The office needs 6 new devices worth $7200. The order consists of new computers (C) which cost $1425 each and printers (P) which cost $750 each. How many of the new devices are computers and how many are printers?​

Answer:

the answer of r is 8 i hope it will help

Answer:

Buy 2 lollipops for $2.

Step-by-step explanation:

If you divide the total price by total items purchased, you get the price per unit. 2/2=1 or around $1, while 40/30=4/3 or around $1.3. You are paying 1$ per lollipop for the 2 lollipop choice and paying 1.3 dollars per lollipop for the 30 lollipop choice.

Answer:

The answer should be like this;

a) A-B

b) BUC

c) C-A

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

Answer:

Percent error=1.23%

Step-by-step explanation:

We are given that

Estimate length of room=20 feet

Actual length of room=20.25 feet

We have to find the percent error.

To find the percent error we will find the difference between the estimate length and actual length of room.

Difference=Actual length of room-Estimate length of room

Difference=20.25-20

Difference=0.25 feet

Now,

Percent error=[tex]\frac{Difference}{actual\;length}\times 100[/tex]

Percent error=[tex]\frac{0.25}{20.25}\times 100[/tex]

Percent error=1.23%

The limit of the difference quotient of the above function [tex]f(x)[/tex] at [tex]x=3[/tex] is [tex]3[/tex] such that [tex]f(x)=x^{3} - 4x^{2} + 2[/tex].

The difference quotient of a function [tex]f(x)[/tex] is [tex]\frac{f(x+h)-f(x)}{h}[/tex].

The given equation is, [tex]f(x)=x^{3} -4x^{2} +2[/tex]

So, [tex]f(x+h)=(x+h)^{3} -4(x+h)^{2} +2= x^{3} +h^{3}+3x^{2} h+3xh^{2} -4x^{2} -4h^{2} -8xh+2[/tex]

Now, [tex]f(x+h)-f(x)[/tex]

[tex]=x^{3}+h^{3}+3x^{2}h+3xh^{2}-4x^{2}-4h^{2}-8xh+2-x^{3}+4x^{2}-2[/tex]

[tex]=h^{3}+3x^{2}h+3xh^{2}-4h^{2}-8xh[/tex]

So, [tex]\frac{f(x+h)-f(x)}{h} =\frac{h^{3}+3x^{2}h+3xh^{2} -4h^{2}-8xh }{h}[/tex]

[tex]=h^{2}+3x^{2}+3xh-4h-8x[/tex]

Now, at [tex]x=3[/tex],

[tex]h^{2}+3x^{2}+3xh-4h-8x=h^{2}+27+9h-4h-24=h^{2}+5h+3[/tex]

If   [tex]h[/tex]→[tex]0[/tex], the value of [tex]h^{2}+5h+3=3[/tex]

Thus, the limit of the difference quotient of the above function [tex]f(x)[/tex] at [tex]x=3[/tex] is [tex]3[/tex].

Learn more about the limit of the difference quotient here- https://brainly.com/question/17008881

#SPJ2

Answer:

F) Convenience Sampling

Step-by-step explanation:

Samples may be classified as:

Convenient: Sample drawn from a conveniently available pool.

Random: Basically, put all the options into a hat and drawn some of them.

Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.

A statistics student interviews the last fifteen attendees to arrive.

Conveniently available, so convenience, and the correct answer is given by option F.

Answer:

D

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

Answer:

Frustum Volume =

[PI * height * (small radius^2 + (small radius * large radius) * + large radius^2)] / 3

Frustum Volume = PI * 10 * ( 1.5^2 + 1.5*3.75 + 3.75^2 ) / 3

Frustum Volume = 31.41592654 * (2.25 +5.625 +14.0625) / 3

Frustum Volume = (31.41592654 * 21.9375) / 3

Frustum Volume = 689.1868884713 / 3

Frustum Volume = 229.72896282 cubic cm

Source: http://www.1728.org/volcone.htm

Step-by-step explanation:

Answer:

0.88

Step-by-step explanation:

x 01234

f(x) 0.41 0.37 0.16 0.05 0.01

The mean or average is the expected value :

E(X) = Σ(x * p(x)) = (0 * 0.41) + (1 * 0.37) + (2 * 0.16) + (3 * 0.05) + (4 * 0.01)

E(X) = 0 + 0.37 + 0.32 + 0.15 + 0.04

E(X) = 0.88

Answer:

a) 0.4658 = 46.58% probability that the chosen ball is blue

b) 0.322 = 32.2% probability that it came from the first urn

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability that the chosen ball is blue?

6/20 = 0.3 of 0.5(first urn)

12/19 = 0.6316 out of 0.5(second urn).

So

[tex]P(A) = 0.3*0.5 + 0.6316*0.5 = 0.4658[/tex]

0.4658 = 46.58% probability that the chosen ball is blue.

b. If the chosen ball is blue, what is the probability that it came from the first urn?

Event A: Blue Ball

Event B: From first urn

From item a., [tex]P(A) = 0.4658[/tex]

Probability of blue ball from first urn:

0.3 of 0.5. So

[tex]P(A \cap B) = 0.3*0.5 = 0.15[/tex]

Probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.4658} = 0.322[/tex]

0.322 = 32.2% probability that it came from the first urn

Answer:

The cutoff time be for concert setup should be of 51.4 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average time it takes their sound tech to set up for a show is 56.1 minutes, with a standard deviation of 6.4 minutes.

This means that [tex]\mu = 56.1, \sigma = 6.4[/tex]

If the band manager decides to include only the fastest 23% of sound techs on the tour, what should the cutoff time be for concert setup?

The cutoff time would be the 23rd percentile of times, which is X when Z has a p-value of 0.23, so X when Z = -0.74.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.74 = \frac{X - 56.1}{6.4}[/tex]

[tex]X - 56.1 = -0.74*6.4[/tex]

[tex]X = 51.4[/tex]

The cutoff time be for concert setup should be of 51.4 minutes.

Answer:

Step-by-step explanation:

5 ) c

6) c

7) b

8) a

Answer:

0,00567×10¹

Step-by-step explanation:

Para convertir a notación decimal:

0.00567×10¹

Answer:

Step-by-step explanation:

[tex]\frac{34-40}{8}= -.75[/tex]

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

( − ∞ , ∞ )

Set-Builder Notation:

{ x | x ∈ R }

Step-by-step explanation:

hope that helps bigger terms

Answer:

Step-by-step explanation:

Given function h(x).

Shift left:

Shift down:

Given function is,

→ h(x)

As we shift left,

→ h(x) = h(x + 3)

As we shift down,

→ h(x + 3) = h(x+3)-5

Then the equation is,

→ h(x+3)-5

It is correct answer.

Answer:

where is the statement

Step-by-step explanation:

its incomplete po

Answer:

1-x^2/x^3 - 1 = 1/x

Step-by-step explanation:

First rewrite x^3 as x^2 * x cancel x^2  in both numerator and denominator.

   Write below

1 - 1/x - 1

Subtract

   1 - 1 = 0

now simplify

1 -1 /x - 1 = 1/x

1/x  = Answer

Can you Understand

Answer:

Domain: {1, 2, 3, 4}

Step-by-step explanation:

The domain of the graph (input values) is the number of pizzas which are plotted on the x-axis while the range (output values) is the cost of pizza, plotted on the y-axis (vertical axis)

The domain therefore would consists of each x-coordinate that represent each point on the graph, which are {1, 2, 3, 4}

Answer:

The answer for both linear equations is A. x = 2, y = 7

Step-by-step explanation:

First start by plugging in the variables with the given numbers (2,7). We'll start with 6x + 3y = 33.

6x + 3y = 33

6 (2) + 3 (7 )= 33 <--- This is the equation after the numbers are plugged in.

12 + 10 = 33

33 = 33 <---- This statement is true, therefore it is the correct pair.

Now we are not done, to confirm that this pair works with both equations we need to solve for 4x + y = 15 to see if it works. Linear Equations must have the variables work on both equations.

4x + y = 15 <----- We are going to do the exact same thing to this equation.

4(2) + 7 = 15

8 + 7 = 15

15 = 15  <-- 15=15 is a true statement therefore this pair works for this equation.

Therefore,

A. x = 2, y = 7 is the correct answer

Sorry this is a day late, I hope it helps.

Answer:

Step-by-step explanation:

First remove the parentheses.

As the sign outside the second parentheses is  a + then the signs of the terms inside stay the same.

So the first one + (-3x +2) is just -3x + 2.

All the others on the left column are answered in the same way.

No. 4:

(-2x + 10 + (-8x - 1)     Just remove the parentheses, we get:

-2x + 10 - 8x - 1           (we leave out the + before the second parentheses).

= -2x - 8x + 10 - 1        

= -10x + 9

6. 8x + 8 + ( -6x - 1)

= 8x + 8 - 6x - 1

= 8x - 6x + 8 - 1

= 2x + 7.

- the other expressions on the right side column are solved in the same way.

Answer:

The remainder is 3x - 4

Step-by-step explanation:

[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]

So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]

In this case our dividend is always P(x).

Part 1

When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]

When [tex]x = 1[/tex],

[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]

--------------------------------------------------------------------------------------------------------------

Part 2

When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]

When [tex]x = -3[/tex],

[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]

--------------------------------------------------------------------------------------------------------------

Part 3

When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]

We will call [tex]a + b = -1[/tex] equation 1

From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]

We will call [tex]3a - b = 13[/tex] equation 2

Now we can create a system of equations using equation 1 and equation 2

[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]

By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]

So equation 1 + equation 2:

[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]

Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.

So substituting [tex]a = 3[/tex] into equation 1:

[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]

Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.

So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:

[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]

Therefore, the remainder is [tex]3x - 4[/tex].

Answer:

hi, see mate the third angle is not in the photo, please upload another one

Answer:

-28

Step-by-step explanation:

if c = 3 and x = -5 than,

-c + 5x = -3 + 5 * (-5) = -3 + (-25) = - 28

Answer:

B

Step-by-step explanation:

THere are 52/4= 13 hearts we can draw

The number of ways to draw 3 hearts from 13 is

13C3= 286

The number of ways to draw 3 cards from 52 is

52C3= 22100

divide these

286/22100= 11/850

This is answer B

Answer Deleted

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Answer:

4.48 years

Step-by-step explanation:

The formula for simple interest is

A = P(1+r*t), with A being the final amount, P being the initial amount, r being the interest rate, and t being the time. Plugging our values in, we get

1750 = 1500(1+0.0372 * t)

Note that 3.72 was translated into 0.0372 as changing percents to decimals requires dividing by 100

Expanding our equation, we get

1750 = 1500 + 55.8 * t

subtract 1500 from both sides to isolate the t and its coefficient

250 = 55.8 * t

divide both sides by 55.8 to get t

t = 4.48

Answer: 75%

Step-by-step explanation:

Answer:

Attached images

It was just easier for me this way.

Let me know in comments if you have questions.

Step-by-step explanation: