Simply the question in the picture

Answer:

Infinity

Step-by-step explanation:

It is equal to nothing.

2x+2=2x+2

-2x     -2x    

2=0x+2

-2      -2

0=0

Answer:

( − ∞ , ∞ )

Step-by-step explanation:

Distribute the 2 in 2 (x+1)

2 ⋅ x = 2 x

2 ⋅ 1 = 2

Combine:

2 x + 2

Equation is now:

2 x + 2 = 2 x + 2

Subtract 2 from both sides of the equation:

2 x = 2 x

Divide both sides by 2:

x=x

Both sides of the equation are the same:

x = x

Any real number or:

( − ∞ , ∞ )

Answer:

1) The engine torque is approximately 134.33 N·m

2) The speed of the engine  is approximately 4,469.15 revolutions per minute

Step-by-step explanation:

1) The drag coefficient, [tex]c_d[/tex], is given by the formula;

[tex]c_d = \dfrac{2 \cdot F_d}{\rho \cdot u^2 \cdot A}[/tex]

Where;

[tex]c_d[/tex] = 0.28

[tex]F_d[/tex] = The drag force

ρ = The fluid density = 0.00206 slugs/ft³ = 1.06168037 kg/m³

u = The object's flow speed = 130 mi/h = 58.1152 m/s

A = The frontal area = 19.8 ft² = 1.83948 m²

[tex]F_d = \dfrac{c_d \cdot \rho \cdot u^2 \cdot A }{2}[/tex]

∴ [tex]F_d[/tex] = (0.28 × 1.06168037 × (58.1152)² × 1.83948)/2 ≈ 923.4 N

We have;

[tex]F_d = \dfrac{M_e \cdot \varepsilon _0 \cdot \eta _d }{r}[/tex]

Where;

[tex]M_e[/tex] = The engine torque

ε₀ = The overall gear reduction ratio = 2.5

[tex]\eta _d[/tex] = The drivetrain efficiency = 0.88

r = The wheel radius = 12.6 inches = 0.32004 meters

[tex]\therefore M_e = \dfrac{F_d \cdot r }{ \varepsilon _0 \cdot \eta _d}[/tex]

[tex]\therefore M_e = \dfrac{F_d \cdot r }{ \varepsilon _0 \cdot \eta _d} \approx \dfrac{923.4 \times 0.32004 }{ 2.5 \times 0.88} \approx 134.33 \ N\cdot m[/tex]

The engine torque = [tex]M_e[/tex] ≈ 134.33 N·m

The engine torque ≈ 134.33 N·m

2) The speed of the engine, [tex]n_e[/tex], is obtained from the following formula;

[tex]v = \dfrac{2 \cdot \pi \cdot r \cdot n_e \cdot (1 - i)}{\varepsilon _0}[/tex]

Where;

v = The vehicle's speed = 130 mi/h = 58.1152 m/s

r = The wheel radius = 12.6 inches = 0.32004 meters

i = The drive axle slippage = 3% = 3/100 = 0.03

ε₀ = The overall gear reduction ratio = 2.5

[tex]\therefore n_e = \dfrac{v \times \varepsilon _0 }{2 \times \pi \times r \times (1 - i)} = \dfrac{58.1152 \times2.5 }{2 \times \pi \times 0.32004 \times (1 - 0.03)} \approx 74.486 \ rev /second[/tex]

The speed of the engine in revolution per minute = 60 seconds/minute × 74.486 rev/second ≈ 4,469.15 revolutions per minute

The speed of the engine  ≈ 4,469.15 revolutions per minute.

Answer:

We start with this equation:

If x intercept is -4 then y = 0 giving us another point (-4, 0)

(4, -7) and (-4, 0)

slope = y difference / x difference = (-7 -0) / (4 --4) =

-7 / 8

Step-by-step explanation:

Answer:

$6

Step-by-step explanation:

Ok, first thing is first, we need to find what 20% of 30 is. We do that by setting 20% in decimal form and multiplying that by 30.

So first,

0.20 * 30

We cross out the zero in 30 and move the decimal point one spot to the right in 0.20. So now we have:

= 2.0 * 3

Which really is,

= 2 * 3

Which equals,

6

Or,

$6

Yes! We got our answer! Nice work!

(The total bill including the tip would be $36 in case you needed to know)

Answer:

3.450*10^4

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Given

a² - 1 = 0 ( add 1 to both sides )

a² = 1 ( take the square root of both sides )

a = ± [tex]\sqrt{1}[/tex] = ± 1

solution is { 1, - 1 } → D

Answer:

D) {1, -1}

Step-by-step explanation:

Please share the instructions for this problem:  Solve a^2 - 1 = 0, or find the roots of a^2 - 1 = 0.

