The data show the list and selling prices for several expensive homes. Find the regression​ equation, letting the first variable be the independent​ (x) variable. Find the best predicted selling price of a home having a list price of ​$ million. Use a significance level of 0.05.

Answer:

No solution

Step-by-step explanation:

[tex]-38 - 7y = 2 - 7(y + 6)\\\\\mathrm{Expand\:}2-7\left(y+6\right):\quad -7y-40\\-38-7y=-7y-40\\\\\mathrm{Add\:}38\mathrm{\:to\:both\:sides}\\-38-7y+38=-7y-40+38\\\\Simplify\\-7y=-7y-2\\\\\mathrm{Add\:}7y\mathrm{\:to\:both\:sides}\\-7y+7y=-7y-2+7y\\\\Simplify\\\\0=-2\\\mathrm{The\:sides\:are\:not\:equal}\\No\: solution[/tex]

Answer:

No solution

Step-by-step explanation:

First do distribute property

-38-7y=2-7y-42

then combine like terms the 2 and the -42

-38-7y=-40-7y add 7y from both sides

-38+y=-40 add 38 to -40 you get -2

0=-2 no solution

Answer:

[tex]\mathbf{\int_C F*dr= -125}[/tex]

Step-by-step explanation:

Given that:

[tex]F(x,y,z) = ( x+ y^2) i + (y +z ^2) j+(z + x^2)k[/tex]   , where C is the triangle with vertices (5, 0, 0), (0, 5, 0), and (0, 0, 5).

The objective is to use Stokes' Theorem  to evaluate CF. dr

Stokes Theorem : [tex]\int_c F .dr = \iint _s \ curl \ F. dS[/tex]

To estimate curl F , we need to find the partial derivatives:

So;

[tex]P = x+y^2[/tex]

partial derivative is:

[tex]\dfrac{\partial P }{\partial y }= 2y[/tex]

[tex]\dfrac{\partial P }{\partial z }= 0[/tex]

[tex]Q = y + z^2[/tex]

partial derivative is:

[tex]\dfrac{\partial Q }{\partial x }= 0[/tex]

[tex]\dfrac{\partial Q }{\partial z }= 2z[/tex]

[tex]R = z +x^2[/tex]

partial derivative is:

[tex]\dfrac{\partial R }{\partial x }= 2x[/tex]

[tex]\dfrac{\partial R }{\partial y }= 0[/tex]

These resulted into

curl F = (0 - 2z)i + ( 0 -2x) j + ( 0 - 2y) k

= ( -2z, -2x, -2y )

The normal  vector and the equation of the plane can be expressed as follows:

If a = (0,5,0 - ( 5,0,0)

a = ( -5,5,0 )

Also ,

b = (0, 0,5) - (5,0,0)

b = (-5. 0,5)

However,

[tex]a \times b = \begin {vmatrix} \begin{array} {ccc} i &j&k \\-5&5&0 \\-5&0&5 \\ \end {array} \end {vmatrix}[/tex]

a × b = (25 - 0)i - (-25-0)j+ (0+25)k

a × b = 25i +25j +25k

∴ the normal vector can be n = (1,1,1)

If we assume x to be x = (x,y,z)

and [tex]x_0 = (5,0,0)[/tex]

Then

[tex]n*(x-x_0) =0[/tex]

[tex](1,1,1)*(x-5,y-0,z-0) =0[/tex]

[tex]x-5+y+z =0[/tex]

collecting like terms

x +y +z  = 5

now, it is vivid that from the equation , the plane of the  normal vector =(1,1,1)

Similarly, x+y+z = 5 is the projection of surface on the xy - plane such that the line x +y = 5

Thus; the domain D = {(x,y) | 0 ≤ x ≤ 5, 0 ≤ y ≤ 5 - x}

To evaluate the line integral using Stokes' Theorem

[tex]\iint_S \ curl \ F .dS= \iint _S (-2z,-2y,-2x) *(1,1,1) \ dS[/tex]

[tex]\iint_S \ curl \ F .dS= \iint _S -2z-2y-2x \ dS[/tex]

[tex]\iint_S \ curl \ F .dS= \iint _S -2(5-x-y)-2y-2x \ dS[/tex]

[tex]\iint_S \ curl \ F .dS= \iint _S -(10) \ dS[/tex]

[tex]\int_C F*dr= \int ^5_0 \ \int ^{5-x}_0 -10 \ dy \ dx[/tex]

[tex]\int_C F*dr= -10 \int^5_0 (5-x) \ dx[/tex]

[tex]\int_C F*dr= -10 \begin {bmatrix} 5x - \dfrac{x^2}{2} \end {bmatrix}^5_0[/tex]

[tex]\int_C F*dr= -10 \begin {bmatrix} 25 - \dfrac{25}{2} \end {bmatrix}[/tex]

[tex]\int_C F*dr= -10 \begin {bmatrix} \dfrac{25}{2} \end {bmatrix}[/tex]

[tex]\mathbf{\int_C F*dr= -125}[/tex]

Answer:

4y

Step-by-step explanation:

[tex]y- (-3y)\\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\=y+3y\\\\=4y[/tex]

Hello there! :D

I love showing people how to use this concept, so lets get right to it! If you have trouble with negative (-) signs and how they interact with each other, I suggest you watch some Khan academy videos, it could realy help you in the future! :)

Alright, so here's the general rule: (multiplication and division)

-,-= +

-,+ = -

+,+=+

So, with this rule, I think we can solve!

