I WILL GIVE BRAINLIEST!!!! Your friend stands on the roof of her house, which is 12.2 m off the ground, and kicks a soccer ball to you so that it is initially moving horizontally at 13.9 m/s. What is its speed as it hits the ground? The time is 1.58 seconds.

Answers

Answer 1

Answer:

16.74 m/s

Explanation:

From the question, the parameters given are:

Height h = 12.2 metres

Initial velocity U = 13.9 m/s

Time t = 1.58 s

The range or distance covered by the ball will be

R = u^2/g

Where g = 9.8 m/s^2

R = 13.9^2/9.8

R = 193.21/9.8

R = 19.72 m

Let first calculate the acceleration by using the formula below

R = Ut + 1/2at^2

Substitute all the parameters into the formula

19.72 = 13.9 × 1.58 - 1/2 × a × 1.58^2

19.72 = 21.962 - 1.2482a

Collect the like terms

-1.2482a = 19.72 - 21.962

- 1.2482a = - 2.242

a = 2.242/1.2482

a = 1.796 m/s^2

Using equation 1 to find the final speed

V = U + at

V = 13.9 + 1.796 × 1.58

V = 13.9 + 2.838

V = 16.74 m/s

Therefore, it hit the ground at speed 16.74 m/s


Related Questions

An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25 x 104 J of work to drive the motion of the train. What is the total energy that needs to be put into the engine.

Answers

Answer:

Only about 12%–30% of the energy from the fuel you put in a conventional vehicle is used to move it down the road, depending on the drive cycle. The rest of the energy is lost to engine and driveline inefficiencies or used to power accessories. Therefore, the potential to improve fuel efficiency with advanced technologies is enormous.

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?

Answers

Answer:

on the body of the container of the chemical and it also on the shelf where the chemical is kept in the laboratory.

Explanation:

The information on the chemical and physical properties of a specific chemical should  be located on the body of the container of the chemical. when storing chemicals in a laboratory the properties, both chemical and physical properties of the chemical should be written out and pasted on the body of the container that contains the chemicals.and also o the shelf where the chemical is kept in the laboratory or workplace .

4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
a) What is their speed during that run?
b) What is their velocity?
I
c) If they kept running at that velocity for another 1.3 seconds, what would their
final position be?

Answers

Answer:

(a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

Explanation:

Given that,

A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.

Suppose, the distance between 40 yard line and 25 yard line is 20 yard.

(a). We need to calculate their speed during that run

Using formula of speed

[tex]v=\dfrac{d}{t}[/tex]

Where. d = distance

t = time

Put the value into the formula

[tex]v=\dfrac{18.288}{2}[/tex]

[tex]v=10\ m/s[/tex]during that run

(b). We need to calculate their velocity

Using formula of speed

[tex]v=\dfrac{\Delta d}{\Delta t}[/tex]

Put the value into the formula

[tex]v=\dfrac{22.86-36.58}{2}[/tex]

[tex]v=-6.86\ m/s[/tex]

Negative sign shows the direction of motion.

(c). If they kept running at that velocity for another 1.3 seconds,

We need to calculate the final position

Using formula of position

[tex]d=vt[/tex]

Put the value into the formula

[tex]d=6.86\times1.3[/tex]

[tex]d=8.91\ m[/tex]

Hence, (a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

HELP PLEASE !!!!!!! If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball? The gravitational force is greater than the drag. The net force on the ball is zero. The drag is greater than the gravitational force. The net force on the ball is directed upward.
physics

Answers

Answer:

A. The gravitational force is greater than the drag.

Explanation:

Remember that the second Newton's law says that:

F = m*A

Force equals mass times acceleration.

With this we will see that the correct option is:

"The gravitational force is greater than the drag."

We know that the ball is accelerating downwards, and there is no horizontal motion. Because the acceleration is downwards, we know that the net force must be downwards (for the second law).

Now, what must be true about the net forces acting on the ball? let's analyze each statement:

1) "The gravitational force is greater than the drag."

The gravitational force is what causes the objects to fall down to the ground, so if the ball is falling, this will always be true.

2) " The net force on the ball is zero."

We know that the ball is accelerating, thus the net force can not be zero, this is false.

3) "The drag is greater than the gravitational force. "

This is the opposite to the first option, this is false.

4) "The net force on the ball is directed upward."

