The angle between u and (5, -5, -2) is Acute.
To determine the angle between two vectors, we can use the dot product formula. Given vectors u and v, the dot product u · v is calculated as:
u · v = (u1 * v1) + (u2 * v2) + (u3 * v3)
If u · v > 0, the angle between u and v is acute.
If u · v = 0, the angle between u and v is right.
If u · v < 0, the angle between u and v is obtuse.
Let's calculate the dot products to determine the angles:
u · (-1, 4, 5) = (4 * -1) + (-1 * 4) + (4 * 5) = -4 - 4 + 20 = 12
Since u · (-1, 4, 5) > 0, the angle between u and (-1, 4, 5) is acute.
u · (-8, 0, 8) = (4 * -8) + (-1 * 0) + (4 * 8) = -32 + 0 + 32 = 0
Since u · (-8, 0, 8) = 0, the angle between u and (-8, 0, 8) is right.
u · (-3, 1, -3) = (4 * -3) + (-1 * 1) + (4 * -3) = -12 - 1 - 12 = -25
Since u · (-3, 1, -3) < 0, the angle between u and (-3, 1, -3) is obtuse.
u · (5, -5, -2) = (4 * 5) + (-1 * -5) + (4 * -2) = 20 + 5 - 8 = 17
Since u · (5, -5, -2) > 0, the angle between u and (5, -5, -2) is acute.
(-1, 4, 5) makes an acute angle with u.
(-8, 0, 8) makes a right angle with u.
(-3, 1, -3) makes an obtuse angle with u.
(5, -5, -2) makes an acute angle with u
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The magnitude of proju(v) is:
|proju(v)| = √((40/33)^2 + (-10/33)^2 + (40/33)^2) ≈ 1\
Suppose u = 〈4,-1,4).
(-1,4,5) makes an acute angle with u.
To find the angle between two vectors, we can use the dot product formula:
u · v = |u| |v| cosθ
where θ is the angle between u and v.
Let v = (-1, 4, 5). Then,
u · v = (4)(-1) + (-1)(4) + (4)(5) = 16
|u| = √(4^2 + (-1)^2 + 4^2) = √33
|v| = √((-1)^2 + 4^2 + 5^2) = √42
So,
cosθ = (u · v) / (|u| |v|) = 16 / (√33 √42) ≈ 0.787
θ ≈ 38.5°
Since 0 < θ < 90°, the angle between u and v is acute.
(-8,0,8) makes a right angle with u.
To verify this, we can again use the dot product formula:
u · v = |u| |v| cosθ
Let v = (-8, 0, 8). Then,
u · v = (4)(-8) + (-1)(0) + (4)(8) = 0
|u| = √(4^2 + (-1)^2 + 4^2) = √33
|v| = √((-8)^2 + 0^2 + 8^2) = √128
So,
cosθ = (u · v) / (|u| |v|) = 0 / (√33 √128) = 0
Since cosθ = 0, θ = 90° and the angle between u and v is a right angle.
(-3,1,-3) makes an obtuse angle with u.
Using the same process as before, we have:
u · v = (4)(-3) + (-1)(1) + (4)(-3) = -28
|u| = √33
|v| = √((-3)^2 + 1^2 + (-3)^2) = √19
So,
cosθ = (u · v) / (|u| |v|) = -28 / (√33 √19) ≈ -0.723
θ ≈ 139.3°
Since θ > 90°, the angle between u and v is obtuse.
(5,-5,-2) makes 4 with u.
To find the projection of v = (5, -5, -2) onto u, we can use the projection formula:
proju(v) = ((u · v) / |u|^2) u
u · v = (4)(5) + (-1)(-5) + (4)(-2) = 10
|u|^2 = 4^2 + (-1)^2 + 4^2 = 33
So,
proju(v) = ((u · v) / |u|^2) u = (10 / 33) 〈4,-1,4) = 〈40/33,-10/33,40/33)
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in a school, the ratio of the number of boys to the number of girls is 2:3 and the ratio of the number of girls to the number of teachers is 7:3. what is the ratio of the number of students to the number of teachers
Answer:
35:9
Step-by-step explanation:
The ratios can be combined by making the common element be represented by the same number.
Adjusted ratiosThe common element in the two ratios is the number of girls. In the first ratio, girls are represented by 3 ratio units. In the second ratio, they are represented by 7 ratio units. Multiplying the first ratio by 7 and the second ratio by 3 will make the number of girls the same in both.
boys : girls = 2 : 3 = 14 : 21
girls : teachers = 7 : 3 = 21 : 9
Then the extended ratio can be written ...
boys : girls : teachers = 14 : 21 : 9
The number of students is the total of the numbers of boys and girls, so we have ...
students : teachers = (14 +21) : 9
students : teachers = 35 : 9
20 POINTS ILL MARK U BRAINLIEST PLS
Answer:
13 + [tex]\sqrt{89}[/tex]
or
22.43398... (depends on how you round it)
Step-by-step explanation:
1. The question stated that the radius of the circle O is 5, so the length of AO and CO is 5.
2. Since line AB and line CB are both tangent to the circle, they have the same length. CB is 8, so AB will also be 8.
--> Both triangle AOB and COB share one side, and the other side (radius) has the same length, so the third side must be the same length
3. Tangent means having a 90-degree angle with the radius. We know that the triangle AOB is a right triangle since the angle OAB is 90 degrees.
We can use the Pythagorean theorem to find side OB. OB^2 = AO^2 + AB^2.
--> OB^2 = 25 + 64
--> OB^2 = 89
--> OB = [tex]\sqrt{89}[/tex]
Now that we know the lengths of all three sides, we can add them up.
--> 5 + 8 + [tex]\sqrt{89}[/tex]
--> 13 + [tex]\sqrt{89}[/tex]
or
--> 22.43398113....
X:Y=3:2 and Y:Z=7:4 what is X:Y:Z
Answer:
21:14:8
Step-by-step explanation:
X:Y=3:2
Y:Z=7:4
X:Y=21:14
Y:Z=14:8
X:Y:Z=21:14:8
HURRY PLEASE
What is measure of
First, find the supplement of the angle that is 105 degrees.
105 + 75 = 180
Now, we can find complete the lower left triangle's angles.
39 + 75 + ? = 180
? = 66 degrees
The 66 degree angle of the lower left triangle and angle x are vertical angles. Vertical angles are congruent.
Therefore, the measure of angle x is 66 degrees.
Hope this helps!
One factor of the polynomial 3x3 + 20x2 - 21x + 88 is (x + 8). what is the other factor of the polynomial? (note: use long division.)
oa (3x2 - 4x+11)
b. (3x - 4x)
c. (3x2 +11)
d. (3x2 + 4x - 11)
The other factor of the polynomial is a. 3x2-4x+11
Given polynomial is 3x3 + 20x2 - 21x + 88 and the factor is (x+8)
We need to find another factor using long division method
So,
We will divide the polynomial by the factor to find the another factor
Therefore,
[tex]\sqrt[x+8]{3x^3+20x^2-21x+88}[/tex]
Now calculating
First multiplying [tex]3x^2[/tex] with (x+8) so , [tex]3x^2[/tex] will be in the quotient
We get [tex]3x^3+24x^2[/tex]
simplifying the calculation for [tex]3x^3+20x^2[/tex] and [tex]3x^3+24x^2[/tex]
We get the remainder is [tex]-4x^2-21x+88[/tex]
Second we will multiply -4x with (x+8) Where -4x will be in the quotient
We get [tex]-4x^2-32x[/tex] and then we will simplify the equation
We get 11x +88 as a remainder
The quotient we get is [tex]3x^2-4x[/tex]
Third we will multiply +11 with (x+8) Where +11 will be in the quotient
we get 11x+88
Simplifying the equation we get the remainder 0
So the quotient we get is (3x2 - 4x+11)
Hence the another factor of the polynomial is (3x2 - 4x+11)
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WILL MAKE BRAINLIEST!! Solve for b
Answer: 32
Step-by-step explanation:
The line is straight meaning 180 angle. When finding B you subtract 148 by 180 which would be 32.
