Answer:
3.48 atm
Explanation:
The first step is to determine the number moles of sulfuric acid. To do this find the molar mass of sulfuric acid.
Molar Mass of H2SO4 = (1 g/mol*2) + (32 g/mol) + (16 g/mol * 4) = 98 g/mol
Then divide the mass of sulfuric acid by the molar mass of the sulfuric acid to get the number of moles of sulfuric acid.
(10 g)/(98 g/mol) = 0.10204 mol
Then use the molar ratios to determine the moles of gas produced. In this case all of the ratios are 1 to 1 meaning that 0.10204 mol of H2SO4 produces 0.10204 mol of H2O and 0.10204 mol of SO3. That means that 0.2041 moles of gas are produced as a result of the reaction.
The next thing to do is to convert the temperature to Kelvin since gas equations need Kelvin. To do this add 273.15.
350 degrees C + 273 = 623.15 K
Now the PV=nRT can be used and when solving for pressure the equation can be written P=nRT/V.
P = pressure and is the unknown
V = volume and is 3.00 L
n = moles of gas and is 0.2041 mol
R = gas constant and is 0.08205 L atm/mol K
T = temperature and is 623.15 K
P = (0.2041 mol * 0.08205 L atm/mol K * 623.15 K) / 3.00 L
P = 3.4785 atm which is 3.48 atm when rounded to three significant figures
I hope this helps. Let me know if anything is unclear.
The total pressure of the container has been 3.48 atm.
In the decomposition of 10 grams of sulfuric acid, the moles of sulfuric acid has been:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of sulfuric acid = [tex]\rm \dfrac{10\;g}{98\;g/mol}[/tex]
Moles of sulfuric acid = 0.1024 moles.
The balanced chemical equation for the reaction results in the formation of 1 mole of water and 1 mole of [tex]\rm SO_3[/tex]. Thus, the decomposition of 1 mole of gas produces 2 moles of the product.
The moles of the product by decomposition of 0.1024 moles of sulfuric acid has been:
1 mole sulfuric acid = 2 moles product
0.1024 moles sulfuric acid = 0.2048 moles product.
From the ideal gas equation:
PV = nRT
P = pressure
V = volume = 3 L
n = moles = 0.2048 moles
R = constant = 0.08205 L atm/mol K
T = temperature = 623.15 K
Substituting the values:
Pressure × 3 L = 0.2048 mol × 0.08205 L atm/mol K × 623.15 K
Pressure = 3.4785 atm.
The pressure of the system has been 3.48 atm.
For more information about the pressure of the system, refer to the link:
https://brainly.com/question/908756
What do all living things need to survive?
Answer:
air,water,and food.
Explanation:
Some animals need to obtain their energy from plants.
The energy produced when nucleons fuse together is called the: Select the correct answer below:
a. strong nuclear force
b. nuclear fusion energy
c. nuclear binding energy
d. none of the above
Answer:
Option C (nuclear binding energy) is the appropriate choice.
Explanation:
At either the nuclear scale, the nuclear binding energy seems to be the energy needed to remove and replace a structure of the atom itself into the characterize elements (to counteract the intense nuclear arsenal). Nuclear warheads (bargaining power) bind everything together neutrons as well as protons within an elementary particle.Some other options in question aren't relevant to the particular instance. So that the option preceding will also be the right one.
How is safety achieved during scientific investigations?
Answer investment
Explanation: you have to have saftey while you still do science
What is the empirical formula of a hydrocarbon if complete combustion or 2.900 mg of the hydrocarbon produced 9.803 mg of CO2 and 2.006 mg of H2O? Be sure to write C first in the formula.
Answer:
The empirical formula of the hydrocarbon is CH.
Explanation:
The following data were obtained from the question:
Mass of hydrocarbon = 2.9 mg
Mass of CO2 = 9.803 mg
Mass of H2O = 2.006 mg
Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.
This is illustrated below:
Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol
Mass of CO2 = 9.803 mg
Mass of C in the compound =?
