Answer:
[tex]UV = 10[/tex]
Step-by-step explanation:
Given
[tex]TU : UV : VW = 2 : 5 : 5[/tex]
[tex]TW = 24[/tex]
Required
Determine UV
From the given parameters, we have that:
Ratio of TU = 2
Ratio of UV = 5
Ratio of VW = 5
First, we have to add up the total ratio;
Total = Ratio of TU + Ratio of UV + Ratio of VW
[tex]Total = 2 + 5 + 5[/tex]
[tex]Total = 12[/tex]
Next is to calculate the length of UV; as follows;
[tex]UV = \frac{Ratio\ of\ UV}{Total\ Ratio} * TW[/tex]
Substitute 5 for Ratio of UV; 12 for Total Ratio and 24 for TW
[tex]UV = \frac{5}{12} * 24[/tex]
[tex]UV = \frac{5 * 24}{12}[/tex]
[tex]UV = \frac{120}{12}[/tex]
[tex]UV = 10[/tex]
Hence; length of UV is 10 units
I would appreciate some help :)
Answer:
See below
Step-by-step explanation:
(a) Remember that the median of any data set is represented by the " middle line " of the box plot. The median of Brand X would be 13, and the median of Brand Y would be 16.
(b) The median of each respective box plot is not in range of their respective boxes. Therefore Brand X has a much smaller time span that Brand Y. This proves that one would favor Brand Y over Brand X.
Select the correct answer.
Which expression simplifies to 2V15?
O A. 17
19
V30
D. V60
HELP!! im doing the plato test rn
Answer:
D
Step-by-step explanation:
Prime factorize 60
[tex]\sqrt{60}=\sqrt{2*2*3*5}=2\sqrt{3*5}=2\sqrt{15}[/tex]
At $15 per square foot, the cost of installing flooring in a room with these dimensions a.$121.50 b.$1215.00 c.$1290.00 d.$81
Answer:
b. $1215.00
Step-by-step explanation:
The area of the room can be figured any of several ways. One easy way is to figure the area of the enclosing 8 ft by 12 ft rectangle, then subtract area of the 3 ft by 5 ft cutout at upper left.
A = (8 ft)(12 ft) - (3 ft)(5 ft) = (96 -15) ft^2 = 81 ft^2
At a cost of $15 for each square foot, the installed flooring will cost ...
($15 /ft^2)(81 ft^2) = $(15·81) = $1215
Use the distributive property to evaluate the expression. Which statement is equal to 8(26)? Which expression shows the result after using the distributive property? Evaluate the expression.
Answer:
8(20 + 6)
8(20) +8(6)
208
Step-by-step explanation:
Got it right EDGE 2021
The value of 8(26) after using the distributive property will be 208.
What is a number system?The number system is a way to represent or express numbers.
A decimal number is a very common number that we use frequently.
Since the decimal number system employs ten digits from 0 to 9, it has a base of 10.
As per the given, 8(26)
8(26) = 8(20 + 6)
By using the distributive property of multiplication,
8(26) = 8 × 20 + 8 × 6
⇒ 160 + 48
⇒ 208
Hence "The value of 8(26) after using the distributive property will be 208".
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Multiply the following numbers and write your answer in the correct number of sig figs: 210.6 X 56.0
Answer:
11,793.6
Step-by-step explanation:
Find the percentage of: 21% of 18 use a set of fraction operations method to find the percentage.
Answer:
4.8%
Step-by-step explanation:
21% of 18
following the BODMAS rule, OF means multiplication
and also this sign% always means 100
so,it will be 21/100 * 18/1
this a laptop so i cant put it in a fraction way.....okay
this is how it shows...21/100 * 18/1
lets divide....
21/100 * 18/1
we will use 2 to divide
2 in 100=50
2 in 18=9
so it will be 21/50 * 9/1
nothing can divide so we will multiply
21*9/50*1
189/50=3.78≈4.8%
Two angles are supplementary one angle is 2/3 the measure of the other one find both angles
Answer:
The measures are 108 deg and 72 deg.
Step-by-step explanation:
The larger angle has measure x.
The smaller angle has measure (2/3)x.
They are supplementary, so the sum of their measures is 180 degrees.
x + (2/3)x = 180
(3/3)x + (2/3)x = 180
(5/3)x = 180
(3/5) * (5/3)x = (3/5) * 180
x = 108
(2/3)x = 2/3 * 108 = 72
Answer: The measures are 108 deg and 72 deg.
Please someone help me...
