Someone please help me with this algebra problem

Answer:

Step-by-step explanation:

Picture this circumstance occurring within a circle. The center of the circle is where all the blades meet. That means that in terms of a circle's parts, these blades are the radii of the circle. And if they are all evenly spaced out, and there are 3 of them, the central angle in between each pair is 120 degrees (360/3). Once we know that, we can use the arc length formula for a circle which is

[tex]AL=\frac{\theta}{360}*2\pi r[/tex] and filling in:

[tex]AL=\frac{120}{360}*2(3.1415)(131)[/tex] so

AL = 274.4 feet

well, let's take a look at two independent events

A)  the potato is hot

B) it's raining

now, the potato could be hot whether is raining or not, A is totally independent of B, so what's the probability of "the potato being hot, GIVEN that it's raining" P(A | B)  is the same as if it wasn't raining, or P(A), the fact that B occurred, doesn't affect A at all, the potato is hot regardless, rain or not.  So P(A | B) = P(A).

Answer:

10

Step-by-step explanation:

Apply difference of squares.

[tex](x + y)(x - y) = {x}^{2} - {y}^{2} [/tex]

[tex](2 + 6i)(2 - 6i) = {2}^{2} - {6i}^{2} [/tex]

[tex] = 4 + 6[/tex]

[tex] = 10[/tex]

Answer:

Condition A= 320 inches

Condition B= 190 Degrees F

Condition C= 2240 inches

Condition D= 350 inches

Condition E= 110 Degrees F 8 inches

Condition F= 180 Degrees F

Step-by-step explanation:

4 inches

8 inches

70 inches

60 D

40 D

90 D

4 inches

8 inches

70 D

5 inches

7 inches

12 inches

30 D

80 D

8 inches

40 D

80 D

60 D

Answer:

Condition A= 320 inches

Condition B= 190 Degrees F

Condition C= 2240 inches

Condition D= 350 inches

Condition E= 110 Degrees F 8 inches

Condition F= 180 Degrees F

Step-by-step explanation:

Answer:

a₂₀ = 77

Step-by-step explanation:

There is a common difference between consecutive terms , that is

5 - 1 = 9 - 5 = 13 - 9 = 4

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 4 , then

a₂₀ = 1 + (19 × 4) = 1 + 76 = 77

Answer:

600g of Flour

Step-by-step explanation:

According to the question every 15 biscuits is 50g it need 50g of sugar and flour is 3 times the amount it needs for 15 biscuits so 50*3=150 now we know 15 biscuits need 150g of flour so 30 requires 300 and 300g +300g is equal to 600g of flour.

Answer:

600 g of flour.

Step-by-step explanation:

If Deon needs 50 g of sugar to make 15 biscuits, and she is going to make 60 biscuits, then she will need 200 g of sugar, since 60/15 is 4.

If the amount of flour she needs is equal to the amount of sugar multiplied by three, or 3x, if x is the amount of sugar, then she will need 200 x 3 g of flour.

Therefore, she will need 600 g of flour.

Answer:

CF = 8.5

Step-by-step explanation:

Given 2 intersecting chords, then

The product of the parts of one chord is equal to the product of the parts of the other chord, that is

CF × DF = BF × EF , substitute values

CF × 14 = 7 × 17

14CF = 119 ( divide both sides by 14 )

CF = 8.5

Answer:

40%

Step-by-step explanation:

ok so first find the og price:

100% - 20% = 80%

so 80% = 200

let the 100% be x:

x * 0.8 = 200

x= 250

100% = 250

(difference/ og price) * 100% = the percentage decrease/ increase

(250-150/250)* 100% = 40%

OR

((the final price/ og price) * 100%) - 100%

((150/250)*100%) - 100% = 40%

There was a 40% decrease from the og price to the final price of 150.

Given:

The expression is:

[tex]b^2+20b[/tex]

To find:

The a monomial so that the trinomial may be represented by a square of a binomial.

Solution:

If an expression is [tex]x^2+bx[/tex], then be need to add square of half of coefficient of x, i.e., [tex]\left(\dfrac{b}{2}\right)^2[/tex] in the given expression to make in perfect square.

We have,

[tex]b^2+20b[/tex]

Here, coefficient of b is 20,so wee need to add square of half of coefficient of b, i.e., [tex]\left(\dfrac{20}{2}\right)^2[/tex].

[tex]\left(\dfrac{20}{2}\right)^2=10^2[/tex]

[tex]\left(\dfrac{20}{2}\right)^2=100[/tex]

Therefore, we need to add 100 to make [tex]b^2+20b[/tex] a perfect square binomial.

Answer:

8.5

Step-by-step explanation:

QR is 10

PQRS AREA is 45

10 times 4.5 is 45

meaning BC and PQ is 4.5

4.5 plus 4.5 is 9

26 minus 9 is 17

17 divided by two is 8.5

AB is 8.5

Answer:

If you are talking about inequalities, t < r.

Step-by-step explanation:

Since s is bigger than t and r is bigger than s,

r should be bigger than t obviously.

Answer:

y = 3/2x +1

Step-by-step explanation:

The y int = is 1 by observation

To calculate the slope it is rise over run

3/2 as for every 3 up the line moves 2 across

Answer:

1/12

Step-by-step explanation:

Chances of getting a 1 are 1/6 and chances of getting a prime number excluding 1 is 3/6. 3/6 x 1/6= 3/36 or 1/12 chance.

Answer:

in picture

Step-by-step explanation:

Brainliest please

Answer:

this is the best way for the question

Answer:

3m-8n

Step-by-step explanation:

Set up an equation:

(5m-3n)-(2m+5n) = ?

Solve:

   5m-3n

-  2m+5n

   3m-8n

Hope this helps!

Answer:

Pythagoras theorem states that c²=a²+b²

14²=12²+x²

14²-12²=x²

196-144=x²

52=x²

√52=√x²

7.2111025509279785=x

rounded up to the nearest hundredth=7.21

Answer:  no

Step-by-step explanationn.  .......................................................w:eorkeok,feoferkeorkoe

Answer:

[tex]10[/tex].

Step-by-step explanation:

See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".

Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:

[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.

Sum of these digits:

[tex]\text{A} + 9\, x= 2021[/tex].

Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].

Therefore:

[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].

[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].

[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].

Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].

Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Proof:

The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".

For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.

Either of the following must be true:

If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.

Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.

let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].

Answer:

y= -1/15x + 16/15

Step-by-step explanation:

When two lines are perpendicular to each other that means their slopes are the negative reciprocals of each other.

So that means if a line has has a slope of 6, a line perpendicular to that line will have a slope of -1/6.

(a reciprocal is when the fraction is flipped over)

In this case, the negative reciprocal of 15 would be -1/15. So the slope of the line that is perpendicular would be -1/15.

The equation we would have so far for that line would be: y=-1/15x+b

Now we have to find the 'b' or the y intercept, which we can get by plugging in the point that was given (1,1), which is on that line.

Which gives us 1=-1/15(1)+b.

1=-1/15+b

1+1/15=b

Then you solve for b and get b= 16/15.

The equation of the line that is perpendicular to the given line is y= -1/15x + 16/15.

The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is

y = 15x - 14.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

Let the equation of a line is y = mx + c.

The line is perpendicular to y = 15x + 45.

y = 15x + 45 is in the form of y = mx + c

This means,

Slope = 15

m = 15

The line passes through the point (1, 1) = (x, y).

This means,

y = mx + c

1 = 15 x 1 + c

1 = 15 + c

c = 1 - 15

c = -14

The equation of the line is y = 15x - 14.

Thus,

The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is

y = 15x - 14.

Learn more about equation of a line here:

https://brainly.com/question/23087740

#SPJ2

Answer:

x ≈ 28.8°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{3.9}{8.1}[/tex] , then

x = [tex]sin^{-1}[/tex] ([tex]\frac{3.9}{8.1}[/tex] ) ≈ 28.8° ( to the nearest tenth )

Answer:

[tex] - \frac{2}{6} [/tex]

Step-by-step explanation:

Use distributive property to simplify both sides.

[tex] \frac{1}{6} (1 - 6x) = - \frac{1}{3} ( 6x + \frac{1}{2} )[/tex]

Use the Golden Rule of Algebra: (What we do to one side, we must do to the other).

[tex] \frac{1}{6 } - x = - 2x - \frac{1}{6} [/tex]

[tex] \frac{1}{6} = - x - \frac{1}{6} [/tex]

[tex] \frac{2}{6 } = - x[/tex]

[tex]x = - \frac{2}{6} [/tex]

Answer:

Step-by-step explanation:

[tex]\frac{1}{6}[/tex](1-6x) = - [tex]\frac{1}{3}[/tex](6x+[tex]\frac{1}{2}[/tex])

distribute in the fractions

[tex]\frac{1}{6}[/tex] - 1x = -2x - [tex]\frac{1}{6}[/tex]

subtract [tex]\frac{1}{6}[/tex]  from both sides

-[tex]\frac{1}{6}[/tex]+[tex]\frac{1}{6}[/tex]-1x = -2x -[tex]\frac{1}{6}[/tex]-[tex]\frac{1}{6}[/tex]

-1x = -2x -[tex]\frac{2}{6}[/tex]

-x = -2x - [tex]\frac{1}{3}[/tex]

[tex]\frac{1}{3}[/tex] = -2x + x

[tex]\frac{1}{3}[/tex] = -x

- [tex]\frac{1}{3}[/tex] = x

x = - [tex]\frac{1}{3}[/tex]

see?  :/  

This is because the nth term is found by adding the previous two terms

F(n) = nth term

F(n-1) = term just before the nth term

F(n-2) = term before the F(n-1) term

F(n) = F(n-1) + F(n-2)

We can re-index values of n to say this equivalent statement

F(n+2) = F(n+1) + F(n)

Based on either equation mentioned, adding F(51) and F(52) will get us F(53). In other words, the 51st and 52nd terms add to the 53rd term.

Step-by-step explanation:

This construction bisects the pqr angle.

This is done by placing a compass on the pqr angle and marking construction lines at the points c and a.

Then at where the construction lines at points c and a meet the lines qr and qp draw 2 more from that placement.

Then draw a line running through angle pqr and where the construction lines meet at point b.

Hope this helps and good luck!

Answer:

The third one

Step-by-step explanation:

All show complementary angles ( angles that add up to 90 degrees ) except for the third one

First one: shows a square within the two angles which indicates that the angles form a right angle ( 90 degree angle ) meaning that they are complementary angles

Second: the angles add up to equal 90 ( 50 + 40 = 90 ) hence they are complementary angles

Third one: the angles form a straight line. Angles that form a straight line add up to equal 180 and are known as supplementary angles

Fourth: the angles shown add up to 90 ( 65 + 25 = 90) hence they are complementary angles

All are complementary but the third one

Answer:

Entrance fee=15, fee per games played=2.50

Step-by-step explanation:

x=fee per games played, y=entrance fee

19x+y=62.50 equation 1

10x+y=40 equation 2

y=40-10x isolate y in equation 2

19x+40-10x=62.50 substitute y value from equation 2 into equation 1

9x=22.50

x=2.50

solve for y by substituting x value in either equation

10x+y=40

10(2.50)+y=40

25+y=40

y=15

Check answer:

19x+y=62.50

19(2.50)+15=62.50

47.50+15=62.50

62.50=62.50

Answer:

hope it will be helpful to you

Step-by-step explanation:

anb shade and anbnc shade

Answer:

(0, 170) (5, 150) (60, -170)

Step-by-step explanation:

Plug each x value into the equation. The point is located on the line if the y values match.

Ex. -4 (170) + 170 = -510 this point is not on the line

-4 (0) + 170 = 170 this point is on the line because it is a "true" statement

Answer:

(0, 170) (5, 150) (60, -170)

Step-by-step explanation: