Answer:
it C
Explanation:
and have a good day :)))
Answer : (c) Newton's second law
The formula (F = m x a) comes under Newton's second law of motion, which revolves around the concept of momentum and force.
A student is helping his teacher move a 40.0 kg aquarium. What net sideways force must he exert on the aquarium to slide it across the floor so that it accelerates at 0.50 m/s2?
Answer:
20 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of aquarium = 40 kg
Acceleration (a) = 0.50 m/s²
Force (F) =?
Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as:
Force (F) = mass (m) × acceleration (a)
F = m × a
With the above, we can obtain the force needed to slide the aquarium as follow:
Mass (m) of aquarium = 40 kg
Acceleration (a) = 0.50 m/s²
Force (F) =?
F = m × a
F = 40 × 0.5
F = 20 N
Therefore, a force of 20 N is needed to slide the aquarium.
Hi i need help. thNKS
Answer:
8
Explanation:
Groups go down, periods go across :)
please help urgent
Four forces are exerted on an object as shown below:
look at attachment
In which direction will the object move?
Up
Down
Left
Right
true or false. A small pick-up truck traveling at 55 km/h has more momentum than a full-sized bus traveling at the same speed
Answer: true
because the small truck is going fast and has momentum, so the bus and the truck have the same amount of momentum.
Objects change motion due to forces. When they become unbalanced, their motion changes, while balanced forces cause constant motion. Unbalanced forces result in a change of velocity. What is it called when velocity changes?
Answer:
Balanced forces: When a number of forces acting on a body do not cause any change in its state of rest or of uniform motion along a straight line then the forces are said to be balanced forces. In other words, a body is said to be underbalanced forced when the resulting force acting on the body is zero.
The balanced forces:
⋅ Cannot set any stationary body into motion.
⋅ May change the shape and size of soft objects.
⋅ Cannot change the speed/velocity of a moving body.
Unbalanced forces:
When the resultant of all the forces acting on a body is not zero, then forces are called unbalanced forces.
Example:
⋅ Game of tug of war: When the forces exerted by both the teams are equal, then the rope does not move. But, if the force applied by team A is greater than team B, then the rope, as well as members of the weaker team, i.e., B, will be pulled towards A. The unbalanced force can (a) Set a stationary body in motion.
⋅ Set a moving body at rest.
⋅ Change the direction of motion.
Explanation:
give me an one thanks please
A block slides down a 30.0 degree inclined plane at an acceleration of 2.0 m/s^2. What is the coefficient of friction between the block and the inclined plane? Use g=10.0 m/s^2
A) .20
B) .25
C) .30
D) .35
Answer:
D) .35
Explanation:
m = Mass of block
g = Acceleration due to gravity = [tex]10\ \text{m/s}^2[/tex]
[tex]\theta[/tex] = Angle of inclination = [tex]30^{\circ}[/tex]
a = Acceleration of block = [tex]2\ \text{m/s}^2[/tex]
[tex]\mu[/tex] = Coefficient of friction between the block and the inclined plane
f = Frictional force = [tex]\mu mg\cos\theta[/tex]
As the forces are conserved in the system we have
[tex]mg\sin\theta-f=ma\\\Rightarrow mg\sin\theta-\mu mg\cos\theta=ma\\\Rightarrow g(\sin\theta-\mu\cos\theta)=a\\\Rightarrow \sin30^{\circ}-\mu\cos30^{\circ}=\dfrac{2}{10}\\\Rightarrow \dfrac{1}{2}-\mu\dfrac{\sqrt{3}}{2}=0.2\\\Rightarrow \mu=\dfrac{\dfrac{1}{2}-0.2}{\dfrac{\sqrt{3}}{2}}\\\Rightarrow \mu=\dfrac{0.3\times 2}{\sqrt{3}}\\\Rightarrow \mu=0.3464\approx 0.35[/tex]
The coefficient of friction between the block and the inclined plane is 0.35
Martina travels from her house to her moms office building, From there she walks to school. After school, she walks to the library and then to a friends house before finally ending back at home. Fine Martina's totoal distance traveld
Answer:
it matters how far she traveled
Explanation:
To determine a waves' frequency, you must know the (2 points)
Select one:
a. distance it travels
b. number of oscillations in a given period of time
c. distance between the crest and trough
d. height of the wave
Answer:
b
to determine the frequency you must know oscillations and the given time
Two 5.0-kg carts collide on a one-dimensional air track. The total momentum of the carts was 4.9 kg m/s rightwards before the collision. After the collision, one cart is moving leftwards at 0.15 m/s. what is the velocity of the second cart?