Step-by-step explanation:
First factor out the negative sign from the expression and reorder the terms
That's
[tex] \frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \cot(6A) - \cot(2A) } [/tex]
Using trigonometric identities
That's
[tex] \cot(x) = \frac{1}{ \tan(x) } [/tex]Rewrite the expression
That's
[tex]\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \frac{1}{ \tan(6A) } } - \frac{1}{ \frac{1}{ \tan(2A) } } [/tex]
We have
[tex] - \frac{1}{ \tan(2A) - \tan(6A) } - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{ \tan(6A) \tan(2A) } } [/tex]Rewrite the second fraction
That's
[tex] - \frac{1}{ \tan(2A) - \tan(6A) } - \frac{ \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) } [/tex]Since they have the same denominator we can write the fraction as
[tex] - \frac{1 + \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) } [/tex]
Using the identity
[tex] \frac{x}{y} = \frac{1}{ \frac{y}{x} } [/tex]Rewrite the expression
We have
[tex] - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{1 + \tan(6A) \tan(2A) } } [/tex]Using the trigonometric identity
[tex] \frac{ \tan(x) - \tan(y) }{1 + \tan(x) \tan(y) } = \tan(x - y) [/tex]Rewrite the expression
That's
[tex] - \frac{1}{ \tan(2A -6A) } [/tex]Which is
[tex] - \frac{1}{ \tan( - 4A) } [/tex]Using the trigonometric identity
[tex] \frac{1}{ \tan(x) } = \cot(x) [/tex]Rewrite the expression
That's
[tex] - \cot( - 4A) [/tex]Simplify the expression using symmetry of trigonometric functions
That's
[tex] - ( - \cot(4A) )[/tex]Remove the parenthesis
We have the final answer as
[tex] \cot(4A) [/tex]As proven
Hope this helps you
Answer: see proof below
Step-by-step explanation:
Use the following identities:
[tex]\cot\alpha=\dfrac{1}{\tan\alpha}\\\\\\\cot(\alpha-\beta)=\dfrac{1+\tan\alpha\cdot \tan\beta}{\tan\alpha-\tan\beta}[/tex]
Proof LHS → RHS
Given: [tex]\dfrac{1}{\tan 6A-\tan 2A}-\dfrac{1}{\cot 6A-\cot 2A}[/tex]
Cot Identity: [tex]\dfrac{1}{\tan 6A-\tan 2A}-\dfrac{1}{\dfrac{1}{\tan 6A}-\dfrac{1}{\tan 2A}}[/tex]
Simplify: [tex]\dfrac{1}{\tan 6A-\tan 2A}-\dfrac{1}{\dfrac{1}{\tan 6A}\bigg(\dfrac{\tan 2A}{\tan 2A}\bigg)-\dfrac{1}{\tan 2A}\bigg({\dfrac{\tan 6A}{\tan 6A}\bigg)}}[/tex]
[tex]= \dfrac{1}{\tan 6A-\tan 2A}-\dfrac{1}{\dfrac{\tan 2A-\tan 6A}{\tan 6A\cdot \tan 2A}}[/tex]
[tex]= \dfrac{1}{\tan 6A-\tan 2A}-\dfrac{\tan6A\cdot \tan 2A}{\tan 2A-\tan 6A}[/tex]
[tex]= \dfrac{1}{\tan 6A-\tan 2A}-\dfrac{\tan6A\cdot \tan 2A}{\tan 2A-\tan 6A}\bigg(\dfrac{-1}{-1}\bigg)[/tex]
[tex]= \dfrac{1}{\tan 6A-\tan 2A}+\dfrac{\tan6A\cdot \tan 2A}{\tan 6A-\tan 2A}[/tex]
[tex]= \dfrac{1+\tan6A\cdot \tan 2A}{\tan 6A-\tan 2A}[/tex]
Sum Difference Identity: cot(6A - 2A)
Simplify: cot 4A
cot 4A = cot 4A [tex]\checkmark[/tex]
To estimate the percentage of defects in a recent manufacturing batch, a quality control manager at selects every th that comes off the assembly line starting with the until she obtains a sample of . What type of sampling is used? A. Systematic B. Stratified C. Convenience D. Simple random E. Cluster
Answer: systemic
Step-by-step explanation:
is 0.987987 repeating rational or irrational
Answer:
is repeating rational
I need help. I don’t understand what I have to do
Answer:
Hey there!
3x-5+2x+2+3x+5
3x+2x+3x-5+2+5
8x+2=90
8x=88
x=11
Let me know if this helps :)
Step-by-step explanation:
Hey, there!!
