Answer:
By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.
Step-by-step explanation:
For examples,
Let's consider squares of 3, 11, 25, 37 and 131.
[tex] {3}^{2} = 9[/tex]
8 is a multiple of 4, and 9 is more than 8.
[tex] {11}^{2} = 121[/tex]
120 is a multiple of 4 and 121 is one more than it.
[tex] {25}^{2} = 625[/tex]
624 is a multiple of 4 and 625 is one more than it.
[tex] {37}^{2} = 1369[/tex]
1368 is a multiple of 4 and 1369 is one more than 1368.
[tex] {131}^{2} = 17161[/tex]
17160 is a multiple of 4.
I need help with this math problem not sure what to do?
Answer:
B. 14
Step-by-step explanation:
It's asking for function f + function g. Then it wants you to use 2 as the x value. So you have:
(f+g)(x) = 2x^2 + 3x + x - 2
(f+g)(x) = 2x^2 + 4x -2
Then using 2 as x:
(f+g)(2) = 2(2^2) + 4* 2 -2
(f+g)(2) = 8 + 8 - 2
(f+g)(2) = 14
Hope that helps, and let me know if I did any of that wrong.
Some number times 7 is equal to the number increased by 9
Write out the equation. Do not solve the equation.
Answer:
7x = x + 9.
Step-by-step explanation:
7 × something = something + 9, right?
So, 7x = x + 9.
Un automóvil consume 4 galones de gasolina al recorrer 180 kilómetros y para recorrer 900 kilómetros necesita 20 galones ¿cuántos kilómetros recorre por galón? ¿Cuantos galones consumirá en 2700 kilómetros?
Answer:
45 km por galón
60 galones en 2700 Km
Step-by-step explanation:
180 / 4
45 km por galón
900 / 45
20 galones
2700 / 45
60 galones en 2700 Km
What is the domain of this function y= 1/ square root 2-x
Answer:
Domain:
( − ∞ , 2 ] , { x | x ≤ 2 }
Range:
[ 0 , ∞ ) , { y | y ≥ 0 }
At any point in time, there could be bicycles, tricycles, and
cars in the school parking lot. Today, there are 53 wheels in
total.
If there are 15 bicycles, tricycles,
and cars in total, how many
tricycles could be in the parking lot? List all possible answers.
Answer:
There may be 1 or 3 tricycles in the parking lot.
Step-by-step explanation:
Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:
13 x 4 + 1 x 3 + 1 x 2 = 57
11 x 4 + 1 x 3 + 3 x 2 = 53
10 x 4 + 3 x 3 + 2 x 2 = 53
8 x 4 + 5 x 3 + 2 x 2 = 51
10 x 2 + 1 x 3 + 4 x 4 = 39
9 x 3 + 1 x 2 + 5 x 4 = 49
Therefore, there may be 1 or 3 tricycles in the parking lot.
How do I solve this?
Answer:
Step-by-step explanation:
4x+3y=13
5x-4y=-7
Which of the following statements about points are false?
Check all that apply.
A. Their sizes vary.
B. They have no size and no dimensions,
C. They have no length or height.
D. Their size depends on their dimensions.
Answer:
their sizes vary
Step-by-step explanation:
their sizes vary
Identify the transformation that occurs to create the graph of h(x).
H(x)=f(x+3)
Answer: The graph moved left 3 units.
(x, y) = (x - 3, y)
Rohit thinks of a 4 digit number. The digit in the one’s place is 3 more than the digit in the ten’s place, but 5 less than the digit in the thousand’s place. The value of the hundred’s place is 600. The digit in thousand’s place is the greatest odd number. What is the number Rohit is thinking of?
Answer:
9614
Step-by-step explanation:
Generic number with 4 digit
1000t + 100h + 10y + x
x = 3 + y
x = m - 5
h = 6
m = 9
if we substitute the value we have:
x = 9 - 5 = 4
4 = 3 + y
y = 1
Final number
9614
The slope of a line is 2 and the point (1, 1) lies on the line. What is the y-intercept of this line? (0, -1) (0, 5) (-2, 0)
Answer:
(0, -1)
Step-by-step explanation:
It's helpful if we think of slope in the context of rise over run.
Since the point (1, 1) lies on the line, because of the slope 2, if we subtract x by 1 to get to x = 0, then we'll be subtracting y by 2.
By that logic, the answer must be (0, -1).
A merchant keeps marble in a cylindrical plastic container that has a diameter of 28cm and height of 35cm. A marble has a diameter of 25mm. Determine the number of marbles that can be stored in such a container if air space accounts for 20% between marbles.
Answer:
2107 marbles can be stored in the container.
Step-by-step explanation:
Since a merchant keeps marble in a cylindrical plastic container that has a diameter of 28cm and height of 35cm, and a marble has a diameter of 25mm, to determine the number of marbles that can be stored in such a container if air space accounts for 20 % between marbles, the following calculation must be performed, knowing that the volume of a cylinder is equal to height x π x radius²:
35 x 3.14 x (28/2) ² = X
109.9 x (14 x 14) = X
109.9 x 196 = X
21,540.4 = X
In turn, the volume of each 25mm diameter marble is equal to:
25mm = 2.5cm
4/3 x 3.14 x 1.25³ = X
4.18666 x 1.953125 = X
8.1770 = X
21,540.4 x 0.8 = 17,232.32
17,232.32 / 8,177 = 2,107.41
Therefore, 2107 marbles can be stored in the container.
Which inequality is true? Use the number line to help.
