Solve the system of linear equations using substitution. Use a pencil and paper. Which expression would be easier to substitute into the other​ equation, in order to solve this​ problem? Explain your reasoning.
x=4y-9
x+4y=3

Answer:

Its not A!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Its not!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The binomial distribution is solved as

a) The probability that no more than 2 students out of the random 5  plan to go out on vacation is P ( X ≤ 2 ) = 0.0579

b) The probability that more than 2 students out of the random 5  plan to go out on vacation is P ( X > 2 ) = 0.9421

The binomial distribution is a type of probability distribution that predicts the likelihood of obtaining one of two outcomes given a set of inputs. It summarizes the number of tries where each trial has the equal chance of producing the same result.

The formula for Binomial Distribution is given by

P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ

where

n = number of trials

x = number of successes

p = probability of getting a success in one trial

q = probability of getting a failure in one trial

q = 1 - p

Given data ,

Let the probability be represented as P

Now , the total number of trials = 5

The number of students going for vacation be represented as n

Now , the probability of success p = 0.8

So , the value of q = 0.2

a)

The probability that no more than 2 students out of the random 5  plan to go out on vacation is P ( X ≤ 2 ) = P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ

Substituting the values , we get

The probability that no more than 2 students out of the random 5  plan to go out on vacation is P ( X ≤ 2 ) = 0.0579

The probability that no more than 2 students out of the random 5  plan to go out on vacation is P ( X ≤ 2 ) = 5.79 %

b)

The probability that more than 2 students out of the random 5  plan to go out on vacation is P ( X > 2 ) = P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ

Substituting the values , we get

The probability that more than 2 students out of the random 5  plan to go out on vacation is P ( X > 2 ) = 0.9421

The probability that more than 2 students out of the random 5  plan to go out on vacation is P ( X > 2 ) = 94.21 %

Hence , the binomial distribution is solved

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Answer:

The amount the company charges in dollars can be represented as a linear function of the number of hours the employee works. We can use the slope-intercept form of a linear equation to graph this relationship:

y = mx + b

where y is the amount charged in dollars, x is the number of hours worked, m is the hourly rate charged by the company, and b is the initial charge for coming to the customer's home.

In this case, we have:

m = $50/hour (hourly rate)

b = $25 (initial charge)

Substituting these values into the equation, we get:

y = 50x + 25

This is the equation of a line with a slope of 50 and a y-intercept of 25. To graph this line, we can plot the y-intercept at (0, 25) and then use the slope to find other points on the line. For example, if the employee works for 1 hour, the company will charge:

y = 50(1) + 25 = $75

So we can plot the point (1, 75) on the graph. Similarly, if the employee works for 2 hours, the company will charge:

y = 50(2) + 25 = $125

So we can plot the point (2, 125) on the graph.

By connecting these points with a straight line, we get the graph of the linear function that represents the relationship between the number of hours worked and the amount charged by the company:

Step-by-step explanation:

A home priced at $200,000 is the same distance from the mean price in Florida and Ohio.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.

For Florida, the z-score of a home priced at $240,000 is given as follows:

Z = (200000 - 240000)/16000

Z = -2.5.

For Ohio, the z-score of a home priced at $240,000 is given as follows:

Z = (200000 - 170000)/12000

Z = 2.5.

Same absolute value of z-score, hence the houses are the same distance from the mean for each state.

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Please report this so a moderator can delete this answer. I was not finished with my answer and accidentally posted it. I will not have enough time to add it before the editing timer is up.

The average normal stress in the links connecting:

(a) points B and D is:

|σ_max| = 13.7 MPa

(b) points C and E is:

|σ_max| = 13.0 MPa

To determine the maximum value of the average normal stress in the links connecting points B and D, we need to calculate the bending moment and the axial force in the link. Assuming the links are in pure bending, we can use the bending stress formula to calculate the maximum normal stress:

σ_max = Mc / I

where M is the bending moment, c is the distance from the neutral axis to the outer fiber, and I is the moment of inertia of the cross-sectional area.

The bending moment in the link BD can be calculated as the sum of the moments due to the applied loads and the reactions at the pins. The axial force can be calculated as the sum of the forces in the link due to the applied loads.