Let's simply work with it,
MA is perpendicular to AT.
To find: angle HAT.
Now,
angle HAT + (2x + 2)° + (3x + 5)° = 90° { As MA perpendicular to AT. }
Now,
Replace angle HAT by (3x - 5)°.
(3x-5)° + (2x+2)° + (3x+5)° = 90°
Open brackets,
3x - 5° + 2x + 2° + 3x + 5° = 90°
Add like terms.
8x + 2°= 90°
8x = 90°-2°
[tex]x = \frac{88°}{8} [/tex]
x= 11°.
Now, finding the value of angle HAT.
(3x-5)° = 3×11°-5°
Therefore, angle HAT is 28°.
Hope it helps...
On her first quiz in social studies,Meg answered 92% of the questions correctly.On her second quiz,she answered 27 out of 30 questions correctly. On which quiz did Meg have the better score?
Answer:
on her first quiz
Step-by-step explanation:
27/30=
27÷30=
0.9=
09×100/100=
0.9×100%=
(0.9×100)% =
90%
Answer:
first quiz
Step-by-step explanation:
100 divided by 30 times 27<92%
You have to catch the bus at 11:15am for a movie! It
takes you twenty minutes to shower and dress, fifteen minutes to eat breakfast, and ten
minutes to walk to the bus stop. By what time should you get you get up?
Answer:
Hey there!
To solve this problem, we must first find the total amount of time it takes for you to get ready in the morning!
20 minutes for shower + 15 minutes to eat + 10 minutes to walk.
This is a total of 20+15+10 or 45 minutes.
For our answer, we have that you should wake up 45 minutes before 11:15, which is 10:30 AM.
Let me know if this helps :)
Answer:
10:30 am
Step-by-step explanation:
11:15 am - 20 min = 10:55 am10:55 am - 15 = 10:40 am10:40 am - 10 = 10:30 amI hope this helps!
In the figure below, one side of the right triangle is a diameter of the semicircle.
10 units
6 units
8 units
What is the approximate total area of the shaded part of the figure?
Answer:
Option (A)
Step-by-step explanation:
One side of the given triangle is a diameter of the semicircle given.
Measure of the diameter = 10 units
Total area of the semicircle = [tex]\frac{1}{2}\pi (r^{2})[/tex]
= [tex]\frac{1}{2}\pi (5)^2[/tex]
= 39.27 square units
Area of the right triangle = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]
= [tex]\frac{1}{2}(6)(8)[/tex]
= 24 square units
Area of the shaded region = Area of the semicircle - Area of the right triangle
= 39.27 - 24
= 15.27 square units
≈ 15 square units
Therefore, option (A) will be the answer.
Determine whether the vectors u and v are parallel, orthogonal, or neither.
u = <10,0>, V = <0,-9>
Answer:
Orthogonal.
Step-by-step explanation:
Given:
u = <10, 0>
v = <0, -9>
In unit vector notation, the above vectors can be re-written as:
u = 10i + 0j
v = 0i - 9j
Now, note the following:
(i) two vectors, u and v, are parallel to each other if one is a scalar multiple of the other. i.e
u = kv
or
v = ku
for some nonzero value of a scalar k.
(ii) two vectors are orthogonal if their dot product gives zero. i.e
u . v = 0
Let's use the explanations above to determine whether the given vectors are parallel or orthogonal.
(a) If parallel
u = k v
10i + 0j = k (0i - 9j) ?
When k = 1, the above equation becomes
10i + 0j ≠ 0i - 9j
When k = 2,
10i + 0j ≠ 2(0i - 9j)
10i + 0j ≠ 0i - 18j
Since we cannot find any value of k for which u = kv or v = ku, then the two vectors are not parallel to each other.
(b) If Orthogonal
u.v = (10i + 0j) . (0i - 9j)
[multiply the i components together, and add the result to the multiplication of the j components]
u.v = (10i * 0i) + (0j * 9j)
u.v = (0) + (0)
u.v = 0
Since the dot product of the two vectors gave zero, then the two vectors are orthogonal.
please help me out!
simplify:
|-5| + 2
Answer:
7
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Recall that absolute value is the positive of a real number so
|-5| = 5
This added to 2 gives 7
gage bought a new car for $29000 to use while he is away at college. The car decreases in value by 11% annually. What would the cars value after 4 years?
The value of the gauge car after 4 years will be $18195.25.
What is compound interest?Compound interest is applicable when there will be a change in principle amount after the given time period.
