£4100 is deposited into a bank paying 13.55% interest per annum , how much money will be in the bank after4 years

Answer:

Therefore, for Ruhama's average to be less than 80, the value of x must be less than 80.

Step-by-step explanation:

Let's use the formula for the average (or mean) of a set of numbers: average = (sum of numbers) / (number of numbers)

To find the value of x that makes Ruhama's average less than 80, we need to solve the following inequality:

(75 + 80 + 85 + x) / 4 < 80

Multiplying both sides by 4 gives:

75 + 80 + 85 + x < 320

Simplifying:

x < 320 - 75 - 80 - 85 x < 80

Answer:

D. -1/2

Step-by-step explanation:

slope = rise/run = 1/-2 = -1/2

a) The mean, median, and mode price of the cars bought by the car dealer are:

b) If the car dealer sells the cars for 20% more than the purchase prices, the mean, median, and mode prices will increase to:

c) With the payment of an additional Euro 1,000 as transfer fees, the mean, median, and mode prices will increase to:

The mean is the quotient of the total value divided by the number of items in the data set.  It is also known as the average.

The median is the middle value in an ordered list (ascending or descending).

On the other hand, the mode is the value that occurs most often in the data set.

The prices of different cars:

Car 1 = Euro 5,000

Car 2 = Euro 3,000

Car 3 = Euro 2,000

Car 4 = Euro 6,000

Car 5 = Euro 7,000

Car 6 = Euro 2,000

Car 7 = Euro 3,000

Car 8 = Euro 9,000

Car 9 = Euro 3,000

Car 10 = Euro 4,000

Total value = Euro 44,000

Mean = Euro 4,400 (Euro 44,000/10)

Mode = Euro 3,000

Median = Euro 3,500 (Euro 3,000 + Euro 4,000)

b) Markup = 20%

Cost price = 100%

Selling price = 120% (100 + 20)

Mean = Euro 5,280 (Euro 4,400 x 1.2)

Median = Euro 4,200 (Euro 3,600 x 1.2)

Mode = Euro 3,600 (Euro 3,000 x 1.2)

c) Additional Transfer Fees of Euro 1,000:

Mean = Euro 6,280 (Euro 4,400 x 1.2 + Euro 1,000)

Median = Euro 5,200 (Euro 3,600 x 1.2 + Euro 1,000)

Mode = Euro 4,600 (Euro 3,000 x 1.2 + Euro 1,000)

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There are 20 students who wrestle and 20 students who play basketball, for a total of 40 students altogether.

What is read-draw-write process?

The Read-Draw-Write process is a problem-solving strategy that can be used to help students organize their thoughts and work systematically through a problem. It involves three steps:

Read the problem: Students should carefully read and understand the problem they are trying to solve.

Draw a diagram or picture: Students should create a visual representation of the problem to help them better understand it and identify any relationships between the different parts of the problem.

Write an equation or statement: Students should use the information from the problem to write an equation or statement that represents the relationships between the different parts of the problem.

To solve the problem using the Read-Draw-Write process:

Read:

There are as many students who wrestle as students who play basketball

There are 20 students who play basketball

Draw:

Let "wrestle" represent the number of students who wrestle

Let "B Ball" represent the number of students who play basketball

Write:

We know that "wrestle" = "B Ball"

We also know that "B Ball" = 20

So we can substitute "B Ball" with 20 in the first equation:

wrestle = B Ball

wrestle = 20

Therefore, there are 20 students who wrestle and 20 students who play basketball, for a total of 40 students altogether.

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By answering the presented questiοn, we may cοnclude that Since a line equatiοn parallel tο this οne will have the same slοpe, the slοpe οf the parallel line is alsο 5/6.