Answer:
1.13 m/s right
Explanation:
Momentum before = momentum after
p₀ = p
p₀ = m₁ v₁ + m₂ v₂
4.9 kg m/s = (5.0 kg) (-0.15 m/s) + (5.0 kg) v
4.9 kg m/s = -0.75 kg m/s + (5.0 kg) v
5.65 kg m/s = (5.0 kg) v
v = 1.13 m/s
Answer: 1.13 m/s equivalent to 1.1 m/s
Explanation:
Energy is
A) conserved
OB) created only
OC) destroyed only
OD) created or destroyed
Answer:
A
Explanation:
Conserving energy produces a higher quality of life. Reduced emissions result in cleaner air quality. In addition, it helps create a healthier planet, or at least helps sustain the resources we already have
Two identical spheres (of equal mass) a distance of 10 meters apart exert a force of gravity of 0.00050 N on each other. What are their masses?
Answer:
From the following statements about mechanical waves, identify those that are true for transverse mechanical waves only, those that are true for longitudinal mechanical waves only, and those that are true for both types of waves.
Explanation:
car 1 is traveling south at 18 m/s and has a full load, giving it a total mass of 14,650 kg. Car 2 is traveling north at 11 m/s and has a mass of 3,825 kg. After the collision, car 1 has a final velocity of 6 m/s south. What is the velocity of car 2
Answer:
v_{4}= 80.92[m/s] (Heading south)
Explanation:
In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.
ΣPbefore = ΣPafter
where:
P = linear momentum [kg*m/s]
Let's take the southward movement as negative and the northward movement as positive.
[tex]-(m_{1}*v_{1})+(m_{2}*v_{2})=-(m_{1}*v_{3})+(m_{2}*v_{4})[/tex]
where:
m₁ = mass of car 1 = 14650 [kg]
v₁ = velocity of car 1 = 18 [m/s]
m₂ = mass of car 2 = 3825 [kg]
v₂ = velocity of car 2 = 11 [m/s]
v₃ = velocity of car 1 after the collison = 6 [m/s]
v₄ = velocity of car 2 after the collision [m/s]
[tex]-(14650*18)+(3825*11)=(14650*6)-(3825*v_{4})\\v_{4}=80.92[m/s][/tex]
Which phrase best describes Osorno?
shield volcano
active volcano
dormant volcano
explosive volcano
Answer:
dormant
Explanation:
Answer:
dormant
Explanation:
A jet liner must reach a speed of 82 m/s for takeoff. If the
runway is 1500 m long, what acceleration must the jet
have?
Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial ([tex]v_{o}[/tex]) and final speeds ([tex]v_{f}[/tex]), measured in meters per second, of the aircraft and likewise the runway length ([tex]d[/tex]), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed ([tex]a[/tex]), measured in meters per square second:
[tex]a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}[/tex]
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]d = 1500\,m[/tex], then the acceleration that the jet must have is:
[tex]a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}[/tex]
[tex]a = 2.241\,\frac{m}{s^{2}}[/tex]
The acceleration that the jet liner that must have is 2.241 meters per square second.
Please help me↓
This topographical map has contour lines 5 ft of elevation (height above sea level) apart; the numbers on the thicker lines are elevation in feet. What is the difference in elevation between the two points marked?
Point II is 45 ft lower.
Point II is 10 ft lower.
Point II is 10 ft higher.
Point II is 45 ft higher.
Answer:
unmmm u can say that it is going mt 15s
Answer: Did you get the answer?
Explanation:
how we will gonna solve this question?
0.05cm=_______=mm
Answer:
It would be 0.5 millimeter !
Explanation:
1 cm is equal to 10 mm. You'll just need to move the decimal point over ! :))
how does the index of refraction of an unknown substance compare to the index of refraction of a vacuum? explain how the speed and the refraction of light would behave in both?
Answer:
By measuring the speed of light in both in space and that unknown substance
Explanation:
Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density.
By measuring the speed of light in that medium and dividing it by speed of light 3*10^8 we can measure the refractive index of any medium
Analyze the chemical reaction below
16 g CH4 + 64 g O2 → 44 g CO2 + 36g H2O
Explain the law of conservation of mass and describe how the equation represents the law of conservation of mass.
Answer:
Explanation:
The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .
In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass
Is this physically plausible?
Answer:
stop useing my awnsers just to deleate them
Explanation:
Answer the following questions
Answer:
9 - 10N to the left
10 - There is no change on the object
Explanation:
Can I have brainliest answer pls?
I can’t figure it out my question is:
--- are complex and may be change when new information is available or new technologies are developed.
My choices to choose from are:
Laws
Hypothesis
Theories
Procedures
Determine the activity of the sample of cerium when the sample was 20 seconds old
Answer:
There are [tex]3.779\times 10^{23}[/tex] atoms when the sample of cerium is 20 seconds old.
Explanation:
The decay of isotopes is modelled after the following exponential expression:
[tex]N(t) = N_{o}\cdot e^{-\left(\frac{\ln 2}{t_{1/2}}\right)\cdot t }[/tex] (1)
Where:
[tex]N_{o}[/tex] - Initial number of atoms, dimensionless.
[tex]N(t)[/tex] - Current number of atoms, dimensionless.
[tex]t[/tex] - Time, measured in seconds.
[tex]t_{1/2}[/tex] - Half-time, measured in seconds.
