For a project in his Geometry class, Mamadou uses a mirror on the ground to measure the height of his school's football goalpost. He walks a distance of 13.75 meters from his school, then places a mirror on flat on the ground, marked with an X at the center. He then steps 2.6 meters to the other side of the mirror, until he can see the top of the goalpost clearly marked in the X. His partner measures the distance from his eyes to the ground to be 1.75 meters . How tall is the goalpost? Round your answer to the nearest hundredth of a meter .

Answer: x= 112°, y = 34°

Step-by-step explanation:

"Angles formed by drawing lines from the ends of the diameter of a circle to its circumference form a right angle."

"The angle formed at the centre of the circle by lines originating from two points on the circle's circumference is double the angle formed on the circumference of the circle by lines originating from the same points."

x = 180° - 68° = 112°

y = 68 ÷ 2 = 34°

Circle theorems source: https://revisionmaths.com/gcse-maths-revision/shape-and-space/circle-theorems#:~:text=Angles%20formed%20by%20drawing%20lines%20from%20the%20ends,the%20point%20on%20the%20circumference%20our%20triangle%20touches.

Answer:

0.2 = n

Step-by-step explanation:

Since we want to express 3:15 as n:1, we can say that they are equal ratios, so

3:15 = n:1. Next, ratios can be written as fractions, so 3/15 = n/1 .

3/15 = n/1

Since anything divided by 1 equals itself, we can write this as

3/15 = n

0.2 = n

Answer:

The capital is $ 309365.

Step-by-step explanation:

What is the capital that I need, if I want to obtain a profit of $ 9745 in 5 months applying a rate of 6.3?

Let the capital is P.

Simple interest, I =$ 9745

Rate, R = 6.3 %

Time, T = 5 months

Use the formula of the simple interest.  

[tex]9745=\frac{P\times 6.3\times 5}{1200}\\\\P = 309365[/tex]

SUM OF ALL INTERIOR ANGLE = 180

[tex]y + y + 72 = 180 \\ 2y + 72 = 180 \\ 2y = 180 - 72 \\ 2y = 108 \\ y = \frac{108}{2} \\ y = \frac{ \cancel{108}^{ \: \: \: \tiny{54}} }{ \cancel{2}} \\ y = 54 \degree[/tex]

the sum of triangle is 180 :

[tex]y + y + 72 = 180 \\ 2y + 72 = 180 \\ 2y = 180 - 75 \\ 2y = 108 \\ y = \frac{108}{2} \\ y = 54[/tex]

Answer:

We know that the box has:

0.6lb of caramels

3.6lb of coconut.

Then the total mass of candy in the box is:

0.6lb + 3.6lb = 4.2lb

This is the 100% of the box.

Now, we can write this as:

4.2lb = 100%

For example, if we want to know which percentage is caramels, we write the equation:

0.6lb = X

We want to find the value of X

Then we have two equations:

0.6lb = X

4.2lb = 100%

Let's take the quotient of these two equations:

(0.6lb/4.2lb) = X/100%

Now we can solve this for X:

(0.6lb/4.2lb)*100% = X = 14.3%

the caramels represent the 14.3% of the wheight of the box.

And for the coconut candy, we have the relation:

3.6lb = Y

Now let's do the same again, we start with the two equations:

3.6lb = Y

4.2lb = 100%

Take the quotient:

(3.6lb/4.2lb) = Y/100%

Solve for Y:

(3.6lb/4.2lb)*100% = Y = 85.7%

Now we found the percentage that represent each type of candy in the box.

Hello,

A:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]

B:

[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]

First, we need to set up our two equations. For the picture of this scenario, there is one length (L) and two widths (W) because the beach removes one of the lengths. We will have a perimeter equation and an area equation.

P = L + 2W

A = L * W

Now that we have our equations, we need to plug in what we know, which is the 40m of rope.

40 = L + 2W

A = L * W

Then, we need to solve for one of the variables in the perimeter equation. I will solve for L.

L = 40 - 2W

Now, we can substitute the value for L into L in the area equation and get a quadratic equation.

