Suppose a current of is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:

A dam: 3

solar cells: 2

food: 1

a rocket: 1

Answer:

1: yes

Explanation:

Answer:

Explanation:

N₂ (g ) + 4H⁺( aq ) + 4e⁻ = N₂H₄ ( aq )

H⁺ ion comes from acidic medium . 4 positive charge on proton is balanced by 4 electron to make left hand side neutral because right hand side is neutral .

Answer:

C. average transnational kinetic energy of the particles in an object.

Explanation:

Answer:

that they all dissolved went on watef

Answer:In ionic compounds, electrons are transferred between atoms of different elements to form ions. But this is not the only way that compounds can be formed. Atoms can also make chemical bonds by sharing electrons equally between each other. Such bonds are called covalent bonds. Covalent bonds are formed between two atoms when both have similar tendencies to attract electrons to themselves (i.e., when both atoms have identical or fairly similar ionization energies and electron affinities). For example, two hydrogen atoms bond covalently to form an H2 molecule; each hydrogen atom in the H2 molecule has two electrons stabilizing it, giving each atom the same number of valence electrons as the noble gas He.

Compounds that contain covalent bonds exhibit different physical properties than ionic compounds. Because the attraction between molecules, which are electrically neutral, is weaker than that between electrically charged ions, covalent compounds generally have much lower melting and boiling points than ionic compounds. In fact, many covalent compounds are liquids or gases at room temperature, and, in their solid states, they are typically much softer than ionic solids. Furthermore, whereas ionic compounds are good conductors of electricity when dissolved in water, most covalent compounds are insoluble in water; since they are electrically neutral, they are poor conductors of electricity in any state.

Answer:

The answer is CH4<CH3OCH3<CH4O<CaCO3

Explanation:

The order of the lowest to highest normal boiling point:

H₂ < O₂ < H₂CO₃ < H₂O < CaO

The boiling point is the temperature at which the vapor pressure of the liquid becomes equal to the atmospheric pressure.  At this temperature, the liquid phase is changed into a vapor phase.

The boiling point is the temperature point at which the material transforms into the gas phase in the liquid phase. The Celsius scale was created on the basis of the ice or water melting point and the liquid water or vapor boiling point. Each substance consists its own boiling point.

The boiling point of Calcium oxide is 2850° C as it has a strong force of attraction between the ions. The boiling point of water as we already know is equal to 100° C.

The boiling point of the oxygen gas is -183°C and the boiling point of the hydrogen gas is  - 252.8°C.  The boiling point of carbonic acid is 333.6°C.

Therefore, CaO has the highest, and hydrogen gas has the lowest normal boiling point among the given compounds.

Learn more about Boiling point, here
https://brainly.com/question/2153588

#SPJ6

Answer:

Yes, because it match the octet rule!!

It is double bond lewis structure of ch2s!!

Explanation:

Answer:

1. Mn = +7

2. S = +4

3. C = +4

4. P = +4

5. O = -1

Explanation:

The oxidation number of each element in a compound is as follows:

1. Mn in KMnO4

KMnO4 = 0

Where; K = +1, O = -2, Mn = x

+1 + x -2(4) = 0

1 + x - 8 = 0

x - 7 = 0

x = +7

2. S in SO2

SO2 = 0

Where; S = x, O = -2

x + -2(2) = 0

x - 4 = 0

x = +4

3. C in COCl2

COCl2 = 0

Where; C = x, O = -2, Cl = -1

x + -2 + -1(2) = 0

x + -2 + -2 = 0

x -2 - 2 = 0

x - 4 = 0

x = +4

4. P in PF4

PF4 = 0

Where; P = x, F = -1

x + -1 (4) = 0

x - 4 = 0

x = +4

5. O in K2O2

K2O2 = 0

Where; K = +1, O = x

+1(2) + x(2) = 0

2 + 2x = 0

-2x = 2

x = -1

Answer:

it is the one below that. NO, because it debt net the octet rule

Answer:

V = 296.6 liters of oxygen.