You estimate that there are 40 marbles in a jar. the actual amount is 34 marbles. find the percent error. round to the nearest tenth of a percent if necessary.
The percentage error of the given estimation is 17.7%.
The percentage error of any estimation is calculated as:
Percentage error = {(|Actual Value - Estimated Value|)/Actual Value}*100%.
In the question,
The estimated value is given to be 40 marbles.
The actual value is given to be 34 marbles.
We are asked to find the percentage error of this estimation.
We know that:
Percentage error = {(|Actual Value - Estimated Value|)/Actual Value}*100%.
Substituting the values, we get:
Percentage error = {(|34 - 40|)/34}*100%,
or, Percentage error = 6/34*100%,
or, Percentage error = 17.6470 % = 17.7% (Rounding to the nearest tenth, that is, up to one decimal place).
Thus, the percentage error of the given estimation is 17.7%.
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what is the monthly interest payment for an account with a balance of $100 and an APR of 12%
Monthly interest payment is $100.
According to the statement
balance in account = $100
APR = 12%
we use the formula Balance formula to solve this problem.
So, BALANCE * [APR / 12 month] to find monthly interest payment
Here balance is the starting amount in the bank account
And APR is the type of interest rate applied on the amount
And 12 month is the time period for which APR is applicable.
So, substitute the values in it then
Monthly interest payment = 100 * [12/12]
After solving the equation become
Monthly interest payment = 100*1
Monthly interest payment = 100$
So, Monthly interest payment is $100.
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Find the maximum and minimum values of the curve y=2x³-3x²-12x+10
[tex] \underline{ \orange{\huge \boxed{ \frak{Answer : }}}}[/tex]
Let ,
[tex] \sf \large \color{purple} y = 2 {x}^{3} - 3 {x}^{2} - 12x + 10 \: --( \: 1 \: )[/tex]
[tex] \: \: \: [/tex]
Now , Diff wrt ' x ' , we get :
[tex] \sf \: \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} - 3 {x}^{2} - 12x + 10) \\ \sf \: \sf \: \frac{dy}{dx} = \frac{d}{dx} \: 2(3 {x}^{2} ) - \frac{d}{dx} 3 {x}^{2} - \frac{d}{dx} 12x + \frac{d}{dx} 10 \\ \sf \: \frac{dy}{dx} =2(3 {x}^{2} ) - 3(2x) - 12(1) + 0 \\ \sf \: \frac{dy}{dx} =6 {x}^{2} - 6x - 12 + 0 \\ \: \sf \red{\frac{dy}{dx} = 6 {x}^{2} 6x - 12 -- (2)}[/tex]
[tex] \: \: \: [/tex]
For maxima or minima \frac{dy}{dx} = 0
[tex] \: \: \: [/tex]
[tex] \sf \: 6 {x}^{2} - 6x - 12 = 0[/tex]
[tex] \: \: \: [/tex]
Divided by 6 on both side , we get.
[tex] \: \: \: [/tex]
[tex] \sf \: {x}^{2} - x - 2 = 0 \\ \sf \: {x}^{2} - 2x + x - 2 = 0 \\ \sf \: x(x - 2) + 1(x - 2) = 0 \\ \sf \: (x - 2)(x + 1) = 0 \\ \sf \: x - 2 = 0 \: \: \bold or \: \: x + 1 = 0 \\ \sf \fbox{x = 2 \: } \: \bold or \: \fbox{ x = - 1}[/tex]
[tex] \: \: \: [/tex]
Again Diff wrt ‘ x ’ , we get.