A = W(40 - 2W)

A = -2W^2 - 40W

The maximum area will occur where the derivative equals 0, or at the absolute value of the x-value of the vertex of the parabola.

V = -b/2a

V = 40/2(2) = 40/4 = 10

Derivative:

-4w - 40 = 0

-4w = 40

w = |-10| = 10

To find the other dimension, use the perimeter equation.

40 = L + 2(10)

40 = L + 20

L = 20m

Therefore, the dimensions of the area are 10m by 20m.

Hope this helps!

Answer:

Width: 10 m

Length: 20 m

Step-by-step explanation:

Hi there!

Let w be equal to the width of the enclosure.

Let l be equal to the length of the enclosure.

1) Construct equations

[tex]A=lw[/tex] ⇒ A represents the area of the enclosure.

[tex]40=2w+l[/tex] ⇒ This represents the perimeter of the enclosure. Normally, P=2w+2l, but because one side isn't going to use any rope (sandy beach), we remove one side from this equation.

2) Isolate one of the variables in the second equation

[tex]40=2w+l[/tex]

Let's isolate l. Subtract 2w from both sides.

[tex]40-2w=2w+l-2w\\40-2w=l[/tex]

3) Plug the second equation into the first

[tex]A=lw\\A=(40-2w)w\\A=40w-2w^2\\A=-2w^2+40w[/tex]

Great! Now that we have a quadratic equation, we can do the following:

4) Solve for w

[tex]A=-2w^2+40w[/tex]

Factor out -2w

[tex]A=-2w(w-20)[/tex]

For A to equal 0, w=0 or w=20.

The average of 0 and 20 is 10, so the width that will max the area is 10 m.

5) Solve for l

[tex]40=2w+l[/tex]

Plug in 10 as w

[tex]40=2(10)+l\\40=20+l\\l=20[/tex]

Therefore, the length of 20 m will max the area.

I hope this helps!

Answer:

2

Step-by-step explanation:

x + 3 = 5

x = 5 - 3

x = 2

Therefore, x=2 in the given equation

Answer:

2

Step-by-step explanation:

x+3=5

x=5-3

x=2

Hope it helps

Answer: Cant see the photo

Step-by-step explanation:

I cannot really see the photo

Answer:

$ 20d

Step-by-step explanation:

Since each Apple costs d dollars , therefore 20 will cost , $ 20d .

The correct expression that gives the cost of 20 apples, in dollars, is 20a/d. So, correct option is A.

To find the cost of 20 apples, we need to determine the expression that correctly calculates the cost based on the given variables.

Given that a represents the cost of one apple in dollars and d represents the number of dollars, we can identify the expression that calculates the cost of 20 apples.

Let's analyze each option:

A. 20a/d: This expression calculates the cost of 20 apples by multiplying the cost of one apple (a) by 20 and then dividing by d. Therefore, this expression correctly gives the cost of 20 apples in dollars.

B. 20d/a: This expression calculates the cost of 20 apples by multiplying the number of dollars (d) by 20 and then dividing by the cost of one apple (a). This does not give the correct cost of 20 apples.

C. a/20d: This expression calculates the cost of 20 apples by dividing the cost of one apple (a) by 20 and then dividing by d. This does not give the correct cost of 20 apples.

D. 20/ad: This expression calculates the cost of 20 apples by multiplying 20 by d and then dividing by the cost of one apple (a). This does not give the correct cost of 20 apples.

Therefore, the correct expression that gives the cost of 20 apples, in dollars, is A. 20a/d.

To learn more about equation/expression click on,

https://brainly.com/question/26372151

#SPJ2

Complete question is:

If a apples cost d dollars, which of the following expressions gives the cost of 20 apples, in dollars?

A. 20a/d

B. 20d/a

C. a/20d

D. 20/ad

Answer:

(fg)(x) = (4x^2 + x^4)(x^2 + 4)^(1/2)

Step-by-step explanation:

Mathematically;

(fg)(x) = f(x) * g(x)

so we have;

4x^2 +x^4 * √(x^2 + 4)

But √(x^2 + 4) = (x^2 + 4)^(1/2)

So we have;

(fg)(x) = (4x^2 + x^4)(x^2 + 4)^(1/2)

Answer: 7.7 miles

Step-by-step explanation:

2.5x + 5.75 = 25 (x = each mile traveled)

2.5x = 25 - 5.75

2.5x = 19.25

x = 7.7 miles

Answer:

Fourth term of given arithmetic progression a(4) = 30

Step-by-step explanation:

Given incomplete information:

a(n) = 7n - 1 9

Assume Correct information:

a(n) = 7(n - 1) + 9

Find:

Fourth term of given arithmetic progression

Computation:

Fourth term of given arithmetic progression = a(4)

So,

Number of term (n) = 4

So,

a(n) = 7(n - 1) + 9

a(4) = 7(4 - 1) + 9

a(4) = 7(3) + 9

a(4) = 21 + 9

a(4) = 30

Fourth term of given arithmetic progression a(4) = 30

Answer:

hope it helps

Answer:

The answer is D (-0.7)

Step-by-step explanation:

Using d formular,a is 1,b is -5,c is -4

Input ur values and u will get ur answer

Answer:

x = -4 ±3

x = -7,-1

Step-by-step explanation:

x^2 + 8x     = -7

1/2 B ^ 2 = 16

x^2 + 8x  + 16    = 16 -7

(x + 4) ^2 = 9

x + 4 = ±3

x = -4 ±3

x = -7,-1

Answer:

54788347589535276

Step-by-step explanation:

you simply add the given values...

Answer:

By the Substitution property, the measure of angle ABC is equal to GHI.

Step-by-step explanation:

According to the Question,

Since we have,

On substituting the value of from equation (1) to equation (2)

We get, ∠ABC = ∠GHI ∴ ∠ABC ≅ ∠GHI

Thus, By the Substitution property  

The measure of angle ABC is equal to angle GHI.

5 + (1 + 1)3 × 2

5 + (2) 3 x 2

5 + 6 x 2

5 + 12

17

Answer:

17

Step-by-step explanation:

5 + (1+1)3*2

1+1= 2

5+2*3*2

3*2= 6

6*2= 12

12+5=17

Ax

B

Step-by-step explanation:

.....

...

..

Answer:

A(-9, 8), B(-5, 5), C(1, 13), D(-3, 16) → 50 square units

I(-6, 2), J(2, 2), K(2, -8), L(-6, -8) → 80 square units

Q(10, 0), R(15, 5), S(25, -5), T(20, -10) → 100 square units

U(0, 5), V(15, 20), W(25, 10), X(10, -5) → 300 square units

Step-by-step explanation:

The area of a rectangle, given the coordinates of the  vertices is found as follows;

1) The vertices of the rectangle ABCD are; A(-9, 8), B(-5, 5), C(1, 13), and D(-3, 16)

The length of side AB = √((-9 - (-5))² + (8 - 5)²) = 5

The length of side BC = √((1 - (-5))² + (13 - 5)²) = 10

The length of side CD = √((1 - (-3))² + (13 - 16)²) = 5

The length of side DA = √(((-9) - (-3))² + (8 - 16)²) = 10

The area of rectangle ABCD = 5 × 10  = 50 square units

2) The vertices of the rectangle EFGH are; E(30, 20), F(39, 29), G(49, 19), and H(40, 10)

The length of side EF= √((39 - 30)² + (29 - 20)²) = 9·√2

The length of side FG = √((39 - 49)² + (29 - 19)²) = 10·√2

The length of side GH = √((40 - 49)² + (10 - 19)²) = 9·√2

The length of side HE = √((40 - 30)² + (10 - 20)²) = 10·√2

The area of rectangle EFGH = 9·√2 × 10·√2  = 180 square units

3) The vertices of the rectangle IJKL are; I(-6, 2), J(2, 2), K(2, -8), and L(-6, -8)