For example, if you give anyone $500 at the rate of 10% annually then $500 is your principle amount. After 1 year the interest will be $50 and hence principle amount will become $550 now for the next year the interest will be $550, not $500.
Given,
Principle amount (P) = $29000
Rate of decrement (R) = 11%
Time period(T) = 4 years
Percentage decrement over T time period is given by
Final amount = P[tex][1 - R/100]^{T}[/tex]
Final amount = 29000[tex][1 - 11/100]^{4}[/tex]
Final amount = 29000(0.89)⁴
Final amount = $18195.25.
Hence, The value of the gauge car after 4 years will be $18195.25.
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The value of the car after 4 years is $18195.24989.
Given,
Gage bought a new car for $29000 to use while he is away at college.
The car decreases in value by 11% annually.
We need to find what would the cars value after 4 years.
we have,
Cost of the car = $29000
The car decreases annually by = 11%
1st-year decrease.
$29000 x 11/100 = $3190
The cost of the car after 1st year = $29000 - $3190 = $25810
2nd-year decrease.
$25810 x 11/100 = $2839.1
The cost of the car after 2nd year = $25810 - $2839.1 = $22970.9
3rd-year decrease.
$22970.9 x 11/100 = $2526.799
The cost of the car after 3rd year = $22970.9 - $2526.799 = $20444.101
4th-year decrease.
$20444.101 x 11/100 = $2248.85111
The cost of the car after 4th year = $20444.101 - $2248.85111 = $18195.24
Thus the value of the car after 4 years is $18195.24989.
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Suppose the equation of line p is x = 2 and the equation of line q is x = –1. What translation is equivalent to (Rp ∘ Rq) (ΔABC)?
Answer:
T(6,0)
Step-by-step explanation:
Reflection across two parallel lines results in translation by double the distance between them. Assuming this means ...
Rp(Rq(∆ABC))
the translation is to the right by 6 units.
_____
The attached figure shows the reflections we understand to be indicated by the notation (Rp ∘ Rq) (ΔABC).
Answer:
above
Step-by-step explanation:
victor needs 30 feet of rope. the rope he want to buy is sold by the yard. he know that there are 3 feet in the 1 yard. how many yards should he buy?
Answer: 10 yards
Step-by-step explanation:
Covert 30 feet into yards to find how many yards he should buy.
[tex]\frac{30}{3} = \frac{x}{1}[/tex] Solve by cross product
3x = 30
x = 10
3x=9 divide each side by 3 x=3
Answer:
3
Step-by-step explanation:
3x=9
3(3)=9
3/3=0=9/3=3
answer=3
really need help solving this problem
Answer:
y = 8
Step-by-step explanation:
[tex] \frac{y}{4} = \frac{5 + 5}{5} \\ \\ \frac{y}{4} = \frac{10}{5} \\ \frac{y}{4} = 2 \\ y = 4 \times 2 \\ y = 8[/tex]
At present the sum of Geetha's age and her daughter's age is 44 years. After 2 years, Geetha's age will be three times that of her daughter's age. Find their present ages.
Answer:
Geetha is 32.5 years old
her daughter is 11.5 years old
Step-by-step explanation:
sum of their ages is 44 years
G + D = 44
in two years, Geetha's age is 3 times her daughters age. (to find present age, subtract 2)
G = 3D - 2
substitute
(3D - 2) + D = 44
combine like terms
4D - 2 = 46
4D = 46
D = 11.5
plug in D to either equation
G + (11.5) = 44
G = 32.5
G = 3(11.5) - 2
G = 32.5
Two friends went fishing on a lake. One friend’s lure went 23 feet below the lake’s surface, while the other friend’s lure sank to a depth of 81 feet below the surface. What was the difference in the depths of the lures?
Answer:
58 feet
Step-by-step explanation:
Find the difference by subtracting 23 from 81.
81 - 23
= 58 feet
-8 + 10 + (-3) -(-2)
Answer:
1
Step-by-step explanation:
-8 + 10 + (-3) - (-2)
=> -8 + 10 - 3 + 2
=> 12 - 11
=> 1
Answer:
1Step-by-step explanation:
[tex]-8+10+\left(-3\right)-\left(-2\right)\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:\\\\-8+10=2\\\\=2+\left(-3\right)-\left(-2\right)\\\\\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a\\\\+\left(-3\right)=-3\\\\=2-3-\left(-2\right)\\\\2-3=-1\\\\=-1-\left(-2\right)\\\\=-1+2\\\\=1[/tex]
the density of concentrated sulphuric acid is 1.8 g/cm.calculate the volume of 3.1 kg of the acid
Step-by-step explanation:
[tex]density = \frac{mass}{volume} \\ volume = \frac{mass}{density} \\ changing \: 1.8 {gcm}^{ - 3} to \: {kgm}^{ - 3} \\ multiply \: by \: 1000 \\ = 1800 {kgm}^{ - 3} \\ volume = \frac{3.1}{1800} \\ = 0.00172 {m}^{ 3} [/tex]
The volume of 3.1 kg of concentrated sulfuric acid is 1722.22 [tex]cm^{3}[/tex].