The acceleration and the net force have the same direction, if the ball is accelerating downwards, then the net force is directed downwards. This is false.

Then the only true statement is the first one:

"The gravitational force is greater than the drag."

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Dust particles fall down when a carpet or a piece of cloth is beaten by a stick,why?​

Answers

Dust particles fall down when we hit the carpet or a piece of cloth with a stick because it loses it inertia of rest and move forward, but dust particles fall down in absence of the carpet.

800 J of heat is needed to raise the temperature of 2 kg of iron by 1°C. What is the heat capacity of 3.6 kg of iron?​

Answers

Answer: 1440 J/kg/degree Celsius

Explanation:

Heat capacity = thermal energy required / change in heat

Two balls are released from the same height on the moon. They both reach the ground at the same time. Which statement is correct about the two balls

Answers

Answer:

same acceleration

Explanation:

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?

Answers

Answer:

Both

Explanation:

A box 5cm long, 4cm wide and 6cm high would have what volume? Show your work

Answers

Explanation:

volume= length×width×height

5cm×4cm×6cm = 20×6= 120cm³

A cell membrane has a thickness of about 7 nm. How many cell membranes would it take to make a stack 3.4 in high?

Answers

Answer:

486 of cell membranes

Explanation:

one cell membrane has 7*10^-9m as the height

So, by dividing 3.4 with 7*10^-9 you will get the number of cell require to form the height.

3.4/(7*10^-9)=485.71

because we can't have decimal number of cell we would round it into three significant figures, 486.

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle

Answers

Answer:

11 protons, 12 neutrons, 10 electrons

Explanation:

Sodium has an atomic number of 11, so it has 11 protons.

The atomic mass is 23, so there are 23 − 11 = 12 neutrons.

The charge is +1, so there is 1 more proton than electrons, so there are 10 electrons.

A car traveling at 30 mis runs out of gas while traveling up a 10o slope. How far up the hill will the car coast before starting to roll back down

Answers

Answer:

5.21 miles

Explanation:

The set up will be a right angle triangle (an inclined plane). The height of the inclined plane is the opposite side of the triangle while the distance traveled by the car along the slope will be the hypotenuse with angle of inclination of 10°.

Using the SOH trigonometry identity i.e sinθ = opposite/hypotenuse

sin 10° = opposite/30

opposite = 30sin10°

opposite = 5.21 miles

Hence the car must have traveled 5.21 miles up the hill before starting to roll back down.

Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?

Answers

Answer:

Displacement = 7 meters

Explanation:

Given that,

Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.

The attached figure shows the motion of Jaune.

We know that, Displacement = final position - initial position

Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.

Displcement = 15 m - 8 m

Displacement = 7 m

So, the displacement of Jaune is 7 meters.

Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during the trip their velocity was -20 m/s? Explain

Answers

Answer:

Yes , it is possible .

Explanation:

Suppose they travelled from A to B , a distance of 800 m at a velocity of

40m /s and then come back on the same path covering a distance of 200 m at the rate of 20/ s .In other words their velocity in their return journey was -20m /s .

Net displacement = 600 m

Total time taken = (800 / 40) + (200 / 20)

= 20 + 10 = 30 s

Average velocity = net displacement / total time

= 600 / 30 = 20 m /s .

Hence average velocity of 20 m /s is possible .  

The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
65
4.
70
2
75
2
80
1
85
7
90
5

Answers

Answer:

Solution

x f fx

65 4 260

70 2 140

75 2 150

80 1 80

85 7 595

90 5 450

total N=21 Summation fx=1675

We know

Mean= Summation fx/N

=1675/21

=79.8

Hence, the required mean is 79.8 ans.

The scores of students on a recent exam. The mean of the scores is  51.42857.

What is mean?

The mean is the ratio of addition of all the observation values and the number of observations.

The mean of the score is equal to

Mean =  {(65×4)+(70×2)+(75×2)+(80×1)+(85×7)+(90×5)} / (4+2+2+1+7+5)

Mean = 51.42857

Therefore, the mean of the scores is  51.42857.

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As a 1850 kg car is traveling down a road, it experiences a force of friction of 121 N and a force of air resistance if 186N. If the engine is not applying any force, what is the acceleration of the car

Answers

Answer:

  -0.166 m/s²

Explanation:

F = Ma

a = F/M = (121 N +186 N)/(1850 kg) = 0.166 m/s²

The acceleration of 0.166 m/s² is in the direction opposite to the direction of travel, so might be considered to be negative.

Answer:

 -0.166 m/s²            

As a 1850 kg car is traveling down a road, it experiences a force of friction of 121 N and a force of air resistance if 186N. If the engine is not applying any force, what is the acceleration of the car

Which motor and body should Devon use to build the car with the greatest acceleration? motor 1, with body 1 motor 1, with body 2 motor 2, with body 1 motor 2, with body 2

Answers

Answer:

hello your question is incomplete below is the complete question

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in the table.

Which motor and body should Devon use to build the car with the greatest acceleration?

motor 1, with body 1

motor 1, with body 2

motor 2, with body 1

motor 2, with body 2

answer: Motor 2 body 1

Explanation:

F = ma

hence a ( acceleration ) = F / m

force of motor 2 = 15 N since the mass of the motor is the same and that of the bodies aren't given

The motor and body that would produce the greatest acceleration would be : Motor 2 Body 1  if the mass of Body 1 is less than the mass of Body 2

Answer:

c

Explanation:

What is the current in a circuit that has a power of 200 W and a resistance of 150 Ω

Answers

Answer:

Current = 1.15 A

Explanation:

Since we are finding the current

Power in a circuit can be found by using the formula

[tex]P = I ^{2} R[/tex]

Where

I is the current

R is the resistance

P is the power

From the question

Power = 200 W

Resistance = 150 Ω

Substitute the values into the above formula and solve for the current

That's

[tex]200 = 150{I}^{2} [/tex]

Divide both sides by 150

We have

[tex] {I}^{2} = \frac{200}{150} \\ = \frac{4}{3} [/tex]

Find the square root of both sides

We have

[tex]I = \sqrt{ \frac{4}{3} } [/tex]

= 1.154700

We have the final answer as

Current = 1.15 A

Hope this helps you

Tech A says that when a fuse has blown, it just has to be replaced, because it performed its job. Tech B says that when a fuse has blown, the circuit has to be diagnosed because the fuse was probably not the problem. Who is correct

Answers

Answer:

tech B

Explanation:

im assuming its ASE or CDX i got my ase certification

you should also always replace that fuse its there to stop a harmful amount of voltage to said thing like a starter or a a fan

What is your average velocity or speed if you travel 500 km in 3 hours

Answers

Answer:

166.6 km/h

Explanation:

500/3

=166.6

A light beam travels through a diamond (n=2.42) to pure water (n=1.33). The refracted ray will:
a) bend toward the normal
b) bend away from the normal
c) remain unchanged
d) bend toward the normal then away

Answers

Answer:

b) bend away from the normal

Explanation:

According to snell's law , if i be the angle of incidence and r be the angle of refraction

sin i / sin r = 1.33 / 2.42

sin i / sin r = .55

Hence sin r > sin i

r > i

In other words angle of refraction will be more than angle of incidence . So, the ray will bend away from the normal .

How much time does it take for a car with a speed of 85 m/s to drive a distance of 200 m? (1 point)

Answers

The car will take 2.35 seconds to drive a distance of 200 m.

What is speed?

Speed is a physical quantity that is a measure of the rate of change in the position of an object. It is the rate of change of distance with respect to time. Speed is a scalar quantity and is expressed as the magnitude of velocity, which is the rate and direction of motion of an object. Speed is measured in meters per second (m/s).

To find the time it takes for the car to drive a distance of 200 m with a speed of 85 m/s, we can use the formula:

time = distance / speed

Plugging in the values given, we get:

time = 200 m / 85 m/s

Simplifying this expression, we get:

time = 2.35 s

Therefore, it takes 2.35 seconds for the car to drive a distance of 200 m with a speed of 85 m/s.

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HELP ME PLS!

Determine the presssure at the bottom of a container filled
with gasoline, if the height of the container is 200 cm long.
The gasoline's density is 680 kg/m3.

Answers

Explanation:

Pressure = Height * Density * acc. due to gravity

P = 2 * 680 * 9.8 = 13, 328 Pa

Answer:

13328pa

Explanation:

p = hgd

h = height = 200cm = 2m

g = 9.8m/s²

d = density = 680kg/m³

p = pressure

p = 2 x 9.8 x 680 = 13328pa

A woman dropped a dime in a wishing well , she heard it 30 sec later ..Find velocity on impact while moving at 9.8 m/s 2

Answers

Answer:

The velocity at impact is 222.2 m/s

Explanation:

The given information are;

The time at which the woman heard the sound of the coin after dropping it into the wishing well = 30 seconds

The average speed of sound in air = 344 m/s

The time in which the dime travel = t₁

The time in which the sound travel = t₂

1/2 × 9.8 × t₁² = 344 × t₂

t₁ + t₂ = 30

4.9·t₁² = 344 × (30 - t₁)

4.9·t₁² + 344·t₁ - 10320 = 0

Which gives -344±

[tex]t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 4.9 \times 10320}}{2\times 4.9}[/tex]

t₁  = 22.676 seconds or -92.9 seconds

Therefore the correct natural time is t₁  = 22.676 seconds

The velocity at impact, v = g×t₁ = 9.8 × 22.676  = 222.2 m/s

The velocity at impact= 222.2 m/s.

If a man travels from 0m to 5m then back to -3m, all in four seconds, what is the mans displacement?

Answers

Answer:

-3 m

Explanation:

Displacement is the final position minus the initial position.

Δx = x − x₀

Δx = -3 m − 0 m

Δx = -3 m

An automobile travels a displacement of 75km 45 degrees north of east. How many kilometers north does it travel?

Answers

Answer:

It travelled 53.03 Km North.

The distance traveled by the automobile is 53.03 km north.

The given parameter:

the displacement of the automobile, = 75 km 45 degrees north of east.

To find:

the distance traveled by the automobile

The vertical component of the displacement is equal to the distance traveled by the automobile in north.

[tex]distance \ towards \ north = 75 \ km \ \times \ sin(45)\\\\distance \ towards \ north = 75 \ km \times 0.7071\\\\distance \ towards \ north = 53.03 \ km \ north[/tex]

Thus, the distance traveled by the automobile is 53.03 km north.

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if an object is moving with constant speed then its distance-time graph will be a straight line. (a)along time axis. (b)along distance axis (c)parallel to time axis (d)inclined to time axis

Answers

Answer: (d)inclined to time axis

Explanation:

For a moving object, the distance equation can be written as:

D = S*t

if S = 0, we will have a line parallel to the time axis.

if S = infinity we will have a line parallel to the distance axis.

Both options are discarded here, as S = ∞ is not possible, and S = 0 would mean that the object is not moving.

where D is the distance moved at the time t, t is the variable, and S is the speed of the object.

As S is constant, this equation defines a linear relationship.

The graph of this line will be a line that is not parallel either to the time axis nor the distance axis, this will be an inclined line that goes between them.

So the correct option is: (d)inclined to time axis

Which sport requires participants to wear safety equipment during competition?

Answers

Answer:

Football

Explanation:

Answer:

Hockey

Explanation:

The answer is hockey because in order to play hockey you have to have a lot of safety equipment because people play hockey by being very close to one another. Also, getting hurt during playing hockey without proper equipment can cause many damages to your body.

Hope this helps! :D

What is the angular separation of two spectral lines of wavelengths 497 nm and 251 nm formed in the third order with a diffracting grating having 587 lines per millimeter

Answers

Answer:

34.8°

Explanation:

Given the following :

Number of lines (N) = 587mm

529mm to m = 587*1000 = 587000 per meter

d = 1 / N ; 1/587000 = 0.00000170357

Wavelength of light waves :

λ1 = 497nm = 497 × 10^-9 m

λ2 = 251nm = 251 × 10^-9 m

Angular position in 3rd order; m=3

For

λ1 ; dsinθ3 = 3λ1 ;

λ2 = dsinθ3 = 3λ2

Substituting values

dsinθ3 = 3λ1 =

0.00000189 * sinθ3 = 3 * 497 × 10^-9

θ3(1) = sin^-1(1491 * 10^-9 / 0.00000170357)

θ3(1) = sin^-1(0.8752208)

θ3(1) = 61.07°

λ2 = dsinθ3 = 3λ2

0.00000189 * sinθ3 = 3 * 251 × 10^-9

θ3(2) = sin^-1(753 * 10^-9 / 0.00000170357)

θ3(1) = sin^-1(0.4420129)

θ3(1) = 26.23°

Angular separation :

61.07° - 26.23° = 34.84°

34.8°

A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?

Answers

Answer:

Here is the answer.

Explanation:

Balanced forces- they are those forces that produce 0 resultant forces.

therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.

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