The simulation shows a game of tug-of-war. Place a blue team and a red team with same-sized people on each side of the rope. What can you say about the sizes of the left and right arrows?​

Answers

Answer 1

Answer:

When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:

This is the answer on Plato

Answer 2

Answer:

When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:


Related Questions

how we will gonna solve this question?

0.05cm=_______=mm

Answers

The answer is 0.5mm

Answer:

It would be 0.5 millimeter !

Explanation:

1 cm is equal to 10 mm. You'll just need to move the decimal point over ! :))

Which phrase best describes Osorno?
shield volcano
active volcano
dormant volcano
explosive volcano

Answers

Answer:

dormant

Explanation:

Answer:

dormant

Explanation:

Energy is
A) conserved
OB) created only
OC) destroyed only
OD) created or destroyed

Answers

Conserved.

Your explanation is that energy can be neither created, nor destroyed. Therefor, created wouldn’t be an answer, destroyed, or both. A is the only option left.

Hope this helps.

Answer:

A

Explanation:

Conserving energy produces a higher quality of life. Reduced emissions result in cleaner air quality. In addition, it helps create a healthier planet, or at least helps sustain the resources we already have

Calculate the kinetic energy of a 1 kg object moving at 4.5 ms. Round to the first decimal.

Answers

Answer:

91.21

Explanation:

Kinetic energy =1/2 mv2 substitute the values I. E 1/2 *1 *4.5^2= 91.21

A student is helping his teacher move a 40.0 kg aquarium. What net sideways force must he exert on the aquarium to slide it across the floor so that it accelerates at 0.50 m/s2?

Answers

Answer:

20 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of aquarium = 40 kg

Acceleration (a) = 0.50 m/s²

Force (F) =?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as:

Force (F) = mass (m) × acceleration (a)

F = m × a

With the above, we can obtain the force needed to slide the aquarium as follow:

Mass (m) of aquarium = 40 kg

Acceleration (a) = 0.50 m/s²

Force (F) =?

F = m × a

F = 40 × 0.5

F = 20 N

Therefore, a force of 20 N is needed to slide the aquarium.

A hole is punched at A in a plastic sheet by applying a 660-N force P to end D of lever CD, which is rigidly attached to the solid cylindrical shaft BC. Design specifications require that the displacement of D should not exceed 15 mm from the time the punch first touches the plastic sheet to the time it actually penetrates it. Determine the required diameter of shaft BC if the shaft is made of a steel with G.

Answers

Answer:

hello your question lacks some data and required diagram

G = 77 GPa,  т all = 80 MPa

answer : required diameter = 252.65 * 10-^3 m

Explanation:

Given data :

force ( P )  = 660 -N force

displacement = 15 mm

G = 77 GPa

т all = 80 MPa

i) Determine the required diameter of shaft BC

considering the vertical displacement ( looking at handle DC from free body diagram )

D' = 0.3 sin∅  ,   where D = 0.015

hence ∅ = 2.8659°

calculate the torque acting at angle ∅  of  CD on the shaft BC

Torque = 660 * 0.3 cos∅

             = 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N

hello attached is the remaining part of the solution

The required diameter of shaft BC will be 252.65 ×10⁻³A shaft's diameter is the line that goes through its center and splits it into two equal halves.

What is the diameter?

A diameter is a line that travels through the center of a sphere and intersects the circumference at opposing ends. It measures twice as long as the sphere's radius

The given data in the problem is;

P is the force = 660 N

d is the displacement = 15 mm

G is the constant= 77 GPa

τ is the shear stress= 80 MPa

From the torsional equation;

[tex]\frac{\tau}{R} =\frac{T}{j} \\\\ \frac{\pi}{32} \times d^4=\\\\ \tau =\frac{T \times R}{J} \\\\\ \tau =\frac{T \times (\frac{d}{2} )}{J} \\\\ 80= \frac{32 \times 190 \times \frac{d}{2} }{\pi} \\\\\\d=252.65 \times 10^{-3}[/tex]

Hence the required diameter of shaft BC will be 252.65 ×10⁻³.

To learn more about the diameter refer to the link;

https://brainly.com/question/5501950

Use the computational model of a cannon and cannonball shown to answer the question below.