Answer D is correct.  Try substituting 1 for a, and then -1 for a.  In both cases the given equation is true.

Answer:

The first step is to place the compass needle on one of the ends of the given segment AB, and draw an arc above and below the segment AB

Step-by-step explanation:

The steps to construct a perpendicular to segment AB are;

1) Place the compass needle on one of the ends of the given segment AB, and draw an arc above and below the segment AB

2) With the same compass width, place the compass needle on the other end of segment AB, and draw an arc above and below the segment AB intersecting the arcs constructed in step 1 above. Label the point of intersection as C and D

3) With a straight edge, draw a line joining the points of intersection C and D of the two arcs. The line CD. is the perpendicular bisector of the segment AB.

Answer:

A and B

Step-by-step explanation:

Given

(3x + 7)(2x - 5) = 0

Equate each factor to zero and solve for x

3x + 7 = 0 ⇒ 3x = - 7 ⇒ x = - [tex]\frac{7}{3}[/tex] → A

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = [tex]\frac{5}{2}[/tex] → B

The roots of the quadratic equation are x = -7/3 and x = 5/2.

The correct option is A and B.

For variable x : ax² + bx + c = 0, where a≠0 is a standard quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution since it is a second-order polynomial equation, which is guaranteed by the algebraic basic theorem.

Given:

A quadratic equation in the factored form,

(3x+7) (2x-5) = 0.

So, 3x + 7 = 0 or 2x - 5 = 0

x = -7/3 and x = 5/2

Therefore, the roots are x = -7/3 and x = 5/2

To learn more about the quadratic equation;

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Answer:

10/8 or 5/4

Step-by-step explanation:

It is pretty easy. If you look at the problem it says "1/8 of a gram of honey to make 1/10 of a cake" That means that we should multiply 1/8 by 10 so it will become a whole cake.

1/8 * 10 = 10/8

If you want we can simplify it.

5/4

And that's your answer!

Answer:

The correct answer will be "1197.93".

Step-by-step explanation:

According to the question:

Semi annual coupon:

= [tex]10 \ percent\times \frac{1000}{2}[/tex]

= [tex]50[/tex]

Number of periods:

= [tex]20\times 2[/tex]

= [tex]40[/tex]

Semi annual YTM:

= [tex]\frac{8}{2} \ percent[/tex]

= [tex]4 \ percent[/tex]

Now,

The market value of bond will be:

= PV of Coupons + PV of Par Value

On putting the values, we get

= [tex]50\times (\frac{(1-(1+4 \ percent)^{-40})}{4 \ percent} )+\frac{1000}{(1+4 \ percent)^{40}}[/tex]

= [tex]1197.93[/tex]

Note: percent = %

Answer:

(a) [tex]3\frac{2}{3}[/tex] boxes of cat food had been sold.

(b) [tex]\frac{11}{3}[/tex] boxes of cat food had been sold.

Step-by-step explanation:

From the question,

Polly stacked the tins from five boxes of cat food onto an empty shelf and there were 15 tins of cat food in each box. That is,

5 × 15 tins of cat food were stacked onto the empty shelf.

5 × 15 = 75

Hence, 75 tins of cat food were stacked onto the empty shelf.

Also, from the question,

At the end of the week there were 20 tins left on the shelf and the rest of the tins had been sold, that is

75 - 20 tins had been sold

75 - 20 = 55

Hence, 55 tins of cat food had been sold.

To determine the number of boxes of cat food that had been sold,

Since there are 15 tins of cat food per box, then

we will divide 55 tins of cat food that had been sold by 15 tins of cat food per box

55 ÷ 15 = [tex]\frac{55}{15}[/tex]

Hence, [tex]\frac{55}{15}[/tex] boxes of cat food had been sold

(a) As a mixed number

[tex]\frac{55}{15} = 3\frac{2}{3}[/tex]

Hence, [tex]3\frac{2}{3}[/tex] boxes of cat food had been sold.

(b) As an improper fraction

[tex]\frac{55}{15} = \frac{11}{3}[/tex]

Hence, [tex]\frac{11}{3}[/tex] boxes of cat food had been sold.

The price at which they will sell the car is $34.30.

A discount reduces the carrying value of the model car. If the price of the car is discounted by 5% everyday, it means that the car decreases at an exponential rate. When there is an exponential decrease, the value of the car falls faster with the passage of time.

Exponential functions have this form [tex]e^{x}[/tex]

Where:

The formula that can be used to determine the price at which they will sell the car is:

Selling price = initial value x (1 - discount rate)^number of days

$40 x (1 - 0.05)^3

$40 x 0.95^3 = $34.30

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Answer:

D.

Step-by-step explanation:

D. 60 + 12w = 95 + 7W

Answer:

6 mugs

Step-by-step explanation:

6*4=24

add the remainder 2 to get 26,

since its just asking for the 4 boxes the answer is 6

Answer:

So the volume expands as kinetic energy is gained and the more mass there is the more kinetic energy there will be. Hopefully this helps you and if it doesn't I will add on to it, just lmk.

Answer:

Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R

Step-by-step explanation:

Answer:

we need the picture

Step-by-step explanation:

Answer:

add a picture please

Step-by-step explanation:

Answer:

y=.75x-2

Step-by-step explanation:

4,1

8,4

3/4 or .75x

to check answer:

(.75*8)=6

6-2

4

The equation of the line shown in the graph is y = 4x / 5 -2.

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,

Points located on the graph that lies on the line are (0, -2), and (2.5, 0)

The slope of the line is given as,

m = (y₂ - y₁) / (x₂ - x₁)

Substitute the value in the above equation,

m = 0+ 2 / 2.5 -0 = 20/25
m = 4 / 5

The equation of the line is given as

y - y₁ = m (x - x₁)

Substitute the one point (-2, 0) and m in the above equation,
y + 2 = 4/5 (x - 0)

y = 4x / 5 -2

Thus, the equation of the line shown in the graph is y = 4x / 5 -2.

Learn more about slopes here:

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Answer:

169.72

Plz like if you like my answer

Answer:

The  probability   [tex]P(\^ p > 0.80) = 0.99957[/tex]

Step-by-step explanation:

From the question we are told that

     The population proportion is  p  =  0.90

     The sample size is  n  =  30

  Generally mean of the sampling distribution is  [tex]\mu_{\= x } = p = 0.90[/tex]

Generally the standard deviation is mathematically represented as

      [tex]\sigma = \sqrt{\frac{p( -p )}{n} }[/tex]

=>    [tex]\sigma = \sqrt{\frac{0.90( 1 -0.90 )}{100} }[/tex]

=>    [tex]\sigma = 0.03[/tex]

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

       [tex]P(\^ p > 0.80) = P(\frac{ \^ p - p }{ \sigma } > \frac{0.80 - 0.90}{0.03} )[/tex]

Generally [tex]\frac{\^p - p}{\sigma} = Z(The standardized \ value \ of \^ p)[/tex]

So  

    [tex]P(\^ p > 0.80) = P(Z > -3.33 )[/tex]

From the z-table [tex]P(Z > -3.33 ) = 0.99957[/tex]

So

    [tex]P(\^ p > 0.80) = 0.99957[/tex]

Answer:

rational

Step-by-step explanation:

it can be written as a ratio like 42260/1

brainliest?? please

Answer:

Rational

Step-by-step explanation:

This number is a whole, even number. It does not fit the criteria to be irrational because it can be written as a simple fraction

Answer:

A - chase did not make a mistake

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Chase did not make a mistake, to get rid of the fraction you multiply both sides by three giving you g-3=9.

and then he adds 3 to both sides giving g=12

Answer:

the mean is 5

Step-by-step explanation:

because if you add all the numbers and divide by the number of digits you should get the equation 40/8= 5 and that´s the answer

Answer: 5

Step-by-step explanation:

add up all the numbers, then divide by how many integers there are.

2+3+4+4+4+5+8+10=40

40 divided by 8 equals 5

9514 1404 393

Answer:

  6.302×10^7 kg

Step-by-step explanation:

Since we want to find the difference in mass, we need to have the same exponent on both numbers. For that purpose, it is convenient to change the representation of the train's mass to 0.998×10^7 kg.

The carrier has more mass by the amount of ...

  7.3×10^7 -0.998×10^7 = (7.300 -0.998)×10^7 = 6.302×10^7 . . . kg

_____

Your (scientific or graphing) calculator or a spreadsheet can figure this for you and give you the scientific notation display.

Answer:

W (6,-7) X(3,-6) Y (1,-3) Z(7,-1)

Step-by-step explanation:

This is the answer because to do this you have to know that the 180 degress (x,y) changes to (-x,-y) The negative sign means opposite so, if it is Z(-7,1) it changes to (7,-1).

Hope this helped!

Answer:

5

Step-by-step explanation:

2x+10+3x-6=29

5x+4=29

5x=25

x=5

Answer:

P(2,3) thats the answer ;)

Answer:

a. Practically speaking, you compute the differential in much the same way you compute a derivative via implicit differentiation, but you omit the variable with respect to which you are differentiating.

Aside: Compare this to what happens when you differentiate both sides with respect to some other independent parameter, say :

b. This is just a matter of plugging

Step-by-step explanation:

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