When twο expressiοns are equal, a mathematical equatiοn is a statement stating that equality. Twο sides are jοined by the algebraic symbοl (=), and tοgether they make up an equatiοn. Fοr instance, the claim that "2x + 3 = 9" means that "2x plus 3" equals the number "9" is made in this argument. Finding the value(s) οf the variable(s) necessary fοr the equatiοn tο be true is the gοal οf sοlving equatiοns.

There are variοus types οf equatiοns, including regular and nοnlinear οnes with οne οr mοre elements. "x² + 2x - 3 = 0" is an equatiοn that raises the variable x tο the secοnd pοwer. Mathematical disciplines like algebra, calculus, and geοmetry all make use οf lines.

the given equatiοn:

[tex]$\begin{array}{c}{{5x-6y=30}}\\ {{-6y=-5x+30}}\\ {{y=(5/6)x-5}}\end{array}$[/tex]

Sο the slοpe οf the given line is 5/6.

Since a line parallel tο this οne will have the same slοpe, the slοpe οf the parallel line is alsο 5/6.

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Thus, the rectangular fence has a 15-meter width.

We must determine the fence's length. The equation A=lw, where l seems to be the length & w is the width, determines the surface area A of a rectangle.

Let the variable "w" stand in for the rectangular fence's width.

We are aware that the fence's perimeter measures 54 metres in total.

Since a rectangle's opposite sides are identical in length and the fence contains four sides, we may write the following equation to get the perimeter:

(Length + Width)2 = the perimeter

Inputting the values provided yields:

54 = 2(12 + w)

After simplifying and finding "w," we arrive at:

54 = 24 + 2w

2w = 30

w = 15

Hence, the rectangular fence's width is 15 meters.

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The probability that less than 70 are dissatisfied with their vacation time is  approximately 0.000008.

The normal distribution can be used to approximate this binomial distribution.

The probability that less than 70 are dissatisfied with their vacation time is approximately 0.0082, using the normal curve approximation.

Using the binomial formula:

n = 500

p = 0.16

q = 1 - p = 0.84

We want to find P(X < 70), where X is the number of people out of 500 who are dissatisfied with their vacation time.

P(X < 70) = Σi=0^69 (500 choose i) * 0.16^i * 0.84^(500-i)

Using technology, we can find this probability to be approximately 0.000008.

To show that this distribution can be approximated by the normal distribution, we need to check if the conditions for the normal approximation are met:

np = 500 * 0.16 = 80 ≥ 10

nq = 500 * 0.84 = 420 ≥ 10

Since both conditions are met, we can use the normal distribution to approximate this binomial distribution.

To use the normal curve to approximate the probability that less than 70 are dissatisfied with their vacation time, we need to standardize the binomial distribution:

μ = np = 80

σ = sqrt(npq) = sqrt(500 * 0.16 * 0.84) ≈ 4.58

We want to find P(X < 70), which is equivalent to finding the probability that a standard normal variable Z is less than (69.5 - 80) / 4.58 = -2.37.

Using a standard normal table or technology, we find this probability to be approximately 0.0082.

Therefore, the probability that less than 70 are dissatisfied with their vacation time is approximately 0.0082, using the normal curve approximation.

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Answer:

Step-by-step explanation:

1st find v solving 3v + 1 = 7

3v + 1 = 7

3v = 7 - 1

3v = 6

v = 6 : 3

v = 2

v + 8 =

replace v with 2

2 + 8 = 10

Answer:

10

Step-by-step explanation:

Solve for the value of the variable, v, in the given equation of 3v + 1 = 7, by isolating the variable. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

~

First, subtract 1 from both sides of the equation:

[tex]3v + 1 = 7\\3v + 1 (-1) = 7 (-1)\\3v = 7 - 1\\3v = 6[/tex]

Next, divide 3 from both sides of the equation:

[tex]3v = 6\\\frac{3v}{3} = \frac{6}{3} \\v = \frac{6}{3} \\v = 2[/tex]

Then, plug in 2 for v in the first given expression:

[tex]v + 8\\=(2) + 8\\=10[/tex]

10 is your answer for v + 8 when 3v + 1 = 7.

~

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Explanation:

There are 3 ways to select the single math book and [tex]4\times3\div2 = 12\div2 = 6[/tex] ways to pick the two other books that are either physics or history (order doesn't matter). This is effectively because we have [tex]3+1 = 4[/tex] books that are either physics or history, and we're using the nCr combination formula.

Overall, there are [tex]3\times6 = 18[/tex] ways to select the three books such that one is math, and the other two are either physics or history.

-------------------

There are [tex]3+3+1 = 7[/tex] books total. Since we're selecting 3 of them, we use the nCr formula again and you should get 35.

Or you could note how [tex](7\times6\times5)\div(3\times2\times1) = 210\div6 = 35[/tex]

This says there are 35 ways to select any three books where we can tell the difference between any subject (ie we can tell the difference between the math books for instance).

-------------------

We found there are 18 ways to get what we want out of 35 ways to do the three selections. Therefore, the answer as a fraction is 18/35

a. Coefficient of .x³in (1 + .x)⁶ is 20. b. Coefficient of .x³ in (2.x - 3)⁶ is -540. c. Coefficient of .x³ in (x + 1)²⁰ + (x - 1)²⁰ is zero. d. Coefficient of .x³ y³ in (.x + 1)⁴ is 4.

a. To find the coefficient of .x³ in the expansion of (1 + .x)⁶, we can use the binomial theorem. The coefficient of .x³ is given by the expression 6C₃(1)³(.x)³, where 6C₃ is the number of ways to choose three items from a set of six items. Evaluating this expression gives us:

6C₃(1)³(.x)³ = (6!)/(3!3!)(1³)(.x)³ = 20(.x)³

Therefore, the coefficient of .x³ in (1 + .x)⁶ is 20.

b. Similarly, we can use the binomial theorem to find the coefficient of .x³ in the expansion of (2.x - 3)⁶. The coefficient of .x³ is given by the expression 6C₃(2.x)³(-3)⁶, which simplifies to:

6C₃(2³)(.x)³(-3)⁶ = 6C₃(8)(.x)³(729)

The value of 6C₃ is 20, so we have:

20(8)(.x)³(729) = 116,640(.x)³

Therefore, the coefficient of .x³ in (2.x - 3)⁶ is -116,640.

c. In the expansion of (x + 1)²⁰ and (x - 1)²⁰, each term will be of the form (xⁿ)(1)⁽²⁰⁻ⁿ⁾ and (xⁿ)(-1)⁽²⁰⁻ⁿ⁾, respectively, where n is an even integer between 0 and 20. Since the powers of x are even, the only term that can contain .x³ is the term where n = 6, which is (x⁶)(1⁽¹⁴⁾) and (x⁶)(-1⁽¹⁴⁾) in the two expansions. Adding these two terms together gives us:

(x⁶)(1⁽¹⁴⁾ - 1⁽¹⁴⁾) = 0

Therefore, the coefficient of .x³ in (x + 1)²⁰ + (x - 1)²⁰ is zero.

d. To find the coefficient of .x³ y³ in (.x + 1)⁴, we can use the binomial theorem once again. The coefficient of .x³ y³ is given by the expression 4C₁(1³)(.x)³(y)¹, which simplifies to:

4C₁(1³)(.x)³(y)¹ = 4(.x)³(y)

Therefore, the coefficient of .x³ y³ in (.x + 1)⁴ is 4.

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Without the table indicating the stated premium rates and applicable discounts, the monthly property insurance cannot be computed. Hence, on the assumption that the rate is 2.5% and the discount applicable is 7.5% the premium per month will come to $152.24

The simple definition of Property Insurance is, it is an insurance policy that covers a policyholder for the structure of a building and its contents against stated or agreed perils.

