The heat (kJ) released to the surroundings : -70.56 kJ
Further explanationReaction
CH₄(g) + 3Cl₂(g) → CHCl₃(l) + 3HCl(g) ΔH°=-336 kJ
For 3 mol HCl formed ⇒ ΔH°=-336 kJ
23.0 g of HCl :
mol[tex]\tt \dfrac{23}{36.5}=0.63[/tex]
Heat released for 0.63 mol HCl :
[tex]\tt \dfrac{0.63}{3}\times -336=-70.56~kJ[/tex]
The heat (kJ) released to the surroundings at the given equation is 70.7KJ.
The calculation is as follows:We know that
[tex]Moles\ or\ HCl\ formed = mass \div molar\ mass\\\\= 23.0\div 36.46[/tex]
= 0.631 mole
Since energy should be related at the time when 3 moles of HCI should be generated = 336 K
Now energy released is
[tex]= (336\div 3)\times 0.631[/tex]
= 70.65 kJ
Hence we can conclude that heat released to the surrounding is 70.7 kJ.
Learn more: brainly.com/question/17127206
The heat of vaporization of acetic acid is . Calculate the change in entropy when of acetic acid condenses at .
The question is incomplete, the complete question is;
The heat of vaporization ΔHv of acetic acid HCH3CO2 is 41.0 /kJmol. Calculate the change in entropy ΔS when 954.g of acetic acid condenses at 118.1°C. Be sure your answer contains a unit symbol. Round your answer to 3 significant digits.
Answer:
-1.67 JK-1
Explanation:
Since Heat of vaporization of acetic acid = 41.0 kJ/mol
Therefore:
Heat of condensation of acetic acid = -41.0 kJ/mol
Mass of acetic acid = 954 g
Temperature of condensation = 118.1 °C or 391.1 K
Number of moles of acetic acid = 954 g/60g/mol = 15.9 moles
Heat evolved during condensation = 15.9 moles * -41.0 kJ/mol = -651.9 KJ
Entropy change (ΔS) = Heat evolved/ Temperature = -651.9 KJ/391.1 K
Entropy change (ΔS) = -1.67 JK-1
How many milliliters of a 12-molar HCl must be diluted to obtain 2.0 liters of 3.0-molar HCl?
Answer: 500ml
Explanation:
Using the Dilution formula that
C₁V₁=C₂V₂
Where
C₁=the molarity of concentrated solution
= 12 M
V₁ = Volume of the concentrated solution
=?
C₂=the molarity of the diluted solution
=3.0M
V₂= Volume of the diluted solution= 2 liters
Changing 2 liters to millilitres
1000ml= 1 Liters
2Liters=2000ml
Bringing the formulae and inputting the given values
C₁V₁=C₂V₂
12 x V₁= 3.0 x 2000ml
V₁= 3.0 x 2000 / 12
V₁=500ml
Therefore 500ml of 12-molar HCl mst be diluted to obtain 2 Liters of 3.0 Molar HCl.
Each molecule of lycopene contains 40 atoms of carbon (plus other atoms). The mass percent of carbon in lycopene is 84.49%. What is the molar mass of lycopene?a. 1137.2 g/mol
b. 405.9 g/mol
c. 480.4 g/mol
d. 473.4 g/mol
e. 568.6 g/mol
Answer: 568g/mol
Explanation:
It should be noted that there are 40 atoms of carbon in lycopene.
Since mass of 1 carbon = 12g/mol
Mass of 40 carbon atoms = 40 × 12g/mol = 480g/mol
Let the molar mass of lycopene be represented by x.
Therefore the molar mass of carbon = x × mass percent of carbon in lycopene
x × 84.49% = 480g/mol
x × 0.8449 = 480g/mol
x = 480/0.8449
x = 568g/mol
The molar mass of lycopene is 568g/mol
Compounds of copper(II) are generally colored, but compounds of copper(I) are usually colorless. Use crystal field theory to explain why this is true.
Answer:
See explanation
Explanation:
The crystal field theory assumes the interaction between the central metal ion and ligands to be purely electrostatic.
The five d orbitals remain degenerate until they are surrounded by ligands which split the degeneracy of the d orbitals depending on the crystal fields formed to give either square planar, octahedral, tetrahedral or other kinds of crystal fields.
The electronic configuration of Cu II ion is 1s2 2s2 2p6 3s2 3p6 3d9. Its colour arises from an incomplete d orbital which makes d - d electron transition possible.
