A mole of a monatomic ideal gas at point 1 (101 kPa, 5 L) is expanded adiabatically until the volume is doubled at point 2. Then it is cooled isochorically until the pressure is 20 kPa at point 3. The gas is now compressed isothermally until its volume is back to 5 L (point 4). Finally, the gas is heated isochorically to return to point 1.
a. Draw the four processes and label the points in the pV plane.
b. Calculate the work done going from 1 to 2.
c. Calculate the pressure and temperature at point 2.
d. Calculate the temperature at point 3.
e. Calculate the temperature and pressure and point 4.
f. Calculate the work done going from from 3 to 4.
g. Calculate the heat flow into the gas going from 3 to 4. g

Answer:

 t_{out} = [tex]\frac{v_s - v_r}{v_s+v_r}[/tex] t_{in},      t_{out} = [tex]\frac{D}{v_s +v_r}[/tex]

Explanation:

This in a relative velocity exercise in one dimension,

let's start with the swimmer going downstream

its speed is

         [tex]v_{sg 1} = v_{sr} + v_{rg}[/tex]

The subscripts are s for the swimmer, r for the river and g for the Earth

with the velocity constant we can use the relations of uniform motion

           [tex]v_{sg1}[/tex] = D / [tex]t_{out}[/tex]

           D = v_{sg1}  t_{out}

now let's analyze when the swimmer turns around and returns to the starting point

        [tex]v_{sg 2} = v_{sr} - v_{rg}[/tex]

         [tex]v_{sg 2}[/tex] = D / [tex]t_{in}[/tex]

         D = v_{sg 2}  t_{in}

with the distance is the same we can equalize

           [tex]v_{sg1} t_{out} = v_{sg2} t_{in}[/tex]

          t_{out} =  t_{in}

           t_{out} = [tex]\frac{v_s - v_r}{v_s+v_r}[/tex] t_{in}

This must be the answer since the return time is known. If you want to delete this time

            t_{in}= D / [tex]v_{sg2}[/tex]

we substitute

            t_{out} = \frac{v_s - v_r}{v_s+v_r} ()

            t_{out} = [tex]\frac{D}{v_s +v_r}[/tex]

Answer:

the interaction in the protein is greater than the surface with water

\frac{F_i}{F_s} = \frac{\epsilon_s}{ \epsilon_i} \ > 1

Explanation:

The electric force  for a charge is

          F = [tex]\frac{1}{4\pi \epsilon} \ \frac{q^2}{r^2}[/tex]

In the exercise indicate that the charge is q and the distance r is maintained, the test charge is another  

therefore if we use the index i for the dielectric constant ([tex]\epsilon_i[/tex]) in the protein

         [tex]F_{i} = \frac{1}{4\pi \epsilon_i} \frac{q^2}{r^2}[/tex]  

the electric force in water with dielectric constant ([tex]\epsilon_s[/tex])

           [tex]F_s = \frac{1}{4\pi \epsilon_s} \frac{q^2}{r^2}[/tex]

            [tex]\epsilon_i < \epsilon_s[/tex]

if we look for the relationship between these forces

          [tex]\frac{F_i}{F_s} = \frac{\epsilon_s}{ \epsilon_i} \ > 1[/tex]

therefore the interaction in the protein is greater than the surface with water

Answer:

Iris

Explanation:

The iris seems to be the illuminated portion of the eyes which really covers the pupil. It controls the amount of light reaching the eye. The lens is indeed a translucent layer of the retina that serves to concentrate light and objects on the lens.

Answer:

I hope this helps.

Explanation:

Answer:

electric current passing through it will be 50mA

Explanation:

electric current = charge / time

current = 0.05 A = 50mA

If 0.5C charge passes through a wire in 10 seconds, then 50mA current is flowing through the wire. Thus, the correct option is C.

Electric current is the flow of electricity in an electronic circuit. It is the amount of electricity flowing through a electronic circuit. It is generally measured in amperes (A). The larger the value in amperes, the more electricity is flowing in that circuit.

The formula for calculation of Electric current is:

I = Q/T

where, I = electric current,

Q = amount of charge,

T = time required

Therefore, the current flowing in the wire is:

I = 0.5C/ 10 seconds

I = 0.05 A or 50mA (1mA = 10⁻³A)

Therefore, the correct option is C.

Learn more about Electric current here:

https://brainly.com/question/2264542

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Answer:

   F₁> F₂

Explanation:

For this exercise Newton's second law is used, in the adjoint we can see the unapplied forces in this exercise.

Y axis y

        N- W = 0

in this axis there is no movement

X axis

          F -fr = m a

as they indicate that the velocity is consonant the acceleration is worth zero

          F - fr = 0

friction force has the expression

           fr = μ N

           fr = μ mg

we substitute

           F = μ m g

by the time the block is stopped the deferred force is

           F₁ = μ_s m g

when it begins to move the force should decrease to

           F₂ = μ_k k m g

as the static coefficient is greater than the dynamic coefficient

             F₁> F₂

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

The net force on the block will result constant speed of the block which is zero acceleration.