Given (based on assumption) that the applicable annual rate is 2.5%

and that:

Hence annual premium will be:

= (67,000 + 12000) * (2.5/100) * 0.925

Annual Premium Payable = $1,826.89.............A

Recall that we are asked to derive the monthly Insurance premium.

This is thus given as: Answer in A/12

→  1,826.89/12

= $152.24

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Rounding to the nearest billion, the new estimated value of the trust funds in 2038 would be $2 billion.

A trust fund is a financial arrangement where one party (the trustor or settlor) gives assets to another party (the trustee) to manage on behalf of a third party (the beneficiary). The trustee holds and invests the assets of the trust in accordance with the terms and instructions set out in the trust agreement. Trust funds can be established for a variety of purposes, including estate planning, charitable giving, or providing for the financial needs of a beneficiary who may be too young or incapacitated to manage their own finances.

Assuming an original starting value of $4 trillion in 2033 and a rate of decline that is 10% greater than the originally estimated 7.6% rate, the new rate of decline would be 7.6% + (10% * 7.6%) = 8.36%.

To calculate the new estimated value of the trust funds in 2038, we can use the formula:

Value in 2038 = Starting Value * (1 - Rate of Decline)ⁿ

Plugging in the values, we get:

Value in 2038 = $4 trillion * (1 - 0.0836)⁵

Value in 2038 = $4 trillion * 0.6002

Value in 2038 = $2.401 trillion

Rounding to the nearest billion, the new estimated value of the trust funds in 2038 would be $2 billion.

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If the number of drinks consumed by a small group is 4, 4, 6, 7, and 8, the number 6 would be the median for that group.

The median is a measure of central tendency in a set of data, and it represents the middle value of the data set when the values are arranged in order. To find the median of a set of data, we follow these steps:

Arrange the data in order from smallest to largest (or from largest to smallest).

If the number of data points is odd, the median is the middle value.

If the number of the data points is even, then the median is the average of the two middle values.

For example, if we have the data set {2, 4, 5, 7, 9}, we would arrange it in order to get {2, 4, 5, 7, 9}. Since there are an odd number of data points (5), the median is the middle value, which is 5.

If we have the data set {2, 4, 5, 7, 9, 10}, we would arrange it in order to get {2, 4, 5, 7, 9, 10}. Since there are an even number of data points (6), the median is the average of the two middle values, which are 5 and 7. Therefore, the median is (5 + 7)/2 = 6.

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With the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.

A Venn diagram is a visual representation that makes use of circles to highlight the connections between different objects or limited groups of objects.

Circles that overlap share certain characteristics, whereas circles that do not overlap do not.

Venn diagrams are useful for showing how two concepts are related and different visually.

When two or more objects have overlapping attributes, a Venn diagram offers a simple way to illustrate the relationships between them.

Venn diagrams are frequently used in reports and presentations because they make it simpler to visualize data.

So, we need to find:

A ∪ B

Now, calculate as follows:

The collection of all objects found in either the Blue or Green circles, or both, is known as A B. Its components number is:

8 + 7 + 14 + 6 + 1 + 8 = 44

n(A∪B) = 44

Therefore, with the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.

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Answer:

Step-by-step explanation:

kbggfdtddcsfbdfserenis amazing

Answer: B)

Step-by-step explanation:

Answer:

250 and 250.1

Answer:

250.1

Step-by-step explanation:

5002 divided by 20 equals 250.1

The sample mean X is an unbiased estimator for θ.

To find a suitable statistic as an unbiased estimator for θ, we need to find a function of sample Y, YS, ..., Yn whose expected value is equal to θ.

X = (Y + YS + ... + Yn) / n

To show that X is unbiased, we need to calculate its expected value and show that is equal to θ:

E[X] = E[(Y + YS + ... + Yn) / n]

= (1/n) E[Y + YS + ... + Yn]

= (1/n) [E[Y] + E[YS] + ... + E[Yn]]

= (1/n) [nθ] (by the given density function)

= θ

Therefore, sample mean X is an unbiased estimator for θ.

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Answer:

No

She needs 3/80 cup more

Step-by-step explanation:

She needs 3/8 cup plus 3/5 cup.

3/8 + 3/5 = 15/40 + 24/40 = 39/40

She has 15/16 cup

15/16

39/40 = 78/80

15/16 = 75/80

She has 75/80 cup and needs 78/80 cup.

She does not have enough sugar.

78/80 - 75/80 = 3/80

She needs 3/80 cup more.

Step 1: Calculate the total volume of the desired 5% alcohol solution.

910 mL = 0.0910 L

Step 2: Calculate the amount of 5% alcohol solution needed.

(0.0910 L) * (0.05) = 0.00455 L

Step 3: Calculate the amount of pure water needed.

(0.0910 L) - (0.00455 L) = 0.08645 L

Step 4: Calculate the amount of 65% alcohol mixture required.

(0.00455 L) / (0.65) = 0.007 L

Step 5: Calculate the amount of pure water in the 65% alcohol mixture.

(0.007 L) * (1 - 0.65) = 0.00245 L

Step 6: Calculate the total amount of pure water required.

(0.08645 L) + (0.00245 L) = 0.0889 L

To obtain the desired 910 mL of 5% alcohol solution, you will need 0.007 L of 65% alcohol mixture and 0.0889 L of pure water.

The Taylor's series for [tex]1 + 3e^x + x^2[/tex] at [tex]x=0[/tex] is :

[tex]1 + 3e^x+ x^2 = 5 + 3x + (3/2)x^2 + (1/3)x^3 + ...[/tex]

What do you mean by Taylor's series ?

The Taylor's series is a way to represent a function as a power series, which is a sum of terms involving the variable raised to increasing powers. The series is centered around a specific point, called the center of the series. The Taylor's series approximates the function within a certain interval around the center point.

The general formula for the Taylor's series of a function f(x) centered at [tex]x = a[/tex] is:

[tex]f(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...[/tex]

where [tex]f'(a), f''(a), f'''(a),[/tex] etc. are the derivatives of f(x) evaluated at [tex]x = a[/tex].

Finding the Taylor's series for [tex]1 + 3e^x + x^2[/tex] at [tex]x=0[/tex] :

We need to find the derivatives of the function at [tex]x=0[/tex]. We have:

[tex]f(x) = 1 + 3e^x + x^2[/tex]

[tex]f(0) = 1 + 3e^0 + 0^2 = 4[/tex]

[tex]f'(x) = 3e^x+ 2x[/tex]

[tex]f'(0) = 3e^0 + 2(0) = 3[/tex]

[tex]f''(x) = 3e^x + 2[/tex]

[tex]f''(0) = 3e^0 + 2 = 5[/tex]

[tex]f'''(x) = 3e^x[/tex]

[tex]f'''(0) = 3e^0 = 3[/tex]

Substituting these values into the general formula for the Taylor's series, we get:

[tex]f(x) = f(0) + f'(0)x + f''(0)x^2/2! + f'''(0)x^3/3! + ...[/tex]

[tex]f(x) = 4 + 3x + 5x^2/2 + 3x^3/6 + ...[/tex]

Simplifying, we get:

[tex]f(x) = 5 + 3x + (3/2)x^2 + (1/3)x^3 + ...[/tex]

Therefore, the Taylor's series for [tex]1 + 3e^x + x^2[/tex] at [tex]x=0[/tex] is :

[tex]1 + 3e^x+ x^2 = 5 + 3x + (3/2)x^2 + (1/3)x^3 + ...[/tex]

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Answer:

The correct answer is (b+2)

Step-by-step explanation:

(3b-7) + (-2b+9)

3b-7-2b+9

3b-2b+9-7

b+2 Ans

Answer:

b+2 is the answer of this expression.

