The box plot represents the number of tickets sold for a school dance.

A horizontal line labeled Number of Tickets sold that starts at 7, with tick marks every one unit up to 32. The graph is titled Tickets Sold for A Dance. The box extends from 15 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 8 and 31.

Which of the following is the appropriate measure of variability for the data, and what is its value?

The IQR is the best measure of variability, and it equals 13.
The IQR is the best measure of variability, and it equals 6.
The range is the best measure of variability, and it equals 13.
The range is the best measure of variability, and it equals 6.

The price of a child ticket is $4 and the price of a senior citizen ticket is $10

Let's call the price of a senior citizen ticket "x" and the price of a child ticket "y".

On the first day, the school sold 3 senior citizen tickets and 4 child tickets for a total of $46, so we can write the equation:

3x + 4y =46

On the second day, the school took in $48 by selling 4 senior citizen tickets and 2 child tickets, so we can write another equation:

4x + 2y = 48

Now that we have two equations, we can use substitution or elimination to find the value of x and y.

For substitution, we can solve one equation for one variable and then substitute that expression into the other equation. For example, let's solve the first equation for x:

x = (46 - 4y)/3

Then, we can substitute this expression for x into the second equation:

4((46 - 4y)/3) + 2y = 48

Expanding the left side of the equation:

(184 - 16y)/3 + 2y = 48

Multiplying both sides by 3:

184 - 16y + 6y = 144

Combining like terms on the left side:

184 - 10y = 144

Subtracting 184 from both sides:

-10y = -40

Dividing both sides by -10:

y = 4

So the price of a child ticket is $4. To find the price of a senior citizen ticket, we can substitute this value back into the equation we solved for x:

x = (46 - 4y)/3 = (46 - 4 * 4)/3 = (46 - 16)/3 = 30/3 = $10

So the price of a senior citizen ticket is $10.

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The given line y = -2x + 3 will cross the y-axis at (0, 3).

A coordinate plane is a two-dimensional plane that consists x-axis and a y-axis. These are perpendicular to each other and will be intersected at the point called the origin.  

The coordinates of the point that lies on the y-axis are (0, y), Similarly, the coordinates of the point that lies on the x-axis are (0, x).    

Here we have

The equation of the line is y = -2x + 3  

To find the required point take x = 0

=> y = -2(0) + 3

=> y = 0 + 3

=> y = 3

Therefore,

The given line y = -2x + 3 will cross the y-axis at (0, 3).

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The markup is of amount $97.5

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

P = $500

i = 0.5%

n= 1

Using the formula

F = P + P x i x n

F= 500 + 500 x 0.005 x 1

F= 500+ 2.5

F= $502.5

So, the team need to raise

= 600- 502.5

= $97.4

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Answer:

6048 should be multiplied by 98.

Step-by-step explanation:

6048 = 2⁵ * 3³ * 7

To make 6048 a perfect cube, 6048 should be multiplied by 2 * 7 * 7.

2* 7 *7 = 98

Check: 6048 * 98 = 592704

592704 = 2⁶ * 3³ * 7³

[tex]\sqrt[3]{592704}= 2 * 2 * 3 * 7[/tex]

              = 84

Answer:

-5

Step-by-step explanation:

−15a = 75

a = 75/-15

a = -5

Let's say event A is the selection of four positive numbers, event B the selection of four negative numbers, and event C the selection of two positive and two negative numbers.

Since four numbers are chosen without replacement,  n(A) = 6 × 5 × 4 × 3 = 360  n(B) = 8 × 7 × 6 × 5 = 1680. In event C, four numbers are to be chosen without replacement such that two numbers are positive and two numbers are negative.

This can be done in following ways:  + + – – OR + – + – OR + – – + OR – + – + OR – – + + OR – + + –  ∴ n(C) = 6 × 5 × 8 × 7 + 6 × 8 × 5 × 7 + 6 × 8 × 7 × 5 + 8 × 6 × 7 × 5 + 6 × 5 × 8 × 7 + 8 × 6 × 5 × 7  = 6 × (8 × 7 × 6 × 5)  =10080  Here, total number of numbers = 14  ∴ n(S) = 14 × 13 × 12 × 11 = 24024

Since A, B, C are mutually exclusive events,

Required probability = P(A) + P(B) + P(C)

= n(A)/n(S) + n(B)/n(S)+ n(C)/n(S)

= 360+1680+10080/24024

= 505/1001

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Answer:

-67

Step-by-step explanation:

- 203 - (-136)

The 2 minuses cancel out each other, turning it into a plus sign.

-203 + 136 = -67

Basic addition

Step-by-step explanation:

Because there is a double negative in between 203 and 136 that would turn into a positive

So

-203+136

Now because 203 is negative you would take 203 and subtract 136 to get 67

Because 136 is less then 203 it would still be negative

So

The answer is -67

The number of months for which the company made no profit is 18 months.

