Sorry it’s twisted but please help, thank you!

Answer: the acceleration of the truck a_t is 0.6911 m/s²

Explanation:

Given the data in the question;

There is no external force on the system; net force on the system is 0

Mass of the truck with the woman M = 1767 kg + 41 kg = 1808 kg

mass of the car m = 833 kg

car acceleration a_c = 1.5 m/s²

now let a_t be the acceleration of the truck in opposite direction

Action force on the car = Reaction force on the car

ma_c = Ma_t

a_t = ma_c / M

we substitute

a_t = (833 × 1.5) / 1808

a_t = 1249.5 / 1808

a_t = 0.6911 m/s²    

Therefore, the acceleration of the truck a_t is 0.6911 m/s²

Explanation:

The water molecules begins to leave their fixed position and begins to move as the temperature increases.

When ice melts, it undergoes a state change from solid to liquid and with increasing temperature becomes a gas.

Answer:

The mass of Jupiter is 1.9 x 1027 kg. It is hard to fully understand a number that large, so here are a few comparisons to help. It would take 318 times Earth's mass to equal Jupiter's.

Explanation:

Answer:

it is due to anamolous expansion of water as water cools from 4dg.c to 0dg.c. it expand making ice lighter than water to float

Answer:

1962

Explanation:

w = f × d

= 20×9.81 × 10

= 1962

Answer: direct

Explanation: as the time (independent variable) goes on the temperature drops, it’s cooling down because time is passing by

Answer:

By preventing the government from taking property without fair payment.

Explanation:

Answer 1

Please mark me as brilliant and thank you

Answer:

this is under the wrong section

Answer:

hope its helps

good luck

Answer:

0.1 cm/s

Explanation:

16 min 40 second = 1000 sec

1m = 100cm

100/1000 = 0.1   (speed = distance/time)

Answer number four because it is one of the factors evaluating science

Explanation:

100N please mark me brainliest

Answer:

We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.

Explanation:

Let suppose that intensity is distributed uniformly in a spherical configuration. By dimensional analysis, we get that intensity is defined by:

[tex]I = \frac{\dot W}{\frac{4\pi}{3}\cdot r^{3}}[/tex] (1)

Where:

[tex]I[/tex] - Intensity, measured in watts per square meter.

[tex]r[/tex] - Radius, measured in meters.

If we know that [tex]\dot W = 10\,W[/tex] and [tex]I = 1\,\frac{W}{m^{2}}[/tex], then the radius is:

[tex]r^{3} = \frac{\dot W}{\frac{4\pi}{3}\cdot I }[/tex]

[tex]r = \sqrt[3]{\frac{3\cdot \dot W}{4\pi\cdot I} }[/tex]

[tex]r = \sqrt[3]{\frac{3\cdot (10\,W)}{4\pi\cdot \left(1\,\frac{W}{m^{2}} \right)} }[/tex]

[tex]r \approx 1.337\,m[/tex]

We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.

Answer:

A

Explanation:

1000ml = 1l

397ml = 0.397l

Answer:

The time it takes the ball to stop is 0.021 s.

Explanation:

Given;

mass of the softball, m = 720 g = 0.72 kg

velocity of the ball, v = 15.0 m/s

applied force, F = 520 N

Apply Newton's second law of motion, to determine the time it takes the ball to stop;

[tex]F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.72 \ \times \ 15}{520} \\\\t = 0.021 \ s \\[/tex]

Therefore, the time it takes the ball to stop is 0.021 s.

Answer:

The final speed of the semi truck is 30.11 m/s.

Explanation:

Given;

mass of the motorcycle, m₁ = 200 kg

initial speed of the motorcycle, u₁ = 40 m/s

mass of the semi truck , m₂ = 18,000 kg

initial speed of the semi truck, u₂ = 30 m/s (same direction as u₁)

If the two vehicles stick together after collision, the final speed of the motorcycle will be equal to final speed of the semi truck = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(200 x 40) + (18,000 x 30) = v(200 + 18,000)

8000 + 540,000 = v(18,200)

548,000 = v(18,200)

[tex]v = \frac{548,000}{18,200} \\\\v = 30.11 \ m/s[/tex]

Therefore, the final speed of the semi truck is 30.11 m/s.