Step-by-step explanation:

(3b-7) and (-2b+9)

3b+(-2b) + (-7+9)

(3b-2b) + 2

b+2

The length of HK is equal to: A. √768 units.

In Mathematics and Geometry, Pythagorean's theorem is represented by the following mathematical expression:

z² = x² + y²

Where:

x, y, and z represent the side length of any right-angled triangle.

Based on the diagram for right-angled triangle GHK, we can logically deduce that the height splits GK into 2 parts:

Hypotenuse = 8 units.

Hypotenuse = 32 - 8 = 24 units.

By applying the geometric mean theorem for right-angled triangles, we have:

Height = √(m × n)

Height = √(8 × 24) = √(192) units

In order to determine the length of HK in right-angled triangle GHK, we would have to apply Pythagorean's theorem:

HK² = 192² + 24²

HK² = 192 + 576

HK² = 768

HK = √(768) units.

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Answer:

1/16

Step-by-step explanation:

1/8 is left

1/2 of 1/8 = 1/16

The value of the probability of selecting a blue marble from the bag is 1/3

The probability of selecting a blue marble can be found by dividing the number of blue marbles by the total number of marbles in the bag.

From the given information, we know that there are 4 blue marbles out of a total of 12 marbles in the bag.

Therefore, the probability of selecting a blue marble is:

Probability of selecting a blue marble = Number of blue marbles / Total number of marbles

This gives

Probability of selecting a blue marble = 4/12

Simplifying the fraction by dividing both the numerator and denominator by 4, we get:

Probability of selecting a blue marble = 1/3

So, the probability of selecting a blue marble from the bag is 1/3 or 0.33 as a decimal.

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The required answers are 80.8, 79,and g(42) > f(42).

Part A:

To determine the test average for the math class after completing test 2, we need to evaluate the function f(x) at x=2. That is,

[tex]$$f(2) = 0.9(2) + 79 = 80.8$$[/tex]

Therefore, the test average for the math class after completing test 2 is 80.8.

Part B:

To determine the test average for the science class after completing test 2, we need to find the equation of the linear function g(x) that passes through the given points (1,78) and (2,79). The slope of the line passing through these points is

[tex]$m=\frac{y_2-y_1}{x_2-x_1}=\frac{79-78}{2-1}=1$$[/tex]

We can use the point-slope form of a line to find the equation of the line passing through the point (1,78) with slope m=1. That is,

[tex]$$y-78 = 1(x-1)$$[/tex]

Simplifying, we get

y = x + 77

Therefore, the test average for the science class after completing test 2 is

g(2) = 2 + 77 = 79

Part C:

To determine which class had a higher average after completing test 42, we need to evaluate f(42) and g(42) and compare the results. We have

[tex]$$f(42) = 0.9(42) + 79 = 117.8$$[/tex]

To find (42), we need to extend the linear function g(x) beyond the given data points by assuming that the function is linear and continues with the same slope m=1. That is,

g(x) = x + 77

for all [tex]$x\geq 1$[/tex]. Therefore,

[tex]$$g(42) = 42 + 77 = 119$$[/tex]

Since g(42) > f(42), we conclude that the science class had a higher average after completing test 42.

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-3y+7x ≥ -3y-14

solving linear inequalities

To solve the inequality, we need to isolate the variable, x. First, we can simplify the expression by adding 3y to both sides:

-3y + 7x ≥ -3y - 14 + 3y

Simplifying the right side, we get:

-3y + 7x ≥ -14

Next, we can isolate x by subtracting 3y from both sides:

-3y + 7x - 3y ≥ -14 - 3y

Simplifying the left side, we get:

4x ≥ -14 - 3y

Finally, we can isolate x by dividing both sides by 4:

x ≥ (-14 - 3y) / 4

Therefore, the solution to the inequality is:

x ≥ (-14 - 3y) / 4

Note that the inequality sign remains the same because we did not multiply or divide by a negative number.

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