This question is incomplete, the complete question is;
Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the following steps in the correct order;
- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.
- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.
- Transfer the pipette to the receiving vessel.
- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.
- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.
- Suck up a third volume of liquid past the 10.00 ml calibration mark.
- Discard the first two pipette volumes of the liquid to rinse the pipette.
Answer:
- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.
- Discard the first two pipette volumes of the liquid to rinse the pipette.
- Suck up a third volume of liquid past the 10.00 ml calibration mark.
- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.
- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.
- Transfer the pipette to the receiving vessel.
- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.
Explanation:
First of all, We use a suction device to suck up liquid into pipet. Then we will fill the pipet up to the 10 mL marks and will discard the initial two volumes of liquid and will take a final third volume. We will replace the bulb with index finger and will drain it by placing the tip of pipet at the wall of beaker and drain the liquid.
Arranged in the following steps correctly;
- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.
- Discard the first two pipette volumes of the liquid to rinse the pipette.
- Suck up a third volume of liquid past the 10.00 ml calibration mark.
- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.
- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.
- Transfer the pipette to the receiving vessel.
- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.
What can the flow of electrons be easily compared to?
a.The flow of mud
b.The flow of water
c.The flow of wind
d.The flow of gravity
A student adds 34.2 mL of water to 72.3 mL of a 7.50 M glucose solution. (i) Will this solution be concentrated or dilute
Answer:
The solution will be dilute
Explanation:
The concentration of a solution is defined as the ratio between an amount of solute (Glucose, in this case) and an amount of solvent (Water in this case).
As the student is adding some water (Solvent), the amount of solute per amount of solvent will decrease. That is, if the concentration decreases,
the solution will be dilute
HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED
Answer:
C₃H₄O₄
Explanation:
In order to get the empirical formula of a compound, we have to follow a series of steps.
Step 1: Divide the percent by mass of each element by its atomic mass.
C: 34.6/12.01 = 2.88
H: 3.9/1.01 = 3.86
O: 61.5/16.00 = 3.84
Step 2: Divide all the numbers by the smallest one, i.e., 2.88
C: 2.88/2.88 = 1
H: 3.86/2.88 ≈ 1.34
O: 3.84/2.88 ≈ 1.33
Step 3: Multiply all the numbers by a number that makes all of them integer
C: 1 × 3 = 3
H: 1.34 × 3 = 4
O: 1.33 × 3 = 4
The empirical formula is C₃H₄O₄.
3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic energy (they will at the same temperature), which molecules have the greatest average speed
Answer: Hydrogen molecules will have greatest average speed.
Explanation:
The formula for average speed is :
[tex]\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}[/tex]
R = gas constant
T = temperature
M = Molecular Mass
Now putting all the values:
[tex]\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}[/tex]
[tex]\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}[/tex]
[tex]\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8[/tex]
Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed
CONVERSIONS
Complete the following conversions
3. Given the following reaction, how many moles of Al2O3 will be produced if 1.35 moles of Fe are produced?
(8 points)
2 AI 3 Feo
3 Fe + Al2O3
+
it’s number 3 pls help
Answer:
Number of moles of Al₂O₃ = 0.45 mol
Explanation:
Given data:
Number of moles of Fe produced = 1.35 mol
Number of moles of Al₂O₃ = ?
Solution:
2Al + 3FeO → 3Fe + Al₂O₃
now we will compare the moles of iron and Al₂O₃
Fe : Al₂O₃
3 : 1
1.35 : 1/3×1.35 = 0.45 mol
What is meant by the term average mass
Answer:
Explanation:
The average atomic mass (sometimes called atomic weight) of an element is the weighted average mass of the atoms in a naturally occurring sample of the element. Average masses are generally expressed in unified atomic mass units (u), where 1 u is equal to exactly one-twelfth the mass of a neutral atom of carbon-12.
What is the mass in grams of 2.25 mol of the element iron, Fe?