On the other hand, the electron configuration of copper I is 1s2 2s2 2p6 3s2 3p6 3d10. We can see that the d orbital is completely filled. Hence copper I ion has no color due to its completely filled d- orbitals
Which is produced in a synthesis reaction?
A) a single element
B) single compound
C) single ion
D) single atom
Answer:
A single compound is produced in a synthesis reaction.
Explanation:
What are chemical reactions?
Chemical reactions are when two or more reactants chemically react with one another to create one or more substances as products. There are five types: synthesis, decomposition, single-replacement, double-replacement, and combustion.
Types of Reactions and Examples of Each
A synthesis reaction takes two or more reactants and reacts chemically to turn them all into one substance.
An example of a synthesis reaction is the reaction that takes place between sodium (Na) and chlorine (Cl) to create table salt.This reaction would be displayed as [tex]{\text{Na} + \text{Cl} \rightarrow \text{NaCl}}.[/tex]The parent reaction for a synthesis reaction is [tex]\text{A} + \text{B} \rightarrow \text{AB}.[/tex]A decomposition reaction takes one reactant and breaks itself into two or more products.
An example of a decomposition reaction would be the decomposition of hydrogen (H₂) and oxygen (O) to create two diatomic molecules - H₂ + O₂. This reaction would be displayed as [tex]\text{H}_{2}\text{O} \rightarrow \text{H}_{2} + \text{O}_{2}.[/tex]The parent reaction for a decomposition reaction is [tex]\text{AB} \rightarrow \text{A} + \text{B}[/tex].A single-replacement reaction takes place when two compounds chemically combine but one of the elements bonds with a different element.
An example of a single-replacement reaction would be the single-replacement of calcium and water to create calcium hydroxide and dihydrogen.This reaction would be displayed as [tex]\text{Ca} + \text{H}_{2} \text{O} \rightarrow \text{CaO} + \text{H}_{2}.[/tex]The parent reaction for a single-replacement reaction is [tex]\text{A} + \text{BX} \rightarrow \text{AX} + \text{B}.[/tex]A double-replacement reaction works in the same way as a single-replacement reaction - however, instead of one replacement, there are two replacements.
An example of a double-replacement reaction would be the double-replacement of sodium bicarbonate (baking soda) and vinegar to produce carbonic acid and sodium acetate.This reaction would be displayed as [tex]\text{NaHCO}_{3} + \text{HC}_{2} \text{H}_{3} \text{O}_{2} \rightarrow \text{NaC}_{2} \text{H}_{3} \text{O}_{2} + \text{H}_{2} \text{O} + \text{CO}_{2}.[/tex]The parent reaction for a double-replacement reaction is [tex]\text{AX} + \text{BY} \rightarrow \text{AY} + \text{BX}.[/tex]A combustion reaction is the introduction of heat or energy and oxygen to decompose reactants into carbon dioxide and water.
An example of a combustion reaction would be the burning of propane in a grill.This reaction would be displayed as [tex]\text{C}_{3} \text{H}_{8} + \text{5O}_{2} \rightarrow \text{3CO}_2 + \text{4H}_2 \text{O}.[/tex]The parent reaction for a combustion reaction is [tex]\text{Hydrocarbon} + \text{O} \rightarrow \text{CO}_2 + \text{H}_2 \text{O}.[/tex] A hydrocarbon is a substance that is only hydrogen and carbon.Therefore, based on the above information, we can determine that a single compound, or option B, is the product of a synthesis reaction.
Answer:
single compound
Explanation:
A synthesis reaction will take more than two reactants. It will chemically mix together and then it forms a synthesis reaction. The elements involved are single compounds.
Our answer is single compounds.
The movement of water is able to transport minerals and nutrients. Which statement best explains why water is able to do this?
A. Water has a density of one gram per milliliter
B. Water is an excellent solvent
C. Water absorbs heat energy
D. Water is a liquid at room temperature
Give the name for the molecular compound O3Cl2.
Answer:
dichlorine trioxide
Explanation:
di-2 tri-3 there are three oxygens and two chlorines.
Answer:
Dichlorine Trioxide
Explanation:
The molar mass and molecular weight of Cl2O3 is 118.904.