[tex] \sf \: \frac{d}{dx} =(\frac{dy}{dx} ) = 6\frac{d}{dx} - 6\frac{d}{dx}x - \frac{d}{dx}12 \\ \sf \: \frac{ {d}^{2}y }{ {dx}^{2} } = 6(2x) - 6(1) - 0 \\ \sf \: \sf \bold{ \frac{ {d}^{2}y }{ {dx}^{2} } =12x - 6}[/tex]
[tex] \: \: \: [/tex]
At x = 2
[tex] \: \: \: [/tex]
[tex]\sf \: \frac{ {d}^{2}y }{ {dx}^{2} } =12(2) - 6 \\ \: \: \: \sf \: = 24 - 6 \\ \: \: \: \: \sf \red{ = 18 > 0}[/tex]
At x = -1
[tex] \: \: \: [/tex]
[tex]\sf \: \frac{ {d}^{2}y }{ {dx}^{2} } =12( - 1) - 6 \\ \: \: \: \sf \: = - 12 - 6 \\ \: \: \: \: \sf \red{ = - 18 < 0 }[/tex]
[tex] \: \: \: [/tex]
x = 2 gives minima value of function.
[tex] \: \: \: [/tex]
x = -1 gives maxima value of function.
[tex] \: \: \: [/tex]
Now, put x = 2 in eqⁿ ( 1 )
[tex] \: \: \: [/tex]
[tex] \sf \: y \: minima \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2( {2})^{3} - 3 ({2})^{2} - 12(2) + 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: \: \: \: = 2(8) - 3(4) - 24 + 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: \: \: \: \: = 16 - 12 - 24 + 10 \\\sf \: \: \: \: \: \: \: \: \: \: = - 20 + 10 \\\sf \color{red}{\boxed{ = - 10}}[/tex]
[tex] \: \: \: [/tex]
The Point of minima is ( 2 , -10 ).
[tex] \: \: \: [/tex]
Now , put x = -1 in eqⁿ ( 1 )
[tex]\sf \: y \: maxima \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2( { - 1})^{3} - 3 ({ - 1})^{2} - 12( - 1) + 10 \\\sf \color{red}{\boxed{ = 17}}[/tex]
[tex] \: \: \: [/tex]
The point of maxima value is ( -1 , 17 ).
[tex] \: \: \: [/tex]
[tex] \: \: [/tex]
Hope Helps! :)
A circle is formed when a plane slices through a cone. Which of the following describes the relationship between the plane and the cone
The plane is parallel to the base of the cone describes the relationship between the plane and the cone
A circle is a spherical form without boundaries or edges or we can say that A circle is a closed, curved object with two dimensions in geometry.
The produced cross-section is a circle when a plane slices a cone such that the plane is parallel to the base of the cone.
Ellipse is the shape that is produced when a plane cuts a cone at an angle such that it misses the base or the vertex. (As shown in figure)
Hence A circle is formed when a plane slices through a cone and the plane is parallel to the base of the cone
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Write the equation of the line of best fit using the slope-intercept formula y = mx + b. Show all your work, including the points used to determine the slope and how the equation was determined.
The equation of the line of best fit is y = 1.7x - 58
How to determine the equation?We start by drawing the line of best fit (see attachment)
From the attached graph, we have the following points
(x, y) = (70, 75) and (61, 60)
The slope (m) is:
m = (y2 - y1)/(x2 - x1)
This gives
m = (60 - 75)/(61 - 70)
Evaluate
m = 1.7
The line of best fit is then calculated as:
y = m(x - x1) + y1
This gives
y = 1.7(x - 70) + 61
This gives
y = 1.7x - 119 + 61
Evaluate
y = 1.7x - 58
Hence, the equation of the line of best fit is y = 1.7x - 58
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A college's basketball team will play 33 games next winter. Each game can result in one of 2 outcomes: a win or a loss. Find the total possible number of outcomes for the season record.
The total possible number of outcomes for the season record is [tex]2^{33}[/tex].
What is an outcome?An event that may be given a mathematical probability is known as an outcome in mathematics (an outcome of an experiment). The amount of potential outcomes for a particular experiment determines the probability assigned to each result.The result of an experiment is a number of outcomes.
According to the question,
The basketball team at a college will play 33 games next winter. There are only two possible outcomes for each game: a win or a loss.
So, the total number of possible outcomes for the season record=[tex]2^{33}[/tex].