126 g Fe
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
2.25 mol Fe
Step 2: Identify Conversions
Molar Mass of Fe - 55.85 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 2.25 \ mol \ Fe(\frac{55.85 \ g \ Fe}{1 \ mol \ Fe})[/tex]Multiply: [tex]\displaystyle 125.663 \ g \ Fe[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
125.663 g Fe ≈ 126 g Fe
mass
6.00 g of a certain compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 180. g/mol, is burned
completely in excess oxygen, and the mass of the products carefully measured:
product
carbon dioxide 8.80 g
3.60 g
Use this information to find the molecular formula of X.
water
alo
O
х
?
The molecular formula =C₆H₁₂O₆
Further explanationGiven
6.00 g of a certain compound X
The molecular molar mass of 180. g/mol
CO₂=8.8 g
H₂O=3.6 g
Required
The molecular formula
Solution
mass C in CO₂ :
= 1.12/44 x 8.8
= 2.4 g
mass H in H₂O :
= 2.1/18 x 3.6
= 0.4 g
Mass O in compound :
= 6-(2.4+0.4)
= 3.2 g
Mol ratio C : H : O
= 2.4/12 : 0.4/1 : 3.2/16
= 0.2 : 0.4 : 0.2
= 1 : 2 : 1
The empirical formula : CH₂O
(CH₂O)n=180 g/mol
(12+2+16)n=180
(30)n=180
n=6
(CH₂O)₆=C₆H₁₂O₆
Two electron(s) are removed from an carbon atom. Enter the chemical symbol of the element.
Answer:
[tex]C^{2+}[/tex]
Explanation:
When a proton is removed, it changes the whole element. However, when electrons are removed, it becomes an ion. Since we are removing two electrons, we are subtracting a negative number, giving us positive two as our net ionic charge. Therefore, the answer is [tex]C^{2+}[/tex]
Which characteristic is used to classify metamorphic rocks as foliated or non-foliated?
Answer: d. Arrangement of grains
Explanation:
Edge:)))
Suppose a current of 220.mA is passed through an electroplating cell with an aqueous solution of AgNO3 in the cathode compartment for 79.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer:
0.0195 g
Explanation:
Ag^+(aq) + e -------> Ag(s)
Since 1 electron was transferred, that means 96500C of electricity was required
108 g is deposited 96500 C
xg is deposited 220 × 10^-3 × 79.0
x = 108 × 220 × 10^-3 × 79.0/96500
x= 19.5 × 10^-3 g
x= 0.0195 g
What is the molar mass of CuCIO3
147.05 g/mol
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableExplanation:Step 1: Define
CuClO₃
Step 2: Find MM
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol
A homogeneous mixture is?
Answer:
two components of the same thing
Explanation:
Of the following, which most likely involves a chemical reaction?
NEED ASAP PLEASE
Select one:
a. Boiling water turns a fresh egg into a hard boiled egg.
b. Dissolving salt in water produces a transparent liquid.
c. A huge wave knocks down a beach home.
d. Wind turns a generator to produce electricity.
When does a chemical bond form between two atoms? Select one :
O a. When attractive forces are greater than repulsive forces.
O b. When potential energy is lowest for the pair.
O c. When potential energy is greatest for the pair .
O d. When repulsive forces are greater than attractive forces.
An aqueous solution of ethanol, CH3CH2OH, has a concentration of 5.82 mol/L and has a density of 0.957 g/mL. What are the mass percent and mole fraction of CH3CH2OH in this solution
Answer:
1. Mass percent of ethanol = 28.02 %.
2. Mole fraction of ethanol = 0.13.
Explanation:
1. To find the mass percent we need to use the following equation:
[tex]\%_{m/m} = \frac{m_{e}}{m_{s}} \times 100[/tex]
Where:
[tex]m_{e}[/tex] is the mass of ethanol
[tex]m_{s}[/tex] is the mass of the solution
We need to calculate the mass of ethanol and the mass of the solution:
[tex] d = \frac{m_{s}}{V} [/tex]
Where:
d: is the density of the solution = 0.957 g/mL
V: is the volume = 1 L
[tex] m_{s} = d*V = 0.957 \frac{g}{mL}*\frac{1000 mL}{1 L}*1 L = 957 g [/tex]
Now, from the concentration we can find the mass of ethanol:
[tex] C = \frac{n_{e}}{V} = \frac{m_{e}}{M_{e}*V} [/tex]
Where:
[tex]M_{e}[/tex]: is the molar mass of ethanol = 46.07 g/mol
[tex]n_{e}[/tex]: is the number of moles of ethanol = m/M
[tex] m_{e} = C*M*V = 5.82 \frac{mol}{L}*46.07 \frac{g}{mol}*1 L = 268.13 g [/tex]
Finally, the mass percent of ethanol is:
[tex]\%_{m/m} = \frac{268.13 g}{957 g} \times 100 = 28.02 \%[/tex]
2. The mole fraction of ethanol is given by:
[tex] \chi_{e} = \frac{n_{e}}{n_{s}} [/tex]
The number of moles of ethanol is:
[tex]n_{e} = \frac{m_{e}}{M_{e}} = \frac{268.13 g}{46.07 g/mol} = 5.82 moles[/tex]
And the moles of the solution is:
[tex] n_{s} = n_{e} + n_{w} [/tex]
Where w is for water
[tex] n_{s} = n_{e} + \frac{m_{w}}{M_{w}} [/tex]
[tex] n_{s} = n_{e} + \frac{m_{s} - m_{e}}{M_{w}} [/tex]
[tex]n_{s} = 5.82 moles + \frac{957 g - 268.13 g}{18 g/mol} = 44.09 moles[/tex]
Hence, the mole fraction of ethanol is:
[tex]\chi_{e} =\frac{5.82 moles}{44.09 moles}=0.13[/tex]
I hope it helps you!
17. Which of the following
hydrocarbon undergo addition
reaction:
С3Н6
С2Н6
ОООО
С3Н8
CH4
Answer:
С3Н6.
Explanation:
Hello!
In this case, since addition reactions imply that a radical or some radicals are added to the parent chain, we notice that only unsaturated hydrocarbons are able to undergo addition whereas saturated ones undergo substitution reactions as they already have all the carbon bonds bonded to leaving groups.
In such a way, we can rule out C2H6, C3H8 and CH4 as they are all alkanes; therefore, only С3Н6 is able to undergo an addition reaction due to the C=C which is able to lose one of those bonds and allow an incoming radical to get included into the parent chain.
Best regards!
6.How many molecules of carbon dioxide are in 400 grams of the substance?
Answer: 5.47x10^24 molecules
Explanation:
6.02214076x10^23 molecules CO2 = 44g
400g = (400/44)*6.02214076*10^23 = 5.47x10^24
According to the concept of Avogadro's number, there are 54.75 ×10²³ molecules of carbon dioxide are 400 grams of the substance.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number .Number of moles= 400/44=9.09 moles which is number of molecules =9.09×6.023×10²³= 54.75 ×10²³ .
Learn more about Avogadro's number,here:
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How many moles are in 60.0 grams of water?
3.33 mol H₂O
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
60.0 g H₂O (Water)
Step 2: Identify Conversions
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 60.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})[/tex]Multiply: [tex]\displaystyle 3.32963 \ mol \ H_2O[/tex]Step 4: Convert
Follow sig fig rules and round. We are given 3 sig figs.
3.32963 mol H₂O ≈ 3.33 mol H₂O
Complete combustion of 3.10 g of a hydrocarbon produced 9.90 g of CO2 and 3.55 g of H2O. What is the empirical formula for the hydrocarbon
Answer: C9H16
Explanation:
molar mass C = 12.011, H = 1.008, O = 15.999, CO2 = 44.01, H2O = 18.00
9.9g CO2 = 0.225 mol, 3.55 g H2O = 0.200 mol
long way
molecules CO2 = 1.355x10^23 —> atoms of C
molecules H2O = 1.204x10^23 —> molecules H2
C:H2 = 1.355/1.204 = 1.125. —> C9H16
short way
molar massesCO2:H2O = 0.225:0.2 = 9:8
–> C9H16
verify
molar mass C9H16 =124
3.1g = 0.025 mol
oxidise C9H16 + 13O2 —> 9CO2 + 8H2O
0.025 mol + 13*0.025 mol (0.35mol) —> 9*0.025 + 8*0.025 —> 0.0.225 + 0.2
which type of organism carries out cellular respiration
Answer:Prokaryotic cells carry out cellular respiration within the cytoplasm and eukaryotic cells carry out respiration in the mitochondria
Explanation:
A sample of 25.0 mL of 0.120 M Ca(OH)2(aq) is titrated with 0.150 M HCl(aq). What volume of HCl(aq) is needed to completely neutralize the Ca(OH)2(aq)
Answer:
[tex]V_{HCl}=48.0 mL[/tex]
Explanation:
Hello!