Which is the largest number? O A. 2.2 x 108 O B. 2.9 O C. 2.5 x 10-5 D. 2.8 x 106
Answer:
2.2 x 10⁸
Explanation:
We are to find the largest number from the given set of numbers:
2.2 x 10⁸
2.9
2.5 x 10⁻⁵
2.8 x 10⁶
The largest number is the first one; 2.2 x 10⁸ ;
2.2 x 100 000 000
the other numbers are far lesser than this number;
For Hydrogen bonding H atom needs to be bonded to which other atoms?
Idenify each statement below as either oxidation or reduction.
1.
F + e- ----> F-
2.
2I- ----> I2 + 2e-
Answer:
1 = oxidation
2 = reduction
Explanation:
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
2I- ----> I₂+ 2e⁻
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
F + e⁻ ----> F⁻
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
HELP ME PLEASE I will mark brainliest
Answer:
Nice pic there
Explanation:
No need
according to the law of energy conservation, the total amount of energy is constant, then why does the chemical energy in electric cells got used up?
Answer:
The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.
Explanation:
This means that a system always has the same amount of energy unless it's added from the outside. is the total internal energy of a system.
What property of gases confirms that the space between the particles of gas is significantly larger than when the same substance is in a liquid state?
A. Mobility
B. Reactivity
C. Volatility
D. Compressibility
Answer:
D. Compressibility
Explanation:
If an ideal gas has a pressure of 5.87 atm,
a temperature of 26.86 ∘C,
and a volume of 77.31 L,
how many moles of gas are in the sample?
Answer:
5.87/26.86=77.31/...Explanation:
after solving this u can find the answer in easy way
Sean plated an unknown metal onto his silver earring which initially weighed 1.41 g. He constructs an electrolytic cell using his ring as one of the electrodes. After running the cell, 0.022 moles of the unknown metal was plated onto his ring and the mass of the ring increased to 3.952 g. What is the atomic weight of the unknown metal in g/mol
Answer:
115 g/mol
Explanation:
Step 1: Given data
Initial mass of the earring (mi): 1.41 gFinal mass of the earring (mf): 3.952 gMoles of the unknown metal deposited (n): 0.022 molStep 2: Calculate the mass of the unknown metal deposited
An earring is plated in an electrolytic cell. The mass of the unknown metal deposited can be calculated using the following expression.
m = mf - mi
m = 3.953 g - 1.41 g
m = 2.54 g
Step 3: Calculate the molar mass (M) of the unknown metal
0.022 moles of the metal have a mass of 2.54 g. The molar mass of the metal is:
M = m/n
M = 2.54 g / 0.022 mol
M = 115 g/mol
What is an aqueous solution and what does it do?
Answer:
An Aqueous solution is used to reference any solution where water acts as the solvent. A lot of substances can dissolve in water including acids and bases and when they do this they become aqueous solutions.
Aqueous solutions are denoted by the symbol (aq) in solutions as shown in this reaction below where Sodium Chloride is dissolved in water;
NaCl(s) → Na+(aq) + Cl-(aq)
Aqueous solutions are capable of conducting electricity if electrolytes are the ones dissolved in the water.
There are however some substances that cannot form aqueous solutions because they cannot dissolve well in water for example, organic substances like oils.
Find the mass (in g) of 1.00 atom of lead.
Answer:
207g
Explanation:
207.2 to be more specific
Please help me it’s due today at 6:00pm please help me please please
Answer:
a) an opposing force act on it
i hope its true
A 2.4L balloon filled with helium at room temperature 25oC is put into liquid nitrogen
(-196oC). What will the new volume be?
Answer:
V₂ = 0.62 L
Explanation:
Given data:
Initial volume = 2.4 L
Initial temperature = 25°C
Final temperature = -196°C
Final volume = ?
Solution:
Initial temperature = 25°C (25+273 = 298 K)
Final temperature = -196°C ( -196+273 = 77 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 2.4 L × 77 K / 298 k
V₂ = 184.8 L.K / 298 K
V₂ = 0.62 L
If salt water has a density of 1.2 g/mL, which object listed below would SINK? *
Object 1 with a density of 1.14 g/cm3
Object 3 with a density of 1.62 g/cm3
Object 4 with a density of 0.8 g/cm3
Object 2 with a density of 0.92 g/cm3
Draw the structure of the bromohydrin formed when (E)-2-hexene reacts with Br, H20.
Use the wedge hash bond tools to indicate stereochemistry where it exists.
• If the reaction produces a racemic mixture, draw both stereoisomers.
Separate multiple products using the - sign from the drop-down menu.
a
С P
opy to
2
2/10
OOOO. [+
Answer:
See explanation and image attached
Explanation:
The addition of a halohydrin to an alkene proceeds via the bromium cyclic intermediate.