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Evaluate: 2^-4=
A. 1/8
B. -8
C. -16
D. 1/16
Answer:
D.
[tex] \frac{1}{16?} [/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation: }[/tex]
[tex]\mathbf{2^{-4}}[/tex]
[tex]\huge\textbf{Simplify it: }[/tex]
[tex]\mathbf{2^{-4}}[/tex]
[tex]\mathbf{\approx \dfrac{1}{2^4}}[/tex]
[tex]\mathbf{= \dfrac{1}{2\times2\times2\times2}}[/tex]
[tex]\mathbf{= \dfrac{1}{4\times4}}[/tex]
[tex]\mathbf{= \dfrac{1}{16}}[/tex]
[tex]\huge\textbf{Therefore, your answer should be: }[/tex]
[tex]\huge\boxed{\frak{Option\ D. \ \dfrac{1}{16}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]F(x)=4x^3+7x^2x-1. G(x)=4x-2 find (f-g)(x)
Answer:
4x^3 + 7x^2 - 3x + 1
Step-by-step explanation:
BTW your question, there is a sign misssing
Find the center and radius of the circle with the equation: (x-5)^2 + (y+1)^2 = 4 a. center: (-5, 1) radius: 4 c. center: (-5, 1) radius: 2 b. center: (5, -1) radius: 4 d. center: (5, -1) radius: 2
Answer:
d
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
(x - 5 )² + (y + 1)² = 4 ← is in standard form
with centre (5, - 1 ) and r = [tex]\sqrt{4}[/tex] = 2
Help please having trouble solving these two problems
Answer:
First function:
Zeros = 6 and -6. Y-intercept = (0,72). X-intercepts = (6,0) and (-6,0).
Second function:
Zeros = 3 and -3. Y-intercept = (0, -27). X-intercepts: (3, 0) and (-3, 0).
Step-by-step explanation:
The zeros are x-intercept numbers.
The y-intercept can be found when the function is in standard form. Plug in 0 for x, then solve.
Hope this helps!
Answer:
1. x₁ = 6, x₂ = -6
2. x₁ = 3, x₂ = -3
Step-by-step explanation:
Given functions:
[tex]1)\ f(x) = -2(x-6)(x+6)[/tex]
[tex]2)\ f(x)=(x-3)(3x+9)[/tex]
..................................................................................................................................................
Zero Product Property: If m • n = 0, then m = 0 or n = 0.
Standard Form of a Quadratic: ax² + bx + c = 0.
..................................................................................................................................................
1. f(x) = -2(x - 6)(x + 6)
Step 1: Set the function to zero.
[tex]\implies 0 = -2(x-6)(x+6)[/tex]
Step 2: Divide both sides of equation by [tex]-2[/tex].
[tex]\implies \dfrac{0}{-2} = \dfrac{-2(x-6)(x+6)}{-2}[/tex]
[tex]\implies 0=(x-6)(x+6)[/tex]
Step 3: Apply the Zero Product Property.
[tex]x_1 \implies x-6=0[/tex]
[tex]x_2 \implies x+6=0[/tex]
Step 4: Solve for x in both equations.
[tex]x-6+6=0+6 \implies \boxed{x_1 = 6}[/tex]
[tex]x+6-6=0-6 \implies \boxed{x_1 = -6}[/tex]
The zeros (x-intercepts) of this function are: [tex]x_1=6,\ x_2=-6[/tex].
.................................................................................................................................................
2. f(x) = (x - 3)(3x + 9)
Step 1: Set the function to zero.
[tex]\implies 0 = (x - 3)(3x + 9)[/tex]
Step 2: Apply the Zero Product Property.
[tex]x_1 \implies x-3=0[/tex]
[tex]x_2 \implies 3x + 9=0[/tex]
Step 3: Solve for x in both equations.
[tex]x-3+3=0+3 \implies \boxed{x_1 = 3}[/tex]
[tex]3x=-9 \implies \dfrac{3x}{3}=\dfrac{-9}{3} \implies \boxed{x_1 = -3}[/tex]
The zeros (x-intercepts) of this function are: [tex]x_1=3,\ x_2=-3[/tex].
..................................................................................................................................................
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Ralph Warren purchased 27 shares of stock at 16 3/8 per share. He paid a $27.50 brokerage fee. He later sold all 27 shares at 17 5/8 and paid a $28.75 brokerage fee. (36) What was his total cost for the stock including his brokerage fee? (37) What did he receive from the sale of the stock after he paid the brokerage fee? (38) Did he have a capital gain or loss? (39) How much was the gain or loss? (40) What was the net change from 16 3/8 to 17 5/8?
Based on the number of shares that Ralph Warren purchased, the total cost of the stock was $469.63. The amount he received from sales was $447.13. The capital loss was $22.50.
What was the gain on the sale of the shares?The cost of the stock was:
= (27 x 16³/₈) + 27.50
= $469.63
The amount received from sales:
= (27 x 17⁵/₈) - 28.75
= $447.13
This capital gain (loss):
= 447.13 - 469.63
= -$22.50
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What is the slope of the equation y =5/4x-7/4?
Answer is 5/4The slope is the number next to the “x” in the y intercept formula
y= m (slope) x + b
Answer: m= 5/4
Step-by-step explanation:
La ecuación general de la recta es y=mx+by=mx+b, donde m es la pendiente y b es la intersección en y
y=mx+by=mx+b
the market price of article is rs 3000. a discount of 30% was agreed. find the sale price of the article and the amount of discount.
Answer: 2400
Step-by-step explanation:
3000 x 20/100 = 600
Discount = 600
Sale price of the article: 3000-600 = 2400
Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin
Yes, because both figures are rectangles and all rectangles are similar. Option B is correct option.
According to the statement
We have given that the two rectangles EFGH and ABCD and we have show that the these rectangles Are dilation at origin or not.
So, According to the given diagram
Yes, the rectangle EFGH is a result of dilation of rectangle ABCD with a center of dilation of rectangle at the origin.
Also The scale factor of the dilation is greater than one as the image is bigger than the pre-image i.e. there is a stretch.
The scale factor could be calculated by the ratio of the sides of the image to the pre-image rectangle.
According to the diagram In Rectangle ABCD:
Its vertices have coordinates A(-3,3), B(3,3), C(3,0) and D(-3,0).
Now consider rectangle EFGH:
Its vertices have coordinates E(-4,4), F(4,4), G(4,0) and H(-4,0).
Hence the scale factor is becomes from these values is:
EF/AB = EH/AD = FG/BC = HG/DC = 4/3.
Hence the scale factor becomes 4/3.
Also
∠A=∠B=∠C=∠D=∠E=∠F=∠G=∠H=90°
( When a shape is dilated the two shapes are similar.And similar shapes have equal interior angles , corresponding sides are proportional ).
So, Yes, because both figures are rectangles and all rectangles are similar. Option B is correct option.
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which situation is most likley to show a constant rate of change
Option B. The situation that would be more likely to show a constant rate of change would be B. The distance traveled by a truck driving at a constant speed compared with time.
How to solve for the rate of changeThis is the factor that is used to determine if there is a decrease or an increase in a given factor.
A good way to d this is by the use of time and speed to compare the distance that is being traveled.
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Complete question
Which situation is most likely to show a constant rate of change?
A. The weight of a child compared with its age in months
B. The distance traveled by a truck driving at a constant speed compared with time
C. The cost of a new car compared with the number of tires it has
D. The outside temperature compared with the time of day
A paragraph proof
uses inductive reasoning to prove a statement.
contains a table with a logical series of statements and reasons.
uses a visual chart of the logical flow of steps needed to reach a conclusion.
contains a set of sentences explaining the steps needed to reach a conclusion.
A paragraph proof D. contains a set of sentences explaining the steps needed to reach a conclusion.
What is a paragraph proof?It should be noted that a paragraph proof simply means a way of presenting a mathematical proof.
In this case, it contains a set of sentences explaining the steps needed to reach a conclusion.
In conclusion, the correct option is D.
