Answer:
264 m
Explanation:
The complete question is
Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if it flies past you at a speed of v = 0.75c
using the length contraction relationship,
[tex]l = l_{0} \sqrt{1 - \beta ^{2} }[/tex]
where [tex]\beta = \frac{v}{c}[/tex]
[tex]l[/tex] is the relativistic length
[tex]l_{0}[/tex] is the actual length = 400 m
v is the velocity of the spaceship
c is the speed of light
since v = 0.75c
v/c = 0.75
substituting, we have
[tex]l = 400 * \sqrt{1 - 0.75 ^{2} }[/tex] = 400 x 0.66 = 264 m
If the f-number of a camera lens is doubled, say from F4.0 to F8.0, that means the diameter of the lens aperture is
Answer:
The diameter is halved or reduced by a factor of 2
Explanation:
Because
f number = F/D
That is f number is inversely proportional to diameter so if it is doubled diameter is halved
A ball rolls down a roof that makes an angle of 30.0 degrees to the horizontal. It rolls off the edge of the roof with a speed of 5.00 meters per second. The distance straight down to the ground from the edge of the roof is 7.00 meters. a) How long is the ball in the air
Answer:
0.97s
Explanation:
First of all solving the second equation of motion in the vertical direction we have
Vy= Vosinစ
= 5m x sin 30= 2.5m/s
So solving for t time in second equation of motion we will have
t= - Vy +or- √(Vy²- 4{g/2)- h)/ (2g/2)
Substituting 7m for h
We have
t = -2.5+or- √ 2.5²-4(4.9)-7/9.3
We have
t= 0.97s as the positive rational answer
A runner with a mass of 70 kg accelerates from 0 m/s to 8 m/s in 9 s. Find the magnitude of the net force (in newtons) on the runner using the alternate form of Newton's second law. Round your answer to the nearest whole number.
Explanation:
F = ma
F = m Δv / Δt
F = (70 kg) (8 m/s − 0 m/s) / 9 s
F ≈ 62 N
An object has a mass of 120 kg on the moon what is the force of gravity acting on the object on the moon
Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.
Explanation:
Answer:
Hey there!
W=mg, where m is the mass and g is the acceleration of gravity.
The acceleration of g on the moon is about 1.622 m/s^2, so plugging that in as a value gives us W, the force is equal to approximately 197 Newtons.
Let me know if this helps :)
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1 15 the speed of light
Answer:
Te wavelength is 3.66 x 10^-11 m
Explanation:
Question is
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1/15 the speed of light.
De Broglie's wavelength is gotten as
λ = h/mv
where
λ is the wavelength of the electron
h is the Planck's constant = 6.67 x 10^-34 J-s
m is the mass of an an electron = 9.109 x 10^-31 kg
v is the speed of the electron.
The speed of the electron is given as 1/15 of the speed of light
Speed of electron = 1/15 of 3 x 10^8 = 2.0 x 10^7 m/s
substituting values, we have
λ = (6.67 x 10^-34)/(9.109 x 10^-31)x(2.0 x 10^7) = 3.66 x 10^-11 m
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2.
a. Find the mass flow rate.
b. Find the volume flow rate.
c. Find the flow speed at point 1.
d. Find the flow speed at point 2.
e. Find the gauge pressure at point
Answer:
A. To find the mass flow rate.
We use= 220 x 0.355/ 60
= 1.3kg/s
B. Volume flowrate is = mass flowrate / density
But density is 1000kg/m³
= 1.3kg/s/ 1000kg/m³
= 0.0013m³/s
C. Flow speead at 1
= 0.0013m³/s / (2 x 10-2m)²
= 6.5m/s
D.flow speed at 2
0.0013m³/s / (8x 10-2m)²
=1.63m/s
E. Gauge pressure at point 1
= 152+ 1/1000 ( 1.63)²- 6.5² + 1000( 9.8) ( 0-1.35)
= 119kpa
A thin, light wire 75.1 cm long having a circular cross section 0.555 mm in diameter has a 25.4 kg weight attached to it, causing it to stretch by 1.10 mm.
A) what is the stress of the wire.
B) what is the strain in the wire.
C) find the Young Modulus for the material of the wire.
Answer:
(a) 3.23×10⁸ N/m²
(b) 1.46×10⁻³
(c) 2.21×10¹¹ N/m²
Explanation:
(a) Stress = Force/Area.
Stress = F/A................ Equation 1
But,
F = mg................. Equation 2
Where m = mass, and g = acceleration due to gravity
A = πd²/4................. Equation 3
d = diameter of the circular cross section.
Substitute equation 2 and equation 3 into equation 1
Stress = 4mg/πd²............. Equation 4
Given: m = 25.4 kg, d = 0.555 mm = 0.000555 m
Constant: g = 9.8 m/s², π = 3.142
Substitute these values into equation 4
Stress = 4(25.4)(9.8)/(3.142×0.00555²)
Stress = 995.68/(3.08×10⁻⁶)
Stress = 3.23×10⁸ N/m²
(b)
Strain = ΔL/L.............. Equation 5
Where ΔL = extension, L = Length.
Given: ΔL = 1.1 mm = 0.0011 m, L = 75.1 cm = 0.751 m
Substitute into equation 5
Strain = 0.0011/0.751
Strain = 1.46×10⁻³.
(c)
Young modulus = Stress/Strain
Young modulus = 3.23×10⁸/ 1.46×10⁻³
Young modulus = 2.21×10¹¹ N/m²
Waves on a String: The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel
Answer:
The wavelength of the sound wave is 7.58 m
Explanation:
Given;
speed of wave in steel, v = 5000 m/s
frequency of the wave in steel, f = 660 Hz
The wavelength of a sound wave is given by;
λ = v / f
where;
v is the speed of sound wave in steel
f is the frequency of sound wave in steel
λ is the wavelength of the sound wave in steel
λ = 5000 / 660
λ = 7.58 m
Therefore, the wavelength of the sound wave is 7.58 m
A worker needs to know the temperature inside an oven. He takes a 2 kg iron bar out of the oven and places it in a 1 kg aluminum container partially filled with 2 kg of water. If the water temperature rises from 21 ° C to 50 ° C, what was the temperature of the oven? Neglect other heat changes.
Answer:
350°C
Explanation:
Heat gained by water and aluminum = heat lost by iron
q₁ + q₂ = -q
m₁C₁ΔT₁ + m₂C₂ΔT₂ = -mCΔT
(1 kg) (900 J/kg/°C) (50°C − 21°C) + (2 kg) (4186 J/kg/°C) (50°C − 21°C) = -(2 kg) (449 J/kg/°C) (50°C − T)
(900 J/°C) (29°C) + 2 (4186 J/°C) (29°C) = -2 (449 J/°C) (50°C − T)
26,100 J + 242,788 J = -44,900 J + 898 (J/°C) T
898 (J/°C) T = 313,788 J
T = 350°C
An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has the larger de Broglie wavelength?
Explanation:
The De-Broglie wavelength in terms of potential difference is given by:
[tex]\lambda=\dfrac{h}{\sqrt{2meV} }[/tex]
Where,
h is Planck's constant
m is mass of charged particle
V is potential difference
e is the amount of charge
It means that the De-Broglie wavelength is inversely proportional to the mass.
Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.
A photocell is based upon the photoelectric effect. A light beam illuminates a metallic plate, and under certain conditions electrons are ejected from the metal. In order to measure the maximum kinetic energy of the electrons, another plate is kept at a negative enough potential that the emitted electrons are slowed down and stopped.
Explain how the particle-like aspect of light can explain the following:
(i) the absence of delay in the observation of current,
(ii) the existence of a cut-off frequency which is independent of the intensity of light,
(iii) the fact that the maximum kinetic energy of the electrons only depends on the frequency, not the intensity.
Answer:
i) photons, they collide with the electrons
ii)when the energy of the photons is less than the work function there is no way to get out electrons
iii) he energy depends on the frequency in this Planck postulate
Explanation:
This exercise the photo cell is used for the photoelectric effect, this effect was explained by Einstein
i) Where the light is supposed to act as a particular, therefore, it is called photons, they collide with the electrons and they can tear off the metal, with a collision it is very fast there is no measurable wait in the process.
ii) since we have a shock process, the equation must be fulfilled
K = h f - Ф
where E = h f is the energy postulated by Plank and Ф the work function of the metal, therefore when the energy of the photons is less than the work function there is no way to get out electrons, which determines a threshold energy in the process
iii) From the same previous equation, the energy depends on the frequency in this Planck postulate, and not on the intensity squared as accepted in classical mechanics.
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweezers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth.