The bromine dissociates heterolytically and attacks the (E)-2-hexene yielding the brominuim ion intermediate. This is now attacked by water with a consequent loss of H^+ to yield the final product.
Since the reaction involves a flat and planar carbocation intermediate, racemization is possible, thereby leading to the two stereoisomers shown in the image attached to this answer.
Calculate the electrical double layer length for pure water at pH 7. Assume temperature is 300K, and give your answer in units of nm.
Answer:
[tex]$\lambda_D =964 \ nm$[/tex]
Explanation:
We know, the double layer length of pure water is given by :
[tex]$\lambda _{D}= \left(\frac{\epsilon k_B T}{2e^2z^2N_AC_i}\right)^{1/2}$[/tex]
[tex]$\lambda _{D}= \left(\frac{(78.3)\times(8.85 \times 10^{-21})\times (1.38 \times 10^{-23})\times 300}{2 \times(1.6 \times 10^{19})^2 \times 1^2 \times (6.023 \times 10^{23})\times (10^{-7}) \times 1000 }\right)^{1/2}$[/tex]
Since, pH = -log [tex]$H^+$[/tex]
[tex]$[H^+]=10^{-7}$[/tex]
[tex]$\lambda_D = \left(93.05 \times 10^_{-14}\right)^{1/2}$[/tex]
[tex]$\lambda_D = \sqrt{93.05} \times 10^{-7}$[/tex]
[tex]$\lambda_D =9.64 \times 10^{-7}$[/tex]
[tex]$\lambda_D =964 \times 10^{-9} \ m$[/tex]
[tex]$\lambda_D =964 \ nm$[/tex]
What bond distance is expected to be longest?
1. A carbon-carbon bond with a bond order of 2
2. A carbon-carbon bond with a bond order of 3
3. A carbon-carbon bond with a bond order of O
4. carbon-carbon bond with a bond order of 1
Answer:
Bond length of C=C is largest(134 pm) because both the carbon atoms have same electronegativity. In case of C=O. and C=N carbon is bonded to highly electronegative atoms so bond length is shoreter as compared to C=C
3. What is the formula for copper (II) iodide?
Cuz12
Cul2
Cul
Cu21
Answer
Cu I ( valance number of copper is 2 and valance number of iodide is 1)
so CuI2 so the answer is B.
How many moles of dinitrogen monoxide are present in 9.3 x 10^22 molecules of this compound?
Answer:
0.15 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities.
From the question we have
[tex]n = \frac{9.3 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.154485...[/tex]
We have the final answer as
0.15 molesHope this helps you
What's is the definition of an atom
Atom, smallest unit into which matter can be divided without the release of electrically charged particles. It also is the smallest unit of matter that has the characteristic properties of a chemical element. As such, the atom is the basic building block of chemistry.
The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into the Periodic Table, where would they go?
group 7
group 6
period 7
period 6
Answer:
period 6
Explanation:
If the lanthanides were inserted into the periodic table, they would go into periodic 6.
Their atomic number is between 57 - 71 from element lanthanum to lutetium.
The elements in this period are 15 in number. They are also know as elements in the f-block.The elements that makes up the series are:
Lanthanum
Cerium
Praseodymium
Neodymium
Promethium
Samarium
Europium
Gadolinium
Terbium
Dysprosium
Holmium
Erbium
Thulium
Ytterbium
Lutetium
Which element has a greater ionization energy?
argon (18) or rubidium (37)
Answer:
Argon
Explanation:
-Ionization energy is the energy that is required to remove an electron.
-Ionization energy increases as you go from left to right the periodic table and decreases as you go from top to bottom of the periodic table.
-The reason why argon has greater ionization energy is because it is very hard to remove as argon is a noble gases. We know noble gases are inactive because they are already stable. If you're stable, you are less likely to gain or lose electron.
A reaction occurs in a calorimeter, resulting in the starting temperature of 38.8 ℃ and final temperature 21.0 ℃. What can you say about the reaction and the enthalpy change (ΔH) during the reaction?
Answer:
hola comoe stas
Explanation:
gracias x los puntos
If scientists managed to produce a plasma on Earth, what might they keep in it?
Answer:The sun's enormous heat rips electrons off the hydrogen and helium molecules that make up the sun. ... Thomas Jefferson National Accelerator Facility
Explanation: