Tâm ống dẫn đặt dưới đường phân giới giữa nước và thuỷ ngân h1 = 820mm, chênh lệch chiều cao cột thuỷ ngân h2 = 880mm (Hg = 13,6). Ap suất dư tại điểm A trong ống dẫn (at)?

Answers

Answer 1

Answer:

P = 79993.43245

Explanation:

Được -

Vị trí tâm ống dẫn dưới đường thuỷ ngân h1 = 820 mm

Chênh lệch chiều cao của cột thủy ngân h2 = 880mm

Tỷ trọng của thủy ngân = 13,5951 g / cm3

P = mật độ * gia tốc do trọng lực a * h

Thay thế các giá trị đã cho, chúng ta nhận được -

P = 13,5951 g / cm3 * 980,665 cm / s2 * (88-82) cm

P = 79993.43245


Related Questions

identification of elements compounds and mixtures from a given table​

Answers

Answer:

the elements are made up of only one kind of atom, the compounds consist of two or more elements that are chemically combined, and the mixtures are physical combination of two or more substances

what is fundamental​

Answers

Fundamental

forming a necessary base or core; of central importance.

"the protection of fundamental human rights"

Ayyo help a girl out please-
An object is pulled to the right using spring balance. The spring balance reads 20N. The object is moving with constant speed, so the net force acting on it is equal to zero. If we consider that the force of pull and the friction force are the only forces acting on the object, what will be the value of the friction force? Explain.

Answers

Answer:

The given details in the question are;

The device with which the object is pulled = A spring balance

The reading on the spring balance as the object is pulled = 20 N = The force with which the object is pulled

The speed with which the object is moving = Constant speed (zero acceleration)

The net force acting on the object = Zero

The forces acting on the object are;

The force of pull and the friction force

Therefore;

The force of pull + The friction force = 0

The force of pull = 20 N

∴ 20 N + The friction force = 0

The friction force = 0 - 20 N = -20N

The magnitude of the friction force = 20 N = The force of pull

(The negative sign in the value of the friction force (-20 N), indicates that the direction of the friction force is opposite to the direction of the force of pull)

Explanation:

when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2.0×10^-5k^-1, calculate its original volume​

Answers

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

What is measurement ?​

Answers

Answer:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

Answer:

The comparison of an unknown quantity with a known quantity is called measurement

Change the following as indicated in the brackets.
8m (km,cm)​

Answers

metres to kilometres = 1/1000

8 m ⇒ 0.008 km

metres to centimetres = × 100

8 m ⇒ 800 cm

Answer:

1000m=1km

so, 8m=8/1000 = 0.008km

1m=100cm

so, 8m=8×100=800

HELPP ILL GIVE BRIANLISG

Answers

Answer:

31. Respiratory System

32. Excretory System

33. Nervous System

34. Reproductive system

35. Skeleton System

Explanation:

Hope it helps you.^_^

Answer:

31. Respiratory System

32. Excretory System

33. Circulatory System

34. Reproductive System

35. Muscular and Skeletal System

Explanation:

In 35. you should write both systems since only one of them may give you half the marks.

Also do put your questions on the health section

Since energy cannot be created or destroyed, how does it exist?

Answers

Answer:

Matter and atoms

In which of these media will mechanical waves travel the slowest in?
a Plastic
b Butter
C Ice
d Air
e Steel

Answers

Answer:

E

Explanation:

it has more mass

The medium in which mechanical waves will travel the slowest in is air which is gaseous medium.

What is mechanical wave?

A mechanical wave is a type of wave that requires material medium for its propagation.

An example of mechanical wave is sound wave because sound wave requires material medium for its propagation.

Sound waves travel fastest in solid, followed by liquid, then least in gasous medium.

Thus, the medium in which mechanical waves will travel the slowest in is air which is gaseous medium.

Learn more about mechanical waves here: https://brainly.com/question/9242091

Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is
A.1
B.2
C.3
D.4
(Ans with explanation pls)

Answers

Answer:

4 capacitors

Explanation:

Given

[tex]n = 5[/tex] --- conducting plates

Required

The number of capacitor (c)

This is calculated as:

[tex]c = n - 1[/tex]

So, we have:

[tex]c = 5 - 1[/tex]

[tex]c = 4[/tex]

please help me..im begging you​

Answers

Answer: The equations in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law

23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law

24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law

25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law

26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law

27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion

Explanation:

(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.

So, PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant

T = temperature

Boyle's law: At constant temperature, the pressure of a gas is inversely proportional to volume.

So, [tex]P_{1}V_{1} = P_{2}V_{2}[/tex]

Charles' law: At constant pressure, the volume of a gas is directly proportional to temperature. So,

[tex]V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}[/tex]

Gay-Lussac's law: At constant volume, the pressure of a gas is directly proportional to temperature.

So,  [tex]P_{1}T_{2} = P_{2}T_{1}[/tex]

Avogadro's law: At same temperature and pressure, the volume of gas is directly proportional to moles of gas.

So, [tex]V_{1}n_{2} = V_{2}n_{1}[/tex]

Combined gas law: When Boyle's law, Charles' law, and Gay-lussac's law are combined together then it is called combined gas law. So,

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex]

Graham's law of effusion: It states that the rate of effusion of a gas is inversely proportional to the square root of mass of its particles.

[tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex]

Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law

23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law

24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law

25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law

26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law

27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion

Please help with this Physics problem!

Answers

Answer:

Explanation:

The equation for Coulomb's Law is

[tex]F=\frac{kq_1q_2}{r^2}[/tex] where k is Coulomb's constant, q1 is one of the charges, q2 is another one of the charges (1 of these has to be the one in question, so we will let that be q2) and r is the distance between them squared.

First thing we are going to do is convert those microCoulombs to Coulombs (C).

q1: [tex]-53.0\mu C*\frac{.000001C}{1\mu C}=-5.3*10^{-5}C[/tex] and

q2: [tex]105\mu C*\frac{.000001C}{1\mu C}=1.05*10^{-4}C[/tex] and

q3: our main particle that we will put in for q2 in the formula converts as follows:

q3: [tex]-88.0\mu C*\frac{.000001C}{1\mu C} =-8.8*10^{-5}C[/tex]  

First we will find the charge between q1 and the main particle:

[tex]F_1=\frac{(9.0*10^9)(5.3*10^{-5})(8.8*10^{-5})}{(1.45)^2}[/tex] Notice that we did not use the negative charges here. We take the negative charge into account depending upon whether or not the charges are repelled or attracted. Both of these charges are negative, so they will repel and the answer will be made negative. Finding the first force:

[tex]F_1=-2.0*10^1N[/tex] (negative because they repel so q1 will move away from the charge in question, which is also negative)

[tex]F_2=\frac{(9.0*10^9)(1.05*10^{-4})(8.8*10^{-5})}{(.95)^2}[/tex] and the charge between these is

[tex]F_2=92N[/tex] and that is to the right, so positive. These charges are opposite, so they attract. The net force is the sum of the forces, so:

[tex]F_1+F_2:[/tex] -2.0 × 10¹ + 92 = 72N (to the right)

A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0

Answers

Answer:

a)   [tex]A=5m/s^2[/tex]

b)   [tex]V=25m/s[/tex]

Explanation:

From the question we are told that:

Velocity [tex]v=90km/h=25m/s[/tex]

Time [tex]t=5.0s[/tex]

a)

Generally From Newton's motion equation for Average acceleration is   mathematically given by

  [tex]A=\frac{V-U}{t}[/tex]

Since its from Rest Therefore

  [tex]U=0[/tex]

 [tex]A=\frac{25m/s-0}{5s}[/tex]

 [tex]A=5m/s^2[/tex]

b)

Generally the equation for Average Velocity is mathematically given by

  [tex]V=u+at[/tex]

 [tex]AT t=1.0s\\\\V=0+5(1)[/tex]

 [tex]V=5m/s[/tex]

 [tex]AT t=2.0s\\\\V=0+5(2)[/tex]

 [tex]V=10m/s[/tex]

 [tex]AT t=5.0s\\\\V=0+5(5)[/tex]

 [tex]V=25m/s[/tex]

 

To change the temperature from kelvin to degree Celsius

TK= ( )⁰C​

Answers

Answer:

-272.1

Explanation:

1K − 273.15 = -272.1°C

Which type of wave causes particles of matter to vibrate in a direction
perpendicular to the direction of its motion?
O A. Sound
B. Transverse
C. Longitudinal
D. Compression

Answers

It’s transverse so the answer is B

Answer:

C.) Longitudinal

How do you find the normal line for an incident light ray on a concave mirror?

Draw a line from the outer edge of the curve to the point of contact for the ray.

Draw two lines diagonally from the outer edges of the curve until they intersect each other.

Draw a line from the center of the curve to the point of contact for the ray.

Draw a line perpendicular from the center of the curve to the point of contact for the ray.

Answers

Answer:

Try different angles

Page
A car is moving at a rate of 72 km/ hr. How far
does the moves stop after 4 seconds

Answers

Answer:

Distance = 80 meters

Explanation:

Given the following data;

Speed = 72 km/hr

Time = 4 seconds

Conversion:

72 km/hr to meters per seconds = 72*1000/3600 = 72000/3600 = 20 m/s

To find the distance covered by the car;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex] Distance = speed * time [/tex]

Substituting into the above formula, we have;

[tex] Distance = 20 * 4 [/tex]

Distance = 80 meters

In Part l, the independent variable was

Answers

Answer:

The independent variable is the variable the experimenter manipulates or changes, and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg

Answers

Answer:

a)  [tex]q=4.92*10^{-8} C[/tex]

b)  [tex]m=4.026*10^{-6} kg[/tex]

Explanation:

From the question we are told that:

Separation distance [tex]d=2.65*10^{-2} m[/tex]

Acceleration 1 [tex]a_1=5.00*10^3 m/s^2,[/tex]

Acceleration 2 [tex]a_2=7.70*10^3 m/s^2,[/tex]

Mass 1 [tex]m_1=6.20*10^{-6}[/tex]

Generally the equation for Force is mathematically given by

 [tex]F=ma[/tex]

For Particle 1

 [tex]F=6.2*10^{-6} *5*10^3[/tex]

 [tex]F=0.031 N[/tex]

Also

 [tex]F=\frac{kq_1*q2}{r^2}[/tex]

Where

 [tex]q_1=q_2[/tex]

Therefore

 [tex]0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}[/tex]

 [tex]q=4.92*10^{-8} C[/tex]

b)

Generally the equation for Force is mathematically given by

 [tex]F=ma[/tex]

 [tex]0.031=7.7*10^3[/tex]

 [tex]m=4.026*10^{-6} kg[/tex]

Directions. Read and understand each item carefully. Write your answers on the space provided.
1. Create a graphic representation based on the following data tabulated on Table 2 and make an interpretation of
the graph. Make sure to coordinate points correctly and trace line to show motion of the object.
Table 2. The distance travelled by a car in a given time.

(Dudes I need this today, pls answer this correctly)​

Answers

Answer:

Please find attached the required graph of the data points

The graph can be interpreted as showing that which was at rest starts  moving at a constant speed of 2 km/min

Explanation:

The table is presented as follows;

[tex]\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}[/tex]

The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper

The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing

The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;

[tex]m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line

When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;

[tex]m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min[/tex]

The graph can be interpreted as showing that the rate of change of the distance travelled by the car per  unit time which is the speed of the car starting from rest is 2 km/min

Subject: science 41. A device used to stop flow of electric current A) open plug key B)Closed plug key C)Both A and B D) Rio start ​

Answers

Answer:

Circuit Breaker - a protective device used to automatically blows and cuts the current when trouble in the circuit such as short circuit or overload occurs

The resistance of a coil is 4.2 ohm at 100 degree centigrade and the temperature coefficient of resistance of its material is 0.004 per degree centigrade. Its resistance at 0 degree centigrade

Answers

Answer:

3 ohms

Explanation:

Applying,

R₁₀₀ = R₀(1+αΔT).............. Equation 1

Where α = coefficient of resistance, ΔT = change in temperature, R₁₀₀ and R₀ = Resistance at 100°C and 0°C respectively

make R' the subject of the equation

R₀ = R₁₀₀/(1+αΔT).............. Equation 2

From the question,

Given:  R₁₀₀ = 4.2 ohm, α = 0.004 per degree, ΔT = 100-0 = 100°C

Substitute these values into equation 2

R₀ = 4.2(1+0.004×100)

