The scale on a map indicates that 1 inch corresponds to an actual distance of 75 miles. Two cities are 5.5 inches apart on the map. What is the actual distance between the two cities?

Answer:

Step-by-step explanation:

The number 5.071 written in english words is "five and seventy-one thousandths

6

+

4

−

8

Step-by-step explanation:

Please mark me as brain list and please like my answer and rate also

Answer:

hope this will help you more

Answer:

there is a 64% chance that the student got both problems wrong

a 32% chance that they got only 1 correct

and a 4% chance that they got both correct

Step-by-step explanation:

There are 25 total possible combinations of answers, with 8 possible combinations where the student would get 1 answer right, and 1 combination where the student would get both answers correct.

[tex]25-9=16[/tex]

[tex]\frac{16}{25} =\frac{x}{100}[/tex]

[tex]\frac{64}{100}[/tex]

[tex]64[/tex]%

[tex]\frac{8}{25} =\frac{y}{100}[/tex]

[tex]\frac{32}{100}[/tex]

[tex]32[/tex]%

[tex]\frac{1}{25} =\frac{z}{100}[/tex]

[tex]\frac{4}{100}[/tex]

[tex]4[/tex]%

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = [tex]\frac{\sqrt{13} }{2}[/tex],  cos A = [tex]\frac{\sqrt{13} }{3}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

b. sin A = [tex]3\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]2\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

c. sin A = [tex]\frac{\sqrt{13} }{3}[/tex],  cos A = [tex]\frac{\sqrt{13} }{2}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

i. First calculate the value of the missing side AB.

Using Pythagoras' theorem;

⇒ (AB)² = (AC)² + (BC)²

Substitute the values of AC and BC

⇒ (AB)² = (36)² + (24)²

Solve for AB

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = [tex]\sqrt{1872}[/tex]

⇒ AB = [tex]12\sqrt{13}[/tex] ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of [tex]12\sqrt{13}[/tex] ft (43.27ft).

ii. Calculate the sine of ∠A (i.e sin A)

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex]             -------------(i)

In this case,

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (i) as follows;

sin A = [tex]\frac{24}{12\sqrt{13} }[/tex]

sin A = [tex]\frac{2}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

sin A = [tex]\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

sin A = [tex]\frac{2\sqrt{13} }{13}[/tex]

iii. Calculate the cosine of ∠A (i.e cos A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = [tex]\frac{adjacent}{hypotenuse}[/tex]             -------------(ii)

In this case,

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (ii) as follows;

cos A = [tex]\frac{36}{12\sqrt{13} }[/tex]

cos A = [tex]\frac{3}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

cos A = [tex]\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

cos A = [tex]\frac{3\sqrt{13} }{13}[/tex]

iii. Calculate the tangent of ∠A (i.e tan A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = [tex]\frac{opposite}{adjacent}[/tex]             -------------(iii)

In this case,

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

Substitute these values into equation (iii) as follows;

tan A = [tex]\frac{24}{36}[/tex]

tan A = [tex]\frac{2}{3}[/tex]

Answer: B. Cannot be determined

Explanation:

We can't use SAS since we don't have two pairs of proportional sides. We only know one pair of sides. This also rules out SSS as well since we'd need 3 pairs of proportional sides.

We can't use AA because we don't have two pairs of congruent angles.

Currently, we simply don't have enough information to determine if the triangles are similar or not.

Answer:

13/17

Step-by-step explanation:

Answer:

The probability that exactly 12 buyers would prefer green

=0.00555

Step-by-step explanation:

We are given that

p=50%=50/100=0.50

n=14

We have to find the probability that exactly 12 buyers would prefer green.

q=1-p

q=1-0.50=0.50

Using binomial distribution formula

[tex]P(X=x)=nC_r p^r q^{n-r}[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^{14-12}[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^2[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{14}[/tex]

[tex]P(x=12)=\frac{14!}{12!2!}(0.50)^{14}[/tex]

[tex]P(x=12)=\frac{14\times 13\times 12!}{12!2\times 1}(0.50)^{14}[/tex]

[tex]P(x=12)=91\cdot (0.50)^{14}[/tex]

[tex]P(x=12)=0.00555[/tex]

Hence, the probability that exactly 12 buyers would prefer green

=0.00555

Answer:

60:100, 6/10, 3/5, 6 to 10, etc.

Step-by-step explanation:

You take the number of girls over total students which is boys + girls. Since there's 40 boys and 60 girls, it's 60 girls to 100 students which can be written in several ways.