The length of side IJ= √((-6 - 2)² + (2 - 2)²) = 8

The length of side JK= √((2 - 2)² + ((-8) - 2)²) = 10

The area of rectangle IJKL = IJ × JK

∴ The area of rectangle IJKL = 8 × 10 = 80 square units

4) The vertices of the rectangle MNOP are; M(5, 5), N(11, 5), O(11, -5), and P(5, -5)

The length of side MN = √((5 - 11)² + (5 - 5)²) = 6

The length of side NO = √((11 - 11)² + ((-5) - 5)²) = 10

The area of rectangle MNOP = 6 × 10 = 60 square units

5) The vertices of the rectangle QRST are; Q(10, 0), R(15, 5), S(25, -5), and T(20, -10)

The length of side QR = √((10 - 15)² + (0 - 5)²) = 5·√2

The length of side RS = √((25 - 15)² + ((-5) - 5)²) = 10·√2

The area of rectangle QRST = 5·√2 × 10·√2 = 100 square units

6) The vertices of the rectangle UVWX are; U(0, 5), V(15, 20), W(25, 10), and X(10, -5)

The length of side UV = √((0 - 15)² + (5 - 20)²) = 15·√2

The length of side VW = √((25 - 15)² + (10 - 20)²) = 10·√2

The area of rectangle UVWX = 15·√2 × 10·√2 = 300 square units

Answer:

A(-9, 8), B(-5, 5), C(1, 13), D(-3, 16)—

(50 square units)

I(-6, 2), J(2, 2), K(2, -8), L(-6, -8)—

(80 square units)

Q(10, 0), R(15, 5), S(25, -5), T(20, -10)—(100 square units)

U(0, 5), V(15, 20), W(25, 10), X(10, -5)—(300 square units)

Step-by-step explanation:

got it right on test, hope I helped

There can be infinitely many pair of integers that have the sum -12.

Example:

1. (-24), (12)

2. (-10), (-2)

3. (-12), (0)

Answer:

Multiple pairs.

Step-by-step explanation:

There are a lot of solutions to this problem. For example:

(-24)+12

(-36)+24

(-48)+36

and so forth.

Answer:

1134

Step-by-step explanation:

We have 3 digits:

a, b, c

a 3 digit number can be written as:

a*100 + b*10 + c*1

Such that these numbers can be:

{1, 2, 3, 4, 5, 6, 7, 8, 9}

Let's assume that:

a < b < c

Then the 3 smaller numbers are:

a*100 + b*10 + c

a*100 + c*10 + b

b*100 + a*10 + c

The 3 larger numbers are:

b*100 + c*10 + a

c*100 + a*10 + b

c*100 + b*10 + a

We know that the sum of the 3 smaller numbers is equal to 540, then:

(a*100 + b*10 + c) + (a*100 + c*10 + b) + (b*100 + a*10 + c) = 540

Let's simplify this:

(a + a + b)*100 + (b + c + a)*10 + (c + b + c) = 540

(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540

The sum of the 3 larger numbers is equal to X, we want to find the value of X:

(b*100 + c*10 + a) + (c*100 + a*10 + b) + (c*100 + b*10 + a) = X

Now let's simplify the left side:

(b + c + c)*100 + (c + a + b)*10 + (a + b + a)*1 = X

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

Then we have two equations:

(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

Notice that the terms are inverted.

By looking at the first equation, we can see that:

(2c + b) = 10    (because the units digit of 540 is 0)

Then, we can see that:

(b + c + a + 1 ) = 14   (the one comes from the previous 10)

finally:

(2a + b + 1) = 5   (the one comes from the previous 14)

Then we can rewrite:

(2*c + b) = 10

(b + c + a) = 14 -1  = 13

(2a + b) = 5 - 1 = 4

Now we can replace these 3 in the equation:

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

(10)*100 + (13)*10 + 4 = X

1000 + 130 + 4 = X

1134 = X

The sum of the 3 largest numbers is 1134.

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✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

Answer:

On a coordinate plane, a trapezoid has points (0, 0), (0.5, 2), (1, 2), (1.5, 0). Step-by-step explanation: If a trapezoid is dilated with a scale factor between 0 and 1, the resulting trapezoid will look smaller than the original trapezoid.

Step-by-step explanation: