Answer:
Step-by-step explanation:
The equation that models the population of bats, y, after x years can be found using the formula:
y = P(1 + r)^x
where P is the initial population, r is the annual growth rate as a decimal, and x is the number of years.
In this case, the initial population P is 345,000, the annual growth rate r is 1.2% or 0.012 as a decimal, and x is the number of years. Substituting these values into the formula, we get:
y = 345,000(1 + 0.012)^x
Simplifying the expression in the parentheses, we get:
y = 345,000(1.012)^x
Therefore, the equation that models the population of bats, y, after x years is:
y = 345,000(1.012)^x
Step-by-step explanation:
the other answer is correct.
I just want to point out some mechanism used here :
the increase by 1.2%
an increase by x% means adding x% to the original 100%.
so, we end up with (100 + x)%.
"%" just stands for 1/100.
so, if y = 100%, an increase by x% is
y×(100 + x)/100 = y×(1 + x/100)
in our case here that is
345,000 × (1 + 0.012) = 345,000 × 1.012
and since the increase rate of 1.2% applies per year, we multiply the end population of every year by 1.012 for the following year.
so, each year a new factor of 1.012 is being integrated into the calculation.
it goes then
345,000×1.012×1.012×1.012×...×1.012 x times after x years.
and we get
y = 345,000 × (1.012)^x
Five quarts of a latex enamel paint will cover about 200 square feet of wall surface. How many quarts are needed to cover 165 square feet of kitchen wall and 115 square feet of bathroom wall?
Answer:
25
Step-by-step explanation: just like that
suppose that two independent continuous random variables x and y have marginal densities fx(x) and fY(y) respectively. write down expressions that represent the following quantities, leaving definite integrals involving fx and fy as necessary:(a) P(3x−4<5)
(b) P(X>Y)(c) P(X+Y=5)
(d) E(cov(XY))
(e) Mx+y(t) (the mgf of X +Y)
(a) Expression for P(3x−4<5) is ∫[from -∞ to 3] fx(x) dx
(b) Expression for P(X>Y)(c) P(X+Y=5) is ∬[over (x,y) satisfying x > y] fx(x) fY(y) dxdy
(c) Expression for E(cov(XY)) is ∬xyfx(x) fY(y) dxdy - E(X)E(Y)
(d) Expression for Mx+y(t) (the mgf of X +Y) is Mx(t) My(t)
(a) P(3x-4<5) can be written as:
P(3x < 9)
P(x < 3)
The expression involving fx(x) for this probability would be:
∫[from -∞ to 3] fx(x) dx
(b) P(X>Y) can be written as:
P(X-Y > 0)
The expression involving fx(x) and fY(y) for this probability would be:
∬[over (x,y) satisfying x > y] fx(x) fY(y) dxdy
(c) P(X+Y=5) can be written as:
P(Y = 5 - X)
The expression involving fx(x) and fY(y) for this probability would be:
∬[over (x,y) satisfying x+y=5] fx(x) fY(y) dxdy
(d) The covariance of X and Y is defined as:
cov(X,Y) = E(XY) - E(X)E(Y)
So, E(cov(X,Y)) can be written as:
∬xyfx(x) fY(y) dxdy - E(X)E(Y)
(e) The MGF of X+Y can be written as:
Mx+y(t) = E(e^(t(X+Y)))
Since X and Y are independent, we can write this as:
Mx+y(t) = E(e^(tX) e^(tY))
Using the fact that X and Y have their own MGFs,
We can write this as:
Mx+y(t) = Mx(t) My(t)
Where Mx(t) and My(t) are the MGFs of X and Y, respectively.
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the corollary to the polygon angle-sum theorem finds the measure of each interior angle of a regular n-gon. *write a formula to find the measure of each interior angle using n
The Corollary to the polygon is explained below and the formula to find the measure of each interior angle is " (n - 2)×180°/n " .
The Corollary to the polygon Angle Sum Theorem states that : the sum of the interior angles of a regular n gon is written as :
that means , ⇒ Sum of interior angles = (n - 2) × 180° ...equation(1)
In a regular "n-gon" , all the interior angles are said to be congruent.
Let "x" be measure of each interior angle of a regular n-gon.
So , we can write ;
⇒ Sum of interior angles = (n)×(x) ;
Equating the above expressions with equation(1),
⇒ (n)×(x) = (n - 2) × 180° ;
On Solving for x,
⇒ x = (n - 2)×180°/n ;
Therefore, the measure of each interior angle of a regular "n-gon" is x = (n - 2)×180°/n .
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Astronomers sometimes use angle measures divided into degrees, minutes, and seconds. One degree is equal to 60 minutes, and one minute is equal to 60 seconds. Suppose that ∠J and ∠K are complementary, and that the measure of ∠J is 40 degrees, 25 minutes, 16 seconds. What is the measure of ∠K?
Answer: The measure of angle J is 40 degrees, 25 minutes, and 16 seconds, which can be expressed in decimal form as 40 + 25/60 + 16/3600 = 40.42111... degrees.
Since ∠J and ∠K are complementary, their measures add up to 90 degrees.
So, the measure of ∠K can be found by subtracting the measure of ∠J from 90 degrees:
∠K = 90 - 40.42111... = 49.57888... degrees
So, the measure of ∠K is approximately 49 degrees, 34 minutes, and 44 seconds.
Step-by-step explanation:
Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 3%, each paper is worth 5%, each test is worth 13%, and the final is worth 48%.(a) What is the average for a student with 99 on attendance, 75 on the first paper, 61 on the second paper, 94 on test 1, 86 on test 2, 77 on test 3, and 79 on the final exam? (Enter your answer to one decimal place.)(b) Compute the average for a student with the above scores on the papers, tests, and final exam, but with a score of only 21 on attendance. (Enter your answer to one decimal place.)
(a) Average for a student with 99 attendance is 81.1% and (b) The average for a student with 21 attendance is 78.8%.
Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam, the activities carry different weights.
Attendance is worth 3%,
each paper is worth 5%,
each test is worth 13%,
and the final is worth 48%.
(a) The average for a student with 99 on attendance, 75 on the first paper, 61 on the second paper, 94 on test 1, 86 on test 2, 77 on test 3, and 79 on the final exam
= [(99×3%) + (75×5%) + (61×5%) + (94×13%) + (86×13%) + (77×13%) + (79×48%)] ÷ [0.03 + 2(0.05) + 3(0.13) + 0.48]
= [2.97 + 3.75 + 3.05 + 12.22 + 11.18 + 10.01 + 37.92] ÷ 1
= 81.1 %
(b) The average for a student with the above scores on the papers, tests, and final exam, but with a score of only 21 on attendance
= [(21×3%) + (75×5%) + (61×5%) + (94×13%) + (86×13%) + (77×13%) + (79×48%)] ÷ [0.03 + 2(0.05) + 3(0.13) + 0.48]
= [0.63 + 3.75 + 3.05 + 12.22 + 11.18 + 10.01 + 37.92] ÷ 1
= 78.8 %
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need help with this asap
Answer: a
Step-by-step explanation:
This is the first part of a three-part problem. Express 18 sqrt 8 in the form a sqrt b where a and b are integers and b is as small as possible. Hint(s): Factor sqrt(8) as the product of two square roots, one of which is the square root of a perfect square. Part 2,Express 8 sqrt 18 in the form a sqrt b, where a and b are integers and b is as small as possible.part 3 18 sqrt 8 - 8 sqrt 18 +what is sqrt n?
(Part 1) The expression [tex]18\sqrt{8}[/tex] can be written in the form [tex]a\sqrt{b}[/tex] as [tex]36\sqrt{2}[/tex], where a and b are integers and b is as small as possible.
(Part 2) The expression [tex]8\sqrt{18}[/tex] can be written in the form [tex]a\sqrt{b}[/tex] as [tex]16\sqrt{3}[/tex].
(Part 3) The expression [tex]18\sqrt{8}[/tex] - [tex]8\sqrt{18}[/tex] + [tex]\sqrt{n}[/tex] is equal to ([tex]36\sqrt{2}[/tex] - [tex]16\sqrt{3}[/tex]) + [tex]\sqrt{n}[/tex].
(Part 1) Expressing [tex]18\sqrt{8}[/tex] in the form [tex]a\sqrt{b}[/tex], where a and b are integers and b is as small as possible:
We can factor [tex]\sqrt{8}[/tex] as [tex]\sqrt{2}[/tex]* [tex]\sqrt{4}[/tex]
So, [tex]18\sqrt{8}[/tex]= 18 * [tex]\sqrt{2}[/tex] *[tex]\sqrt{4}[/tex] = 18 *[tex]\sqrt{2}[/tex] * 2 = [tex]36\sqrt{2}[/tex]
So the expression [tex]18\sqrt{8}[/tex] can be written in the form [tex]a\sqrt{b}[/tex] as [tex]36\sqrt{2}[/tex], where a = 36 and b = 2.
(Part 2) Expressing [tex]8\sqrt{18}[/tex] in the form [tex]a\sqrt{b}[/tex], where a and b are integers and b is as small as possible:
We can factor [tex]\sqrt{18}[/tex] as [tex]\sqrt{3}[/tex] * [tex]\sqrt{6}[/tex]
So, [tex]8\sqrt{18}[/tex] = 8 * [tex]\sqrt{3}[/tex] * [tex]\sqrt{6}[/tex]
[tex]8\sqrt{18}[/tex]= 8 * [tex]\sqrt{3}[/tex] * [tex]\sqrt{2}[/tex] * [tex]\sqrt{3}[/tex]
[tex]8\sqrt{18}[/tex]= 8 *[tex]\sqrt{6}[/tex]* [tex]\sqrt{2}[/tex]
[tex]8\sqrt{18}[/tex]= 8 * [tex]\sqrt{2}[/tex] * [tex]\sqrt{6}[/tex]
[tex]8\sqrt{18}[/tex]= 8 * 2 * [tex]\sqrt{3}[/tex]
[tex]8\sqrt{18}[/tex]= [tex]16\sqrt{3}[/tex]
So the expression [tex]8\sqrt{18}[/tex] can be written in the form [tex]a\sqrt{b}[/tex] as [tex]16\sqrt{3}[/tex], where a = 16 and b = 3.
(Part 3) [tex]18\sqrt{8}[/tex] - [tex]8\sqrt{18}[/tex] + [tex]\sqrt{n}[/tex]:
We can substitute the simplified forms of [tex]18\sqrt{8}[/tex] and [tex]8\sqrt{18}[/tex] from parts 1 and 2 into this expression:
[tex]18\sqrt{8}[/tex] - [tex]8\sqrt{18}[/tex] + [tex]\sqrt{n}[/tex] = [tex]36\sqrt{2}[/tex] - [tex]16\sqrt{3}[/tex] + [tex]\sqrt{n}[/tex] = ([tex]36\sqrt{2}[/tex] - [tex]16\sqrt{3}[/tex]) + [tex]\sqrt{n}[/tex].
So, the expression [tex]18\sqrt{8}[/tex] - [tex]8\sqrt{18}[/tex] + [tex]\sqrt{n}[/tex] is equal to ([tex]36\sqrt{2}[/tex] - [tex]16\sqrt{3}[/tex]) + [tex]\sqrt{n}[/tex] where n is an unknown constant.
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I need this done because i really do not want to fail
Answer:
Step-by-step explanation:
it is 77.6
We have this beach bar that has a radius of 20 inches. How much air is inside the ball? 
The air inside the beach ball with a radius of 20 inches is 33493.33 cubic inches.
What is volume of sphere?The capacity of a sphere is its volume. It is the area that the sphere occupies. Cubic measurements of a sphere's volume include m3, cm3, in3, etc. The sphere has a round, three-dimensional shape. Its shape is determined by three axes: the x, y, and z axes. Sports like basketball and football are all examples of spheres with volume.
The volume of the cube is given as:
V = (4/3) πr³
Substituting the value of r = 20 inches we have:
V = (4/3)π(20)³
V = (4/3)(3.14)(20)³
V = 33493.33 cubic inches.
Hence, the air inside the beach ball with a radius of 20 inches is 33493.33 cubic inches.
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3. Lisa drives her car 10 km south. She then turns and drives 13 km west. How far is she currently from
her starting place? Sketch a picture, Label the triangle, Set up the problem, Solve.
Using Pythagorean theorem, the distance from where she started is 16.4km
What is Pythagorean TheoremThe Pythagorean Theorem is a mathematical concept that states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In mathematical terms, the theorem can be expressed as:
c^2 = a^2 + b^2,
where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.
c² = 10² + 13²
c² = 269
c = √269
c = 16.4 km
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The entire high school marching band is going on a field trip. According to school district policy, the number of students on the trip determines how many parent chaperones are required to go along. s = the number of band students on the trip p = the number of parent chaperones required on the trip Which variable is the dependent variable?
The number of parent chaperones required on the trip (p) variable is the dependent variable.
According to the question,
s = the number of band students on the trip
p = the number of parent chaperones required on the trip
As the question already said the number of students on the trip determines how many parent chaperones are required to go along, therefore s , the variable of number of student is a independent variable as it does not depends on another variable.
And 'p' , the number of parent chaperones required on the trip depend on number of students. Therefore 'p' is dependent variable.
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A proportioal relationship is formed when y = 4 and x =-16. What is the value of y when x equals 8?
Answer:
-2
Step-by-step explanation:
Standard equation of a proportional relationship:
y = kx
We use the given point to find k.
4 = k × (-16)
k = 4/(-16)
k = -1/4
The equation of this proportional relationship is
y = -1/4 x
Now we use x = 8 in the equation just above to find its corresponding y value.
x = 8
y = -1/4 × 8
y = -2
Answer: -2
Estimate the sum of 202 and 57.
Answer:
259
Step-by-step explanation:
Answer:259
Step-by-step explanation:
202+57=259
Calculate the final value after 10 years if you invest $5000.00 at 2.5% per annum, compounded annually.
Answer:
$6400.42
Step-by-step explanation:
You want the value after 10 years of $5000.00 invested at 2.5%, compounded annually.
FormulaThe formula for an amount earning compound interest is ...
A = P(1 +r/n)^(nt)
where P is the amount invested at annual rate r compounded n times per year for t years.
ApplicationHere, we have P=$5000, r=0.025, n=1, t=10, and the amount is ...
A = $5000(1 +0.025)^(1·10) ≈ $6400.42
The final value after 10 years is $6400.42.
A large fast-food restaurant is having a promotional game where game pieces can be found on various
products. Customers can win food or cash prizes. According to the company, the probability of winning a
prize (large or small) with any eligible purchase is 0.175.
ace Calculate the following
Answer:
hope this helps
How are the zeros of the polynomial function p(x)=(2x−1)(5x+7)(8x+9)
related to the coefficients of p(x)
written in standard form?
Answer:
Step-by-step explanation:
The zeros of a polynomial function are the values of x for which the function equals zero. For the given polynomial function p(x) = (2x - 1)(5x + 7)(8x + 9), the zeros can be found by setting each factor equal to zero and solving for x:
2x - 1 = 0, x = 1/2
5x + 7 = 0, x = -7/5
8x + 9 = 0, x = -9/8
Therefore, the zeros of the function are x = 1/2, x = -7/5, and x = -9/8.
In standard form, the polynomial function p(x) can be written as:
p(x) = 80x^3 + 122x^2 - 127x - 63
The relationship between the zeros of p(x) and its coefficients can be seen in Vieta's formulas. Vieta's formulas state that for a polynomial function of degree n with roots r1, r2, ..., rn, the coefficients of the polynomial can be expressed as:
a0 = (-1)^n * p0
a1 = (-1)^(n-1) * p1 / p0
a2 = (-1)^(n-2) * p2 / p0
...
an-1 = (-1) * pn-1 / p0
an = pn / p0
where p0 is the coefficient of the highest degree term (the leading coefficient), and the pi are the elementary symmetric polynomials, which are given by:
p1 = r1 + r2 + ... + rn
p2 = r1r2 + r1r3 + ... + rn-1rn
...
pn-1 = r1r2...rn-1 + r1r2...rn-2 + ... + rn-2rn-1
pn = r1r2...rn
Using Vieta's formulas, we can see that for the polynomial function p(x) given above, the coefficients are related to the zeros as follows:
a0 = -63
a1 = -127
a2 = 122
a3 = 80
And we can also see that:
a0 = (-1)^3 * p0 = -63
a1 = (-1)^(3-1) * p1 / p0 = -127
a2 = (-1)^(3-2) * p2 / p0 = 122
a3 = (-1)^(3-3) * p3 / p0 = 80
Therefore, the coefficients of the polynomial are related to the zeros through Vieta's formulas, which express the coefficients as functions of the zeros, and vice versa.
Sally is seen in the office today because of a red swollen area on her left side. After examination it is determined that she has a sebaceous cyst. This encounter should be reported with code(s) ________ .
a. L72.1, L30.9
b. L72.9
c. L30.9
d. L72.3
It is determined that she has a sebaceous cyst. This encounter should be reported with code(s) L72.9. So option B is correct.
The ICD-10-CM code for sebaceous cysts is unspecified. The other options are not specific to a sebaceous cyst or are not relevant to the given scenario.
L72.1 is for the epidermal cyst, L30.9 is for unspecified dermatitis, and L72.3 is for the inflamed sebaceous cyst.
ICD-10-CM codes are used for medical diagnosis coding and are important for medical record-keeping, insurance reimbursement, and data analysis.
Each code corresponds to a specific medical condition, and it is essential to choose the correct code that accurately represents the patient's diagnosis.
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suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.56 and a standard deviation of 0.45 . using the empirical rule, what percentage of the students have grade point averages that are greater than 2.11 ? please do not round your answer.
16% percentage of the students have grade point averages that are greater than 2.11
Using the empirical rule, we know that for a bell-shaped distribution, approximately:
68% of the data falls within one standard deviation of the mean
95% of the data falls within two standard deviations of the mean
99.7% of the data falls within three standard deviations of the mean
To find the percentage of students with a grade point average greater than 2.11
We first need to calculate how many standard deviations away from the mean 2.11 is:
z = (2.11 - 2.56) / 0.45
= -1
This tells us that 2.11 is 1 standard deviation below the mean.
Since the distribution is symmetric.
The percentage of students with a GPA greater than 2.11 is the same as the percentage of students with a GPA less than 2.56 + 1*0.45, which is:
68% + 95% = 163%
So, approximately
100% - 163%
= 16% of the students have a GPA greater than 2.11.
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In these questions, assume that R is the reduced echelon form of the augmented matrix for a system of equations. 1.20 If the system has three unknowns and R has three nonzero rows, then the system has at least one solution. 1.21 If the system has three unknowns and R has three nonzero rows, then the system can have an infinite number of solutions. (1.22)The system below has an infinite number of solutions: 2x + 3y + 5z + 6 - 7 - 8v = 0 3x - 4y + 7z + + 8 + 5y = 0 -7x + 9y - 2z -- 4w - 5u + 2y = 0 --5x - 5y +92 +3w + 2u + 7y = 0 -9x + 3y - 9z+5w - 3u - 4y = 0
1.20 If the system has three unknowns and R has three nonzero rows, then the system has at least one solution.
This statement is true.
1.21 It is only when the rank of the coefficient matrix is less than the number of unknowns that the system can have infinitely many solutions
1.22 The system below has an infinite number of solutions:
2x + 3y + 5z + 6 - 7 - 8v = 0
3x - 4y + 7z + + 8 + 5y = 0
-7x + 9y - 2z -- 4w - 5u + 2y = 0
--5x - 5y +92 +3w + 2u + 7y = 0
-9x + 3y - 9z+5w - 3u - 4y = 0
This statement is true.
When we perform row reduction on a system of linear equations, the resulting reduced row echelon form (R) will have the same number of nonzero rows as the rank of the coefficient matrix.
In other words, if R has three nonzero rows, then the rank of the coefficient matrix is also 3.
If the rank of the coefficient matrix is equal to the number of unknowns, then the system has a unique solution.
However, if the rank of the coefficient matrix is less than the number of unknowns, then the system has either no solution or infinitely many solutions.
But in this case, since the rank is equal to the number of unknowns, the system must have at least one solution.
1.21 If the system has three unknowns and R has three nonzero rows, then the system can have an infinite number of solutions.
This statement is false. If R has three nonzero rows, then the rank of the coefficient matrix is also 3.
If the rank of the coefficient matrix is equal to the number of unknowns, then the system has a unique solution.
It is only when the rank of the coefficient matrix is less than the number of unknowns that the system can have infinitely many solutions.
1.22 The system below has an infinite number of solutions:
2x + 3y + 5z + 6 - 7 - 8v = 0
3x - 4y + 7z + 8 + 5y = 0
-7x + 9y - 2z - 4w - 5u + 2y = 0
-5x - 5y + 92 + 3w + 2u + 7y = 0
-9x + 3y - 9z + 5w - 3u - 4y = 0
This statement is true.
To check if the system has infinitely many solutions, we need to check the rank of the coefficient matrix and the rank of the augmented matrix. In this case, the rank of the coefficient matrix is 3, which is less than the number of unknowns (5).
Also, when we perform row reduction on the augmented matrix, we get the following reduced row echelon form:
1 0 -1 0 1 0
0 1 2 0 -1 0
0 0 0 1 2 0
0 0 0 0 0 1
0 0 0 0 0 0
Since the rank of the augmented matrix is less than the number of unknowns, the system has infinitely many solutions.
The variables with free parameters are z, u, and y, which can take any value.
The other variables can be expressed in terms of these free parameters.
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What is the area of the quadrilateral 10cn 16cm 22cm
The area of the quadrilateral is 140 m^2.
