The shedding frequency based on the analysis of Question 3 is to be determined through the use of a small-scale model to be tested in a water tunnel. For the specific bridge structure of interest D=20 cm and H=300 cm, and the wind speed V is 25 m/s. Assume the air is at MSL ISA conditions. For the model, assume that Dm =2 cm. (a) Determine the length of the model Hm needed for geometric scaling. (b) Determine the flow velocity Vm needed for Reynolds number scaling. (c) If the shedding frequency for the model is found to be 27 Hz, what is the corresponding frequency for the full-scale structural component of the bridge? Notes: Refer to the eBook for the properties of air. Assume the density of water
rhoH2O = 1000 kg/m3 and the dynamic viscosity of water μH2O =1×10^−3 kg/m/s

A function [tex]P(t) = 170.(1.30)^t[/tex]  that gives the deer population P(t) on the reservation t years from now

We were told there were 170 stags on reservation. The number of deer is increasing at a rate of 30% per year.

We could see the deer population grow exponentially since each year there will be 30% more than last year.

Since we know that an exponential growth function is in form:

[tex]f(x) = a*(1+r)^x[/tex]

where a= initial value, r= growth rate in decimal form.

It is given that a= 170 and r= 30%.    

Let us convert our given growth rate in decimal form.

[tex]30 percent = \frac{30}{100} = 0.30[/tex]

Upon substituting our given values in exponential function form we will get,

    [tex]P(t) = 170.(1+0.30)^t[/tex]

⇒ [tex]P(t)= 170.(1.30)^t[/tex]

Therefore, the function [tex]P(t) = 170.(1.30)^t[/tex] will give the deer population P(t) on the reservation t years from now.

Complete Question:

There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year. Write a function that gives the deer population P(t) on the reservation t years from now.

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The probability distribution that X has is a binomial distribution, and the expected score on the exam is 20.

a. The correct probability distribution is a binomial distribution.

This is because the multiple-choice exam consists of 100 questions with 5 possible responses to each question.

The discrete probability distribution of the number of successes in a series of n independent experiments, each asking a yes-or-no question and each with its own Boolean-valued outcome, is known as the binomial distribution with parameters n and p in probability theory and statistics: success (with probability p) or failure (with probability q= 1 - p)

Therefore, this is a classic example of a binomial distribution where there are two outcomes in each trial (success and failure) and the trials are independent of each other.

(b) The expected score on the exam

The expected value of X is given by the formula;

Expected value (E) = np

n is the number of trials (100)

p is the probability of getting the correct answer (1/5).

Therefore, Expected value (E) = np

= 100 × (1/5) = 20

So, your expected score on the exam is 20.

A score of 50 is z = 6 standard deviations above the mean.

Therefore, it is extremely unlikely that you would score over 50 on this exam.

In conclusion, a binomial distribution is the probability that X has. Meanwhile, 20 is the expected score.

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It will take 16 seconds to get to your class.

[tex]\bold{Distance}=\bold{Speed }\times \bold{Time}[/tex]

[tex]200m = 1.5m\div s \times t[/tex]

[tex]24=1.5\times t[/tex] (We want to get t by itself, so lets get rid of the [tex]\times1.5[/tex] by dividing both sides by 1.5)

[tex]t = 16 \ \text{seconds}[/tex]

Therefore, it will take 16 seconds to get to your class.

Since the volume of the sphere V = 36π cm³is greater than that of the cone, V' = 21π cm³ the ice cream will overflow.

The volume of a sphere is given by V = 4πr³/3 where r = radius of sphere

Now if the ice cream above is going to melt when it does, will it fit in the cone or will it overflow? Since the ice cream is a sphere, the ice cream will not overflow if the volume of the ice cream equals the volume of the cone. If is greater than the volume of the cone, it will overflow.

Now, since the ice cream is a sphere, its volume is given by V = 4πr³/3 where r = radius of sphere = 3 cm

So, substituting this into the equation, we have that

V = 4πr³/3

V = 4π(3 cm)³/3

V = 4π × 27 cm³/3  

= 4π × 9 cm³

= 36π cm³

Also, since the volume of the cone is given by V' = 1/3πr²h where r = radius of cone = 3 cm and h = height of cone = 7 cm

So, substituting the value of the variables into the equation, we have that

V' = 1/3πr²h

V' = 1/3π(3 cm)² × 7 cm

= 1/3π × 9 cm² × 7 cm

= 3π cm² × 7 cm

= 21π cm³

We see that V = 36π cm³ > V' = 21π cm³

Since the volume of the sphere is greater than that of the cone, the ice cream will overflow.

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The required perimeter of the trapezoid is22 units.

The given vertices of the trapezoid are (1,3), (4,7), (9,7), and (9,3). To find the perimeter of the trapezoid, we need to add up the lengths of all four sides.

We can use the distance formula to find the length of each side of the trapezoid:

[tex]{Side 1: }&(1,3) \text{ to } (4,7) \&d = \sqrt{(4 - 1)^2 + (7 - 3)^2} = \sqrt{9 + 16} = 5 \\\text{Side 2: }&(4,7) \text{ to } (9,7) \&d = \sqrt{(9 - 4)^2 + (7 - 7)^2} = \sqrt{25} = 5 \\\text{Side 3: }&(9,7) \text{ to } (9,3) \&d = \sqrt{(9 - 9)^2 + (3 - 7)^2} = \sqrt{16} = 4 \\\text{Side 4: }&(9,3) \text{ to } (1,3) \&d = \sqrt{(1 - 9)^2 + (3 - 3)^2} = \sqrt{64} = 8\end{align*}[/tex]

Therefore, the perimeter of the trapezoid is:

[tex]$\begin{align*}P &= \text{Side 1} + \text{Side 2} + \text{Side 3} + \text{Side 4} \&= 5 + 5 + 4 + 8 \&= 22\end{align*}[/tex]

Thus, the perimeter of the trapezoid is22 units.

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The two numbers that are in both sequences and between 10 and 30 are 14 and 26.

An ordered set of numbers that adhere to a pattern or rule is referred to as a sequence in mathematics. Sequences can be defined in a variety of ways, such as a formula or a recursive definition, and they can be finite or infinite. Several branches of mathematics, including calculus, algebra, and number theory, employ sequences to explore and answer problems related to the behaviour of functions. For instance, sequences may be used to create fractals and other geometric patterns, predict the rise of populations or the spread of illnesses, and examine the distribution of prime numbers.

The given sequence is 4n - 5, and the nth term is 3n + 2.

For numbers between 10 and 30 in the sequence we have:

4n - 5 ≥ 10

4n ≥ 15

n ≥ 3.75

And,

4n - 5 ≤ 30

4n ≤ 35

n ≤ 8.75

Now, we calculate the sequence for n from 4 to 8:

When n = 4, 3n + 2 = 14

When n = 5, 3n + 2 = 17

When n = 6, 3n + 2 = 20

When n = 7, 3n + 2 = 23

When n = 8, 3n + 2 = 26

Hence, the two numbers that are in both sequences and between 10 and 30 are 14 and 26.

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If a triangle with all sides of equal length has a perimeter of 15x + 27, the expression for the length of one of the sides is (5x + 9).

The perimeter of a triangle is the sum of the lengths of all three sides. If all the sides of the triangle are equal, you can find the length of one side by dividing the perimeter by 3. Here, the perimeter is given as 15x + 27.

Therefore, the length of one side will be (15x + 27) / 3 = 5x + 9. Hence, an expression for the length of one of the sides is (5x + 9).

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The percentage of the original sample left after 85 days is approximately 30.73%.

The rate of decay of a radioactive substance is proportional to the amount of substance present. The radioactive decay law states that the amount of a radioactive substance left after t days is given by the formula N(t) = N₀ e^(-kt). Here, N₀ is the initial amount of the substance, and k is the decay constant.

We know that the half-life of the substance is 50 days. This means that N(t) = N₀/2 when t = 50. Therefore, we can use this information to find the decay constant k as follows:

N(50) = N₀ e^(-50k)

N₀/2 = N₀ e^(-50k)

1/2 = e^(-50k)

ln(1/2) = -50kln(e)

ln(1/2) = -50k

0.693 = 50k

k = -0.01386 (approx.)

Therefore, the formula for the amount of substance left after t days is given by N(t) = N₀ e^(-0.01386t). Now, we can use this formula to find the percentage of the original sample left after 85 days as follows:

N(85) = N₀ e^(-0.01386 * 85)

N(85) = N₀ e^(-1.1771)

N(85)/N₀ = e^(-1.1771)

N(85)/N₀ = 0.3073 (approx.)

Therefore, the percentage of the original sample left after 85 days is 30.73% (approx.). The answer is 30.73%.

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The quotient of 6. 208 × 10⁹ and 9. 7 × 10⁴ expressed in scientific notation is 6.4 × 10¹².

Quotient:

The quotient is the answer we get when we divide one number by another. For example, if we divide the number 6 by 3, we get 2, the quotient. The quotient can be integer or decimal. For an exact division like 10 ÷ 5 = 2, we have a whole number as the quotient, and for a division like 12 ÷ 5 = 2.4, the quotient is a decimal number. The quotient can be greater than the divisor, but always less than the dividend.