If the mass of the cannonball increases, and all other initial conditions stay the same, what would happen to the velocity and kinetic energy of the cannonball?

A. The velocity decreases, and the kinetic energy decreases.
B. The velocity decreases, and the kinetic energy increases.
C. The velocity increases, and the kinetic energy decreases.
D. The velocity increases, and the kinetic energy increases.

Answers

Answer:

It would be option B.

Explanation:

Option B. is the right answer because as the mass of the canon increases the kinetic energy will increase as well, but the will decrease due to its greater mass.

If the mass of the cannonball increases, and all other initial conditions stay the same,  the velocity decreases, and the kinetic energy increases.

The kinetic energy of an object is the energy possessed by the object due to its motion.

[tex]K.E = \frac{1}{2} mv^2[/tex]

where;

m is the mass of the objectv is the velocity of the objectK.E is the kinetic energy of the object

When the mass increases, the kinetic energy will increase.

[tex]v^2 = \frac{2K.E }{m}\\\\v=\sqrt{\frac{2K.E }{m}}[/tex]

when the mass increases, the velocity of the cannonball will decrease.

Thus, we can conclude that if the mass of the cannonball increases, and all other initial conditions stay the same,  the velocity decreases, and the kinetic energy increases.

Learn more here:https://brainly.com/question/6498875

Answer the following questions

Answers

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

9- the answer is A 10N to left
10- the answer is C no change in the object
Hope this helps! :))

Hi i need help. thNKS

Answers

Answer:

8

Explanation:

Groups go down, periods go across :)

How does mass affect acceleration during free fall?
Pick a hypothesis below now.

If an object falls freely, then heavy objects accelerate more than light objects.

If an object falls freely, then heavy objects accelerate less than light objects.

If an object falls freely, then heavy objects accelerate nearly the same as light objects.

Answers

the first one, as the mass is higher so it accelerates more

Answer:

it is the 3rd one

Explanation:

If an object falls freely, then heavy objects accelerate nearly the same as light objects.

help me please I can't get the final step​

Answers

Answer:

[tex]\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}[/tex]

Explanation:

Dimensional Analysis

It's given the relation between quantities A, B, and C as follows:

[tex]\displaystyle A=\frac{3}{2}B^mC^n[/tex]

and the dimensions of each variable is:

[tex]A=L^2T^2[/tex]

[tex]B=LT^{-1}[/tex]

[tex]C=LT^2[/tex]

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

[tex]\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n[/tex]

Operating:

[tex]L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)[/tex]

[tex]L^2T^2=L^{m+m}T^{-m+2n}[/tex]

Equating the exponents:

[tex]m+n=2[/tex]

[tex]-m+2n=2[/tex]

Adding both equations:

[tex]3n=4[/tex]

Solving:

[tex]n=4/3[/tex]

[tex]m=2-4/3=2/3[/tex]

Answer:

[tex]\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}[/tex]

If a 40 kg pumpkin is thrown through your neighbors window with an acceleration rate of 2 m/s, what’s the force you through it with?

Answers

Answer:

[tex]\boxed {\boxed {\sf 80 \ Newtons}}[/tex]

Explanation:

Force can be found by multiplying the mass by the acceleration.

[tex]F=m*a[/tex]

The mass of the pumpkin is 40 kilograms.

The acceleration of the pumpkin is 2 meters per second squared.

[tex]m= 40 \ kg \\a= 2 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 40 \ kg *2 \ m/s^2[/tex]

Multiply.

[tex]F= 80 \ kg*m/s^2[/tex]

A kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 80 kg*m/s² is also equal to 80 Newtons (N).

[tex]F=80 \ N[/tex]

The force is 80 Newtons.

Answer:

80 newton

Explanation:

F=ma so we now substitute our values I. E 40kg*2m/s=80 Newton

Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?

Answers

Explanation:

0.10kg

0.5kg×0.2kg=

0.10

how does the index of refraction of an unknown substance compare to the index of refraction of a vacuum? explain how the speed and the refraction of light would behave in both?

Answers

Answer:

By measuring the speed of light in both in space and that unknown substance

Explanation:

Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density.

