six over ten >_______> one over two

Answer:

Step-by-step explanation:

Answer:

190 = 13.78

290 =17.02

390 = 19.74

545 = 23.34

Step-by-step explanation:

if you need simplest ratical let me know

Answer:

P' (2, -4)

Q' (3, -1)

R' (4, -4)

Step-by-step explanation:

Reflection in the y axis

(x, y) → (-x, y)

P(⁻²₋₄ ) → P'(²₋₄ ) ∴ P'(2, -4)

Q(⁻³₋₁ ) → Q'(³₋₁ ) ∴ Q'(3, -1)

R(⁻⁴₋₄ ) → R'(⁴₋₄ ) ∴ R'(4, -4)

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = the blood platelet counts of a group of women

So, X ~ Normal([tex]\mu=257.62, \sigma^{2} =62.1^{2}[/tex])

Now, the empirical rule states that;

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                   =  [tex]\frac{443.9-257.62}{62.1}[/tex]  = 3

       z-score of 71.3 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                =  [tex]\frac{71.3-257.62}{62.1}[/tex]  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Answer:

Only B

Step-by-step explanation:

Did this in Khan Academy.

=> Also, there are 2 '-' symbols in the question.

In Option A, there is only 1 "-' symbol.

In Option B, there are 2 '-' symbols.

Option C says none of the above.

Since, Option B has 2 '-' symbols, it is the correct.

Answer:

[tex]\Huge \boxed{y=-1}[/tex]

[tex]\rule[250]{250}{3}[/tex]

Step-by-step explanation:

[tex]y=14-0.5x[/tex]

The input x is 30. Switching x with 30.

[tex]y=14-0.5(30)[/tex]

Solving for y.

[tex]y=14-15[/tex]

[tex]y=-1[/tex]

[tex]\rule[250]{250}{3}[/tex]

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{y = - 1}}}}}[/tex]

Step-by-step explanation:

Given, Value of x is 30

To find : Value of y

[tex] \sf{y = 14 - 0.5x}[/tex]

Plug the value of x

⇒[tex] \sf{y = 14 - 0.5 \times 30}[/tex]

Multiply the numbers : 0.5 and 30

⇒[tex] \sf{y = 14 - 15}[/tex]

Subtract 15 from 14

⇒[tex] \sf{y = - 1}[/tex]

Hope I helped!

Best regards!!

===============================================

Work Shown:

Part I

[tex]\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\[/tex]

----------

Part II

[tex]\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\[/tex]

----------

Part III

[tex]\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\[/tex]

Answer: the three positive numbers are; 70, 70, 70

Step-by-step explanation:

Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

such that

x + y + z = 210

what is the maximum of xyz

take f(x,y,z) = xyz

Q(x,y,z) = 0

x + y + z -210 = 0

consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

F = xyz + λ(x+y+z-210)

dF/dx = 0 ⇒ yz + λ(1) = 0 ⇒ λ = -yz   ..............equ(1)

dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

dF/dz = 0 ⇒ xy + λ(1) = 0 ⇒ λ = -xy...............equ(3)

Now

equ(1)/equ(2) ⇒ λ/λ = -yz/-xz ⇒ x = +y

equ(1)/equ(3) ⇒ λ/λ = - yz/-xy ⇒ x = +z

⇒ y = z = x

by substitution

x + y + z = 210

x + x + x = 210

3x = 210

x = 210/3 = 70

∴ x, y, z = 70, 70 ,70

MAXIMUM

∛xyz = 70  { when x = y = z = 70}

Answer:

[tex] \frac{3}{5} [/tex]

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

[tex] \frac{9}{25} = (\frac{x}{y})^2 [/tex] (area of similar polygons theorem)

The scale factor of their sides would be [tex] \frac{x}{y} [/tex]. Which is:

[tex] \sqrt{\frac{9}{25}} = \frac{x}{y} [/tex]

[tex] \frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y} [/tex]

[tex] \frac{3}{5} = \frac{x}{y} [/tex]

Scale factor of their sides = [tex] \frac{3}{5} [/tex]

Answer:

3:5

Step-by-step explanation:

Answer:

We conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

Step-by-step explanation:

We are given that using traditional methods it takes 98 hours to receive an advanced flying license. A researcher believes the new technique may reduce training time and decides to perform a hypothesis test.

After performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance.

Let [tex]\mu[/tex] = mean time to receive an advanced flying license.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 98 hours

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 98 hours

Here, the null hypothesis states that it takes 98 hours to receive an advanced flying license.

On the other hand, the alternate hypothesis states the new technique may reduce training time that it takes less than 98 hours to receive an advanced flying license.

Now, it is stated that after performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance. This means we don't have sufficient evidence to support the null hypothesis as our test statistics will fall in the rejection region.

Therefore, we conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

Answer:

$12 up to $15

Step-by-step explanation:

Given

Hourly Earning: $6 - $9 || $9 - $12 || $12 - $15

Frequency:          16        ||         4      ||   10

Required

Determine the limits of the least frequency;

First, we have to determine the lowest frequency;

From the table. the lowest frequency is:

[tex]Lowest = 10[/tex]

Next is to determine the corresponding class limits

The corresponding class limit is $12 up to $15

Answer:

Area of the rectangular pen is: [tex]18 \,x-x^2[/tex]

Step-by-step explanation:

We need to specify that the perimeter of the rectangular area of side x adds to the amount of fence Pablo has (36 feet). Recall as well that the opposite sides of a rectangle are equal, so if there is a side of length x, there must be another one of this size as well (a total of 2 x in the perimeter),let's assume that the perpendicular sides to x are of length y, then:

Perimeter= 2 x + 2 y = 36

so, 2 (x+y)  = 36   then  (x+y) = 18

and therefore the side y should be:

y = 18 - x

Now we can write the formula for representing the area of the rectangle (product of both quantities: x * y

[tex]Area=x\,*\,y = x\,(18-x) =18 \,x-x^2[/tex]

Answer:

P=6x+8

A=2x^2+11x-21

Step-by-step explanation:

Perimeter:

P=2(x+7)+2(2x-3)

P=6x+8

Area:

A=(x+7)(2x-3)

A=2x^2+11x-21

Answer:

I tried to answer but I still would like to know what doesn't make sense.

Considering the identity:

[tex]\sec^2\theta-\tan^2\theta=1 \implies |\sec\theta|\geq1[/tex]

[tex]$\forall\;\theta\in\mathbb{R}-\{(2n+1)\frac{\pi}{2}, n\in\mathbb{Z} \}$[/tex]

The identity is true whenever both sides are defined. It is not supposed to hold the values when we have division by zero, because it is undefined.

If the value doesn't make sense, it is probably not a function, or it is undefined by the given value of [tex]x[/tex].

Let's go back to the definition of function again:

A function relates a set of inputs and a set of allowable outputs where each input is related to only one output. It basically defines the relation of ordered pairs.

Hope it helped you a bit.

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

verified

B.

Answer:

Give him or her brainlist

Step-by-step explanation:

^

|

|

Answer:

It has a negative slope = -2

Step-by-step explanation:

Let y be the price and x be the quantity purchased . Then putting the value of x in the equation we can find the price= y

where  y = −2x+8

x      0       1         2         3         4         5         6        7

y      8       6        4         2         0        -2         -4       -6

So we can plot the demand curve which has a negative slope.

We see from the values above that the slope is negative having a value equal to -2. This means that for every increase in the number of quantities there is a decrease in the price.

the corresponding amount in a 13% increase is: (59 * 13): 100 = $ 7.67

so the current stock price is: 59 + 7.67 = $ 66.67

Answer:

[tex]2.5[/tex]    [tex]-1.25[/tex]      [tex]\sqrt{16}[/tex]        [tex]0.6[/tex]

Step-by-step explanation:

Required

Which of the given parameters can be represented as fraction of integers

Taking them one at a time;

1.  2.5

This can be rewritten as

[tex]2.5 = \frac{2.5}{1}[/tex]

Multiply numerator and denominator by 2

[tex]2.5 = \frac{2.5 * 2}{1 * 2}[/tex]

[tex]2.5 = \frac{5}{2}[/tex]

Hence, 2.5 can be represented as fraction of integers

2.  √14

This can be rewritten as

[tex]\sqrt{14} = 3.74165738677...[/tex]

The ... implies that the decimal continues and this cannot be represented as a fraction

3.  -1.25

This can be rewritten as

[tex]-1.25 = \frac{-1.25}{1}[/tex]

Multiply numerator and denominator by 4

[tex]-1.25 = \frac{-1.25 * 4}{1 * 4}[/tex]

[tex]-1.25 = \frac{-5}{4}[/tex]

Hence, -1.25 can be represented as fraction of integers

4.  5.33333.....

The ... implies that the decimal continues and this cannot be represented as a fraction

5.  √16

[tex]\sqrt{16} = \±4[/tex]

This can be rewritten as

[tex]\sqrt{16} = \±\frac{4}{1}[/tex]

Multiply numerator and denominator by 2

[tex]\sqrt{16} = \±\frac{4 * 2}{1 * 2}[/tex]

[tex]\sqrt{16} = \±\frac{8}{2}[/tex]

Hence, √16 can be represented as fraction of integers

6.  0.6

This can be rewritten as

[tex]0.6 = \frac{0.6}{1}[/tex]

Multiply numerator and denominator by 10

[tex]0.6 = \frac{0.6 * 10}{1 * 10}[/tex]

[tex]0.6 = \frac{6}{10}[/tex]

Hence, 0.6 can be represented as fraction of integers

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

Step-by-step explanation:

Hey there!!

Let angle 2 be x then,

measure of angle 1 is three less than twice of angle 2 = 2x-3.

Now, we have.

Measure of supplementary angle is 180°.

Angle 1 + angle 2 = 180°

x+(2x - 3)= 180°

3x -3=180°

3x= 180°+3°

[tex]x = \frac{183}{3} [/tex]

Therefore, x = 61°.

Now, angle 2 = 61°

angle 1 = (61×2-3)= 119°.

check (119°+61°=180°).

Hope it helps...

Answer: Mass of Lamina is (K/3)

Centre of mass is (3/8, 3pi/16)

Step-by-step explanation:

Find explanation in the attachments

Complete questions:

A deposit of $200 is made in an account at the beginning of each month at an annual interest rate of 3% compounded monthly. The balance in the account after n months is An = 200(401)(1.0025^n - 1).(Round your answers to two decimal places.)

Answer:

Kindly check explanation

Step-by-step explanation:

Given the amount of balance in an account after. 'n' months using the eqation:

An = 200(401)(1.0025^n - 1)

(a) Compute the first six terms of the sequence {An}.

A1 = 200(401)(0.0025) = $200.50

A2 = 200(401)(1.0025^2 - 1) = $401.50

A3 = 200(401)(1.0025^3 - 1) = $603.00

A4 = 200(401)(1.0025^4 - 1) = $805.01

A5 = 200(401)(1.0025^5 - 1) = $1007.53

A6 = 200(401)(1.0025^6 - 1) = $10210.54

B) balance 5 years after n = 5 * 12 = 60

A60 = 200(401)(1.0025^60 - 1) = $12,961.67

C.) balance 15 years after ; n = 15 * 12 = 180

A180 = 200(401)(1.0025^180 - 1) = $45,508.02

Each interior angle of a rectangle measures 90°

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°). The opposite sides of a rectangle are equal and parallel.

According to the property of a rectangle, we have,

Hence, Each interior angle of a rectangle measures 90°

For more references on rectangle, click;

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Answer:

Step-by-step explanation:

[tex] \sf{7h + 2 + 4}[/tex]

Add the numbers

⇒[tex] \sf{7h + 6}[/tex]

Hope I helped!

Best regards!

Answer:

7h+6

Step-by-step explanation:

We are given the expression:

7h + 2 + 4

and asked to simplify.

In order to simplify an expression, we must combine like terms. In this expression, we have 2 constants, or terms without variables. The 2 constants and 2 and 4. Add 2 and 4.

7h + (2+4)

7h+6

There are no more like terms, so this expression is simplified.

The expression 7h+2+4 simplified is 7h +6

Answer:

f(7)=10-14=-4

Answer=-4

Step-by-step explanation:

Answer:

-4

Step-by-step explanation:

f(x)=10-2x

Let x = 7

f(7) = 10 -2(7)

     = 10 -14

     = -4

Answer: 24 m

Step-by-step explanation:

Given: area of the circle is 144 π m² .

Area of a circle = [tex]\pi r^2[/tex], where r= radius of the circle.

Then, [tex]144\pi = \pi r^2[/tex]

Cancelling π from both sides , we get

[tex]144 = r^2[/tex]

Taking square root on both sides , we get'

[tex]12= r[/tex]

i.e. radius = 12 m

Then diameter = 2 (radius ) = 2 (12)= 24 m

Hence, the diameter of the circle is 24 m.

The diameter of the circle is 13.54cm

The formula for calculating the area of the circle is expressed as:

A = πd²/4

d is the diameter of the circle

GIven the following

A = 144m²

Substitute the area into the circle

144 = πd²/4

πd² = 144 * 4

πd² = 576

d² = 576/3.14

d² =183.44

d = 13.54cm

Hence the diameter of the circle is 13.54cm

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Answer:

i dont what it is can u tell me

Step-by-step explanation:

The length side is not a integer. Therefore, The answer is irrational.

The area of a square is given by the formula

A = side x side

In this problem we have

A = 150 square feet.

Now, substitute in the formula

150 = side^2

Now, take the square root both sides

side = √150

Then simplify

side = 5√6 feet

Remember that; A Rational Number is a number that can be made by dividing two integers. soThe length side is not a integer

Therefore, The answer is irrational.

Learn more about the area;

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Answer:

It depends on the measure of the angle you are talking about

Answer:

7/40

Step-by-step explanation:

Simplify the following:

-1/5 + 3/8

Hint: | Put the fractions in -1/5 + 3/8 over a common denominator.

Put -1/5 + 3/8 over the common denominator 40. -1/5 + 3/8 = (-8)/40 + (5×3)/40:

(-8)/40 + (5×3)/40

Hint: | Multiply 5 and 3 together.

5×3 = 15:

(-8)/40 + 15/40

Hint: | Subtract the fractions over a common denominator to a single fraction.

-8/40 + 15/40 = (-8 + 15)/40:

(-8 + 15)/40

Hint: | Subtract 8 from 15.

-8 + 15 = 7:

Answer:  7/40