M = 4kN * 80mm - 8kN * 120mm = -640 Nm

F = 4kN - 8kN = -4kN

        I = bh³ / 12

        I = (8mm) * (36mm)³ / 12 = 186624 mm⁴

       σ_max = (-640 Nm) * (4mm) / 186624 mm⁴ = -13.7 MPa

        |σ_max| = 13.7 MPa

       M = 4kN * 40mm + 8kN * 80mm = 800 Nm

        F = 4kN + 8kN = 12kN

I = bh³ / 12 = (36mm) * (8mm)³ / 12 = 24576 mm⁴

       σ_max = (800 Nm) * (4mm) / 24576 mm⁴ = 13.0 MPa

       |σ_max| = 13.0 MPa

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The vertex form of the equation is,

⇒ y = (d - 4)² - 26

An algebraic equation with the second degree of the variable is called an Quadratic equation.

Given that;

The equation is,

⇒ y = d² - 8d - 10

Now, We can change in vertex form as;

⇒ y = d² - 8d - 10

⇒ y = d² - 8d + 16 - 16 - 10

⇒ y = (d - 4)² - 16 - 10

⇒ y = (d - 4)² - 26

Thus, The vertex form of the equation is,

⇒ y = (d - 4)² - 26

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So x → T(S(x)) satisfies homogeneity.

x → T(S(x)) is a linear transformation from P to M.

The completed statement is: "T maps n onto m if and only if A has pivot columns in every row."

One theorem that explains why this is true is the Rank-Nullity Theorem, which states that the rank of a matrix plus the nullity of the matrix (the dimension of the nullspace) equals the number of columns. If A has pivot columns in every row, then the rank of A is equal to the number of rows, which means that the nullity is 0, and therefore T is onto. Conversely, if T is onto, then the range of T has dimension equal to the number of rows, which means that the rank of A is equal to the number of rows, so A has pivot columns in every row.

To show that the mapping x → T(S(x)) is a linear transformation, we need to show that it satisfies the two properties of linearity: additivity and homogeneity.

Additivity: Let x and y be vectors in P. Then we have:

T(S(x + y)) = T(S(x) + S(y)) (by definition of + in P)

= T(S(x)) + T(S(y)) (since T is linear)

= (x → T(S(x))) + (y → T(S(y))) (by definition of the mapping)

= (x + y) → (T(S(x)) + T(S(y))) (by definition of + in M)

So x → T(S(x)) satisfies additivity.

Homogeneity: Let x be a vector in P and let c be a scalar. Then we have:

T(S(cx)) = T(cS(x)) (by definition of scalar multiplication in P)

= cT(S(x)) (since T is linear)

= c(x → T(S(x))) (by definition of the mapping)

So x → T(S(x)) satisfies homogeneity.

x → T(S(x)) is a linear transformation from P to M.

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Area of the triangle which is the land that the university acquired is 3 miles².

Area of a two dimensional shape is the total region which is bounded by the object's shape.

The land acquired by the university is in the shape of triangle.

Half of the base has length of 1.5 miles.

Total length of base = 2 × 1.5 = 3 miles

Height of the base = 2 miles

Area of the triangle = [tex]\frac{1}{2}[/tex] × base × height

                                 =  [tex]\frac{1}{2}[/tex] × 3 × 2

                                 = 3 miles²

Hence the area of the land is 3 miles².

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Answer:

The number in standard form is 304.014.

Answer:

The Standard form of the number is 44,410.

What is Multiplication?

To multiply means to add a number to itself a particular number of times.

 Multiplication can be viewed as a process of repeated addition.

Here, given number(3 X 100) + (1 X 110) + (4 X 11000)(300) + (110) + (44000)300 + 110 + 44000410 + 4400044410

Thus, the Standard form of the number is 44,410.

By using the unitary method, 28 students in the school band play woodwind instruments.

Unitary method, which involves finding the value of a single unit and then using that value to find the value of multiple units. In this case, the single unit represents the percentage of students who play woodwind instruments.

Here we need to find the value of a single unit

To find the value of a single unit, we need to divide the given percentage by 100. So, 35% can be written as 0.35.

Therefore, the value of a single unit is 0.35.

Now use the unitary method to find the number of students who play woodwind instruments

Now, we can use the value of a single unit to find the number of students who play woodwind instruments. To do this, we multiply the value of a single unit by the total number of students in the band.

So, the number of students who play woodwind instruments is:

0.35 x 80 = 28

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The solution of the system of equations given is (-7/2, 11/2)

A set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.

Given that, a system of equations using any method x+y = 2 and -3x-y = 5,

The equations are:

x+y = 2...(i)

-3x-y = 5...(ii)

Since, the signs of y variable in the both equations are opposite, if we add both the equations the y variable will get eliminated,

Therefore, the most suitable method to solve is elimination method,

Adding equations i and ii,

(x+y = 2) + (-3x-y = 5)

-2x = 7

x = -7/2

Put x = -7/2 in eq(i)

-7/2 + y = 2

-7 + 2y = 4

2y = 11

y = 11/2

Hence, the solution of the system of equations given is (-7/2, 11/2)

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The range of the costs of the surfboard rentals is $ 140.

The interquartile range of the costs is $ 56.

The cost of 6 days of rentals is an outlier.

To find the range, first find the costs of renting the surfboards on the different days.

1 day :

= 28 x 1

= $ 28

2 days :

= 28 x 2

= $ 56

3 days :

= 28 x 3

= $ 84

6 days :

= 28 x 6

= $ 168

The cost can therefore be ordered to be :

28, 28, 28, 56, 56, 56, 84, 84, 84, 168

The range is :

= Largest - Least

= 168 - 28

= $ 140

The interquartile range is :

= Q 3 - Q1

Q 3 :

= 75 / 100 x 10 costs

= 7.5

= $ 84 in the cost arrangement

Q1 :

= 25 / 100 x 10

= 2. 5 position

= $ 28 in the cost arrangement

The IQR is :

= 84 - 28

= $ 56

The cost of 6 days of rentals is an outlier as it is much larger than the rest of the costs.

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The given statement can be expressed in terms of c(x), d(x), f(x), quantifiers, and logical connectives as follows:

a) ∃x(C(x) ∧ D(x) ∧ F(x))

b) ∀x(C(x) ∨ D(x) ∨ F(x))

c) ∃x(C(x) ∧ F(x) ∧ ¬D(x))

d) ¬∃x(C(x) ∧ D(x) ∧ F(x))

e) ∀y∃x(P(x, y))

All of the pupils in your class should be a set. The domain is the set X. Denote

[tex]C(x)-'x has a cat'\\D(x)- 'x has a dog'\\F(x)- 'x has a ferret'[/tex]

a) A kid in your class owns a cat, a dog, and a ferret, so take that into consideration. This implies that ∃x ∈ X so that C(x), D(x), and F(x) are all true assertions. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.

∃x(C(x) ∧ D(x) ∧ F(x))

b) Take into account the claim that "Every student in your class has a cat, a dog, or a ferret." This proves ∀x ∈ X at least one of the claims made by C(x), D(x), and F(x) to be true. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.

∀x(C(x) ∨ D(x) ∨ F(x))

c) Take into account the claim that "Some student in your class has a cat and a ferret, but not a dog." Accordingly, ∃x ∈ X, statements C(x), F(x), and the negation of statement D(x) are true. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.

∃x(C(x) ∧ F(x) ∧ ¬D(x))

d) Take into account the claim that "No student in your class has a cat, a dog, and a ferret." This indicates ∀x ∈ X that neither C(x), D(x), nor F(x) is true. As a denial of the claim in section a), we may state that in terms of C(x), D(x), and F(x) by using quantifiers and logical connectives as follows.

¬∃x(C(x) ∧ D(x) ∧ F(x))

a) Take into account the adage, "There is a student in your class who has this animal as a pet. The three animals are cats, dogs, and ferrets."

This indicates that an element X from the domain exists for each of the propositions C, F, and D such that each statement is true.

Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.

∀y∃x(P(x, y))

The complete question is:-

Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret." Express each of these statements in terms of C(x), D(x), F(x), quantifiers, and logical connectives. Let the domain consist of all students in your class. a) A student in your class has a cat, a dog, and a ferret. b) All students in your class have a cat, a dog, or a ferret. c) Some student in your class has a cat and a ferret, but not a dog. d) No student in your class has a cat, a dog, and a ferret. e) For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.

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A function f with domain R is strictly increasing provided that - f(x) < f(y).

A function f with domain R is not strictly increasing provided that - f(x) >= f(y).

A function f with domain R is not strictly increasing provided that -  x < y, but f(x) >= f(y)

(a) A function f with domain R is strictly increasing provided that for all real numbers x and y, if x < y, then f(x) < f(y).

(b) A function f with domain R is not strictly increasing provided that there exist real numbers x and y such that x < y, but f(x) >= f(y).

(c) A function f with domain R is not strictly increasing provided that there exist two real numbers x and y such that x < y, but f(x) >= f(y), i.e., the function does not strictly increase between x and y.

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The expected number of points per roll is -1.5.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

Outcomes when rolling a number cube.

= 1, 2, 3, 4, 5, or 6.

If the number is odd, you win the same number of points as the number on the cube.

So,

If the number is 1, you win 1 point.

If the number is 3, you win 3 points.

If the number is 5, you win 5 points.

Now,

If the number is even, you lose 4 points.

If the number is 2, you lose 4 points.

If the number is 4, you lose 4 points.

If the number is 6, you lose 4 points.

The probability of rolling an odd number.

= 3/6

= 1/2

Similarly,

The probability of rolling an even number.

= 3/6

= 1/2

Now,

The expected number of points per roll.

= Probability of rolling an odd number x (1 + 3 + 5) + Probability of rolling an even number  x (-4 - 4 - 4)

= (1/2) x (1 + 3 + 5) + (1/2) x (-12)

= (1/2) x 9 - 6

= 9/2 - 6

= (9 - 12)/2

= -3/2

= -1.5

Thus,

The expected number of points per roll is -1.5.

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The difference between the highest guess and the lowest guess, in the whole number, is 120.

Mathematical operations include subtraction. It is employed in order to exclude phrases or objects from the expression.

Given:

A table that shows the relationship between the guessed amount and the number of weeks.

Week          Amount

1                      120

2                      140

3                      160

4                      240

Here, the highest guess is 240.

And the lowest guess is 120.

The difference  between the highest guess and the lowest guess,

= 240 - 120

= 120

120 is a whole number.

Therefore, 120 is the required number.

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The complete question:

A table that shows the relationship between the guessed amount and the number of weeks.

Week          Amount

1                      120

2                      140

3                      160

4                      240

What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number

The region bounded by[tex]x=3√3y,x=0,y=5[/tex] is rotated about the y-axis to form a solid. The volume of this solid is V. The region, the solid and a typical disk or washer can be sketched using the given curves.

To calculate the volume V of the solid obtained by rotating the region bounded by [tex]x=3√3y,x=0,y=5[/tex]about the y-axis, we will use the equation [tex]V=π∫a b[(R)^2-(r)^2]dy,[/tex] where R is the outer radius, r is the inner radius, a is the lower limit of the integral and b is the upper limit of the integral. Substituting the given values, we get

[tex]V=π∫0 5[(3√3y)^2-(0)^2]dy[/tex]

This simplifies to [tex]V=π∫0 5[9y^2]dy.[/tex] Integrating this expression, we get [tex]V=π(5^3-0^3)[/tex]. Substituting the limits, we get [tex]V=π(5^3-0^3)[/tex]. This simplifies to V=125π. Hence, the volume of the solid is 125π.

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The new cereal box requires 11 square inches less cardboard to construct than the original cereal box.

The amount of cardboard required to build a cereal box is determined by its surface area, which includes all six sides of the box.

The original cereal box's surface area can be calculated as follows:

2 * 2.5 * 12 = 60 square inches for the front and back faces

2 * 7 * 12 = 168 square inches on the side faces

2 * 2.5 * 7 = 35 square inches for the top and bottom faces

Surface area total: 60 + 168 + 35 = 263 square inches

Using the new base dimensions, the surface area of the new cereal box can be calculated in the same way:

2 * 3 * 12 = 72 square inches for the front and back faces

2 * 6 * 12 = 144 square inches on the side faces

2 * 3 * 6 = 36 square inches for the top and bottom faces

Surface area total: 72 + 144 + 36 = 252 square inches

To calculate the difference in cardboard required to construct the two cereal boxes, subtract the new box's surface area from the original box's surface area:

263 - 252 = 11

As a result, the new cereal box uses 11 square inches less cardboard than the original cereal box.

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Answer:

3 over 18 puppies per litter

Step-by-step explanation:

usually, you want to go with the smaller number first, it's like a fraction.

Answer:

It has letters

Step-by-step explanation:

Answer:

Step-by-step explanation:To evaluate F(x) at a specific value, we simply replace x with that value in the expression for F(x). In this case, we want to find F(-3), so we substitute -3 for x in the expression for F(x):

F(-3) = 3(-3) - 5

Simplifying the right-hand side:

F(-3) = -9 - 5

F(-3) = -14

Therefore, F(-3) = -14.

Answer:

A. The shirt at Store "A".

Step-by-step explanation:

How to find 10% of 28.

First, we need to convert 10% into a decimal.

To do that, we just divide the number by 100.

[tex]\frac{10}{100}[/tex] [tex]= 0.1[/tex]

Now, we take the original number (28) and multiply it by the decimal

[tex]28 x 0.1 = 2.8[/tex]

Finally, we subtract.

[tex]28.00 - 2.80 = 25.20[/tex]

[tex]25.20[/tex] > [tex]25.00[/tex]

Therefore, Store "A" Has the cheapest shirt

The area of the resulting two-dimensional cross-section is 480 inch².

The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.

Given:

The Resulting Cross section will Have the Size

= 20 inch by 14 inch

So, Area of two dimensional Cross section

=  20 x 14

= 240 inch²

As prism is Sliced so this cross section will on the face of two prism.

