur answer is correct

A =xy

A = 1.6×0.3 = 0.48

(Q.1)

[tex]y = \dfrac{C - e^x}{2x} \implies y' = \dfrac{-2xe^x-2C+2e^x}{4x^2} = \dfrac{-xe^x-C+e^x}{2x^2}[/tex]

Then substituting into the DE gives

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{2\left(\dfrac{C-e^x}{2x}\right) + e^x}{2x}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{C-e^x + xe^x}{2x^2}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = \dfrac{-C+e^x - xe^x}{2x^2}[/tex]

and both sides match, so y is indeed a valid solution.

(Q.2)

[tex]\ln\left(y^x\right)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

This DE is separable, since you can write [tex]\ln\left(y^x\right)=x\ln(y)[/tex]. So you have

[tex]x\ln(y)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

[tex]\dfrac{\ln(y)}y\,\mathrm dy = 3x\,\mathrm dx[/tex]

Integrate both sides (on the left, the numerator suggests a substitution):

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 + C[/tex]

Given y (2) = e ³, we find

[tex]\dfrac12 \ln^2(e^3) = 6 + C[/tex]

[tex]C = \dfrac12 \times3^2 - 6 = -\dfrac32[/tex]

so that the particular solution is

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 - \dfrac32[/tex]

[tex]\ln(y) = \pm\sqrt{3x^2 - 3}[/tex]

[tex]\boxed{y = e^{\pm\sqrt{3x^2-3}}}[/tex]

(Q.3) I believe I've already covered in another question you posted.

Answer:

Answer:

Hello?

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

3^0

Anything raised to the zero power is 1

3^0 =1

Answer:

1

Step-by-step explanation:

Anything to the power of 0 is 1

Eg: 5⁰ = 1

a⁰= 1

(-12)⁰ = 1

Answer:

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Step-by-step explanation:

Marla scored 70% on her last unit exam in her statistics class.

This means that in her statistics class, Marla got 70% of her test correct.

When Marla took the SAT exam, she scored at the 70th percentile in mathematics.

This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.

Explain the difference in these two scores.

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Step-by-step explanation:

[tex]\tan^2 \theta - 3\tan \theta + 2 = 0[/tex]

Let [tex]x = \tan \theta[/tex]

We can then write

[tex]x^2 -3x + 2 = 0\:\:\Rightarrow\:\:(x - 2)(x - 1) = 0[/tex]

or

[tex](\tan \theta - 2)(\tan \theta - 1) = 0[/tex]

The zeros occur when

[tex]\tan \theta = 2\:\:\:\text{or}\:\:\:\tan \theta = 1[/tex]

or when [tex]\theta = 63.4°[/tex] or [tex]\theta = 45°[/tex].

Answer:

different days of the week Do not have the same frequency.

Step-by-step explanation:

Given the data:

Observed values :

Monday (114); Tuesday (152); Wednesday (160); Thursday (164); Friday (179); Saturday (196); Sunday (130).

H0 : frequency are the same

H1 : frequency is not the same

Expected value is the same for all days:

Σ (observed values) * 1/ n

n = number of days in a week. = 7

Expected value = (114+152+160+164+179+196+130) / 7 = 156.428

χ² = Σ (observed - Expected)²/Expected

χ² = (11.508 + 0.125 + 0.082 + 0.366 + 3.257 + 10.01 + 4.465)

χ² = 29.813

The Pvalue(29.813, 6) ;

df = 7 - 1 = 6

The Pvalue(29.813, 6) = 0.000043

α = 0.01

Since, Pvalue < α ; Reject H0 ; and conclude that, different days of the week Do not have the same frequency.

Answer:

The answer is A

Step-by-step explanation:

Hope this helps