By measuring the speed of light in that medium and dividing it by speed of light 3*10^8 we can measure the refractive index of any medium

You are interested in space travel and want to learn more facts about space travel.
Which would be the best source of information? (2 points)
The Star Wars web page NASA web page
A book about planets
A magazine article

Answers

Answer:

A Book about Planets

Explanation:

Answer:

Nasa web page

Explanation:

Is this physically plausible?

Answers

Answer:

stop useing my awnsers just to deleate them

Explanation:

car 1 is traveling south at 18 m/s and has a full load, giving it a total mass of 14,650 kg. Car 2 is traveling north at 11 m/s and has a mass of 3,825 kg. After the collision, car 1 has a final velocity of 6 m/s south. What is the velocity of car 2

Answers

Answer:

v_{4}= 80.92[m/s] (Heading south)

Explanation:

In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.

ΣPbefore = ΣPafter

where:

P = linear momentum [kg*m/s]

Let's take the southward movement as negative and the northward movement as positive.

[tex]-(m_{1}*v_{1})+(m_{2}*v_{2})=-(m_{1}*v_{3})+(m_{2}*v_{4})[/tex]

where:

m₁ = mass of car 1 = 14650 [kg]

v₁ = velocity of car 1 = 18 [m/s]

m₂ = mass of car 2 = 3825 [kg]

v₂ = velocity of car 2 = 11 [m/s]

v₃ = velocity of car 1 after the collison = 6 [m/s]

v₄ = velocity of car 2 after the collision [m/s]

[tex]-(14650*18)+(3825*11)=(14650*6)-(3825*v_{4})\\v_{4}=80.92[m/s][/tex]

I can’t figure it out my question is:
--- are complex and may be change when new information is available or new technologies are developed.

My choices to choose from are:

Laws
Hypothesis
Theories
Procedures

Answers

Theories

If it’s wrong oh well because I just guest buh glad to help :)

What is the correct interpretation of this diagram?


Forces from the left and the right are unbalanced. The object moves left.


Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the right.


Up and down forces are balanced. The object does not move.


Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the left.



Answers

Answer:

where is the diagram?

Explanation:

here is the diagram

hope this helps a little cuz i cant paste pictures here

Four directional arrows with labels five hundred seventy-nine Newtons, four hundred eighty-seven Newtons, five hundred seventy-nine Newtons and six hundred thirty-two Newtons

A 1000-kg car is travelling at 30 m/s (about 67 mph, for context). What is the car's momentum? If the driver then slams on the brakes, applying a force of 7,500 N, how long will it take the car to stop?

Answers

it will take the car 5 seconds to stop

Two identical spheres (of equal mass) a distance of 10 meters apart exert a force of gravity of 0.00050 N on each other. What are their masses?

Answers

Answer:

From the following statements about mechanical waves, identify those that are true for transverse mechanical waves only, those that are true for longitudinal mechanical waves only, and those that are true for both types of waves.

Explanation:

During a thunderstorm a tornado lift a car to a height of 300 m above the ground increasing and strength the tornado flings the car horizontally with the speed of 80.0 m/s how long does the car take to reach the ground how far horizontally does the car travel before hitting the ground

Answers

Answer:

Explanation:

To calculate the time it took the car to hit the ground, we use the formula

speed = distance/time

80 m/s = 300 m/time

time = 300/80

time = 3.75 secs

It must have taken the car 3.75 seconds to hit the ground

To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)

speed = distance/time

80 = distance/3.75

distance = 3.75 x 80

distance = 300 meters

A cartoon shows two friends watching an unoccupied car in free fall after it has rolled off a diff. One friend says to the other, "It goes from zero to sixty mphin about three seconds." Is this statement correct? (Note that 60 mph converts to 26.8 m/s.)

Answers

Answer:

The statement is not correct.

Explanation:

To know if the statement is correct, we shall determine the velocity of the car after 3 s. This is illustrated below.

Data obtained from the question include:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 3 s

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 3)

v = 0 + 29.4

v = 29.4 m/s

Thus, the velocity of the car after 3 s is 29.4 m/s.