Generally speaking, a product's profit is defined as the sum received from sales, which should exceed the product's cost price. It is the gain from any type of commercial activity. In other words, if a product's selling price (SP) is higher than its cost price (CP), there has been a gain or profit. It explains the monetary gain realised if the revenue from the company activity is greater than the costs, such as taxes and expenses, involved in maintaining the business activity.

The cost function is given as: C(x) = 17- 8x - 2x²

The revenue function is given as: R(x) = 5 - 3x

Profit = Revenue - Cost

For no profit the equation becomes:

5 - 3x - 17 + 8x + 2x² = 0

2x² + 5x - 12 = 0

2x² + 8x - 3x - 12 = 0

2x(x + 4) - 3(x + 4) = 0

2x - 3 = 0 and x + 4 = 0

x = 3/2 and x = -4

Since, month cannot be a negative quantity we have x = 3/2.

That is 3/2 (12) = 18 months.

The number of months for which the company made no profit is 18 months.

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so your problem is 2x+y=18 and y=4x+6

solution

solve for the first variable in one of the equations then substitute the result into the other equation

point form:

(2,14)

equation form

x=2, y=14

Answer:(iii) To find the maximum area of the rectangle, we can use the formula for the area of a rectangle, A = lw, where l is the length and w is the width. Since the wire is 40 cm long, we have l = 40 cm - x cm = 40 - x cm. The maximum area occurs when the length and width are equal, so we set l = w and solve for x:

40 - x = x

2x = 40

x = 20

So, the maximum area of the rectangle is A = lw = (40 - x)x = (40 - 20) * 20 = 20 * 20 = 400 cm².

(iv) To show that the maximum area is only possible if the shape formed is a square, we use the result from part (iii) that the maximum area occurs when the width x = 20 cm. If the width is less than 20 cm, the length will be greater than 40 - x, and the area will be smaller. If the width is greater than 20 cm, the length will be less than 40 - x, and the area will be smaller. So, the maximum area is only possible if x = 20 cm, which means the rectangle is a square.

Step-by-step explanation:

Answer: 6) 33° , 7) x=3°

Step-by-step explanation:

The sum of the three angles of any triangle is equal to 180 degrees.

6) ∡SUT= 180-102 = 78 Linear Pair

   ∴ ∡UTS=180-(69+78)

            =180-147

            = 33°

7) ∡DBC=180-123=57 Linear Pair

57+25x+2+15x+1=180

60+40x=180

40x=180-60

      =120

x=120/40=3°

∴ ∡D=77

  ∡C=46

The rate of change of the area of the rectangle as required in the task content is; 87 in²/sec.

It follows from the task content; The length is increasing by 9 in/sec which represents 75% of the initial length and the width is growing at 2 in/sec which represents 40% of the initial width.

Since the area of a rectangle is; A = l × w

A (initial) = 60in².

Therefore, the new area of the rectangle after every second is;

Area (new) = 1.75l × 1.4w

Area (new) = 2.45 lw

This therefore translates to the fact that the area of the rectangle is increasing by a factor of 1.45 which is equivalent to 145% of initial Area.

Therefore, the area is increasing by 1.45 × 60 = 87in²/sec.

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Answer: Roots are real and distinct

Step-by-step explanation:

a = +ve  b = -ve  c = -ve

determinant = +ve

if determinant is positive then roots are real and distinct

The best prediction of the number of tagged salmon in a sample of 2000 is 100.

The best prediction of the number of tagged salmon in a sample of 2000 returning salmon can be estimated using the proportion of tagged salmon in the sample of 400.

The proportion of tagged salmon in the sample of 400 is [tex](\frac{20}{400} )=(\frac{1}{20} )[/tex].

We can use this proportion:

To estimate the number of tagged salmon in a sample of 2000:

Tagged salmon in a sample of 2000 = [tex](\frac{1}{20}) * 2000[/tex] = 100

Therefore, the best prediction of the number of tagged salmon in a sample of 2000 is 100.

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The range of the inverse of g(x) = √(x³ - 1) is [0, ∞).

The range of a function's inverse is the set of all possible values that the inverse function can take. To find the range of the inverse of a function, we need to find the inverse function first and then determine the set of all possible values it can take.

For the function g(x) = √(x³ - 1), we first need to find its inverse. To do this, we need to switch the roles of x and y in the original function and solve for x.

g(x) = y

y = √(x³ - 1)

x³ - 1 = y²

x³ = y² + 1

x = ∛(y² + 1)

since x = g⁻¹(y)  = ∛(y² + 1)

Thus, g⁻¹(x) =  ∛(x² + 1)    (Replace y with x)

This is the inverse of g(x). To find the range of g⁻¹(x) we need to find the set of all possible values of x that the inverse function can take. Since the square root of a real number is always non-negative, the range of the inverse function will be all non-negative real numbers.

So, the range of the inverse of g(x) = √(x³ - 1) is [0, ∞).

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It's impossible to say Sean should base his decision on the marginal cost and marginal benefit of creating another table. The marginal cost of making a table is not the same as the average cost of making a table. As a result, there is insufficient information to determine what Sean should do.

The opportunity cost of an activity is the value of what must be sacrificed in order to engage in the activity (plus the cost). A cost that cannot be recovered at the time a decision must be made.

The science of decision-making is often used as a crude definition of economics. This stems from the fact that economics is frequently concerned with making the best decision in the most efficient manner. One way to quantify this is to consider total costs and total benefits.

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The required form of a parabola in vertex form is y = a(x - h)² + k.

A parabola is a cross-section cut out of the cone and represented by an equation.

Here,

The standard form of a parabola in vertex form is:

y = a(x - h)² + k

where (h, k) is the vertex of the parabola and a determines the direction of opening (a > 0 for an upward-facing parabola and a < 0 for a downward-facing parabola). The coefficient also determines the shape and steepness of the parabola.

Thus, the required form of a parabola in vertex form is y = a(x - h)² + k.

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By applying permutation formula, it can be concluded that the probability that x₂ lies between x₁ and x₃ is 1/3

Permutation is rearranging a collection of objects in a different order from the original order.

P(n,r) = n! / (n-r)!    where

n = number of objects

r = number of object selected

We have three points x₁, x₂, and x₃ are selected at random on line L.

Number of points = 3.

Now we can calculate the number of ways of arranging 3 points:

P(3,3) = 3! / (3 - 3)!

         = 3!

         = 6

There are two arrangements that x₂ lies between x₁ and x₃.

Thus, the probability that X₂ lies between X₁ and X₃ = 2 / 6 = 1/3

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The triangles ΔABC and ΔDEF are congruent with each other by the SAS postulate. And ∠ABC = ∠DEF, ∠BCA = ∠EFD, ∠CAB = ∠FDE, and AB / DE = BC / EF = CA / FD.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180°.

In triangles ΔABC and ΔDEF, then we have

AB = DE

BC = EF

∠ABC = ∠DEF = 92°

Then the triangles ΔABC and ΔDEF are congruent with each other. Then we have

∠ABC = ∠DEF

∠BCA = ∠EFD

∠CAB = ∠FDE

And the corresponding ratios are given as,

AB / DE = BC / EF = CA / FD

The triangles ΔABC and ΔDEF are congruent with each other by the SAS postulate.

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Answer:

C and D

Step-by-step explanation:

Answer:

Surface Area : find the area of each face and add them together.

Volume : multiplying height, width, and depth.

The math equation for this example would be 12 courses divided by 4 courses = 3 semesters.

The formula for computing the minimum number of semesters it would take a student to take all of the courses is calculated by dividing the total number of courses by the number of courses that can be taken in a semester. For example, if a student needs to take 12 courses, and the maximum number of courses that can be taken in a semester is 4, then the minimum number of semesters it would take the student to take all of the courses is 3 semesters. The math equation for this example would be 12 courses divided by 4 courses = 3 semesters. In order to determine the exact number of semesters it would take a student to take all of the courses, the total number of courses must be divided by the number of courses that can be taken in a semester.

The formula for calculating the minimum number of semesters it would take a student to take all of the courses is Total Number of Courses divided by Number of Courses that can be taken in a semester. For example, if a student needs to take 12 courses, and the maximum number of courses that can be taken in a semester is 4, then the minimum number of semesters it would take the student to take all of the courses is 3 semesters. The math equation for this example would be 12 courses divided by 4 courses = 3 semesters.

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By using the data from the bar graph, each of the statistical value are as follows;

Median = 6.

Lower quartile = 4.

Upper quartile = 7.5.

Interquartile range = 3.5

From the information provided in the bar graph above, we can logically deduce the following data set:

Data set = {3, 5, 6, 7, 8}

Median = 6.

For Q₁ of the lower half of the data set, we have:

Lower quartile, Q₁ = {3, 5}

Lower quartile, Q₁ = (3 + 5)/2

Lower quartile, Q₁ = 8/4 = 4.

For Q₃ of the upper half of the data set, we have:

Upper quartile, Q₃ = {7, 8}

Upper quartile, Q₃ = (7 + 8)/2

Upper quartile, Q₃ = 15/2 = 7.5.