[tex]\Sigma F= 0\\\\F - F_f = 0\\\\F - \mu_k F_n= 0\\\\F - \mu_k mg = 0\\\\F - \mu k W = 0\\\\F = F_f\ \ \ or \ \ F = \mu_k W[/tex]

The free body diagram consists of applied force (F) and kinetic frictional force acting in opposite direction.

                        F →  Ф ← Ff

Learn more about free body diagram here: https://brainly.com/question/21691401

Answer:

0.2 – 4.6 seconds   increasing speed in positive direction

4.6 - 7.8 seconds   decelerating speed in a positive direction

8 - 17.2 seconds  accelerating speed in a negative direction

Explanation:

**Plato** **Edmentum**n~ this question is pretty open ended, so its hard to get it wrong honestly, good luck <3 ~

Answer:

0.2 – 4.6 seconds   increasing speed in positive direction

4.6 - 7.8 seconds   decelerating speed in a positive direction

8 - 17.2 seconds  accelerating speed in a negative direction

Explanation:

Answer:

The car ...Explanation:

Answer:

3.277 m

Explanation:

Given :

Maximum Height (Hmax) = (u²sin²θ) / 2g

Xv = Xh + Uv * t + 0.5gt²

Xv and Xh are vertical and horizontal distances

-1 = 0 + sin37 * 1.5 Uv + 0.5*-9.8*1.5^2

-1 = 0 + 0.903Uv - 11.025

-1 + 11.025 = 0.903Uv

10.025 = 0.903Uv

Uv = 10.025 / 0.903

Uv = 11.10 m/s

Hmax = 1 + (u²sin²θ) / 2g

= (11.10^2 * (sin37)^2) / 2*9.8

= 44.624360 / 19.6

= 2.277

Hmax = 1 + 2.277

Hmax = 3.277 m

Answer:

12.5 m/s

Explanation:

Excuse my scribbles!

I had to work backwards using the inelastic collision formula for this problem.

Step 1: Substitute in the values provided in the problem

2.5=(8*0)+(?*?)/(8+?)

Step 2: Subtract block 1's mass from the combined mass to determine block 2's mass

10-8=2     Block 2's mass is 2.

2.5=(8*0)+(2*x)/(8+2)    

Now simplify.

2.5=(2*x)/(8+2)

2.5=2x/10

Step 3: Multiply both sides by the reciprocal

(5)2.5=2x/10(5)

12.5=x

Answer is checked in the attached images!

Answer:

The answer is below

Explanation:

Let x represent the number of ounce of dairy based meal and let y represent the number of vegan option in ounce.

Since the diet must contain at least 2400 mg vitamin C, therefore:

50x + 20y ≥ 2400

Since the diet must contain at least 1800 mg Calcium, therefore:

30x + 20y ≥ 1200

Since the diet must contain at least 1200 calories, therefore:

10x + 40y ≥ 1200

Therefore the constraints are:

50x + 20y ≥ 2400

30x + 20y ≥ 1200

10x + 40y ≥ 1200

x > 0, y > 0

The graph was drawn using geogebra online graphing tool, and the solution to the problem is at:

C(30, 45) and D(48, 18)

dairy-based meal costs $0.042 per ounce and the vegan option costs $0.208 per ounce. The cost equation is:

Cost = 0.042x + 0.208y

At C(30, 45);  Cost = 0.042(30) + 0.208(45) = $10.62

At C(48, 18);  Cost = 0.042(48) + 0.208(18) = $5.76

The minimum cost is at (48, 18). That is 48 dairy based meal and 18 vegan

Answer:

Propulsion system, antigravitational tech

Explanation:

Fuel is extremely inefficient and expensive not to mention it weighs a lot. You really only need to reach escape velocity to leave earth. The rest is just a little amount of boosting to alter course and slow down for landing. I couldn't really think of much. Once we have an antigravitational system then you could say the whole rocket is holding you back because the design would be different. Nobody really knows how to defy gravity but that would be a technolgical limitation for sure.

Answer:

[tex]\boxed {\boxed {\sf 6,000 \ Newtons}}[/tex]

Explanation:

Force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the Kia Soul is 1200 kilograms and its acceleration is 5 meters per square second.

[tex]m= 1200 \ kg \\a= 5 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 1200 \ kg * 5 \ m/s^2[/tex]

Multiply.