Mass of C in the compound =
12/44 x 9.803
= 2.674 mg
Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O = 2.006 mg
Mass of H in the compound =
2/18 x 2.006
= 0.223 mg
Finally, we shall determine the empirical formula of the hydrocarbon as follow:
Carbon (C) = 2.674 mg
Hydrogen (H) = 0.223 mg
Divide by their molar mass
C = 2.674 /12 = 0.223
H = 0.223 / 1 = 0.223
Divide both side by the the smallest
C = 0.223/0.223 = 1
H = 0.223/0.223 = 1
Therefore, the empirical formula of the hydrocarbon is CH.
Calculate the MASS if the density is 2.34 g/mL and the volume is 12.50 mL.
Answer:
mass = 29.25 gExplanation:
The denisty of a substance can be found by using the formula
[tex]Density = \frac{mass}{volume} [/tex]
Making mass the subject we have
mass = Density × volumeFrom the question
Density = 2.34 g/mL
volume = 12.50 mL
Substitute the values into the above formula and solve for the mass
That's
mass = 2.34 × 12.50
We have the final answer as
mass = 29.25 gHope this helps you
what subatomic particles are found in the nucleus of an atom
Answer:
Explanation:
The subatomic particles of protons and neutrons are found in the nucleus of an atom. Protons are particles with a positive charge, while neutrons have no charge. Electrons, which have a negative charge, are particles that can found orbiting outside the nucleus of an atom.
Answer: protons and neutrons
Explanation:
If you add enzyme to a solution containing only the product(s) of a reaction, would you expect any substrate to form?
a. Yes, because the enzyme reduces the standard free energy change for the reaction.
b. No, because the enzyme lowers the transition state energy barrier.
c. No, because product inhibits the enzyme.
d. No, because enzymes catalyze only the forward reaction.
e. Yes, because the reaction proceeds backwards until equilibrium is reached.
Answer:
e
Explanation:
Provided the reaction that leads to the formation of the products can proceed in both forward and backward directions, the correct answer would be yes because the reaction will proceed backward until equilibrium is reached.
For a reaction that can proceed both forward and backward, the addition of a catalyst increases the rate of reaction in both directions based on the fact that a catalyst cannot alter the equilibrium of a reaction.
Hence, if an enzyme is added to the product of a reaction that has the potential to proceed in both forward and reverse reactions, a substrate would be expected to form because the reaction will proceed backward until an equilibrium is reached.
The correct option is e.
A student measures the molar solubility of iron(II) carbonate, FeCO3, in a water solution to be 6.06 × 10-6 M. Based on her data, the solubility product constant for this compound is:______.
a. 8.90 × 10-27
b. 1.21 × 10-5
c. 3.67 × 10-11
d. 1.06 ×10-25
e. 8.17 × 10-27
Answer:
The correct answer is c. 3.67 × 10⁻¹¹
Explanation:
The dissociation equilibrium and ICE table for FeCO₃ is the following:
FeCO₃ (s) ⇄ Fe²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +s +s
E s s
At equilibrium, the solubility product contant (Ksp) expression will be:
Ksp= [Fe²⁺] x [CO₃²⁻]= s x s = s²
Given: s= 6.06 x 10⁻⁶ M, we calculate Ksp as follows:
Ksp= s²= (6.06 x 10⁻⁶ M)²= 3.67 x 10⁻¹¹
Thus, from the given options the correct is c. 3.67 × 10⁻¹¹
write the name of this structure
Answer:
The name of the compound is:
4–bromo–5,5–dichloro–hex–3–ene–1–yne
Explanation:
To the above compound, we simply do the following:
1. Identify the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached.
4. Give the substituents the lowest possible count alphabetically.
5. Combine the above to obtain the name of the compound.
Now, we shall determine the name of the compound as follow:
1. The compound has carbon to carbon triple bond (C≡C) yne and carbon to carbon double bond (C=C) ene.
2. The longest continuous carbon chain is 6 i.e hexane.
3. The substituents group attached are:
i. Bromine (bromo), Br
ii. Chlorine (Chloro), Cl
4. In counting, ene comes before yne. But in this case, ene assumes same position from either side, So we shall consider counting from the side that gives yne the lowest count. Thus, ene is at carbon 3 and yne is at carbon 1. Therefore,
i. Bromo, Br is at carbon 4.
ii. Chloro, Cl appears twice and both are at carbon 5.
5. The name of the compound is:
4–bromo–5,5–dichloro–hex–3–ene–1–yne.