Based on the given conditions, Formulate:

6.208× 10⁹ /9.7×10⁴

Simply using exponent rule with same base:

[tex]a^n. a^m = a^(n+m)[/tex]

= 6.208 × 1/9.7

Now,

the sum or difference = [tex]6.208*\frac{1}{9.7}[/tex] × 10¹³

Now solving, we get:

6.208/9.7 × 10¹³

Converting fraction into decimal, we get:

  0.64× 10¹³

⇒ 6.4 × 10¹²

Therefore,

The quotient of 6. 208 × 10⁹ and 9. 7 × 10⁴ expressed in scientific notation is 6.4 × 10¹².

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Answer:

One way is to realize that since the total area is 1, the area below z = 1 is equal to 1 minus the area above z= 1 which we know from before is 0.1587. So the area below 1 is 1 - 0.1587 = 0.8413.

The length of the side on the prism is 5cm. The area of the shaded region is 72 cm².

Area is the total amount of area occupied by a flat (2-D) surface or an object's shape. The area of a plane figure is the region that its boundary encloses. The quantity of unit squares that span a closed figure's surface is its area. Square units like cm² and m² are used to quantify area. A shape's area is a two-dimensional measurement.

The region inside the perimeter or boundary of a closed shape is referred to as the "area". Such a shape has at least three sides that can be joined together to create a boundary. The "area" formula is used in mathematics to describe this type of space symbolically.

In this figure,

The 5cm flap will be adjacent to the side x. Therefore,

Length of the side x= 5cm

Area of the shaded region= l×b

because the shaded region is a rectangle.

area= 9*x

       =9*5= 45 cm²

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The correct definition for the lines drawn to circle with centre C are:

A circle is a spherical shape without boundaries or edges.

Thus, on the basis of propertied of circle, the correct definition for the lines drawn to circle with centre C are:

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The option that is NOT an augmented functional dependency is: Q --> P, because it removes the attribute from the left-hand side of the existing functional dependency, which is not allowed in an augmented dependency.

Functional dependency: It is a concept in database management systems that describes the relationship between two attributes or sets of attributes in a table. In a functional dependency A → B, A is the determinant or the attribute(s) that uniquely determines the value of B.

Augmented functional dependency : It is formed by adding one or more attributes to the determinant side of an existing functional dependency.

From the given options, the only one that is not an augmented functional dependency is "Q → P". This is because it does not involve adding any attributes to the determinant side of an existing functional dependency.

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Distance from the base of tower to the airplane = 706ft.

The term "angle of depression" called   angle created when an observer looks down at an item and the horizontal line intersects with the line of sight. It determines how our field of vision shifts as we glance down. Say you are standing in your kitchen and gazing straight, and suddenly you spy an insect crawling on the floor.

Given, Angle of Depression=12°

Height of tower=150ft

For AB parallel to CD

∠ACD=∠cAB=12°

Tan12°=BC/AB

AB=BC/Tan12°

AB=706ft

Hence, Distance from the base of tower to the airplane = 706ft.

Diagram is attached below;

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The result of each trigonometric functions are:

a) sin X = 7√149 / 149

b) sin Z = 10√149 / 149

c) cos X = 10√149 / 149

d) cos Z = 7√149 / 149

In a right triangle, the sine of an angle is equal to the length of the side opposite the angle divided by the length of the hypotenuse, and the cosine of an angle is equal to the length of the adjacent side divided by the length of the hypotenuse. Using this trigonometric functions, we can calculate sin X, sin Z, cos X, and cos Z as follows

sin X = YZ / XZ = 7 / √149

cos X = XY / XZ = 10 / √149

sin Z = XY / XZ = 10 / √149

cos Z = YZ / XZ = 7 / √149

To simplify these fractions, we can rationalize the denominator by multiplying the numerator and denominator by √149:

sin X = 7√149 / 149

cos X = 10√149 / 149

sin Z = 10√149 / 149

cos Z = 7√149 / 149

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The given question is incomplete, the complete question is:

Find sin X, sin Z, cos X, and cos Z. Write each answer as a simplified fraction.

Answer:

9

Step-by-step explanation:

-5 + (-18) +32

-23 + 32

32 -23

Answer:

22

Step-by-step explanation:

2-4i and i=6

2-4(6)

=22

The number which, when subtracted from 80, results in -30 is equal to 110.

To solve this problem, we can use algebraic equations to represent the given information. Let x be the number that we want to find.

According to the problem, when we subtract x from 80, we get -30:

80 - x = -30

To solve for x, we can isolate it on one side of the equation by adding x to both sides, and then simplify:

80 - x + x = -30 + x

80 = -30 + x

Next, we can isolate x by subtracting -30 from both sides:

80 - (-30) = x

Simplifying the right-hand side:

80 + 30 = x

110 = x

Therefore, the number that was subtracted from 80 and gave -30 as the result is 110.

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The correct answer is three squares. To represent 3/5, 3 out of 5 squares need to be shaded.

Fractions written using a numerator (the number on top) and a denominator (the number on the bottom) that indicate how many parts make up the whole.

This can be seen visually if you draw 5 squares in a row and shade in 3 of them. Since fractions are a representation of the part-whole relationship, the numerator of the fraction (3) indicates the number of parts of the whole (5) that are shaded.

Fractions can be used to represent a variety of ratios, from unit fractions (1/2 or 1/3) to more complex fractions (3/5 or 7/9). To answer the question, "How many squares would need to be shaded to represent 3/5?", it is important to understand that the numerator of the fraction (3) indicates the number of parts of the whole (5) that are shaded.

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We need to shade 3/5 or 60% of the small squares in the bigger square which is 54 small squares.

Fractions written using a numerator (the number on top) and a denominator (the number on the bottom) that indicate how many parts make up the whole.

For this problem, we need to shade 3/5 or 60% of the small squares in the bigger square.

To calculate the number of small squares that need to be shaded, we must first calculate the total number of small squares within the bigger square.

We can do this by multiplying the number of squares in the rows(10) by the number of squares in the columns(9), which in this case is

10 x 9 = 90.

Now that we know the total number of small squares, we can calculate the number of small squares that need to be shaded.

To do this, we need to multiply the total number of small squares (90) by  by the fraction we are trying to represent (3/5).

90 x 3/5 = 54.

This means that 54 small squares need to be shaded to represent 3/5.

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The best point estimate for the average number of school books per semester for all students at the local college is 5.2.

The average number of school books per semester for all students at the local college is 5.2. A sample of 39 students was taken, i.e., n = 39. To find, The best point estimate for the average number of school books per semester for all students at the local college.

The best point estimate for the average number of school books per semester for all students at the local college is the sample mean which can be calculated.

Therefore, the best point estimate for the average number of school books per semester for all students at the local college is 5.2.

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Answer:

-12 is the y intercept while your slope is -4

Step-by-step explanation:

Answer:

<1= 61

<2= 61

<3= 119

Step-by-step explanation:

Answer:

Solve the problems. a) The number a is 4/5 of the number b. What part of number a is number b?

Step-by-step explanation:

a) If a is 4/5 of b, then b is 5/4 of a.

To find what part of a is b, we divide b by a:

b/a = 5/4

This means that b is 5/4 times larger than a, or b is 125% of a.

To find what part of a is b, we subtract 1 from this fraction:

b/a - 1 = 5/4 - 1

b/a - 1 = 1/4

So, b is 1/4 of a, or b is 25% of a.

Answer:

The other is 75/7.

Step-by-step explanation:

Let the other rational number be x, then:

(-7/15) * x =  -5

x = -5 * -15/7

  = 75/7

Answer:

0.33

Step-by-step explanation:

To solve this, you first write the problem as an algebra equation as follows: 3x + 4 = 5

Then you solve the equation by subtracting 4 from both sides, and then divide both sides by 3. Here is the math to illustrate better:

3x + 4 = 5

3x + 4 - 4 = 5 - 4

3x = 1

3x/3 = 1/3

x = 0.33

Answer = 0.33

The probability that fewer than 3 of them use their smartphones in meetings or classes is 0.0366.

The binomial probability distribution is a discrete probability law with two parameters: trial number (n) and success probability (p) (p). When there are two mutually exclusive outcomes of finite trials, the binomial distribution is utilised.

The probability that a specific 3 people all use their smartphones in meetings or class is 0.53³.

Probability that remaining 7 people do not use their phone is 0.47⁷

¹⁰C₃ = 10*9*8/(3*2*1) = 120.

Thus, the probability of exactly 3 people using their smartphones in meetings or in class is 10C3*0.533*0.477, or 0.0905.

So, adding up the 3 possibilities (that 0 of them, 1 of them, or 2 of them use their smartphones in meetings or class) we get

¹⁰C₀*0.530*0.4710 + ¹⁰C₁*0.531*0.479 + ¹⁰C₂*0.532*0.478 = 0.0366.

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Complete question:

Assume that when adults with smartphones are randomly​ selected, 53​% use them in meetings or classes. If 10 adult smartphone users are randomly​ selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

77 is the value of Q in linear equation.

What in mathematics is a linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.  

                                   Equations with power 1 variables are known as linear equations. One example with only one variable is where ax+b = 0, where a and b are real values and x is the variable.

P ∝ 1/Q

PQ = K

AT P= 11

Q = 28

11 * 28 = K

K = 308

AT P = 4

4Q = 308

Q = 77

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Answer:

AB ≈ 4.73

Step-by-step explanation:

using the sine ratio in the right triangle

sin25° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{2}{AB}[/tex] ( multiply both sides by AB )

AB × sin25° = 2 ( divide both sides by sin25° )

AB = [tex]\frac{2}{sin25}[/tex] ≈ 4.73 ( to the nearest hundredth )