Answer:

[tex]v=10^4\ m/s[/tex]

Explanation:

Given that,

The length of a vacuum tube, d = 2 m

Time, [tex]t=2\times 10^{-4}\ s[/tex]

We need to find the average speed of the  electron during this time. Average speed is equal to total distance covered divided by total time taken.

Here, total distance = length of the vacuum tube

[tex]v=\dfrac{2}{2\times 10^{-4}}\\\\=10^4\ m/s[/tex]

So, the average speed of the electron is [tex]10^4\ m/s[/tex].

Answer:

[tex]F$\approx$76[/tex]

Explanation:

From the question we are told that

Point charges [tex]q_1=1.60uC[/tex]

                       [tex]q_2=-22.25uC[/tex]

Displacement [tex]d=6.50cm=>0.065m[/tex]

Generally the equation for Coulomb's law is Mathematically given as

[tex]F=\frac{k*q_1*q_2}{r^2}[/tex]

Therefore

[tex]F=\frac{9*10^9*-22.25*10^-^6*(1.60)*10^-^6}{(6.50*10^-^2)^2}[/tex]

[tex]F=-75.83431953[/tex]

[tex]F$\approx$-76[/tex]

with  -(negative) showing form of force Magnitude => [tex]F$\approx$76[/tex]

Answer:

Like all the planets in our solar system, Earth and Mars orbit the sun. But Earth is closer to the sun, and therefore races along its orbit more quickly. Earth makes two trips around the sun in about the same amount of time that Mars takes to make one trip.

Answer:

2 ms^2

Explanation:

Given that the mass of the refrigerator  is 200Kg

The net force acting on the refrigerator is 400N

The time takes is 4s

From Newtons's second law of motion;

F =ma

a = F/m

a = 400/200

a = 2 ms^2

This is a constant acceleration

Answer:

its true!!

Explanation: have a nice day !!

Answer:

After 1 half-life (500 years), 500 g of the parent isotope will remain. After 2 half-lives (1000 years), 250 g of the parent isotope will remain. After 3 half-lives (1500 years), 125 g of the parent isotope will remain. After 4 half-lives (2000 years), 62.5 g of the parent isotope will remain.

Explanation:

Answer:

Explanation:

B. Their speed

Answer: b. Their speed

Explanation:

Answer:

search omni calculator and these problems can be solved easily:) hope this helps! 62.43

Answer:

1 g/cm3

Explanation:

just had it and this was the answer

Answer:

[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]

Explanation:

From the question we are told that

Voltage change [tex]\frac{dv}{dt}=-0.03volts/sec[/tex]

Resistance change [tex]\frac{dR}{dt}=0.02ohms/sec[/tex]

Resistance [tex]R=100[/tex]

Current [tex]I=0.02[/tex]

Generally the equation for ohms law is mathematically represented as

[tex]V=IR[/tex]

Therefore

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

Resolving the Rate of current changing [tex]\frac{dI}{dt}[/tex] as subject of formula

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

[tex]R\frac{dI}{dt} =\frac{dv}{dt} -I\frac{dR}{dt}[/tex]

[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dv}{dt} -I\frac{dR}{dt})[/tex]

Therefore

[tex]\frac{dI}{dt} =\frac{(-0.03) -(0.02)(0.02)}{100}[/tex]

[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]

Therefore the current decreases at a rate

[tex]\frac{dI}{dt} =3.04*10^-^4amps/sec[/tex]

Answer:

The answer is "[tex]1.96^{\circ} \ and \ 3.94^{\circ}[/tex]"

Explanation:

[tex]N= 1000 \frac{slit}{cm} \\\\\lambda=550 nm\ \ =550 \times 10^{-9} \ m\\\\width=1.6 \ cm[/tex]

We can find the distance between any two adjacent slits by using

[tex]\to d= \frac{1.6}{N}\\\\ \therefore\\ \to d= \frac{1.6}{1000} \ cm= 1.6 \times 10^{-5} m\\[/tex]

We know that the angle of the mth fringe is given by                  

[tex]\sin \theta_m = \frac{m\lambda}{d}\\\\ \sin \theta_1 = \frac{1\lambda}{d}\\\\\theta_1 = \sin^{-1} \frac{1\lambda}{d}\\\\\theta_1 = \sin^{-1}(\frac{1 \times 550 \times 10^{-9}}{1.6 \times 10^{-5}})\\\\ \theta_1=1.96^{\circ}\\\\[/tex]

Using the same way:  

[tex]\sin \theta_2 = \frac{2\times \lambda}{d}\\\\\theta_2 = \sin^{-1} \frac{2\times \lambda}{d}\\\\\theta_2 = \sin^{-1}(\frac{2 \times 550 \times 10^{-9}}{1.6 \times 10^{-5}})\\\\\theta_2=3.94^{\circ}\\\\[/tex]

By using the Huygens formula, the angles of the first two orders are 4 degrees and 8 degrees approximately.

Given that a 1.6cm wide diffraction grating has 1000 slits.

The slit spacing = (1.6 x [tex]10^{-2}[/tex]) / 1000

The slit spacing = 1.6 x [tex]1.6^{-5}[/tex]

Also, it is given that It is illuminated by light of wavelength 530 nm

Sin∅ = nλ/d

When n = 1

Sin∅ = 530 x [tex]10^{-9}[/tex]/1.6 x [tex]10^{-5}[/tex]

Sin∅ = 0.033125

∅ = [tex]Sin^{-1}[/tex] ( 0.033125)

∅ = 1.898 x 2

The angle of the first order = 2∅

2∅ = 4 degrees approximately

When n = 2

Sin∅ = nλ/d

Sin∅ = 2 x 530 x [tex]10^{-9}[/tex]/1.6 x [tex]10^{-5}[/tex]

Sin∅ = 0.06625

∅ = [tex]Sin^{-1}[/tex] ( 0.06625)

The angle of the second order = 2∅

2∅ = 3.7986 x 2

2∅ = 8 degrees approximately

Therefore, the angles of the first two orders are 4 degrees and 8 degrees approximately.

Learn more here: https://brainly.com/question/13902808

The question is incomplete. The complete question is :

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.

Solution :

Given :

Mass of earth, [tex]$M_e = 5.97 \times 10^{24} \ kg$[/tex]

Mass of moon, [tex]$M_m = 7.34 \times 10^{22} \ kg$[/tex]

Mass of each human, [tex]$m_p =65 \ kg$[/tex]

Therefore mass of total population, [tex]$M_p = 65 \times 7 \times 10^{9} \ kg$[/tex]

                                                           [tex]$M_p = 4.55 \times 10^{11} \ kg$[/tex]

Let the earth is at the origin of the coordinate system. Then,

Since [tex]$M_e>> M_p$[/tex]

         [tex]$M_m>> M_p$[/tex]

Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.

      [tex]$X_{cm} = \frac{5.97 \times 10^{24}+ 7.34 \times 10^{22} \times 3.84 \times 10^5}{5.97 \times 10^{24}+ 7.34 \times 10^{22}}$[/tex]

              [tex]$= 4.68 \times 10^6 \ m$[/tex]

[tex]$ 4.68 \times 10^3 \ km$[/tex] from the earth.

Answer:

alot

Explanation:

cuz he pushed for a long time

Answer:

3.6, make sure you study

Answer:

m = 327.07 kg

Explanation:

Given that,

Kinetic energy of a motorcycle, E = 57800 J

Velocity of the motorcycle, v = 18.8 m/s

We need to find the mass of the motorcycle. The kinetic energy of an object is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

m is mass

[tex]m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg[/tex]

So, the mass of the motorcycle is 327.07 kg.

Given that,

Mass of a woman, m = 60 kg

She runs up a staircase 15 m high in 20 s.

To find,

Power expanded.

Solution,

Power = rate of doing work

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\=441\ W[/tex]

So, the required power is 441 W.

Answer:

24.775N

Explanation:

According to Newton's second law

\sum Fx = ma

F- Ff = ma

F and Ff are the forces acting on the object

m is the mass

a is the acceleration

Given

Ff = 10N

m = 7.5kg

a = 1.97m/s²

Required

F

Substitute the given parameters into the formula

F - 10 = 7.5(1.97)

F-10= 14.775

F= 10+14.775

F = 24.775N

Hence the greatest possible magnitude of the other force is 24.775N