Now we clear the half-time within (1):
[tex]\ln \frac{N(t)}{N_{o}} = -\frac{t\cdot \ln 2}{t_{1/2}}[/tex]
[tex]t_{1/2} = -\frac{t\cdot \ln 2}{\ln \frac{N(t)}{N_{o}} }[/tex]
If we know that [tex]N_{o} = 5\times 10^{23}[/tex], [tex]N(t) = 2\times 10^{23}[/tex] and [tex]t = 66\,s[/tex], then the half-life of the isotope is:
[tex]t_{1/2}=-\frac{(66\,s)\cdot \ln 2}{\ln \frac{2}{5} }[/tex]
[tex]t_{1/2}\approx 49.927\,s[/tex]
And the decay equation for the sample is described by:
[tex]N(t) = (5\times 10^{23})\cdot e^{-0.014\cdot t}[/tex]
Lastly, if we get that [tex]t = 20\,s[/tex], then the activity of the sample of cerium is:
[tex]N(20) = (5\times 10^{23})\cdot e^{(-0.014)\cdot (20)}[/tex]
[tex]N (20) \approx 3.779\times 10^{23}[/tex]
There are [tex]3.779\times 10^{23}[/tex] atoms when the sample of cerium is 20 seconds old.
What is the correct interpretation of this diagram?
Forces from the left and the right are unbalanced. The object moves left.
Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the right.
Up and down forces are balanced. The object does not move.
Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the left.
Answer:
where is the diagram?
Explanation:
here is the diagram
hope this helps a little cuz i cant paste pictures here
Four directional arrows with labels five hundred seventy-nine Newtons, four hundred eighty-seven Newtons, five hundred seventy-nine Newtons and six hundred thirty-two Newtons
A book is placed on a table and a bike moves on a road. Which statement is correct? (3 points)
The book has potential energy (Pe) and the bike has kinetic energy (Ke).
Answer:
C
Explanation:
The book has potential energy and the bike has kinetic energy.
You are interested in space travel and want to learn more facts about space travel.
Which would be the best source of information? (2 points)
The Star Wars web page NASA web page
A book about planets
A magazine article
Answer:
A Book about Planets
Explanation:
Answer:
Nasa web page
Explanation:
Which of the following objects has no kinetic energy ?
Answer:
delivery truck
Explanation:
All the objects such as delivery truck stopped at a light has no kinetic energy. Thus, the correct option is A.
What is Kinetic energy?Kinetic energy is the energy of motion, it is observable as the movement of an object or the subatomic particles of an object. Every moving object and particle have certain amount of kinetic energy. A person who is walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of the kinetic energy at work.
The example in which the delivery truck stopped at a light is an example which has no kinetic energy. Kinetic energy is due to motion of the object.
Therefore, the correct option is A.
Learn more about Kinetic energy here:
https://brainly.com/question/26472013
#SPJ6
Your question is incomplete, most probably the complete question is:
Which of the following objects has no kinetic energy?
a. delivery truck stopped at a light
b. eagle in flight over a park
c. cannonball fired from a cannon
d. diver falling from a diver board
During a thunderstorm a tornado lift a car to a height of 300 m above the ground increasing and strength the tornado flings the car horizontally with the speed of 80.0 m/s how long does the car take to reach the ground how far horizontally does the car travel before hitting the ground
Answer:
Explanation:
To calculate the time it took the car to hit the ground, we use the formula
speed = distance/time
80 m/s = 300 m/time
time = 300/80
time = 3.75 secs
It must have taken the car 3.75 seconds to hit the ground
To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)
speed = distance/time
80 = distance/3.75
distance = 3.75 x 80
distance = 300 meters
Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?
Explanation:
0.10kg
0.5kg×0.2kg=
0.10
How does mass affect acceleration during free fall?
Pick a hypothesis below now.
If an object falls freely, then heavy objects accelerate more than light objects.
If an object falls freely, then heavy objects accelerate less than light objects.
If an object falls freely, then heavy objects accelerate nearly the same as light objects.
Answer:
it is the 3rd one
Explanation:
If an object falls freely, then heavy objects accelerate nearly the same as light objects.
help me please I can't get the final step
Answer:
[tex]\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}[/tex]
Explanation:
Dimensional Analysis
It's given the relation between quantities A, B, and C as follows:
[tex]\displaystyle A=\frac{3}{2}B^mC^n[/tex]
and the dimensions of each variable is:
[tex]A=L^2T^2[/tex]
[tex]B=LT^{-1}[/tex]
[tex]C=LT^2[/tex]
Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):
[tex]\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n[/tex]
Operating:
[tex]L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)[/tex]
[tex]L^2T^2=L^{m+m}T^{-m+2n}[/tex]
Equating the exponents:
[tex]m+n=2[/tex]
[tex]-m+2n=2[/tex]
Adding both equations:
[tex]3n=4[/tex]
Solving:
[tex]n=4/3[/tex]
[tex]m=2-4/3=2/3[/tex]
Answer:
[tex]\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}[/tex]