Mathematics High School

Re-write the following expression using ADDITION ONLY:
12- 3+16 - 37 - (-20)

Answers

Answer 1

12- 3+16 - 37 - (-20)
=9+16-37-(-20)
=25-37-(-20)
=-12-(-20)
=8
(therefore ur answer would be 8)

Answer 2

Answer:

12- 3+16 - 37 -( 20)

Step-by-step explanation:

Two negatives are a positive , this really helps

Related Questions

A washer and a dryer cost $587 combined. The washer costs $63 less than the dryer. What is the cost of the dryer?

Answers

Answer:

The dryer costs $325.

Step-by-step explanation:

Let w represent the cost of the washer and d represent the cost of the dryer.

They cost $587 combined. In other words:

[tex]w+d=587[/tex]

The washer costs $63 less than the dryer. Therefore:

[tex]w=d-63[/tex]

Thus, we have the system of equations:

[tex]\displaystyle \begin{cases} w+d = 587 \\ w=d-63\end{cases}[/tex]

We can solve it using substitution. Substitute the second equation into the first. Hence:

[tex](d-63)+d=587[/tex]

Combine like terms:

[tex]2d-63=587[/tex]

Add 63 to both sides:

[tex]2d=650[/tex]

And divide both sides by two. Hence:

[tex]d=325[/tex]

The dryer costs $325.

Further Notes:

And since the washer is $63 less, the washer costs:

[tex]w=(325)-63=262[/tex]

The washer costs $262.

Find the area of the region between the curve x^3+2x^2-3x and the x-axis over the interval [-3,1]

Answers

Answer:

[tex]\displaystyle A = \frac{32}{3}[/tex]

General Formulas and Concepts:

Calculus

Integrals

Definite IntegralsArea under the curve

Integration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Area of a Region Formula: [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Curve: x³ + 2x² - 3x

Interval: [-3, 1]

Step 2: Find Area

Set up: [tex]\displaystyle A = \int\limits^1_{-3} {(x^3 + 2x^2 - 3x)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + \int\limits^1_{-3} {2x^2} \, dx - \int\limits^1_{-3} {3x} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + 2\int\limits^1_{-3} {x^2} \, dx - 3\int\limits^1_{-3} {x} \, dx[/tex][Integrals] Integrate [Integration Rule - Reverse Power Rule]: [tex]\displaystyle A = (\frac{x^4}{4}) \bigg| \limits^1_{-3} + 2(\frac{x^3}{3}) \bigg| \limits^1_{-3} - 3(\frac{x^2}{2}) \bigg| \limits^1_{-3}[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle A = -20 + 2(\frac{28}{3}) - 3(-4)[/tex]Evaluate: [tex]\displaystyle A = \frac{32}{3}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Which expressions are in the simplest form? Check all that apply.

(Please help, I've been stuck on this all afternoon)

Answers

Answer:

All options are correct.

Step-by-step explanation:

We have to find the expression which are in the simplest form.

A.[tex]x^{-3}+y^3[/tex]