Required:
a. What is the pressure on an atom if light from the tweezers is totally absorbed? ?
b. If this pressure were exerted on a tritium atom, what would be its acceleration?
Answer:
Explanation:
a )
If it is totally absorbed pressure is calculated as follows .
Pressure = I / c where I is intensity of light falling .
= 1000 / 3 x 10⁸
= 3.33 x 10⁻⁶ N / m²
b ) weight of tritium atom
= 3 x 1.67 x 10⁻²⁷ kg
acceleration = force / mass
= 3.33x 10⁻⁶ / 3 x 1.67 x 10⁻²⁷
= .6646 x 10²¹ m /s²
= 66.46 x 10¹⁹ m / s²
How do you recognise a chemical
An air track glider is attached to a spring. The glider is pulled to the right and released from rest at t=0 seconds. It then oscillates with a period of 2.40s and a maximum speed of 30.0 cm/s. What is the glider's position at t=0.300s?
Answer:
The glider's position at t=0.300s is 8.1 cm
Explanation:
Given;
maximum speed of the glider, [tex]v_{max}[/tex] = 30.0 cm/s = 0.3 m/s
period of the oscillation, T = 2.4 s
Maximum speed of oscillation is given by;
[tex]v_{max}[/tex] = ωA
Where;
A is the amplitude of the oscillation
ω is the angular speed
[tex]\omega = \frac{2\pi}{T} \\\\\omega =\frac{2\pi}{2.4}\\\\ \omega = 0.833 \pi[/tex]
The amplitude of the oscillation is given by;
[tex]A = \frac{v_{max}}{\omega} \\\\ A = \frac{0.3}{0.833\pi}\\\\ A = 0.1146 \ m[/tex]
The position of the particle is given by;
x(t) = A cosωt
x(0.3) = (0.1146)cos(0.833π x 0.3)
x(0.3) = (0.1146)cos(0.833π x 0.3)
x(0.3) = (0.1146)cos(45)
x(0.3) = 0.081 m
x(0.3) = 8.1 cm
Therefore, the glider's position at t=0.300s is 8.1 cm
A gas is compressed by an adiabatic process that decreases its volume by a factor of 2.
In this process, the pressure
In this process, the pressure
a) increases by a factor of more than 2.
b) increases by a factor of 2.
c) does not change.
d) increases by a factor of less than 2.
Answer
OPTION A is correct
a)increases by a factor of more than 2.
Explanation:
adiabatic process is a process that takes place without the transfer of heat or mass between a thermodynamic system and its surroundings.
It is a process in which no heat transfer takes place. It does not denote that the temperature is constant.
Then from an adiabatic system,
we know that
PV= constant
PV^γ= constant
γ=ratio of specific heat for the gas
Where P= pressure of the system
V= volume of the system
We can say P= 1/(V^γ)
Where γ >1
Which means the pressure is inversely proportional to the volume raise to power of gamma sign and whenever the pressure increases the volume decreases with V^γ.
The question says the volume is decreased by factor of two then V^γ will also decreased by factor of 2.
That means (2^γ) > 2
Since our γ > 1 Therefore, the pressure increases by a factor of more than 2.
Answer:
a) increases by a factor of more than 2.
Explanation:
In an adiabatic process,
[tex]PV^{Y} = constant[/tex]
we can say that the volume is inverse to the pressure as
[tex]V^{Y}[/tex]∝ [tex]\frac{1}{P}[/tex]
where
[tex]P[/tex] is the pressure
[tex]V[/tex] is the volume
[tex]Y[/tex] is the adiabatic index, and it is always greater than 1
If volume V is decreased by a factor of 2, then it is actually decreased by a factor of [tex]2^{Y}[/tex] in proportion to the pressure, and since [tex]Y[/tex] is always greater than 1, it is actually decreased by a factor greater than 2 in proportion to the pressure.
This means that the pressure will also increase by a factor greater than 2.
Now you try! Draw the arrows to represent the motion described, then calculate the distance
and displacement for the object.
A car drives 12 meters North and 15 meters South What is the car's distance and
displacement
Distance = 27m
Displacement = 3 metres South
Explanation:
Distance is a scalar quantity and it represents the length of the path taken by a body.
Displacement is a vector quantity and it represents the distance between the start and end points of a body.