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Answer:
D: contains a set of sentences explaining the steps needed to reach a conclusion.
Marina correctly simplified the expression StartFraction negative 4 a Superscript negative 2 Baseline b Superscript 4 Baseline Over 8 a Superscript negative 6 Baseline b Superscript negative 3 Baseline EndFraction, assuming that a not-equals 0, b not-equals 0. Her simplified expression is below.
Negative one-half a Superscript 4 Baseline b Superscript empty box
What exponent should Marina use for b?
The exponent Marina should use for b is: D. 7.
How to Divide Exponents with the same Base?When dividing, you subtract the exponents. I.e. [tex]a^m \div a^n = a^{m - n}[/tex].
Using the rule, we would also subtract the exponents of b in the simplified expression. Thus:
[tex]b^4 \div b^{-3}[/tex]
Subtract the exponents
4 -(-3) = 4 + 3 = 7.
Therefore, the Maria should use the exponent b = 7.
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Answer: D
Step-by-step explanation:
can someone please help me with this problem?
Evaluate 2x for each value of x. Write your answers in simplest form. Show your work!
1. x = 1/4
2. x = 1/3
3. x = 1/2
4. x = 1/6
5. x = 1/7
6. x = 1/8
7. x = 2/3
8. x = 3/4
1. 1/2
2.2/3
3. 1
4. 1/3
5. 2/7
6. 1/4
7. 4/3
8. 3/2
How to evaluate the valueTo find 2x of the vale of x, we have to multiply the value of 'x' by 2
1. x = 1/4
[tex]2x = 2 * \frac{1}{4}[/tex] ⇒ [tex]\frac{2}{4}[/tex] ⇒[tex]\frac{1}{2}[/tex]
2. x = 1/3
[tex]2x = 2 * \frac{1}{3}[/tex] ⇒[tex]\frac{2}{3}[/tex]
3. x = 1/2
[tex]2x = 2* \frac{1}{2}[/tex] ⇒ [tex]\frac{2}{2}[/tex] ⇒ [tex]1[/tex]
4. x= 1/6
[tex]2x = 2* \frac{1}{6}[/tex] ⇒ [tex]\frac{2}{6}[/tex] ⇒ [tex]\frac{1}{3}[/tex]
5. x = 1/ 7
[tex]2x = 2 * \frac{1}{7}[/tex] ⇒ [tex]\frac{2}{7}[/tex]
6. x = 1/8
[tex]2x = 2 * \frac{1}{8}[/tex] ⇒ [tex]\frac{2}{8}[/tex] ⇒ [tex]\frac{1}{4}[/tex]
7. x = 2/3
[tex]2x = 2 * \frac{2}{3}[/tex] ⇒ [tex]\frac{4}{3}[/tex]
8. x = 3/4
[tex]2x = 2 * \frac{3}{4}[/tex] ⇒ [tex]\frac{6}{4}[/tex] ⇒ [tex]\frac{3}{2}[/tex]
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Find RS.
A. 12
B. 5
C. 10
D. 9
Answer:
5
Step-by-step explanation:
(2x - 6) + 1 + (x - 4) = 18
3x - 9 = 18
3x = 27
x = 9
RS = x - 4 = 9 - 4 = 5
Answer:
B. 5
Step-by-step explanation:
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PQ + QR + RS = 18
This statement is equivalent to the following:
(2x - 6) + 1 + (x - 4) = 18.
This is because we substitute the line segments with their values.
Now that we have an equation to work with, we will solve it. We start by removing the parenthesis as they are not necessary here.
2x - 6 + 1 + x - 4 = 18
Next, we will make it, so x is alone on the left. We will do this by adding 6 and 4 to both sides
2x - 6 (+6) + 1 + x - 4 (+4) = 18 (+6) (+4)
After doing this we are left with the following equation:
2x + 1 + x = 28
Now we will subtract 1 from both sides to make x alone of the left side of the equation.
2x + 1 (-1) + x = 28 (-1)
After we solve this, we get the following:
2x + x = 27
We can add 2x and x and get 3x because 2 + 1 = 3.