R₀ = 4.2/1.4

R₀ = 3 ohms

Calculate the relative density of the liquid if mass of empty relative density bottle is 24.5g and mass of relative density bottle filled with water is 56.2g and mass of relative density bottle filled with liquid is 51.2g

Answers

Answer:

k=0.84

Explanation:

Relative density of liquid is given by:

k=(56.2−24.5)(51.2−24.5)

k=31.726.7

k=0.84

what is the meaning of physics​

Answers

Answer:

physics is the study of functions, systems and and the explainable reasons why they do what they do.

Answer:

physics is the branch of science concerned with the nature and properties of matter and energy. it includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

who is the father of computer but not Charles Babbage can anyone guess​

Answers

Answer:

It's Obusively charles Babbage I guess

b) A stone floor feels very cold to bare feet in winter, but a carpet in
the same room feels comfortably warm. Why is this?

Answers

Answer:

A stone floor feels very cold to bare feet in winter, but a carpet in the same room feels comfortably warm.This is because both the floor and the carpet have the same temperature as both are exposed to the same atmosphere. But the former conducts away the heat from the feet better than the carpet as the latter is a non-conductor. So the feet losing more heat, the floor appears cooler to the feet

Explanation:

Hope it may help you!!

Both actually have same temperature. Our feet are warm. Floor is conductor of heat while carpet is not. When we walk on floor, then floor takes away or conducts the heat from our feet, so we feel cold. While carpet doesn't do that, so we feel warm.

Which power station is the most efficient overall, the normal power station or the combined heat and power station? Give reasons for your answer.

Answers

Answer:

Cogeneration is a more efficient use of fuel or heat, because otherwise-wasted heat from electricity generation is put to some productive use. Combined heat and power (CHP) plants recover otherwise wasted thermal energy for heating.

Explanation:

Which type of radiation can reach the furthest?
A. Beta

B. Gamma

C. Alpha

Answers

Answer:

B. Gamma

Explanation:

The gamma radiation can travel much farther through air than alpha or beta.

(x – 2)² = 5(y + 1), where x and y are measured in centimeters. You need to place a new light bulb in your flashlight. How far away from the vertex of the parabolic mirror should you place the bulb to ensure a perfect beam of light? The bulb should be placed .

Answers

Answer:

The coordinates of the point the bulb should be placed is (2, 0.25)

Explanation:

The given equation of a parabola is presented as follows;

(x - 2)² = 5·(y + 1)

The point the bulb should be placed is the focus of the parabolic mirror to ensure a perfect (straight) beam

The general form of the equation of a parabola is (x - h)² = 4·p·(y - k)

The coordinates of the focus of the parabola for p > 0 f = (h, k + p)

By comparison, h = 2, k = -1, and p = 5/4

∴ The coordinates of the focus of the parabola, f = (2, -1 + 5/4)  = (2, 0.25)

The coordinates of the point the bulb should be placed is at the focus, f =  (2, 0.25).

IM SOO CONFUSED PLS HELP!! The mass of the nucleus is approximately EQUAL to the mass number multiplied by ____ Atomic Mass unit.

a. 1
b. 10
c. 100
d. 1000​

Answers

Answer:

option a.

Explanation:

We can think of an atom as a nucleus (where the protons and neutrons are) and some electrons orbiting it.

We also know that the mass of an electron is a lot smaller than the mass of a proton or the mass of an electron.

So, if all the protons and electrons of an atom are in the nucleus, we know that most of the mass of an atom is in the nucleus of that atom.

Then we define the mass number, which is the total number of protons and neutrons in an atom. Such that the mass of a proton (or a neutron) is almost equal to 1u

Then if we define A as the total number of protons and neutrons, and each one of these weights about 1u

(where u = atomic mass unit)

Then the weight of the nucleus is about A times 1u, or:

A*1u = A atomic mass units.

Then the correct option is:

The mass of the nucleus is approximately EQUAL to the mass number multiplied by __1__ Atomic Mass unit.

option a.

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