Now to the question:
The car drives 12 metres North i.e
North (+ve)
∧
|
| 12m
|
|
The car then drives 15 metres South i.e
|
|
|
| 15m
|
∨
South (-ve)
(a) The car's distance d, is just the total distance covered to drive North and then South. i.e
d = 12m + 15m = 27m
(b) The car's displacement D, however takes into respect, the direction of the car as it drives to and fro.
Let North be taken as positive direction
Let South be taken as negative direction.
This means that;
12 m North = +12 m
15 m South = -15m
Therefore;
D = +12 - 15
D = -3m
Since the displacement is negative, then it means that the direction of the total displacement is South.
Therefore, the displacement is 3 metres South
PS: The arrow diagram has also been attached to this response
hi guys this is my last points and i need some answers :)
1. what is a runoff?
A. A type of precipitation that falls as a mixture of ice and snow B.The water on the surface that soaks deep into the ground C.Tiny droplets of water that condense to form clouds D.Water that moves along the surface of Earth into the oceans
NEXT QUESTION
2.Which statement about oceans is incorrect?
A.Evaporation occurs when water is warmed by the sun.
B.Most evaporation and precipitation occur over the ocean.
C.97 percent of Earth's water is fresh water from the ocean.
D.Water leaves the ocean by the process of evaporation.
Answer:
Number 1: B Number 2: D
Explanation:
Answer:
Hello! Your answer would be D) for one and C) for two.
Explanation:
Run off is when water runs of of things into lakes oceans etc.
So with number two it would be C because not even 3% of our water is fresh.
Represent a vector of 100 N in North-East direction
Answer:
N 100N E
Explanation:
Check image uploaded for the solution
Vittorio needs to clean the dusty mirror hanging on the wall beforehe can use it, but he would like to clean as little of the mirroras possible.
Vittorio would like to be able to see the logo on his shirt.Draw the incident and reflected raysshowing the light from the logo reflecting off the mirror into hiseyes. The rays should meet at the point on the mirror that needscleaning.
Answer:
The drawing is attached below.
Explanation:
According to the drawing, we can see that the point "0" marked on the mirror, is the point that allows the formation of an angle between Vittorio's eyes and the place where his shirt logo is. In summary, the point on the mirror that needs to be cleaned, so that Vittorio can see only the logo of his shirt, is the point that represents equal vertical distances between Vittorio's eyes and the shirt's logo, since these distances present the same angle.
If you have two substances, one with a density of 2.0 g/cm3 and one with a density of 1.3 g/cm3 and you combined them, which one would float on top
other and why?
Explanation:
Assuming the substances are fluids that do not mix, the lighter substance (ρ = 1.3 g/cm³) will float on top of the heavier substance (ρ = 2.0 g/cm³). This is due to Archimedes' Principle, which explains buoyancy.
in a closed energy system, energy is?
Answer:
Explanation:
A closed system can exchange energy but not matter, with its surroundings. An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.
Hope this helped you!
For each statement about the nuclear force select True or False. In nuclei, it is stronger than the Coulomb force. It acts between a proton and an electron. Its strength goes as 1/distance2, like gravity. It acts between a proton and a neutron. It acts between an electron and a neutron. It acts between two neutrons and also between two protons.
Answer:
a) True. The Strong interaction is the strong Coulomb force
e) True. It acts between protons, neutrons and between a proton and a neutron
Explanation:
In this exercise you must answer if there are some statements about the nuclei, let's write some of their characteristics
* at the core there is an attractive force called Strong Interaction
* This interaction acts on protons and neutrons alike
* There is a Coulombian-type repulsive force that acts between protons.
Let's review the claims
a) True. The Strong interaction is the strong Coulomb force
b) False. It acts on the elements of the nucleus and here there are no electrons
c) False. It is much greater than gravity and generally described by an exponential
d) False. It acts between components of the nucleus and here there are no electrons
e) True. It acts between protons, neutrons and between a proton and a neutron
If, while standing on the bank of a stream, you wished to spear a fish swimming in the water out in front of you, would you aim above, below, or directly at the observed fish to make a direct hit? If you decided to instead zap the fish with a laser, would you aim above, below, or directly at the observed fish? Defend your answers.
Answer:
a) below the observed position
b) directly at the observed position
Explanation:
If I'm standing on the bank of a stream, and I wish to spear a fish swimming in the water out in front of me, I would aim below the observed fish to make a direct hit. This is because the phenomenon of refraction of light in water causes the light coming from the fish is refract away from the normal as it passes into the air and into my eyes.
