The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
2 C4H10 + 13O2 -------> 8CO2 + 10H2O
(a) How many moles of water formed?
(b) How many moles of butane burned?
(c) How many grams of butane burned?
(d) How much oxygen was used up in moles?
(e) How much oxygen was used up in grams?

Answers

Answer 1

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

Further explanation

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

Answer 2

0.137moles of water is formed, 0.0274 moles or 1.5892 g of butane burned and 0.1781 moles or 5.6992 g of O₂ is used.

What is combustion reaction?

Those reaction in which fuel is oxidized by the oxygen molecules and produce carbon dioxide and water molecule.

Given chemical reaction is:
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Given mass of water = 2.46 grams

Moles will be calculated as:

n = W/M, where

W = given mass

M = molar mass

(a) Moles of water formed is calculated as:

Moles of water n = 2.46g / 18 g/mol = 0.137moles

(b) From the stoichiometry of the reaction, it is clear that:

10 moles of water = produced by 2 moles of butane

0.137 moles of water = produced by 2/10×0.137=0.0274 moles of butane

(c) Weight of butane is calculated by using moles:

W = 0.0274 × 58 g/mol = 1.5892 g

(d) From the stoichiometry of the reaction, it is clear that:

2 moles of butane = react with 13 moles of O₂

0.027 moles of butane = react with 13/2×0.027=0.1781 moles of O₂

(e) Mass of oxygen is calculated as:
W = 0.1781 x 32 g/mol = 5.6992 g

Hence, (a) 0.137moles, (b) 0.0274 moles, (c) 1.5892 g, (d) 0.1781 moles and (e) 5.6992 g.

To know more about combustion reaction, visit the below link:

https://brainly.com/question/9425444


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Answer:

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Answer:

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Answers

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Further explanation

Given

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Required

The average speed

Solution

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Can be formulated :

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avg speed = 150 m : 23 s

avg speed = 6.52 m/s

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< Question 3 of 25
>
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Answers

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Answers

Answer:

I think it's b.

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Answer:

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Answers

Answer:

Cl-

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The equation of the reaction is;

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Explanation:

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a
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b
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c
2 moles of nitrogen, 6 moles of hydrogen, 1 mole of sulfur

d
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Answers

Answer:

2 moles of nitrogen, 8 moles of hydrogen, 1 mole of sulfur

Explanation: i took the test and got it right

The number of moles for each element in one mole of (NH₄)₂S are:

d. 2 moles of nitrogen, 8 moles of hydrogen, 1 mole of sulfur

Identification of number of moles:

The number of moles can be identified by dividing the given mass by molar mass.

In one mole of (NH₄)₂S there are moles of each participating element i.e. nitrogen, oxygen, hydrogen, and sulfur.

In this molecule, there are 2 moles of nitrogen, 8 moles of hydrogen, and one mole of sulfur.

Thus, option d is correct.

Find more information about One mole here:

brainly.com/question/1358482

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Answers

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Answers

Answer:

E)Li

Explanation:

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Answers

Answer: Mass of zinc  that reacts with 4.11 g of hydrochloric acid to form 9.1 g of zinc chloride and 3.97 g of hydrogen gas is 8.96 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

[tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]

Given: mass of hydrochloric acid = 4.11 g

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As mass of reactant = mass of products

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mass of zinc = 8.96 g

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