Explanation:

The reaction of combustion of sulfur is:

O₂(g) + S(s) → SO₂(g)        (1)

To find the volume of the oxygen we need to use the Ideal Gas Law:

[tex] V = \frac{n_{O}RT}{P} [/tex]   (2)

Where:

V: is the volume

[tex]n_{O}[/tex]: is the number of moles of oxygen

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 273 K (at STP)

P: is the pressure = 1 atm (at STP)

So we need to find the number of moles of oxygen that reacts with sulfur:

[tex]n_{S} = \frac{m}{M}[/tex]

Where:

[tex]n_{S}[/tex]: is the number of moles of sulfur

m: is the mass of sulfur = 425 g

M: is the molar mass of sulfur = 32.065 g/mol                                                                            

[tex]n_{S}=\frac{m}{M} =\frac{425 g}{32.065 g/mol} = 13.25 moles[/tex]

From reaction (1) we have that 1 mol of O₂ reacts with 1 mol of S, hence the number of moles of oxygen is:

[tex] n_{S} = n_{O} = 13.25 moles [/tex]  

Finally, the volume of oxygen is (equation (2)):

[tex]V = \frac{13.25 moles*0.082 L*atm/(K*mol)*273 K}{1 atm} = 296.6 L[/tex]

Therefore, are necessary 296.6 liters of oxygen for the combustion of sulfur.

I hope it helps you!

Answer:

Extinction

Explanation:

When a species becomes extinct, every last specimen has died out

Answer:

Female

Explanation:

Answer: A. Female.

Explanation: The word 'heroine' means a female or a woman that is admired and looked upon for her courage, bravery, and noble qualities.

Answer:

Second element(Titanium); [Ar] 3d2 4s2

Third element(Vanadium):Ar 3d3 4s2

Explanation:

Given that there are only three d orbitals in universe L instead of five, the electronic configuration of the second and third elements in the first transition series will now look thus;

Second element(Titanium); [Ar] 3d2 4s2

Third transition element(Vanadium):Ar 3d3 4s2

Hence, the electronic configuration of Titanium and Vanadium in universe L is just the same as what it is on earth.

Answer:

He or She used the wrong table of bond energies

Explanation:

We know that we obtain the energy of a reaction also known as the enthalpy of reaction from the formula; ΔHo(reaction) = sum of the bond energies of bonds being broken - sum of the bond energies of the bonds being formed.

Combustion is an exothermic reaction for which the value of ΔH is expected to the negative. If ΔH is not negative, then the calculation was not properly done and the wrong values of bond energy were probably used.

Answer:

He or she may have subtracted the bond energies for the reactants from the products.

Explanation:

The unknown substance : Lead

Given

Density of element

mass of unknown substance = 40 g

volume = 3.5 cm³

Required

The density of unknown substance

Solution

Density is the ratio of mass per unit volume  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]

Input the value to find the density of an unknown substance :

ρ = 40 g : 3.5 cm³

ρ = 11.43 g/cm³

If we look at the table, the substance which has a density of 11.43 is Lead

How does the environment play an important role in creating petrified fossils?

The right conditions need to be present in order for fossilization to occur.

Drier environments, such as land, are more susceptible to the effects of erosion and so it is more difficult to preserve the organism before it decays.

Answer:

[tex]\rm C_4 H_8[/tex].

Explanation:

Look up the relative atomic mass of [tex]\rm C[/tex], [tex]\rm H[/tex], and [tex]\rm O[/tex] on a modern periodic table:

Calculate the molecular mass of [tex]\rm CO_2[/tex] and [tex]\rm H_2O[/tex]:

[tex]M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}[/tex];

[tex]M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}[/tex].

Given the mass [tex]m[/tex] of [tex]\rm CO_2[/tex] and [tex]\rm H_2O[/tex] produced, calculate the number of moles of molecules that were produced:

[tex]\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO_2})} \approx 0.80\; \rm mol[/tex];

[tex]\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \approx 0.80\; \rm mol[/tex].

Calculate the number of moles of [tex]\rm C[/tex] atoms and [tex]\rm H[/tex] atoms in these [tex]\rm CO_2[/tex] and [tex]\rm H_2O[/tex] molecules.

The combustion reaction here include two reactants: the hydrocarbon and [tex]\rm O_2[/tex].

As the name suggests, hydrocarbons contain only [tex]\rm C[/tex] atoms and [tex]\rm H[/tex] atoms. On the other hand, [tex]\rm O_2[/tex] contains only [tex]\rm O[/tex] atoms.

Therefore, all the [tex]\rm C[/tex] and [tex]\rm H[/tex] atoms in those [tex]\rm CO_2[/tex] and [tex]\rm H_2O[/tex] molecules are from the unknown hydrocarbon. (With a similar logic, all the [tex]\rm O[/tex] atoms in those combustion products are from [tex]\rm O_2[/tex].)

In other words, that [tex]0.20\; \rm mol[/tex] of this unknown hydrocarbon molecules contains:

Hence, each of these hydrocarbon molecules would contain [tex](0.80\; \rm mol) / (0.20\; \rm mol) = 4[/tex] carbon atoms and [tex](1.60\; \rm mol) / (0.20\; \rm mol) = 8[/tex] hydrogen atoms.

The molecular formula of this hydrocarbon would be [tex]\rm C_{4} H_{8}[/tex].

Answer :

B. Most wind erosion happens in deserts, beaches, and plowed fields.

Answer: [tex]\Delta H^{0} = -879.15 kJ/mol[/tex]

Explanation: Heats of formation is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

Standard Enthalpy Change is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

[tex]\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}[/tex]

For the reaction

   2NH₃   +      3N₂O   →      4N₂    +     3H₂O

2(-46.2)   +     3(82.05)      4(0)    +    3(-241.8)

[tex]\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)][/tex]

[tex]\Delta H^{0}=-725.4-153.75[/tex]

[tex]\Delta H^{0}=-879.15[/tex]

The standard enthalpy change for the reaction is [tex]\Delta H^{0}=-879.15[/tex] kJ

Answer:

D

Explanation:

Human activities that contribute to desertification include the expansion and intensive use of agricultural lands, poor irrigation practices, deforestation, and overgrazing. ... Some meteorologists and soil scientists measure the impacts and length of a drought to determine if it is an example of desertification.

Answer:

S (sulphur)

Explanation:

In a neutral atom, the number of electrons and the number of protons in an element are equal. These numbers are called the ATOMIC NUMBER. That is, in a neutral atom;

proton no. = electron no. = Atomic no.

Hence, in this case where phosphorus atom has an electron number of 15. It means that there are 15 protons and 15 electrons in a phosphorus atom. If one electron is added to these electrons i.e. 15 +1, there will be 16 electrons in the atom, hence, this atom becomes SULPHUR element, which has 16 electrons in its atom, with chemical symbol S.

Answer:

8 electrons

Explanation:

Number of atoms = 128

Half life = 15 s

After each half life, the number of atoms reduces by half. So we need to determine how many half lives are in 60s.

Number of half lives = 60s / 15s = 4

After the first life;

Number of electrons left = 128 / 2 = 64

After the second life;

Number of electrons left = 64 / 2 = 32

After the third half life;

Number of electrons left = 32 / 2 = 16

After the fourth half life;

Number of electrons left = 16 / 2 = 8

Answer:

C. 8

Explanation:

correct on gizmo; After one half-life (15 seconds), about 64 radioactive atoms will remain, half of the original 128. After a second half-life passes (30 seconds total), about 32 radioactive atoms will remain, half of 64. After a third half-life passes (45 seconds), about 16 radioactive atoms will remain. A time of 60 seconds represents four half-lives, so about 8 radioactive atoms will remain.

This question is incomplete, the complete question is;

Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the following steps in the correct order;

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

Answer:

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.  

Explanation:  

First of all, We use a suction device to suck up liquid into pipet. Then we will fill the pipet up to the 10 mL marks and will discard the initial two volumes of liquid and will take a final third volume. We will replace the bulb with index finger and will drain it by placing the tip of pipet at the wall of beaker and drain the liquid.

Arranged in the following steps correctly;

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

Answer:

b. Heat flows from the surroundings to the system and the temperature of the water decreases.

Explanation:

The laws of thermodynamics lets us know that energy is neither created nor destroyed but can be converted from one form to another. Also, energy transfer does accompany chemical reactions in the form of heat.

For an endothermic reaction, heat is absorbed by the system from the surroundings. This leads to a drop in the temperature of the surroundings as energy is removed.

This implies that the water temperature decreases.