Here's the solution:
The density of concentrated sulfuric acid is 1.8 g/[tex]cm^{3}[/tex]. This means that 1.8 grams of concentrated sulfuric acid will occupy 1 cubic centimeter of space.
If we have 3.1 kg of concentrated sulfuric acid, then we have 3100 grams of concentrated sulfuric acid.
The volume of this amount of concentrated sulfuric acid will be:
volume = mass / density
volume = 3100 g / 1.8 g/[tex]cm^{3}[/tex]
volume = 1722.22 [tex]cm^{3}[/tex]
Therefore, the volume of 3.1 kg of concentrated sulfuric acid is 1722.2[tex]cm^{3}[/tex]
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help :/ ill give brainly :>
Answer:
A. Trapezoid
B. Isoclese triangle
c. Equilateral triangle
d. Kite
Answer:
A, Parallelogram (more specifically a trapezoid)
B. Isosceles Triangle
C. Equilateral Triangle
D. Kite
The upper-left coordinates on a rectangle are (-5, 6)(−5,6)left parenthesis, minus, 5, comma, 6, right parenthesis, and the upper-right coordinates are (-2, 6)(−2,6)left parenthesis, minus, 2, comma, 6, right parenthesis. The rectangle has a perimeter of 16units.
Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.
If the coordinates of the top of the triangle (breadth) is (−5,6) and (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:
D = √(y₂-y₁)²+(x₂-x₁)²
Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6
D = √(6-6)²+(-2-(-5))²
D = √0²+3²
D = √9
D = 3 units
Breadth = 3 units
Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.
16 = 2(3+L)
16 = 6+2L
16-6 = 2L
2L = 10
L = 10/2
L = 5 units.
Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.
Answer:
This other person is correct! I checked =)
Step-by-step explanation:
help me plsssssssssssssssssssssssssssssssssssssss
Answer:
[tex] \frac{1}{5} ( - m - 4)[/tex]
Step-by-step explanation:
But method 1 best suits the question
Answer:
[tex] - \frac{1}{5} m - \frac{4}{5} [/tex]
Answer:
-1/5m -4/5
Step-by-step explanation:
2/5 m -4/5 - 3/5 m
Combine like terms
2/5m - 3/5m -4/5
-1/5m -4/5
please help me on this !
Answer:
B.) 20
Step-by-step explanation:
We know the midpoint of half of the segment, which is 5. You can use this to find the length of half, after which you can find the entire length by multiplying by 2:
[tex]RN+NS=RS\\5+5=10\\HR+RS=HS\\10+10=20[/tex]
The length of HS is 20.
A square window in Miranda's house has an area of 255 in2 (squared). What is the perimeter of the window?
Answer:
If you meant the area was 255 in²:
Perimeter is [tex]4\sqrt{255}[/tex], or around 63.89 in.
If you meant that the area was 225 in²:
Perimeter is 60 in
Step-by-step explanation:
If you meant the area was 255 in²:
If we have a square with an area of 255 in², then it's side length will be [tex]\sqrt{255}[/tex] inches long, since the area of a square is [tex]l^2[/tex], where l is the length.
Since [tex]\sqrt{255}[/tex] doesn't return a rational number, we'll leave it as [tex]\sqrt{255}[/tex].
Now that we know the side length, the perimeter of a square is represented as [tex]4l[/tex], where l is the length.
We know the length is [tex]\sqrt{255}[/tex], so we can multiply this by 4.
[tex]4\sqrt{255}[/tex]. This is the simplest it gets.
If you meant the area was 225 in²:
Following the same concept as again:
Length: [tex]\sqrt{225} = 15[/tex]
Perimeter: [tex]4\cdot15=60[/tex] in
Hope this helped!
Answer:
P = 63.87 in
Step-by-step explanation:
area of a square window = 255 in²
find perimeter of the window.
A = s²
255 = s²
s = 15.97 in.
perimeter = 4 * s
P = 4 (15.97)
P = 63.87 in