The isotope 38Sr 90 is one of the extremely hazardous species in the residues from nuclear power generation. The strontium in a 0.500-g sample diminishes to 0.393 g in 10.0 yrs. Calculate the half-life.

Answers

Answer 1

Answer:

Half-life = 28.8 years

Explanation:

The radioactive decay of an atom follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] is actual amount of isotope after time t; k is decay constant and [A]₀ initial amount of isotope

Solving for k:

Ln[0.393g] = -k*10yrs + ln[0.500]

-0.2408 = -k*10yrs

0.02408yrs⁻¹ = k

Half-life, is:

Half-life = ln 2 / k

Half-life = ln 2 / 0.02408yrs⁻¹

Half-life = 28.8 years

Answer 2

The isotope [tex]38Sr^{90}[/tex] is one of the extremely hazardous species in the residues from nuclear power generation. The strontium in a 0.500-g sample diminishes to 0.393 g in 10.0 yrs, the half-life is - 28.78

Formula:

radioactive decay follows first-order kinetics,  

k = [tex]\frac{1}{t}ln\frac{a}{x}[/tex]

Given:  

a = initial amount = 0.5 g  

x = amount of isomer after 10 years = 0.393 g  

t= time   = 10 years

Solution:  

k =  [tex]\frac{1}{10}ln\frac{0.5}{0.393}[/tex]

   = 0.02408  

k = [tex]\frac{0.693}{t/2}[/tex]  

T(1/2) = half-life time

= [tex]\frac{0.693}{k}[/tex]

=   [tex]\frac{0.693}{0.02408}[/tex]

= 28.78 years.

Thus, The isotope [tex]38Sr^{90}[/tex] is one of the extremely hazardous species in the residues from nuclear power generation. The strontium in a 0.500-g sample diminishes to 0.393 g in 10.0 yrs, the half-life is - 28.78

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Answers

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Answers

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S
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Answers

Answer:

26.74g

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The equation of the reaction is;

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