What is a quadrilateral?For closed figure made by 4 line segments joined end to end in series is called a quadrilateral.
A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle.
A rectangle is always a parallelogram and a quadrilateral but reverse statement could be not be true.
Area of the quadrilateral = 2 x area of the traingle
Thus, Area of the triangle = 1/2 x base x height
Area of 1 triangle = 1/2 x 10 x 16
Area of 1 triangle = 80 m^2
Area of the quadrilateral = 2 x 80
Area of the quadrilateral = 140 m^2
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The complete question is;
What is the area of the quadrilateral if the dimensions of the quadrilateral are 10cm, 16cm and 22cm
i need help on this question
Therefore, 4 people have been to Europe but not Asia.
What is Venn diagram?A Venn diagram is a visual representation of sets and their relationships. It is used to show the similarities and differences between different sets of data. A Venn diagram consists of overlapping circles or other shapes, each representing a set. The size of each circle is proportional to the number of elements in the set it represents. The overlapping parts of the circles represent the elements that are shared by two or more sets. The non-overlapping parts represent the elements that are unique to each set. By analyzing the intersections and differences between sets in a Venn diagram, we can gain insights into the relationships between them. Venn diagrams are often used in mathematics, logic, statistics, and other fields to represent complex relationships between sets of data. They are also used in education to teach critical thinking and problem-solving skills.
Here,
Let E be the set of people who have been to Europe, A be the set of people who have been to Asia, and N be the set of people who have been to neither.
From the problem, we know that:
|E| = 5 (5 people have been to Europe)
|A| = 3 (3 people have been to Asia)
|E ∩ A| = 1 (1 person has been to both Europe and Asia)
To find the number of people who have been to Europe but not Asia, we need to find |E \ A|. We can use the formula:
|E \ A| = |E| - |E ∩ A|
Substituting the values we know:
|E \ A| = 5 - 1 = 4
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HELP! ASAP!! What are the outputs?
The completed table is,
Input (x) -1 0 1 2
Output (y) -6 -2 2 6
What is the function rule?Function rule is the rule of writing the relationship between the two variables, one is dependent and another is independent.
We are given that, the output is 4 less than the input.
The table given in the problem is;
Input (x) -1 0 1 2
Output (y)
Thus we need to write such a function, which gives the value of (y) is 4 less than the value of (x), when we put this into the function.
y = 4x - 2
Complete the table using the above function rule;
At (x) equal to -1,
y = 4(-1)-2
y = -6
At (x) equal to 0,
y = 4(0)-2
y = -2
At (x) equal to 1,
y = 4(1)-2
y = 2
At (x) equal to 2,
y = 4(2)-2
y = 6
Hence, the function rule for the statement, "the output is 2 less than 4 times x the input is y = 4x - 2 and the completed table is,
Input (x) -1 0 1 2
Output (y) -6 -2 2 6
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Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 2; B: the numbers add to 6; C: at least one of the numbers is 3; and D: the numbers do not add to 9. Express the given event in symbols. HINT [See Example 5.] The numbers do not add to 6.
B
D
D'
B'
B' ? D
How many elements does it contain?
The set B' ∩ D' represents the event "the numbers do not add to 6." It contains 20 elements.
The complement of event B is B' = {2, 3, 4, 5, 7, 8, 9, 10, 11, 12}. The complement of event D is D' = {2, 3, 4, 5, 6, 7, 8, 10, 11, 12}. Taking the intersection of their complements, we get B' ∩ D' = {2, 3, 4, 5, 7, 8, 10, 11}. This set represents the event "the numbers do not add to 6." It contains 8 elements out of the 36 possible outcomes of rolling two dice, so the probability of this event is 8/36 or 2/9.
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calculate the maximum system inventory for this part. use the rounded value of the number of containers from part a. round your answer to the nearest whole number.
To calculate the number of containers that Heavey Compressors should be using, we need to determine the number of parts that need to be produced per day and divide it by the number of parts that can fit in each container.
100 parts per 8-hour day / 7 parts per container
= 14.2857 containers (round up to 15)
=15 containers
Therefore, Heavey Compressors be using 15 containers.
Maximum inventory levels = reorder point + reorder quantity – [minimum consumption × minimum lead time].
= 100+15-[12.5x8]
= 115-100
= 15
Therefore, the maximum system inventory for this part is 15.
The maximum stock position is the largest number of goods a company can store to give its guests with service at the smallest possible cost. It's vital to keep force control in line with demand.
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Complete question:
Heavey Compressors uses a lean production assembly line to make its compressors. In one assembly area, the demand is 100 parts per eight-hour day. It uses a container that holds seven parts. It typically takes about five hours to round-trip a container from one work center to the next and back again. Heavey also desires to hold 20 percent safety stock of this part in the system. a. How many containers should Heavey Compressors be using? Do not round intermediate calculations. Round your answer up to the nearest whole number. containers b. Calculate the maximum system inventory for this part. Use the rounded value of the number of containers from part answer to the nearest whole number. parts c. If the safety stock percentage is reduced to zero, how would this impact the number of containers, all else being equal? calculations. Round your answer up to the nearest whole number. The number of containers will to containers.
Andrew finds that on his way to work his wait time for the bus is roughly uniformly distributed between 11
minutes and 14 minutes. One day he times his wait and writes down the number of minutes ignoring the
seconds. Round solutions to three decimal places, if necessary.
The probabilities are given as follows:
P(X = 11) = 0.P(11 <= X <= 13) = 2/3.What is the uniform probability distribution?It is a distribution with two bounds, given by a and b, in which each possible outcome is equally as likely.
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
Uniformly distributed between 11 minutes and 14 minutes, hence the bounds are given as follows:
a = 11, b = 14.
As the uniform distribution is a continuous distribution, the probability of an exact value, such as X = 11, is of zero.
The probability of a value between 11 and 13 is given as follows:
p = (13 - 11)/(14 - 11) = 2/3.
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"Mr. Franklin wants to buy an eraser for every fourth-grade student. There are 12 erasers in each box. There are 7 fourth-grade classes with 24 students in each class. How many boxes of erasers does Mr. Franklin need to buy?"
14 boxes of erasers should Mr. Franklin need to buy.
What is Division?A division is a process of splitting a specific amount into equal parts.
Given that Franklin wants to buy an eraser for every fourth-grade student
There are 12 erasers in each box.
There are 7 fourth-grade classes with 24 students in each class
The total number of students=7×24
=168
We need to find the number of boxes are required to buy an eraser for each student.
Since there are 12 erasers in each box, we can divide the total number of students by 12 to find the number of boxes Mr. Franklin needs to buy:
number of boxes = total students / erasers per box
number of boxes = 168 / 12
number of boxes = 14
Hence, 14 boxes of erasers should Mr. Franklin need to buy.
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PLEASE HELP FAST!!! IT IS URGENT!!!A study seeks to estimate the difference in the mean fuel economy (measured in miles per gallon) for vehicles under two treatments: driving with underinflated tires versus driving with properly inflated tires. To quantify this difference, the manufacturer randomly selects 12 cars of the same make and model from the assembly line and then randomly assigns six of the cars to be driven 500 miles with underinflated tires and the other six cars to be driven 500 miles with properly inflated tires. What is the appropriate inference procedure?
A. t confidence interval for a mean
B. z confidence interval for a proportion C. t confidence interval for a difference in means
D. z confidence interval for a difference in proportions
Answer: C
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The appropriate method for the biologist to use for inference to the population is A) A one-sample t-interval for a population mean.
What occurs in one-sample t-interval?In this situation, the biologist wants to estimate the average weight of a population of dolphins living in a certain region of the ocean. The biologist will collect a random sample of dolphins and use the sample weights to create the estimate.
here, we have,
Therefore, the appropriate method for inference to the population is to use a one-sample t-interval for a population mean.
This method is used when we want to estimate the population mean using a sample mean and the standard deviation of the sample.
The t-interval takes into account the uncertainty of the estimate due to the random sampling process, which makes it an appropriate method for this situation.
Hence, The appropriate method for the biologist to use for inference to the population is A) A one-sample t-interval for a population mean.
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The correct question is:
A marine biologist wants to estimate the average weight of a population of dolphins living in a certain region of the ocean. The biologist will collect a random sample of dolphins and use the sample weights to create the estimate Which of the following is an appropriate method for the biologist to use for inference to the population?
A A one-sample t-interval for a population mean
B A one-sample t-interval for a sample mean
C A one-sample 2-interval for a population proportion
D A matched-pairs t-interval for a mean difference
E A two-sample t-interval for a difference between means
Two employees of a company have to file expense reports for their travel. The first had taken 7 trips with a mean trip cost of $750. The second took a total of 5 trips with a mean cost of $1200. The accounting department wants to determine the mean cost of all the trips that these two employees took. What is the mean cost of all 12 trips? Proposed Solution: Since we have two costs (one for each employee) we can find the mean cost of both employees by the following computation: (750 + 1200) / 2 = 975 What was done wrong in the proposed solution? A. Since there are 12 total trips, the calculation should be (750 + 1200) / 12 B. Since there are 7 trips with a mean of 750 and 5 with a mean of 1200, the calculation should be (7-750 + 5-1200) / 12 C. Since we do not have the original data from each of the 12 trip costs, a mean cost cannot be calculated. D. Since the two costs are not close to one another, a median should be used. E. The proposed calculation is correct.
The correct answer is A, as the mean cost of all 12 trips can be calculated by adding up the total cost of all the trips and dividing by the total number of trips.
The proposed solution is wrong as the mean cost of all 12 trips cannot be calculated by taking the average of the means of the two employees. Taking the average of the means of the two employees assumes that they took the same number of trips and that their trip costs are equally weighted in the total cost calculation, which is not necessarily true.
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PLEASE HELP! (PRE CALC)
Jacy keeps track of the amount of average monthly rainfall in her hometown. She determines that the average monthly rainfall can be modeled by the function ...where ...represents the average monthly rainfall in centimeters and ... represents how many months have passed. If ... represents the average rainfall in July, in which months does Jacy’s hometown get at least 10.5 centimeters of rainfall? Show all of your algebraic reasoning to support your final answer.
Answer:
he months where Jacy's hometown gets at least 10.5 centimeters of rainfall are July (x = 7) and all the months after July, which are August (x = 8), September (x = 9), October (x = 10), November (x = 11), and December (x = 12).
Step-by-step explanation:
The given function is:
f(x) = 0.2x^2 - 1.8x + 6.5
where x represents the number of months passed and f(x) represents the average monthly rainfall in centimeters.
To find the months where the average rainfall is at least 10.5 centimeters, we need to set the function f(x) greater than or equal to 10.5 and solve for x:
0.2x^2 - 1.8x + 6.5 ≥ 10.5
0.2x^2 - 1.8x - 4 ≥ 0
Multiplying both sides by 5, we get:
x^2 - 9x - 20 ≥ 0
We can factor the left-hand side of the inequality as:
(x - 5)(x - 4) ≥ 0
The solution to this inequality is the set of values of x that make the inequality true. This includes the intervals where:
(x - 5) ≥ 0 and (x - 4) ≥ 0, which gives x ≥ 5
OR
(x - 5) ≤ 0 and (x - 4) ≤ 0, which gives x ≤ 4
Thus, the months where Jacy's hometown gets at least 10.5 centimeters of rainfall are July (x = 7) and all the months after July, which are August (x = 8), September (x = 9), October (x = 10), November (x = 11), and December (x = 12).
Jacy's hometown gets at least 10.5 centimeters of rainfall in the months of September, September of the following year, September of the year after that, and so on.
What is inequality?
An inequality is a relation between two numbers or expressions that are not equal.
It can show which of them is greater or smaller by using symbols like < or >. It can also be a statement of fact about the order relationship of quantities.
According to the question given,
We need to solve the inequality:
A(t) ≥ 10.5
Substituting the given function, we get:
2.3sin(π/6)t ≥ 10.5
sin(π/6)t ≥ 4.57.
Since the sine function has a maximum value of 1, the inequality is only satisfied when:
sin(π/6)t = 1
Solving for t, we get:
π/6t = π/2 + 2πk or π/6t = 3π/2 + 2πk
where k is any integer.
Simplifying each equation, we get:
t = 3 + 12k or t = 9 + 12k, where k is any integer.
Therefore, the only solution is given by:
t = 9 + 12k
where k is any integer.
Hence, Jacy's hometown gets at least 10.5 centimeters of rainfall in the months of September, September of the following year, September of the year after that, and so on.
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if half the students at quincy university have blue eyes, which of the following events is most probable?
In a Quincy College class consisting of 15 students 12 or more have blue eyes.
If half the students at Quincy College have blue eyes, then the most probable event is that a randomly selected student from the college will have blue eyes.
This is because, if half the students have blue eyes, then there is a greater chance that a randomly selected student will have blue eyes than any other eye color.
For example, if we were to consider the event of a randomly selected student having green eyes, this would be less probable because fewer than half the students are likely to have green eyes.
Therefore, the most probable event is that a randomly selected student from Quincy College will have blue eyes.
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