Then, the Total cross section area

= 2 x 240

= 480 inch²

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The largest and smallest degree of f(x) + a * g(x) if  a be a constant is 4 and 1 respectively.

According to the question  f(x) = x^4-3x^2 + 2 and g(x) = 2x^4 - 6x^2 + 2x -1

f(x) + a * g(x) = x^4-3x^2 + 2 + a( 2x^4 - 6x^2 + 2x -1)

                    = x^4(1 + 2a)x^4 +(-3-6a)x^2 +2 + 2ax -a

The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.

The largest possible degree of f + ag is 4

When a = -1/2, the first two terms disappear and the sum becomes

f + ag = -x +1/2

The smallest possible degree of f + ag is 1.

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The ordered bases for the T-cyclic subspaces generated by z in (a), (b), (c), and (d) are[tex]B={e1, Te1, T^2e1, T^3e1}, B={x^3, 3x^2, 6x, 6}, B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex] and [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex], respectively.

a)The T-cyclic subspace generated by z = e1 = (1,0,0,0) is spanned by the vectors e1, [tex]Te1=(1,b,-c,a+d), T^2e1=(b,-c,a+c,2a+d)[/tex] and [tex]T^3e1=(-c,a+c,2a+d,3a+2d)[/tex]. So the ordered basis for the T-cyclic subspace generated by e1 is [tex]B={e1, Te1, T^2e1, T^3e1}[/tex].

b)The T-cyclic subspace generated by [tex]z=x^3[/tex] is spanned by the vectors [tex]x^3, Tx^3=3x^2, T^2x^3=6x, T^3x^3=6[/tex]. So the ordered basis for the T-cyclic subspace generated by x^3 is [tex]B={x^3, 3x^2, 6x, 6}[/tex].

c)The T-cyclic subspace generated by z=(0 1 1 0) is spanned by the vectors (0 1 1 0), [tex]T(0 1 1 0)=(1 0 0 1), T^2(0 1 1 0)=(0 1 -1 0), T^3(0 1 1 0)=(-1 0 0 -1)[/tex]. So the ordered basis for the T-cyclic subspace generated by (0 1 1 0) is [tex]B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex].

d)The T-cyclic subspace generated by z=(0 1 1 0) is spanned by the vectors (0 1 1 0). So the ordered basis for the T-cyclic subspace generated by (0 1 1 0) is [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex].

The ordered bases for the T-cyclic subspaces generated by z in (a), (b), (c), and (d) are [tex]B={e1, Te1, T^2e1, T^3e1}, B={x^3, 3x^2, 6x, 6}, B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex], and [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex], respectively.

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The equation of the solution passing through (-1,0) is y = x + eˣ.

A slope field is a graphical representation of the solutions to a differential equation at different points in the xy-plane.

In this problem, we are given the equation y = -x + y and asked to sketch the solutions that pass through three different points: (0,0), (-3,1), and (-1,0). To do this, we first plot each of these points on the slope field and draw a short line segment with the same slope as the slope at that point. By repeating this process for several points, we can obtain a rough sketch of the solution curve passing through each point.

Once we have sketched the solution curves, we can try to find the equation of the solution passing through (-1,0). To do this, we need to integrate the differential equation y = -x + y with respect to x, which involves finding the antiderivative of -x + y. In this case, we can use the method of separation of variables to write the differential equation as:

dy/dx = y - x

Dividing both sides by y - x, we get:

dy / (y - x) = dx

Integrating both sides, we obtain:

ln|y - x| = x + C

where C is the constant of integration. Exponentiating both sides and simplifying, we get:

y - x = Ceˣ

where C is the constant of integration. To find the value of C, we can use the initial condition that the solution passes through (-1,0), which means that:

0 - (-1) = Ce⁻¹

Simplifying, we get:

C = e

Substituting this value of C into the equation for the solution, we get:

y - x = eˣ

which is the equation of the solution passing through (-1,0). We can verify that this solution is correct by checking that it satisfies the original differential equation:

dy/dx = y - x

Substituting y = x + eˣ, we get:

d/dx(x + eˣ) = (x + eˣ) - x

Simplifying, we get:

eˣ = eˣ

which is true.

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Complete Question:

The slope field for the equation y = -x + y is shown below EN On a print out of this slope field, sketch the solutions that pass through the points (1) (0,0); (ii) (-3,1); and (iii) (-1,0). From your sketch, what is the equation of the solution to the differential equation that passes through (-1,0)? (Verify that your solution is correct by substituting it into the differential equation.)