The statement "Both its velocity and its acceleration are parallel to the x axis" best describes the motion of the box when the net force on the box is in the positive x direction.
If a net force acts on an object in the positive x direction, the object experiences an acceleration in the positive x direction. According to Newton's second law of motion, the acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass. As a result, the object will move in the positive x direction with a continually increasing velocity. Therefore, both the velocity and acceleration of the box are parallel to the x axis.
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At highway speeds, a particular automobile is capable of an acceleration of about 2.0 m/s At this rate, how long does it take to accelerate from 70km/hto 120km/h? Express your answer to two significant figures and include the appropriate units. .
Answer:
It takes approximately 10.3 seconds to accelerate from 70km/h to 120km/h, when the acceleration is 2.0m/s.
12. Consider the falling and rolling motion of the 2.0 kg ball in the following two resistance-free
situations. In one situation, the ball falls off the top of the platform to the floor. In the other situation,
the ball rolls from the top of the platform along the staircase-like pathway to the floor. Fill in answer
for each the blanks lettered A-K.
PE=100J
KE=0J
PE= F J
KE- GJ
v=__H_m/s
PE=50J
KE-A J
V= B_m/s
PE=_C_J
KE=D J
v=__E__m/s
Answer the questions using logic and a little bit of arithmetic.
Top & Bottom:
1. What is the PE of the ball at the very top of the diagram above?
2.
What is the KE of the ball at the very top of the diagram above?
3. What is the PE of the ball the location shown as I on the diagram above?
4. What is the KE of the ball the location shown as J on the diagram above?
5.
What is the velocity of the ball the location shown as K on the diagram above?
requires a little mental math - but you can use a calculator if you need it.
6. What is the PE of the ball the location shown as F on the diagram above as the ball hits the ground?
10
PE=IJ
KE J J
v=K_m/s
8. What is the velocity of the ball the location shown as H on the diagram above?
your previous answers-don't solve the velocity equation.
7. What is the KE of the ball the location shown as G on the diagram above as the ball hits the ground?
Rolling down the ramp:
9. What is the KE of the ball the location shown as A on the diagram above?
This one
Use logic &
10. What is the velocity of the ball the location shown as B on the diagram above? Use logic & your previous
answers-don't solve the velocity equation.
11. What is the PE of the ball the location shown as C on the diagram above?
12. What is the KE of the ball the location shown as D on the diagram above?
13. What is the velocity of the ball the location shown as E on the diagram above? Use logic & your previo
answers-don't solve the velocity equation.
The PE (potential energy) of the ball at the very top of the diagram is 100 J.
The KE (kinetic energy) of the ball at the very top of the diagram is 0 J.
The PE of the ball the location shown as I on the diagram is 50 J.
The KE of the ball the location shown as J on the diagram is 50 J.
What is friction?Friction is a force that acts between two objects that are in contact with each other and opposes their relative motion.
The velocity of the ball the location shown as B on the diagram can be calculated by the equation KE = 0.5 * m * v^2, where m is the mass of the ball (2 kg) and KE is the kinetic energy (50 J). Solving for velocity, we get v = sqrt(KE / (0.5 * m)) = sqrt(50 / (0.5 * 2)) = 7 m/s.
The PE of the ball the location shown as F on the diagram as the ball hits the ground is 0 J.
The KE of the ball the location shown as G on the diagram as the ball hits the ground can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball (calculated in #5 as 5 m/s). Solving for KE, we get KE = 0 + 0.5 * 2 * 5^2 = 50 J.
Using the equation KE = 0.5*m*v2, the velocity can be determined to be 7.07 m/s for B and E and 10 m/s for H and K.
The 100 J of original mechanical energy is present at each position. So the KE for A is 50 J.
The KE of the ball the location shown as A on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball. The KE at A will be 50J.
The PE of the ball the location shown as C on the diagram can be calculated by conserving energy, meaning that the initial PE at the top of the ramp plus any work done by friction must equal the final KE at this location. This can be expressed as PE + work done by friction = KE, where work done by friction is equal to friction force times distance. So, at C, PE=50J and the KE of the ball the location shown as D on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2 So, KE for D will be50J.
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A bubble of air of volume 3.0 mm3 is under water. The bubble is at a depth where the pressure of the air inside the bubble is four times atmospheric pressure. The temperature of the air in the bubble stays the same as it rises to the surface. What is the volume of the air in the bubble as it reaches the surface?
The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.
How the volume was calculatedThe volume of an ideal gas is proportional to its temperature and inversely proportional to its pressure. Since the temperature of the air in the bubble stays the same, the ratio of the initial pressure to the final pressure is equal to the ratio of the final volume to the initial volume.
Since the pressure inside the bubble at a depth of 4 times atmospheric pressure is 4 times atmospheric pressure, the pressure inside the bubble at the surface is equal to atmospheric pressure.
The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.
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a direct expansion-type evaporator is also called a . flooded evaporator dry-type evaporator multi-circuit evaporator stamped evaporator
A dry-type evaporator is another name for a direct expansion evaporator. An evaporator seems to be a container or platform that converts liquid into vapor.
Evaporator, what is it?In contrast to the condenser, the evaporator absorbs heat from the compartment's air while converting refrigerant liquid to gas. Due to the reduced pressure and heat dissipation, the liquid refrigerant is much cooler than for the fan air surrounding it when it reaches the evaporator.
What sort of evaporator is employed?One of the popular evaporators is the LTV. Basically, it is a liquid separator coupled to a shell and tube heat exchanger. The climbing film evaporator and the descending film evaporator are quite similar. It is the total opposite of something like a falling movie.
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The melting point of MgO is higher than that of NaF. Explanations for this observation include which of the following?I. Mg2+ is more positively charged than Na+.II. O2- is more negatively charged than F-.III. The O2- ion is smaller than the F- ion.Pilihan jawabanI and II onlyII onlyI and III onlyII and III onlyI, II , and III
Because Mg2+ is more positively charged than Na+, MgO has a higher melting point than NaF. Moreover, O2 has a stronger negative charge than F (I & II only, option A)
Ionic solids MgO and Naf both exist. MgO has a higher melting point than NaF because it takes more energy to break the bonds in MgO since it contains higher-charged ions than NaF (Na+ and F).
While Naf (Na+ and F) has a monovalent nature, MgO (Mg2+ and O2) has both divalent (Mg2+ and O2) ions. In the crystal lattice of MgO, the electrostatic forces between the ions are higher than in the case of Naf. As a result, MgO's melting point (2642⁰ C) is greater than NaF's (992⁰ C).
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True/False the four principle types of space our text names are: deep space, flat space, splitspace and ambiguous space
The given statement '' the four principal types of space our text names are: deep space, flat space, split space, and ambiguous space'' is false as the four principal types of space our text names are: atmospheric space, void space, domestic space, and liminal space.
Atmospheric space is the space between objects, where the environment can affect the objects in it. Void space is the empty space that can be found in a room or an area, but can also be found in one’s mind.
Domestic space is the space we create at home, and it is a space that reflects our identity and emotions. Finally, liminal space is a space between two states, where something is neither this nor that and can be seen as a threshold.
All of these spaces are integral to understanding how humans interact with the world, and they all contribute to the overall experience of living.
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A microwave oven emits radiation at a wavelength of 0.500 cm What is the frequency of this radiation? a.) 6.67 x 10-7 Hz b.) 6.00 x 1010 Hz c.) 1.50 x 106 Hz d.) 2.00 Hz
The frequency of a microwave oven that emits radiation at a wavelength of 500 cm would be 6.00 × 10¹⁰ Hz (B)
The frequency of a radiation in physics is the quantity of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time. Heinrich Rudolf's name was given to the SI unit that measures frequency known as the hertz. Additionally, 1 Hz means one cycle per second.
The distance between the two closest points that are in phase with one another is known as a wavelength. As a result, a single full wavelength separates two nearby peaks or troughs on a wave. Typically, the wavelength of a wave is denoted by the letter lambda (λ).
The following formula gives the relationship between wavelength and frequency:
V = f × λ
Where:
V = wave speed
= 3 × 10⁸ m/s (speed of light)
F = frequency
λ = wavelength
= 0.005 m
Thus, the frequency of the microwave would be:
3 × 10⁸ m/s = f × 0.005 m
f = ( 3 × 10⁸ m/s) ÷ (0.005 m)
f = 6 × 10¹⁰ Hz
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6. The resistance of a platinum coil of platinum resistance thermometer at 0 °C is 5 Ohms and at 100 C is 5.39 Ohms. When this thermometer is put in a hot bath, the resistance of platinum wire is found to be 5.795 Ohms. The temperature of the bath is? A. 345.652 K B.400 °C C. 345.652 C D. 400 K
The temperature of the hot bath is approximately 400 °C. (Option B).
How is the Temperature Calculated?To find the temperature of the hot bath, we need to use the temperature coefficient of resistance (α) of platinum and the resistance at 0°C and 100°C as a reference.
The equation to find the temperature is given by:
T = (R/R0 - 1) / α + T0
Where R is the resistance at the hot bath temperature, R0 is the resistance at 0°C, T0 is 0°C, and α is the temperature coefficient of resistance of platinum.
Using this equation and the given values, we can calculate T as:
T = (5.795/5 - 1) / (5.39/5 - 1) * (100 - 0) + 0 = approximately 400 °C
So the temperature of the hot bath is approximately 400 °C .
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In which circumstance would hypnosis be most effective and appropriate?
ITS DUE IN 5 MINSSSSSSs Through his investigation, Nathanial identified when equal forces are applied to an object, the motion of the object does not change. He started a data table to record the evidence from his investigation. Which further evidence can Nathanial use to support his findings? (ANSWER RIGHT NOW, ITS DUE LITERALLY IN 10 MINS)
67 N in row one and 110 N in row two
120 N in row one and 67 N in row two
115 N in row one and 65 N in row two
100 N in row one and 65 N in row two
Answer:
Explanation:
2nd choice: 120 N in row one and 67 N in row two
Applied forces have to be equal in magnitude and opposite in direction to cancel each other out and result in no change to the object's motion
A girl tosses a stone into the air with an initial upward velocity of 8.00 meters/second and hears the splash when it hits the water 4.20 seconds later. How deep is the water level in the well below where she tossed the stone
Deep is the water level in the well below where she tossed the stone is 52.92 m.
Consider the equation of motion s = ut + 0.5 at²
Take the upward direction as positive,
Initial velocity, u = 8 m/s
Acceleration, a = -9.81 m/s²
Time, t = 4.20 s
Substituting
s = ut + 0.5 at²
s = 8 x 4.20 + 0.5 (-9.81) x 4.20²
s = -52.92 m
Depth of well = 52.92 m
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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Four identical electric charges +q are arranged at the vertices of a square with side L If they were released, they would fly apart. (a) Find the charge Q that if placed in the center of the square would result in zero total force on each charge q. (b) Is the equilibrium stable or unstable? Justify your answer.
A square has a charge in the middle and four charges at each of the four corners that are each equal to Q. if the economy is balanced.
An equilibrium is what?As balancing is the definition of the word "equilibrium," it follows that a chemical process reflects an balance between both the reactants and the products involved in the reaction. In some physical processes, such as the melting of ice at 0°C, in which both snow and water are present, the equilibrium state can also be observed.
A charge is what?The physical characteristic of matter that enables it to feel a force when exposed to an electromagnetic field is called electric charge. The two most frequent types of electric charges are positive and negative charges.
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You ride in a boat on a river flowing at 1.8 m/s. Suppose you would like the boat to move directly across the river (in the negative x direction) with a speed of 5.0 m/s. What is the corresponding speed of the boat's velocity relative to the water? What is the corresponding direction of the boat's velocity relative to the water? Express your answer to two significant figures and include appropriate units
The boat's velocity relative to the water is 6.8 m/s, in the negative y direction.
To calculate the boat's velocity relative to the water, we first need to subtract the speed of the river from the desired speed of the boat. The desired speed of the boat is 5.0 m/s, and the speed of the river is 1.8 m/s. Thus, the boat's velocity relative to the water is 5.0 m/s - 1.8 m/s = 3.2 m/s.
To determine the direction of the boat's velocity relative to the water, we need to consider the direction of the river and the desired direction of the boat.
The river is flowing in the positive x direction, while the desired direction of the boat is in the negative x direction. Therefore, the direction of the boat's velocity relative to the water is in the negative y direction.
To calculate the magnitude of the boat's velocity relative to the water, we use the Pythagorean theorem. The magnitude of the boat's velocity relative to the water is equal to the square root of the sum of the squares of its x and y components. Thus, the magnitude of the boat's velocity relative to the water is 6.8 m/s (3.2 m/s in the negative y direction).
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A merry-go-round is spinning in a circle at a constant speed. A child is 4 meters away from the center of the merry-go-round and experiences a centripetal acceleration of 6 m/s^2. What is the tangential velocity of the child?
A.) 1.5 m/s
B.) 24.0 m/s
C.) 9.1 m/s
D.) 4.9 m/s
The velocity is 4.9 m/s.
What is the centripetal acceleration?Centripetal acceleration is the acceleration that acts towards the center of a circular path and is required to maintain an object in circular motion. It is defined as the rate of change of velocity of an object moving in a circular path.
The formula for centripetal acceleration can be expressed as:
a_c = v^2 / r
Given that;
a = v^2/r
a = acceleration
v = tangential velocity
r = radius
Thus;
v = √ar
v = (6 * 4)^1/2
v = 4.9 m/s
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A friend of yours is loudly singing a single note at 400 Hz while racing toward you at 23.0 m/s on a day when the speed of sound is 342 m/s.Part A: What frequency do you hear?Part B:What frequency does your friend hear if you suddenly start singing at 400 ?
You heard a frequency of 428.8 Hz, and your companion heard a frequency of 426.8 Hz.
What is a simple definition of frequency?The quantity of oscillations that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the amplitude is 2 per moment. This same frequency is 100 times per hour if it consumes 1/100 of an hour.
Where is the use of frequency?The frequency of oscillation and granular phenomenon, such as mechanical energy, speech recordings (sound), electromagnetic radiation, and light, is a crucial parameter in science and engineering.
The frequency you heard,
f = f(s) / [1 - (v(s)/v) ]
f = 400 / [1 - 23/342]
f = 400 / (1 - 0.0672)
f = 400 / 0.9328
f = 428.8 Hz
The frequency your friend hearing,
f = f(s) * [1 + (v(s)/v) ]
f = 400 * [1 + 23/342]
f = 400 * (1 + 0.0672)
f = 400 * 1.0672
f = 426.8 Hz
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Part A
A sports car accelerates from rest to 94 km/h in 5.5 s.
What is its average acceleration in m/s².
Express your answer using two significant figures.
V
ΑΣΦ
?
Answer:
The average acceleration of the sports car is 16.9 m/s².
A golf ball (lighter) is fired at a bowling ball (heavier) initially at rest and bounces back elastically. Compared to the bowling ball, the golf ball after the collision has
a) less momentum but more kinetic energy
b) more momentum but less kinetic energy
c) more momentum and more kinetic energy
d) less momentum and less kinetic energy
Compared to the bowling ball, the golf ball after the collision has a) less momentum but more kinetic energy.
The bowling ball's velocity and, consequently, its kinetic energy are significantly lower than those of the golf ball because its mass is significantly greater than that of the latter.
Why is the kinetic energy of a bowling ball greater than that of a golf ball?
First off, heavier objects in motion have more kinetic energy than lighter ones. For example, a bowling ball travelling at 10 m/s (the equivalent of a very fast sprint) has a lot more kinetic energy than a golf ball travelling at the same speed.
How does a collision between a bowling ball and bowling pins alter their kinetic energy?
When two objects collide, some of the kinetic energy is converted during the collision to another form of energy, this is known as an inelastic collision. A portion of the kinetic energy from the bowling ball is transferred to the pins when it strikes them, as evidenced by the way bowling balls and pins scatter and bounce after impact.
Which ball has more inertia, a golf ball or a bowling ball?
As a result of having more mass than a golf ball, a bowling ball will have a higher moment of inertia.
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yvette and zack are driving down the freeway side by side with their windows rolled down. Zack wants to toss his physics book out the window and have it land on yvette's front seat. should he direct his throw outward and toward the front of the car (throw 1), straight outward (throw 2), or outward and toward the back if the car (throw 3)? Explain?
If Zack wants to toss his physics book out the window and have it land on Yvette's front seat, he should throw straight outward (throw 2).
Given that Yvette and Zack are both moving at the same speed, their relative velocities are zero. When a book is thrown, its component of velocity in the car's motion direction is equal to that of the car.
At the time of the throw, the book will be moving at the same speed as the car. Yvette's vehicle travels at the same speed; from the viewpoint of the book, both vehicles are immobile. This indicates that the book only needs to proceed directly to Yvette's front seat. Simply slide the book to Yvette's front seat from here.
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HELP ME QUICKLYYYYY!!! TYYY
Listed in the Item Bank are some important labels for sections of the image below. Drag and drop each label to the corresponding area it identifies in the image.
1: cell membrane
2: nucleus
3: DNA
4: cytoplasm
5: ribosome
Answer:
vamos tú puedes
Explanation:
at a given instant in time, a red car is traveling at twice the velocity of a blue car. which of the following statements is correct? A. The red car has a higher acceleration than the blue car
B. The blue car has a higher acceleration than the red car
C. Both cars have the same acceleration
D. There is nothing we can say about the acceleration of either car
There is nothing we can say about the acceleration of either car
How does acceleration work?
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.
The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.
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state what the gradient of a graph of kinetic friction vs normal force represents
2) Three positive charges are located as shown in the diagram below q1 1cm q3 q1 1cm q2 find the size of electrostatic force exerted by charge q3.
In the schematically drawn circuit shown below, a light bulb is connected in series with a resistor. What is the total resistance in the circuit?
A) 90 ohms
B) 80 ohms
C) 100 ohms
D) 4 ohms
Answer:
100 ohms
Explanation:
the bulb is just a resistor that gets hot and emits light.... series circuit resistance just add together... 10 + 90 = 100 ohms
A boat is docked on the southern shore of a swiftly moving river that is 259.0 m wide. The river flows from east to west with a speed of 4.00 m/s relative to the shore. There is a dock located upstream on the northern side of the river at an angle of 57.0∘
relative to the shore (i.e. north of east). The boat is able to travel at a speed of 6.50 m/s relative to the water.
If the boat travels directly to the dock on the northern shore at a constant speed, how long does it take to get there?
It will take the boat 47.35 seconds to get to the dock on the northern shore.
What is relative velocity?The velocity of an object in relation to another object or observer is defined as relative velocity. The time rate of change of one object's relative position with respect to another object is defined as relative velocity.
We can start by using vector addition to find the velocity of the boat relative to the shore.
The velocity of the boat relative to the water is 6.50 m/s, and the velocity of the water relative to the shore is 4.00 m/s,
Let the boat's relative velocity to shore is v(bs)
water relative velocity to shore is v(ws)
boat's relative velocity to water is v(bw)
So: v(bs) = √(v(bw)² + v(ws)² - 2 × v(bw) × v(ws) × cos(57.0°))
Plugging in the known values, we get:
v(bs) = √(6.50² + 4.00² - 2 × 6.50 × 4.00 × cos(57.0°)) = 5.47 m/s
Next, we can use this velocity to find the time it takes for the boat to cross the river:
t = d / v(bs) = 259.0 m / 7.76 m/s = 47.35 s
Thus, it will take the boat 47.35 seconds.
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(D) A water tank located at a depth of 8 m from ground level is half full of water. This water is pumped up by a water pump in the basement and drilled at 2 mis' access. 10 minutes until the water in the tank is finished 0: The power of the motor is 1 kW and the cross-sectional area of the tank is 2m. ii) Determine the useful work (output) done by the equation/x, (ii) Find the energy required for friction, (iii) Find the efficiency of the pump. (iv) Suggest a way to increase the value of (iii) above. (Density of water = 1000 kgm ]
The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.
What should be the method to calculate the output, friction and efficiency?The weight of the water pushed and the height it is lifted can be multiplied to determine the beneficial work done by the pump. The volume of water in the tank multiplied by its density yields the weight of the water therein. The tank's total volume, which can be determined by multiplying the tank's cross-sectional area by its height, is equal to half of the amount of water in the tank (8 m). The water therefore weighs:
Volume is calculated as cross-sectional area times height (2 m x 8 m = 16 m3).
Weight is equal to volume times density, or 16 m3 times a density of 1000 kg/m3 equals 16,000 kg.
Useful work=Weight x Height = 16,000 kg x 10 m = 160,000 J for useful work.
A proportion of the useful work can be used to estimate the amount of energy needed for friction. This proportion is influenced by the pump's design, the water's viscosity, and other elements. The energy needed for friction can be computed using a 10% friction loss as follows:
Frictional energy equals 0.1 x 160,000 J, or 16,000 J.
The ratio of the pump's useful work to its energy input can be used to calculate the pump's efficiency. The energy input can be estimated as the motor's power (1 kW) times how long it runs for (10 minutes, or 600 seconds). So, the efficiency can be determined as follows: Energy input is calculated as follows: 1 kW x 600 sec = 600,000
Efficiency is calculated as follows: 160,000 J of useful work per 600,000 J of energy input, or 26.7%.
The friction loss can be decreased, the pump's design can be improved to reduce energy losses, or the motor's power can be increased to increase the pump's efficiency. As the beneficial work performed by the pump is directly proportional to the height the water is lifted, increasing the height the water is lifted is another alternative.
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The equation of a wave traveling in a horizontal direction is expressed as y = 5sin(60t - x)
What's the phase angle
(a)90° (b)180° (c)270° (d)360° (e)0°
Answer:
The equation of a transverse wave traveling along a very long string is y=6.0sin(0.020πx+4.0πt), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave, and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x=3.5 cm when t=0.26s?/(a) The amplitude is y
m
=6.0 cm.
(b) We find λ from 2π/λ=0.020π⋅λ=1.0×10
2
cm.
(c) Solving 2πf=ω4.0π, we obtain f=2.0 Hz.
(d) The wave speed is v=λf=(100 cm)(2.0 Hz)=2.0×10
2
cm/.s
(e) The wave propagates in the −x direction, since the argument of the trig function is kx+ωt instead of kx−ωt
(f) The maximum transverse speed (found from the time derivative of y) is
u
max
=2πfy
m
=(4.0πs
−1
)(6.0 cm)=75 cm/s
(g) y(3.5 cm,0.26 s)=(6.0 cm)sin[0.020π(3.5)+4.0π(0.26)]=2.0 cm.
A jogger maintains a constant speed around the boundaries of a rectangular field. Which of the following statements is true? O The acceleration of the jogger is uniform. O The acceleration of the jogger is zero. O The acceleration of the jogger is sometimes uniform. O The acceleration of the jogger is sometimes zero. O The acceleration of the jogger is never zero.
Options e, A jogger maintains a constant speed around the boundaries of a rectangular field. The jogger's acceleration is never zero.
An object's acceleration is a measurement of how quickly its velocity changes.
The jogger's acceleration is not zero since they are altering their velocity every time they get to a corner of the rectangular field. This is referred to as centripetal acceleration and is the acceleration necessary to maintain an object's circular motion at a constant speed.
Although the jogger's pace is constant, their direction is changing, which causes a change in their velocity, which in turn causes a change in their acceleration.
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NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude: The result at certain altitude is: R-0.0533 kPa:km Convert R to J cm Lo
After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.
What is joule?
In both electromagnetic and mechanical applications, the joule was specifically meant to be the unit of energy.The use of the calorie was formally discouraged with the adoption of the definition at the ninth General Conference on Weights and Measures in 1948, which alsoalso added the specification that the joule was to be preferred as the unit of heat in the context of calorimetry.The joule as it appeared in the present International System of Units in 1960 was directly related to this definition.To convert R to J, convert their units,
1 kPa·km = 1.0 × 10⁻⁸ J(cm⁻⁴)
0.0533 kPa·km = -0.0533 × 1.0 × 10⁻⁸ J(cm⁻⁴)
= 5.33 × 10⁻¹⁰ J·cm⁻⁴
Thus, After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.
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Non skull bones of the axial skeleton
Answer:
humerus, phalanges, carpals, etc
Explanation:
these examples are non skull bones of the axial skeleton
Which diagram best shows what happens when light passes through a magnifying glass?
A magnifying glass is a simple optical device that uses a convex lens to produce a magnified image of an object.
What is a magnifying glass?When a magnifying glass is held close to an object, the lens refracts the light that is reflected off the object and causes it to converge or come together at a point. This point is called the focal point, and it is where the magnified image is formed. The image appears larger and closer than the actual object because it is formed by the light that has been bent and converged by the lens.
The magnification produced by a magnifying glass depends on the power of the lens, which is determined by its focal length.
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