Mathematically, interquartile range (IQR) is the difference between lower quartile (Q₁) and upper quartile (Q₃):

IQR = Q₃ - Q₁

IQR = 7.5 - 4

IQR = 3.5

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Answer:about 3

Step-by-step explanation:

The result of the expression 2848 × 4848 × 495948 + 3858 / 384 is equal to 684,114,389,002.05 approximately to 2 decimal place using PEDMAS

P – Parentheses First: B – Brackets First

E – Exponents

D – Division

M – Multiplication

A – Addition

S – Subtraction

The expression 2848 × 4848 × 495948 + 3858 / 384 can be simplified as follows:

2848 × 4848 × 495948 + 3858 / 384

(2848 × 4848) × 495948 + (3858 / 384)

13807104 × 495948 + 10.0469

6811753718272 + 10.0469

684,114,388,992 + 10.0469

684,114,389,002.05

Therefore, the result from applying the right order of mathematics operations for the expression 2848 × 4848 × 495948 + 3858 / 384 is equal to 684,114,389,002.05 approximately to 2 decimal place using PEDMAS.

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The length of YZ in the triangle is 12.5 units

From the question, we have the following parameters that can be used in our computation:

The triangle

On the triangle, we have the following equivalent ratio

YZ : 5 = 10 : 4

Express as fraction

So, we have

YZ/5 = 10/4

This gives

YZ = 5 * 10/4

Evaluate

YZ = 12.5

Hence, the length is 12.5 units

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The odds of an event are calculated by taking the number of positive outcomes and dividing it by the number of negative outcomes.the odds in favor of her teaching both classes are 15:85 or 1:5.5.

a. The probability that she chooses to teach both classes is 15%.

b. The odds in favor of her choosing to teach both classes are 1:5.5.

a. The probability of an event is calculated by taking the number of positive outcomes and dividing it by the total number of outcomes. In this case, the professor has a 50% chance of teaching the first class and a 30% chance of teaching the second class. Therefore, the probability of her teaching both classes is 0.5 x 0.3 = 0.15 or 15%.

b. The odds of an event are calculated by taking the number of positive outcomes and dividing it by the number of negative outcomes. In this case, there is a 15% chance of her teaching both classes and an 85% chance of her not teaching both classes. Therefore, the odds in favor of her teaching both classes are 15:85 or 1:5.5.

The complete question is :

A professor is deciding whether to teach two classes. There is a 50% chance that she will teach the first class and a 30% chance that she will teach the second class.

a. What's the probability that she chooses to teach both classes?

b. What are the odds in favor of her choosing to teach both classes?

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The value of x for each triangle are:

Please note that I only answer the circled number and please refer to the attached picture for any additional annotations.

Note that each triangles are a right angled triangle. We use phytagoras theorem to find any unknown side of a triangle.

x² = 14² + y²

a² = y² + 4²

x² + a² = 18²

x² + a² = 18²

(14² + y²) + (y² + 4²) = 18²

14² + 2y² + 4² = 18²

196 + 2y² + 16 = 324

2y² = 112

y² = 56

x² = 14² + y²

x² = 196 + 26

x² = 252

x = 6√7

(x + 28)² = a² + b²

a² = 28² + 18²

b² = x² + 18²

(x + 28)² = a² + b²

(x + 28)² = (28² + 18²) + (x² + 18²)

x² + 56x + 784 = 1432 + x²

56x = 648

x = 11.6

a² = b² + (x - 12)²

b² = 16² - 12²

x² = 16² + a²

x² = 16² + a²

x² = 16² + (b² + (x - 12)²)

x² = 16² + [(16² - 12²) + (x - 12)²]

x² = 256 + 112 + (x - 12)²

x² = 368 + x² - 24x + 144

24x = 512

x = 21.3

x² = 15² + 6²

x² = 261

x = 3√29

(15 + z)² = x² + y²

y² = z² + 6²

(15 + z)² = x² + y²

(15 + z)² = 261 + (z² + 6²)

225 + 30z + z² = 261 + z² + 36

225 + 30z + z² = 297 + z²

30z = 72

z = 2.4

y² = z² + 6²

y² = 36 + 5.76

y² = 41.76

y = 6.46

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According to the area of rhombus and length of one diagonal, the length of other diagonal is 10.5 cm.

The formula for the length of the diagonal is as follows -

Area = product of diagonal 1 and diagonal 2/2

Keep the values in formula to find the length of diagonal

360 = 40 × diagonal 2/2

Rewriting the equation with diagonal 2 on Left Hand Side of the equation

Diagonal 2 = (360 × 2)/40

Performing multiplication on Right Hand Side of the equation

Diagonal 2 = 420/40

Performing division on Right Hand Side of the equation

Diagonal 2 = 10.5 cm

Thus, the diagonal 2 is 10.5 cm.

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