Answer:

60:100 / 3:5

Step-by-step explanation:

You first add the total number of students which is (40boys + 60girls) which gives us 100 students.

Then arrange the ratio of girls to students as per the question that is 60:100, reduce it to its lowest term that is dividing the ratio by 20, and finally got 3:5

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

Answer:

3^5

Step-by-step explanation:

On the iPad it looks like that but the five is on the top right smaller

Answer:

3⁵

every 3 has it own power that is 1 however that .3 confused us

Answer:

11 hours is right answer i hope it will help you

Answer:

18

Step-by-step explanation:

Supplementary angles means sum of angles is 180.

4x + 4 + 6x - 4 = 180

4x + 6x + 4 - 4 = 180

10x = 180

x = 180 / 10

x = 18

Answer:

x=18 degree

Step-by-step explanation:

If they are supplementary angles, then their sum = 180 degree

4x+4 + 6x-4 =180

4x+6x + 4-4 = 180

10x = 180

x=180/10

x=18

Answer:

B. 200 cu. units

Step-by-step explanation:

Volume of the triangular prism = ½*b*h*l

Where,

b = 8 units

h = 5 units

l = 10 units

Plug in the values

Volume of the prism = ½*8*5*10

= 4*5*10

= 200 cu. units

Answer:

Step-by-step explanation:

correct me if I am wrong

Answer:

16x4−4x2+4x−116x4−4x2+4x−1

=16x4−(4x2−4x+1)=16x4−(4x2−4x+1)

=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2

=(4x2−2x+1)(4x2+2x−1)∵a2−b2=(a−b)(a+b

Step-by-step explanation:

Answer:

Net present value= $25.17

Step-by-step explanation:

We are told that The last dividend paid was $1.55 and that the dividend growth rate is constant at 1.5% for 2 years.

Thus;

1) After 1st year;

1.55 × (1 + 0.015) = 1.57325 Div1

After 2nd year;

1.57325 × (1 + 0.015) = 1.59685 Div2

After that 2 years it grows at 6% Constant rate forever;

1.59685 × (1 + 0.06) = 1.69266 Div3

Let's now use the dividend formula which grows in perpetuity at a rate of "g" since required return is 12%:

Thus;

V = 1.69266/(0.12 - 0.06) = 28.211

Thus; Div2 = 28.211 + 1.59685 ≈ 29.80785

Now, using the financial calculator of the Cash Flow function, we have:

Div0 = 0

Div1 = 1.57325

Div2 = 29.80785

i% = 12

Net present value = (1.57325/(1 + 0.12)) + ((1.59685 + 28.211)/(1 + 0.12)²)

Net present value= $25.17

Answer:

t could be all real numbers.

Step-by-step explanation:

The function D(t) is given by:

[tex]D(t)=-1.5t+12[/tex]

The domain is all the posible x-values for which the function is defined.

In our case, t could be all real numbers.

The answer is the first option.

I hope it helps you!

Answer:

Part 1)

225 feet.

Part 2)

7 seconds.

Step-by-step explanation:

The height h(t) of the ball above the ground after t seconds is modeled by the function:

[tex]h(t)=-16t^2+104t+56[/tex]

Part 1)

We want to determine the maximum height of the ball.

Notice that the function is a quadratic with a negative leading coefficient, so its maximum will be at its vertex point.

The vertex of a parabola is given by:

[tex]\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]

In this case, a = -16, b = 104, and c = 56.

Find the x- (or rather t-) coordinate of the vertex. So:

[tex]\displaystyle t=-\frac{(104)}{2(-16)}=\frac{104}{32}=\frac{13}{4}=3.25\text{ seconds}[/tex]

In other words, the ball reaches its maximum height after 3.25 seconds.

To find the maximum height, substitute this value back into the function. Hence:

[tex]\displaystyle h(3.25)=-16(3.25)^2+104(3.25)+56=225\text{ feet}[/tex]

The maximum height of the ball is 225 feet in the air.

Part 2)

We want to find the amount of time it took for the ball to hit the ground.

When the ball hit the ground, its height above the ground is zero. Therefore, we can set h(t) to 0 and solve for t:

[tex]0=-16t^2+104t+56[/tex]

We can simplify a bit. Divide both sides by -8:

[tex]0=2t^2-13t-7[/tex]

We can factor. Find two numbers that multiply to 2(-7) = -14 and add to -13.

-14 and 1 works! Therefore, split the second term into -14 and 1:

[tex]\displaystyle 0=2t^2-14t+t-7[/tex]

Factor out a 2t from the first two terms and group the last two terms:

[tex]0=2t(t-7)+(t-7)[/tex]

Factor by grouping:

[tex]0=(2t+1)(t-7)[/tex]

Zero Product Property:

[tex]2t+1=0\text{ or } t-7=0[/tex]

Solve for each case:

[tex]\displaystyle t=-0.5\text{ or } t=7[/tex]

Since time cannot be negative, we can ignore the first case.

Therefore, it takes seven seconds for the ball to hit the ground.

Answer:

I don't know the answer to ur question. LOL

Answer:

stop being desperate

nobody is gonna fall in love with some desperate weirdo

Answer:

1.74 or [tex]\frac{103}{59}[/tex]

Step-by-step explanation:

3(x-5) = 8 (11-7x)

3x-15=88-56x

59x=103

x = 1.74

Answer:

1-a

2-h

3-g

4-d

5-c

6-j

7-f

8-k

9-b

10-i

numbers are column A and alphabets are column B!

Answer:

11/12

Step-by-step explanation:

1/4 + 2/3

= 3/12 + 8/12

= 11/12

Answer:

yes your answer is right

Answer:

Yes it's Perfectly correct

Answer:

Range = -1 ≤ y ≤ 2

Step-by-step explanation:

The function's range is the y-values the function can have as its output. -1 is the minimum y-value and 2 is the maximum y-value.

In verse of B.g(x)=[tex]\frac{x+5}{4}[/tex] is:

4x-5

Answer:

Solution given:

B.g(x)=[tex]\frac{x+5}{4}[/tex]

let

g(x)=y

y=[tex]\frac{x+5}{4}[/tex]

Interchanging role of x and y

we get:

x=[tex]\frac{y+5}{4}[/tex]

doing crisscrossed multiplication

4x=y+5

y=4x-5

So

g-¹(x)=4x-5

Given that,

→ g(x) = x+5/4

Then g(x)=y,

→ y = x+5/4

Now we can interchange role of x and y,

→ x = y+5/4

Then use the cross multiplication,

→ 4x = y+5

→ y = 4x-5

Hence, g-¹(x) = 4x-5 is the solution.

Answer:

504 arrangements are possible

Step-by-step explanation:

Arrangements of n elements:

The number of arrangements of n elements is given by:

[tex]A_{n} = n![/tex]

Arrangements of n elements, divided into groups:

The number of arrangements of n elements, divided into groups of [tex]n_1, n_2,...,n_n[/tex] elements is given by:

[tex]A_{n}^{n_1,n_2,...,n_n} = \frac{n!}{n_1!n_2!...n_n!}[/tex]

In this case:

9 pens, into groups of 5, 3 and 1. So

[tex]A_{9}^{5,3,1} = \frac{9!}{5!3!1!} = 504[/tex]

504 arrangements are possible

Answer:

1) 5.64

2) 17.321

1) [tex]\frac{21}{28}[/tex]

2) [tex]\frac{16}{34}[/tex]

3) [tex]\frac{28}{35}[/tex]

4) [tex]\frac{32}{24}[/tex]

Step-by-step explanation:

SOH - CAH - TOA

Sin = [tex]\frac{O}{H}[/tex]   Cos = [tex]\frac{A}{H}[/tex]  Tan = [tex]\frac{O}{A}[/tex]      

O = opposite, A = adjacent, H = hypotenuse

First two,  use Pythagorean Theorem

If you want to calculate the angle on the last 4, use inverse of function and put in the ratio.

For example :

1) Tan Z = [tex]\frac{21}{28}[/tex]

   [tex]Tan^{-1}[/tex] ( [tex]\frac{21}{28}[/tex])

Z = 36.9°

Answer:

5353454

Step-by-step explanation:

Answer: 16 and 24

Step-by-step explanation:

2x+3x= 40

5x = 40

x=8

that means 2x8 equal 16 and 3x8 equals 24 which leads us to the answer

Answer:

265

Step-by-step explanation:

9514 1404 393

Answer:

  265

Step-by-step explanation:

Let t represent the number of tiles needed. Then the area covered by those t tiles will be ...

  area = t·0.34 ft²

We want that area to be 90 ft², so we can solve this equation for t:

  90 ft² = t·(0.34 ft²)

  90 ft²/(0.34 ft²) = t ≈ 264.71

About 265 tiles are needed to cover 90 ft².