3x = 27
We now simplify this equation by dividing both sides by 3.
[tex]\frac{3x}{3}[/tex] = [tex]\frac{27}{3}[/tex]
We again simplify the equation to the following:
x = 9
BUT THATS NOT THE ANSWER!
Now that we know what x is, we can solve for the value of RS.
We input 9 for x in the equation x - 4.
When we do this, we get 9 - 4 which is 5.
And this is our final answer!!
I hope I could help! Have an amazing day and good luck on your homework!
"You can't predict the future, but you can create it"
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Can someone help me out on these geometry questions? ASAP!!!
Write formal proofs the LA Theorm.
Question 4
1) [tex]\angle B[/tex] and [tex]\angle E[/tex] are right angles, [tex]\overline{AB} \cong \overline{DE}[/tex], [tex]\angle A \cong \angle D[/tex] (given)
2) [tex]\triangle CBA[/tex] and [tex]\triangle FED[/tex] are right triangles (a triangle with a right angle is a right triangle)
3) [tex]\triangle CBA \cong \triangle FED[/tex] (LA)
Note: I wrote the names of the triangles in an alternate order because of the word filter.Question 5
1) [tex]\overline{XY} \perp\overline{WZ}[/tex], [tex]\overline{UV} \perp \overline{WZ}[/tex], [tex]\overline{VW} \cong \overline{YZ}[/tex], and [tex]\angle Z \cong \angle W[/tex] (given)
2) [tex]\angle XYZ[/tex] and [tex]\angle UVW[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle XYZ[/tex] and [tex]\triangle UVW[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\triangle XYZ \cong \triangle UVW[/tex] (LA)
5) [tex]\overline{UW} \cong \overline{XZ}[/tex] (CPCTC)
Question 6
1) [tex]\overline{PQ} \perp \overline{QT}[/tex], [tex]\overline{ST} \perp \overline{QT}[/tex], [tex]\overline{PQ} \perp \overline{ST}[/tex] (given)
2) [tex]\angle PQR[/tex] and [tex]\angle RTS[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle PQR[/tex] and [tex]\triangle STR[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\angle PRQ \cong \angle SRT[/tex] (vertical angles are congruent)
5) [tex]\triangle PQR \cong \triangle STR[/tex] (LA)
6) [tex]\overline{QR} \cong \overline{TR}[/tex] (CPCTC)
In 2020 Ashmija invested $10,000 into an account which is growing at 4.5% annually.
Write an equation to model the amount of money in her account D(t), with respect to time, t. Explain what the values represent. [4 Marks]
Use your equation to find how much she will make in 2050 assuming she hasn't made any withdrawals or extra deposits. [3 marks]
The exponential function that models this situation is:
[tex]D(t) = 10000(1.045)^t[/tex]
Using the function, in 2050, she will have $37,453.
What is an exponential function?An increasing exponential function is modeled by:
[tex]A(t) = A(0)(1 + r)^t[/tex]
In which:
A(0) is the initial value.r is the growth rate, as a decimal.For this problem, the parameters are:
A(0) = 10000, r = 0.045.
Hence the equation is:
[tex]D(t) = 10000(1.045)^t[/tex]
2050 is 30 years after 2020, hence the amount is:
[tex]D(30) = 10000(1.045)^{30} = 37453[/tex]
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A shipment of 60 highly sensitive accelerometers is to be accepted or rejected based on the testing of 5 chosen randomly from the lot. The shipment will be rejected if more than 1 of the 5 fail. It is known that 10% of the shipment does not meet the specifications. Let X denote the number of units that fail. What is the standard deviation of the distribution
Using the binomial distribution, it is found that the standard deviation of the distribution is of 0.67.
What is the binomial probability distribution?It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
The parameters are:
n = 5, p = 0.1.
Hence the standard deviation is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5 \times 0.1 \times 0.9} = 0.67[/tex]
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Given cos(x)=1/2, what is the value of cos(x+pi)?
Answer:
-1/2
Step-by-step explanation:
cos(x+pi) = -cos(x), so the answer is -1/2.