[tex]F= 6000 \ kg*m/s^2[/tex]

[tex]F= 6000 \ N[/tex]

Answer:

Force

We know that

F = ma

F = Force

m = mass

a = acceleration

F = 1200 × 5

F = 6000 N

[tex] \\ [/tex]

Answer:

The minimum average speed the opponent must move so that he is in position to hit the ball is approximately 5.79 m/s

Explanation:

The given parameters of the ball are;

The initial speed of the ball = 15 m/s

The direction in which the ball is launched = 50° above the horizontal

The location of the other tennis player when the ball is launched = 10 m from the ball

The time at which the other tennis player begins to run = 0.3 seconds after the ball is launched

The height at which the ball is hit back = 2.1 m above the height from which the ball is launched

The vertical position, 'y', at time, 't', of a projectile motion is given as follows;

y = (u·sinθ)·t - 1/2·g·t²

When y = 2.1 m, we have;

2.1 = (15·sin(50°))·t - 1/2·9.8·t²

∴ 4.9·t² - (15·sin(50°))·t + 2.1 = 0

Solving with the aid of a graphing calculator function, we get;

t = 0.199776187257 s or t = 2.14525782198 s

Therefore, the ball is at 2.1 m above the start point on the other side of the court at t ≈ 2.145 seconds

The horizontal distance, 'x', the ball travels at t ≈ 2.145 seconds is given as follows;

x = u × cos(50°) × t = 15 × cos(50°) × 2.145 ≈ 20.682 m

The horizontal distance the ball travels at t ≈ 2.145 seconds, x ≈ 20.682 m

Therefore, we have;

The time the other player has to reach the ball, t₂ =2.145 s - 0.3 s ≈ 1.845 s

The distance the other player has to run, d = 20.682 m - 10 m = 10.682 m

The minimum average speed the other player has to move with, [tex]v_s[/tex] = d/t₂

∴ [tex]v_s[/tex] = 10.682 m/(1.845 s) ≈ 5.78970189702 m/s ≈ 5.79 m/s

The minimum average speed the opponent must move so that he is in position to hit the ball, [tex]v_s[/tex] ≈ 5.79 m/s.

Answer:

Net force = - 1500 N

Explanation:

We calculate the net force acting using Newton's second Law:

[tex]F_{net}=m*a\\F_{net}=(300 \,kg)*(-5\,m/s^2)\\F_{net}=-1500\,N[/tex]

Answer:

The car C has KE = 100, PE = 0

Explanation:

The principle of conservation of energy states that although energy can be transformed from one form to another, the total energy of the given system remains unchanged.

The energy that a body possesses due to its motion or position is known as mechanical energy. There are two kinds of mechanical energy: kinetic energy, KE and potential energy, PE.

Kinetic energy is the energy that a body possesses due to its motion.

Potential energy is the energy a body possesses due to its position.

From the principle of conservation of energy, kinetic energy can be transformed into potential energy and vice versa, but in all cases the energy is conserved or constant.

In the diagram above, the cars at various positions of rest or motion are transforming the various forms of mechanical energy, but the total energy is conserved at every point. At the point A, energy is all potential, at B, it is partly potential partly kinetic energy, However, at the point C, all the potential energy has been converted to kinetic energy. At D, some of the kinetic energy has been converted to potential energy as the car climbs up the hill.

Therefore, the car C has KE = 100, PE = 0

Answer:

a)  ρ = 6.25 10⁵ μg / m³, b) ρ  = 1 10⁷ μg / m³

Explanation:

Let's analyze the exercise a little before starting, we must know the amount of pollutant in the box, that the one that enters less the one that degrades and with this value find the density or concentration.

Let's start by finding the volume of air that goes into the box

               V = Lh x

Let's find the distance of air that enters per unit of time, as it goes at constant speed

               x = v₀ t

we substitute

               V₀ = Lh v₀ t

At this same time, a quantity of pollutant is distributed

              Q₀ = r t  

the contaminant that is entering reaches the entire box, therefore the total amount of contaminant is

               Q = Qo t

we substitute

               Q = r t²

the net amount of pollutant that remains is that less enters the one that degraded in the same time, as they ask for the steady state

              [tex]Q_{net}[/tex]= Q - k t

the pollutant concentration is

              ρ = Q_net / V

              V = L L h

              ρ =[tex]\frac{r \ t^2 - k \ t}{ L^2 h}[/tex]

              ρ = [tex](r \frac{ L^2}{v_o^2} - k \frac{L}{v_o} ) \frac{1}{L^2 h}[/tex]

               ρ = [tex]\frac{r}{ v_o h} -\frac{k}{v_o L h}[/tex]

let's reduce the magnitudes to the SI system

           r = 10 kg / s

           L = 100 km = 100 10³ m

           h = 1 km = 1 10³ m

           k = dq / dt = 0.20 1/h ( 1h/3600 s) = 5.5555 10⁻⁵  1/s

           v₀ = 4 m / s

let's calculate

The volume of the box

             V = (100 100 1) 109

             V = 1 10¹³ m³

            ρ = [tex]\frac{10}{ 4^2 \ 1\ 10^3 } - \frac{5.5556 \ 10^{-5}}{ 4 \ 100 \ 10^3 1 \ 10^3}[/tex]

            ρ = [tex]6.25 10^{-4} - 1.389 ^{-13}[/tex]

            ρ = 6.25 10⁻⁴ kg / m³

let's reduce to μg / m³

               ρ = 6.25 10⁻⁻⁴ kg / m³ (10⁹ μg / 1kg)

               ρ = 6.25 10⁵ μg / m³

b) in case the air speed decreases to v₀ = 1 m / s

             ρ= \frac{10}{ 1^2 \  1\  10^3 } - \frac{5.5556 \ 10^{-5}}{ 1 \ 100 \ 10^3  1 \ 10^3}

             ρ = 1 10⁻² - 5.5556 10⁻¹³

             ρ =  1 10⁻² kg / m³

             ρ  = 1 10⁷ μg / m³

Answer:

Explanation:The Mass Of The Left Block M1 = 1.3 Kg And The Mass Of The Right Block M2 = 3.1 Kg. The Angle Between The String And The Horizontal Is ... (10%) Problem 8: Two blocks connected by a string are pulled across a horizontal surface by a ... m m, 50% Part (a) Write an equation for the magnitude of the force exerted by the ...

Answer:

The answer is "The last choice".

Explanation:

Please find the complete question in the attachment.

In an external electric field, its electrical energy at positive charge becomes directed to just the electrical domain. Therefore it will speed towards its base plate whenever cyber one is released to rest at h0. It was never going to reach the top plate. Thus,  the last choice corrects because in this the cyber-on never reaches its upper stage.

Answer:

#_time = 7.5 10⁴ s

Explanation:

In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.

            t = [tex]\frac{t_p}{ \sqrt{1- (v/c)^2} }[/tex]

where t_p is the person's own time in an immobile reference frame,

           [tex]t_{p} = t \sqrt{1 - (\frac{v}{c})^2 }[/tex]

let's calculate

we assume that the speed of the space station is constant

              [tex]t_p = 1 \sqrt{1 - \frac{8 \ 10^3}{3 \ 10^8} }[/tex]

             [tex]t_p = 1 \sqrt{1- 2.6666 \ 10^{-5}}[/tex]

             t_ =  0.99998666657   s

therefore the time change is

             Δt = t - t_p

             Δt = 1 - 0.9998666657                  

              Δt = 1.3333 10⁻⁵ s

this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

               #_time = 1 / Δt

               #_time =[tex]\frac{1}{1.3333 \ 10^{-5}}[/tex]

               #_time = 7.5 10⁴ s

Answer:

D The chemicals on the right side of a chamical equation

Answer:

Eat slowly

Explanation:

If you eat slower, you'll chew your food better, which leads to better digestion. Digestion actually starts in the mouth, so the more work you do up there, the less you'll have to do in your stomach. This can help lead to fewer digestive problems. Less stress.

Answer:

O exothermic, because energy is released into the surrounding

Explanation:

From the diagram the energy of the reactant is higher than the energy of the product, thereby making it exothermic. If you study diagram well, exothermic reaction means that the reactions releases energy into the surroundings.

Answer:

Δx = 0.7 m

Explanation:

       [tex]t = \sqrt{\frac{2*1.8m}{ 9.8m/s2} } = 0.6 s (2)[/tex]

       [tex]\Delta x = v_{o} * t = 1.1 m/s* 0.6 s = 0.7 m (3)[/tex]

Answer:

Liquids

Explanation:

Diffusion occurs fastest in liquids.

Postive and negatives attract, positive and positive repel. answer is negatively charged pipe.

sound waves and light energy are not "affected" by static electricity

Answer:

kekemeeimdeiddnekem

Explanation:

mdjdjdiddmjd jjeneeiej

Answer:

It's A

Explanation:

sound waves are longitudinal they need a medium to travel through

Answer:

Cats most commonly contract worms after coming into contact with parasite eggs or infected feces. A cat may walk through an area with eggs or infected feces, and since cats are often such fastidious groomers, they will then ingest the eggs or fecal particles as they clean their fur and feet.

Explanation:

this is the only thing in my book hope it helps

Answer:

They are conductors/conductive. Materials that can transfer thermal energy well are conductive.

Explanation:

Answer:when material allow to heat to pass though them rapidly they are known as Conductors

What are conductors

In physics /electrical engineering They  allow the flow of charge (electrical current) in one or more directions. Materials made of metal are common electrical conductors.

What are examples of conductors

.Silver

.copper

.iron

.aluminum

.brass

Difference between conductors and insulators?

Insulators a material that is a poor conductor (as of electricity or heat)Whereas Conductors are fantastic at allowing the flow of the heat.

Hope this helps

                                                                           -Tobie