Firstly, remember PEMDAS.

Let's look at the signs first. Two negatives equal a positive. Make the 3y in the parenthesis positive. Think of the negative sign as a -1 that is being multiplied by the (-3y) and the y.

That would look like this:

(y) (-1) (-3y)

Now we have:

y*(3y)

So when multiplying a variable by a variable, it becomes squared.

So, we would have 3y^2 or [tex]3y^{2}[/tex]

If you have any questions about this problem feel free to comment on this answer.

I hope this helped you and you have a wonderful day,

Kai xx

Answer:

Step-by-step explanation:

A. Data of the study: All 45 exercise times there were recorded from the participants in the study

B. Parameter of the study: The average amount of time that all clients exercise in one week.

C. Variable of the study: The amount of time that any given client from the fitness center exercises.

D. Population for the study: All clients at the fitness center.

E. Sample of this study: The 45 client from the fitness center who participated in the study.

F. Statistics of the study: The average amount of time that a sample of clients exercises in one week

Answer:

= 7x² + 5x - 9

Step-by-step explanation:

(9x + 1) - (-7x² + 4x + 10)

= 9x + 1 - ( -7x² + 4x + 10)

= 9x + 1 + 7x² - 4x - 10

= 7x² + 5x - 9

Answer:

The map that has a scale of 1 inch to 500 feet must be larger in size

Step-by-step explanation:

Since both maps represent the ame park area, the map that show more detail using 1 inch for every 500 feet, must be larger in size. notice that in order to represent 1000 feet this map needs to use 2 inches, while the other one uses only 1 inch of paper.

Answer:

Rs 30800

Step-by-step explanation:

The formula for compound interest is

A = P[1 + (r/100)]^t, where

A = amount of compounded interest

P = principal amount

r = interest rate

Applying this to our question, we have

A = 25000 [1 + (10/100)] [1 + (12/100)]

A = 25000 (1 + 0.1) (1 + 0.12)

A = 25000 * 1.1 * 1.12

A = 25000 * 1.232

A = 30800

Answer:  see proof below

Step-by-step explanation:

  Statement                      Reason

1. YO = NZ                      1. Given

2. OZ = OZ                     2. Reflexive Property

3. YO + OZ = YZ             3. Segment Addition Property

   NZ + OZ = NO

4. YO + OZ = NZ + OZ    4. Addition Property

5.  YZ = NO                     5. Substitution

6. ∠M ≅ ∠X                      6. Given

7. ∠N ≅ ∠Y                       7. Given

8. ΔMNO ≅ ΔXYZ           8. AAS Congruency Theorem

Step-by-step explanation:

Hope it helps u please mark it as brainlist

Answer:

the answer is647

Step-by-step explanation:

600+30+17

Answer:

647

Step-by-step explanation:

600

+ 30

   17

_____

647

Answer:

w=5000+0.7s

Step-by-step explanation:

please give 5 star I need it

Answer:

-1, -0.5, 0, 0.4, 1/5, 11/2

Step-by-step explanation:

Answer:

  7.7 seconds

Step-by-step explanation:

Put the given height into the formula and do the arithmetic.

  t = √(290.57/4.9) = √59.3 ≈ 7.7 . . . seconds

The object will take 7.7 seconds to hit the ground.

=============================================

Explanation:

If angle x is the reference angle, then the side 9 is the adjacent side (it is the closer leg to angle x). The hypotenuse is 17 as it is opposite the largest angle. The largest side is always opposite the largest angle in a triangle.

-----------------

cos(angle) = adjacent/hypotenuse

cos(x) = 9/17

x = arccos(9/17)

x = 58.034281249203

x = 58

Arccosine is the same as inverse cosine, written as [tex]\cos^{-1}[/tex]

Make sure your calculator is in degree mode.

-------------

Edit:

After finding x, we can find y

x+y = 90

58+y = 90

y = 90-58

y = 32

Step-by-step explanation:

y r y u

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Answer:

Step-by-step explanation:

Hello, please consider the following.

[tex]\begin{aligned} (2x-9)(3x+4)=\ &2(3x+4)\\&-9(3x+4)\\\\ =\ & 6x+8\\&-27x-36\\\\=\ &(6-27)x+8-36\\\\=\ &-21x-28\end{aligned}[/tex]

Thank you.

Answer:

8

Step-by-step explanation:

Numbers divisible by 12 and 30:

So, numbers should be divisible by 60

To find the greatest one divide 586 by 60 and take whole part of quotient, which is 9, so there are 9 multiples of 60 smaller than 586.

Excluding 60 which is less than 75.

So required number is 9 - 1 = 8.

Answer:

Yes based on the result 0.4841 the internet users watch less TV because the mean would be placed at 0.5 and it is less than 0.5

Step-by-step explanation:

a)The variable "weekly time spent watching television" is normally distributed and is skewed right.

b) Mean = x` 2.35 hours

Standard deviation = s/√n = 1.93/√40=1.93/6.3245553= 0.3051598

c) P(2<X<3) = P (2-2.35/ 0.3051598< Z< 3 -2.35/ 0.3051598)

                    = P ( -1.14694 < Z <2.13003)

                     = 0.3729 + 0.4830

=0.8559

So the probability is 0.8559

(0.8559 we check the value of 2.13 from the normal distribution tables and add with the value of 1.14 to get the in between value -1.14694 < Z <2.13003)

d) Here n = 35 , s= 1.93 , mean = 2.35 and x= 1.89  

So Putting the values

P (X ≤ 1.89) = P (Z ≤ 1.89- 2.35/ 1.93 / √35)

              = P ( Z ≤ -0.238341/ 5.9160797)

                  = P ( Z ≤ -0.04028)

= 0.5 - 0.0159

= 0.4841

Similarly again subtracting from 0.5 the value from normal distribution table to get less than or equal to value.

Yes based on the result 0.4841 the internet users watch less TV because the mean would be placed at 0.5 and it is less than 0.5

The mean value is 2.35, SD is 1.93 with an SD error of 0.3051597 and the probability is 0.8559, and yes 0.4841 internet users watch less TV.

It is given that the amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials.

It is required to find the standard deviation and probability.

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

We know the formula for standard error:

[tex]\rm SE = \frac{s}{\sqrt{n} }[/tex]

Where 's' is the standard error

and n is the sample size.

In the question the value of s = 1.93 hours

and sample size n = 40

[tex]\rm SE = \frac{1.93}{\sqrt{40} }\\[/tex]

SE = 0.3051597

For the probability between 2 and 3 hours.

= P(2<X<3)  

[tex]\\\rm =P(\frac{2-x)}{s} < Z < \frac{3-x)}{s})\\\\\rm = P(\frac{(2-2.35)}{0.3051598} < Z < \frac{(3-x)}{0.3051598})\\\\[/tex]         (because the mean value x is 2.35)

=P(-1.14694 <Z < 2.13003)

=0.3729+ 0.4830   ( values get from Z table for -1.14 and 2.13 )

=0.8559

For P(X≤1.89)

[tex]\rm P(Z\leq \frac{(x'-x)}{\frac{s}{\sqrt[]{n} } } )\\\\\rm P(Z\leq \frac{(1.89-2.35)}{\frac{1.89}{\sqrt[]{35} } } )[/tex]

= P(Z ≤ -0.04028)

= 0.5 - 0.0159

=0.4841

Based on the result of 0.4841 the internet users watch less TV because the mean would be placed at 0.5 and it is less than 0.5.

Thus, the mean value is 2.35, SD is 1.93 with an SD error of 0.3051597 and the probability is 0.8559, and yes internet users watch less TV.

Learn more about the standard deviation here:

https://brainly.com/question/12402189

Answer:

10°

Step-by-step explanation:

The angle subtended at the circumference is half the angle subtended at the centre of the circle i.e. 20°÷2=10°

Answer:

-i

Step-by-step explanation:

[tex]\sqrt{-1}[/tex] * [tex]\sqrt{-1}[/tex] * [tex]\sqrt{-1}[/tex] = -i

Answer:

a = 10

b = 2.5

Step-by-step explanation:

The given vector is

<-1, 4>

Let [tex]\vec A[/tex] represents <-1, 4>.

First, the dilation is done by a factor of 2.5.

If the dilation of a vector <[tex]x_1[/tex], [tex]x_2[/tex]> is done by a factor k:

Then the resulting vector becomes:

[tex]<kx_1, kx_2>[/tex]

The resulting [tex]\vec B[/tex] as per above explanation:

[tex]<2.5\times -1, 2.5\times 4> \Rightarrow \vec B \bold{<-2.5, 10 > }[/tex]

Now, it is given that the vector is rotated by [tex]\frac{\pi}{2}[/tex] or [tex]90^\circ[/tex].

The steps to find the resulting vector after the rotation of [tex]\frac{\pi}{2}[/tex] or [tex]90^\circ[/tex], we can use the simple method:

Step 1:  Multiply the [tex]x[/tex] value with -1.

i.e. the vector now becomes <2.5, 10> (Negative sign of x value removed).

Step 2: Swap the values of [tex]x[/tex] and [tex]y[/tex].

So, the resulting vector is:

<10, 2.5>

In other form, we can represent the above vector as:

[tex]\left[\begin{array}{c}10&2.5\end{array}\right][/tex]

Comparing with [tex]\left[\begin{array}{c}a&b\end{array}\right][/tex]

a = 10

b = 2.5

Answer:

The correct answer is -10 and -2.5

Step-by-step explanation:

Plato

Answer:

The  probability is   [tex]P(X < 3) = P(X \le 3-1 = 2 ) = 0.8074[/tex]        

Step-by-step explanation:

From the question we are told that

   The  probability of a tornado is [tex]p = 0.11[/tex]

    The sample  size is  [tex]n = 14[/tex]

Since the number of tornadoes in any calendar year is independent of the number of tornadoes in any other calendar year and  there can be  only  outcome so we can evaluate probability using binomial distribution.

The probability of a tornado not occurring is mathematically evaluated

         [tex]q = 1 - p[/tex]

=>      [tex]q = 1 - 0.11[/tex]

=>      [tex]q = 0.89[/tex]

The probability that there are fewer than 3 tornadoes in a 14-year period is mathematically represented as

      [tex]P(X < 3) = P(X \le 3-1 = 2 ) = \left n } \atop {}} \right. C_2 * p ^2 q^{n- 2 } + \left n } \atop {}} \right. C_1 * p ^1 q^{n- 1 } + \left n } \atop {}} \right. C_0 * p ^r q^{n- 0 }[/tex]

      [tex]P(X < 3) = P(X \le 3-1 = 2 ) = \left 14 } \atop {}} \right. C_2 * (0.11) ^2 (0.89)^{14- 2 } + \left 14 } \atop {}} \right. C_1 * (0.11) ^1 (0.89)^{14- 1 } + \left 14 } \atop {}} \right. C_0 * (0.11) ^0 (0.89)^{14- 0 }[/tex]

       [tex]P(X < 3) = P(X \le 3-1 = 2 ) = 91 * 0.0121*0.247 + 14 * 0.11*0.2198 + 1 * 1 * 0.197[/tex]

[tex]P(X < 3) = P(X \le 3-1 = 2 ) = 0.8074[/tex]        

Answer:

240 000

Step-by-step explanation:

Change in wetlands each year: 60 000 acres

Change in wetlands after 4 years:

60 000 x 4 = 240 000 (acres)

Answer:

0.2146

Step-by-step explanation:

From the picture:

The radius of the circle = r. This means that the area of the circle = πr²

Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²

The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²

The ratio of the area inside the square but outside the circle to the area of the square =  r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146

Answer:

8 inches

Step-by-step explanation:

The computation of the length, in inches of Segment line G prime A prime is shown below:-

Data provided

In two quadrilateral GAME and G'A'M'E',

ME = 35 inches

AM = GE = 56 inches

M'E' = 14 inches

Also, the perimeter of quadrilateral GAME = 167 inches

GA + AM + ME + GE = 167

Now we will put the values into the above equation

GA + 56 + 35 + 56 = 167

GA + 147 = 167

So,

GA = 20 inch

Therefore

GAME is closely related to G'A'M'E'

Now,

By the property of similar figures,

[tex]\frac{M E}{M' E'} = \frac{GA}{G'A'}[/tex]

[tex]G'A' = \frac{M'E'\times GA}{ME} \\\\ = \frac{14\times 20}{35}[/tex]

= 8 inches

Answer: Hi!

To find the volume of a box (or cube), you multiply length times width times height.

In this case, you have all of the measurements, so all we have to do is multiply them together!  

5cm * 8cm * 10cm = 400

So, the volume of this box is 400cm^3!

Hope this helps!

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

[tex]r=\frac{ep}{1\pm e*cos\theta}[/tex]

Given the conic equation: [tex]r=\frac{12}{3-10cos\theta}[/tex]

We have to make it to be in the form [tex]r=\frac{ep}{1\pm e*cos\theta}[/tex]:

[tex]r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }[/tex]

Comparing with  [tex]r=\frac{ep}{1\pm e*cos\theta}[/tex]

e = 10/3 = 3.3333, p = 6/5

b) since the eccentricity = 3.33 > 1, it is a hyperbola

c) The equation of the directrix is x = ±p = ± 6/5

Answer:

If the present age is x, then age n years later/hence = x + n. If the present age is x, then age n years ago = x – n. The ages in a ratio a: b will be ax and bx. If the current age is y, then 1/n of the age is y/n.

Answer:

826×3569=2947994 ans