In this case, since the reaction between calcium hydroxide and hydrochloric acid shows a 2:1 mole ratio between them:
[tex]2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O[/tex]
We need to use the following mole ratio:
[tex]2n_{Ca(OH)_2}=n_{HCl}[/tex]
That can be written in volumes and concentrations:
[tex]2M_{Ca(OH)_2}V_{Ca(OH)_2}=M_{HCl}V_{HCl}[/tex]
Thus, we solve for the volume of HCl as it is the unknown:
[tex]V_{HCl}=\frac{2M_{Ca(OH)_2}V_{Ca(OH)_2}}{M_{HCl}}[/tex]
Therefore, we plug in to obtain:
[tex]V_{HCl}=\frac{2*0.120M*25.0mL}{0.150M} \\\\V_{HCl}=48.0 mL[/tex]
Best regards!
Calculate the percentage of water in the compound CaSO4 x 6H2O
The percentage of water in the compound CaSO₄.6H₂O = 44.26%
Further explanationGiven
Compound CaSO₄. 6H₂O
Required
The percentage of water
Solution
MW CaSO₄. 6H₂O :
= 40 + 32 + 4.16 + 12.1 + 6.16
= 244
MW 6H2O :
= 12.1 + 6.16
= 108
%water = (108 : 244) x 100%
%water = 44.26
The percentage of water in the compound CaSO₄.6H₂O is 44.26%
Calculation of percentage:Since MW CaSO₄. 6H₂O :
= 40 + 32 + 4.16 + 12.1 + 6.16
= 244
Now
MW 6H2O :
= 12.1 + 6.16
= 108
So, percentage of water = (108 : 244) x 100%
= 44.26
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How many moles of calcium, Ca, are in 5.00 g of calcium?
0.125 mol Ca
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
5.00 g Ca
Step 2: Identify Conversions
Molar mass of Ca - 40.08 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 5.00 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})[/tex]Multiply: [tex]\displaystyle 0.12475 \ mol \ Ca[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.12475 mol Ca ≈ 0.125 mol Ca
Write out an example of a single replacement reaction involving silver and zinc.
Answer:
whats zinc?
Explanation:
What is the mass, in grams, of 0.0490 mol of iron(III) phosphate
Answer:
m = 7.39 g.
Explanation:
Hello!
In this case, since the molar mass of iron (III) phosphate is 150.82 g/mol based on its molecular formula (FePO₄), we can compute the mass in grams of 0.0490 moles of this compound by setting up the following dimensional analysis:
[tex]m=0.0490mol*\frac{150.82g}{1mol} \\\\m=7.39 g[/tex]
Best regards!
HELP ME SLOVE RN IT IS FOR CHEM
Answer:
NARUTOOOO
Explanation:
The frequency of the stretching vibration of a bond in IR spectroscopy depends on what two quantities?
Answer:
Strength of the bond
Masses of the bonded atoms.
Explanation:
The lack of such groups means that they are not endogenous in the concentrate. 1. A bond's spreading frequency relies on the frequency of the bond and the concentrations of the atoms that are bonded.
Salad oil floats on water. Water has a density of 1.0 g/cm3. What can you say about the density of the salad oil?
Answer:
Density of the oil is lesser than that of the water
Explanation:
The density of water is given as 1.0g/cm³.
Salad oil is found to float on water, this implies that the density of this salad oil is lesser than that of the water.
When the density of a substance is greater than another, it will sink. If the density of the salad oil is greater than that of water, then it will sink and not float. Since the oil floats on water, the density of the oil is lesser than that of the water.Density is the mass per unit volume of a substance.
the system that acts as a barrier from the outside the environment is called________
The air barrier system