If I'm to zap the fish with a taser, I would aim directly at the observed fish because the laser (a form of concentrated light waves) will refract into the water, taking the same path the light from the fish took to get to my eyes.
Multiply the number 4.48E-8 by 5.2E-4 using Google. What is the correct answer in scientific notation?
Answer:
[tex]2.32\times 10^{-11}[/tex]
Explanation:
First number is [tex]4.48\times 10^{-8}[/tex]
Second number is [tex]5.2\times 10^{-4}[/tex]
We need to multiply the two numbers.
[tex]4.48\times 10^{-8}\times 5.2\times 10^{-4}=(4.48\times 5.2)\times 10^{(-8-4)}\\\\=23.296\times 10^{-12}[/tex]
In scientific notation : [tex]2.32\times 10^{-11}[/tex]
Hence, this is the required solution.
If we ignore air resistance, a falling body will fall 16t2 feet in t seconds. What is the average velocity between t
Answer:
262.4 m/s
Explanation:
The complete question is
If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.
The distance fallen s = 16t^2
The velocity v = [tex]\frac{ds}{dt}[/tex] = 32t
If we substitute the values of t into the velocity v, we'll have
at t = 8 s, V1 = 32 x 8 = 256 m/s
at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s
Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = 262.4 m/s
What is the best use of an atomic model to explain the charge of the particles in Thomson’s beams?
Answer:
The interpretation of the subject in question is characterized in the discussion section below.
Explanation:
The atom seems to be the smallest particle of negatively charged electrons as well as positive. The negative particulates are comparatively small, as well as distant from both the considerably high beneficial particles. When the negative objects traveled away from the desired ones those who formed an intangible beam which was electrically charged.Thomson would use a closed glass globe with just a single positive and another negative electrode with extraordinarily low present pressure. He was forced to submit those other gases to quite a voltage level, and also that the rise in popularity of emission levels, which have been called cathode rays, must have been observed.As the negatives shifted away from those in the positives, an imaginary electrically conductive beam was formed. Not only that but the negative particles have been completely circumvented due to the extreme distance seen between positively and negatively particle size.Which describes the correct procedure when converting a number from scientific notation to standard notation if the
power of 10 is -107
Answer:
When we have a number in scientific notation like:
Ax10^n.
If n is positive, we need to add n zeros to the right of the value of A (before the decimal point)
Now, if n is negative, we need to add the decimal point n times to the left.
When we do not have any more digits in A to move the decimal point, we start to add zeros.
So for example, if we have:
7.42x10^-5
we move the decimal point 5 times to the left.
7.42x10^-5 = 0.742x10^-4 = 0.0742x10^-3 = 0.00742x10^-2
= 0.000742x10^-1 = 0.0000742.
So if we have n = -107
We move the decimal point to the left until we run out of digits in the number A, after that point, we start adding zeros in between the digits of A and the decimal point, until the number of times we moved the decimal point plus the number of zeros that we added is equal to 107.
If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.
Answer:
The radius is [tex]R = 0.22 5 \ m[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 61 \ A[/tex]
The magnetic field is [tex]B = 1.70 *10^{-4} \ T[/tex]
Generally the magnetic field produced by a current carrying conductor is mathematically represented as
[tex]B = \frac{\mu_o * I}{2 * R }[/tex]
=> [tex]R = \frac{\mu_o * I }{ 2 * B }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]R = \frac{ 4\pi * 10^{-7} * 61 }{ 2 * 1.70 *10^{-4} }[/tex]
=> [tex]R = 0.22 5 \ m[/tex]
a telescope is oriting on a spacecraft aroudn the earth. Speed of 3.25 x 10^5 mass 7500 kg. What is the de Broglie wavelength of the telescope. g
Answer:
2.72 x 10^-43 m
Explanation:
mass of the telescope = 7500 kg
speed of the telescope = 3.25 x 10^5 m/s
de Broglie's wavelength of the telescope is given as
λ = h/mv
where
λ is the wavelength of the telescope
h is the plank's constant = 6.63 × 10-34 m^2 kg/s
m is the mass of the telescope = 7500 kg
v is speed of the telescope = 3.25 x 10^5 m/s
substituting value, we have
λ = (6.63 × 10-34)/(7500 x 3.25 x 10^5)
λ = 2.72 x 10^-43 m
PLEASE HELP WITH PHYSICS HOMEWORK ASAP