Hence, the statement made by the friend is not correct as the car has a falling velocity of 29.4 m/s after 3 s.

A 0.050 kg toy truck moving right at 0.20 m/s collided with a toy car weighing 0.015 kg initially at rest, on a frictionless track. The truck keeps moving right at 0.15 m/s after the collision,

what is the final speed of the race car?

Answers

Answer:

0.1667 m/s

Explanation:

m1V1 + m2V2 = m1V3 + m2V4

0.01 = ( 0.0075) + (0.015 * V4)

V4 = (0.01 - 0.0075) / (0.015)

V4= 0.1667

Answer:

0.167 m/s

Explanation:

Why is the car industry a good example of energy efficiency and human technology over time?

Answers

Answer:

Fortunately, the potential for higher energy efficiency is great. ... For example, landlords of rental residential buildings are not motivated to pay for ... it over time, and the timeframes in which specific technologies can be expected to ... especially for small firms, and many industries prefer to expend their human and financial.    

4 Energy Efficiency | America's Energy Future: Technology. this is a site

Explanation:

Answer:

the car industry is one of the most important industry in the world as it aid easy transportation of goods and man.

Explanation:

cars and other automobiles have aid easy movement of people and goods from one place to another as it is more efficient (does not waste time as compared to traditional means of transportation.)and reliable.

To determine a waves' frequency, you must know the (2 points)
Select one:
a. distance it travels
b. number of oscillations in a given period of time
c. distance between the crest and trough
d. height of the wave

Answers

Answer:

b

to determine the frequency you must know oscillations and the given time

Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most likely do?

He reduced the number of loops in the wire.
He increased the number of loops in the wire.
He reduced the length of the wire.
He increased the length of the wire.

Answers

Answer:

Its A

Explanation:

To reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

What is electromagnetic field strength?

The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.

The strength of an induced emf in a given magnetic field is given by;

emf = NBA/t

where;

N is number of turns of the magnetB is magnetic field strengthA is area of the coil

Decrease in number of turns of the wire, reduces the strength of the magnetic field.

Thus, to reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

Learn more about electromagnet here: https://brainly.com/question/12555869

#SPJ2

Martina travels from her house to her moms office building, From there she walks to school. After school, she walks to the library and then to a friends house before finally ending back at home. Fine Martina's totoal distance traveld

Answers

Answer:

it matters how far she traveled

Explanation:

Analyze the chemical reaction below
16 g CH4 + 64 g O2 → 44 g CO2 + 36g H2O
Explain the law of conservation of mass and describe how the equation represents the law of conservation of mass.

Answers

Answer:

Explanation:

The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .

In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass

A block slides down a 30.0 degree inclined plane at an acceleration of 2.0 m/s^2. What is the coefficient of friction between the block and the inclined plane? Use g=10.0 m/s^2
A) .20
B) .25
C) .30
D) .35

Answers

Answer:

D) .35

Explanation:

m = Mass of block

g = Acceleration due to gravity = [tex]10\ \text{m/s}^2[/tex]

[tex]\theta[/tex] = Angle of inclination = [tex]30^{\circ}[/tex]

a = Acceleration of block = [tex]2\ \text{m/s}^2[/tex]

[tex]\mu[/tex] = Coefficient of friction between the block and the inclined plane

f = Frictional force = [tex]\mu mg\cos\theta[/tex]

As the forces are conserved in the system we have

[tex]mg\sin\theta-f=ma\\\Rightarrow mg\sin\theta-\mu mg\cos\theta=ma\\\Rightarrow g(\sin\theta-\mu\cos\theta)=a\\\Rightarrow \sin30^{\circ}-\mu\cos30^{\circ}=\dfrac{2}{10}\\\Rightarrow \dfrac{1}{2}-\mu\dfrac{\sqrt{3}}{2}=0.2\\\Rightarrow \mu=\dfrac{\dfrac{1}{2}-0.2}{\dfrac{\sqrt{3}}{2}}\\\Rightarrow \mu=\dfrac{0.3\times 2}{\sqrt{3}}\\\Rightarrow \mu=0.3464\approx 0.35[/tex]

The coefficient of friction between the block and the inclined plane is 0.35

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