-2.5 -2 -1.5 -1
-0.5 0
0.5
1
1.5
2
2.5
0 -1.5 0.5
0 -0.50
O-1.5 <-0.5
o 2205
Answer:
C. -1.5 < -0.5
Step-by-step explanation:
On a number line, the farther a number is to the right away from 0, the greater the number. While the farther it is from 0 to the left, the smaller it is.
Thus, the out of the options given, the only inequality given that is true is:
-1.5 < -0.5
This is because, -1.5 on the numberline is farther away to the left from 0 than -0.5. therefore, -1.5 is lesser than -0.5.
Suppose X has a normal distribution with mean 10.0 and standard deviation 5.0 what is the P(2.0
Answer:
what r u answers picks
Step-by-step explanation:
cant answer with out of t
vention 1 of 10
These box plots show daily low temperatures for a sample of days in two
different towns
TWINA
M
41
41
Town 1
1620
MI
D
10
152025 M3540
Degrees (0)
Which statement is the most appropriate comparison of the centers?
O A. The median temperature for both towns is 20"
B. The mean for town A, 30", is greater than the mean for town 8,25"
C. The median temperature for both towns is 30'
D. The median for town A, 30', is greater than the median for town B,
25
PREVIOUS
9 M
Create a circle such that its center is point A and B is a point on the circle.
Answer:
The center of a circle is the point in the circle which is equidistant to all the edges of thr circle. The point a is the center, while point b is an arbitrary point in the circle. Find attachment for the diagram.
Factor 2x^2+15x+25. Rewrite the trinomial with the x-term expanded,using the two factors. Then, group the first two and last two terms together and find the GCF of each.
Answer:
[tex][x + 5][2x+ 5][/tex]
Step-by-step explanation:
Given
[tex]2x^2 + 15x + 25[/tex]
Required
Factorize
Expand the x term
[tex]2x^2 + 5x + 10x+ 25[/tex]
Group into 2
[tex][2x^2 + 5x] + [10x+ 25][/tex]
Take the GCF of each group
[tex]x[2x + 5] + 5[2x+ 5][/tex]
Factor out 2x + 5
[tex][x + 5][2x+ 5][/tex]
How do I solve this?
Answer: 3
Step-by-step explanation: m=2 so 7.5x2 = 15
15/5 is 15 divided by 5 so the answer is 3
what is the value of x? 4/5x-1/10=3/19
Answer:
x=[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Hi there!
We are given the following equation:
[tex]\frac{4x}{5}[/tex]-[tex]\frac{1}{10}[/tex]=[tex]\frac{3}{10}[/tex]
and we need to find the value of x
To do this, we need to isolate the value of x with a coefficient of 1 (1x) on one side. The value of x, or everything else is on the other side
So let's get rid of [tex]\frac{1}{10}[/tex] from the left side by adding [tex]\frac{1}{10}[/tex] to both sides (-[tex]\frac{1}{10}[/tex]+[tex]\frac{1}{10}[/tex]=0).
[tex]\frac{4x}{5}[/tex]-[tex]\frac{1}{10}[/tex]=[tex]\frac{3}{10}[/tex]
+[tex]\frac{1}{10}[/tex] +[tex]\frac{1}{10}[/tex]
___________
[tex]\frac{4x}{5}[/tex]=[tex]\frac{3}{10}[/tex]+[tex]\frac{1}{10}[/tex]
as the fractions on the right side both have the same denominator, we can add them together
[tex]\frac{4x}{5}[/tex]=[tex]\frac{4}{10}[/tex]
Now we need to have the value of 1x. Currently we have [tex]\frac{4x}{5}[/tex].
In order to get x with a coefficient of 1, multiply both sides by the reciprocal of [tex]\frac{4}{5}[/tex], which is [tex]\frac{5}{4}[/tex]
[tex]\frac{5}{4}[/tex]×[tex]\frac{4x}{5}[/tex]=[tex]\frac{4}{10}[/tex]*[tex]\frac{5}{4}[/tex]
which simplifies down to
x=[tex]\frac{20}{40}[/tex]
Now reduce the fraction by dividing the numerator and denominator both by 20
x=[tex]\frac{1}{2}[/tex]
Hope this helps!
The surface area of a roof with dimensions of 40 feet long by 28 feet wide is how many times the surface area of a floor where the dimensions are 16 feet long by 7 feet wide?
Answer:
10 times
Step-by-step explanation:
Multiply 40 by 28
1120
Multiply 16 by 7
112
Divide the two numbers
You get 10
Hope this helps!
Find the standard normal area for each of the following (Round your answers to 4 decimal places.): Standard normal area a.P(1.26 < Z < 2.16) b.P(2.05 < Z < 3.05) c.P(-2.05 < Z < 2.05) d.P(Z > .55)
Answer:
The correct answer is:
(a) 0.0884
(b) 0.0190
(c) 0.9596
(d) 0.2921
Step-by-step explanation:
(a)
= [tex]P(1.26<Z<2.16)[/tex]
= [tex]P(Z<2.16)-P(Z<1.26)[/tex]
= [tex]0.9846-0.8962[/tex]
= [tex]0.0884[/tex]
(b)
= [tex]P(2.05<Z<3.05)[/tex]
= [tex]P(Z<3.05)-P(Z<2.05)[/tex]
= [tex]0.9989-0.9798[/tex]
= [tex]0.0190[/tex]
(c)
= [tex]P(-2.05<Z<2.05)[/tex]
= [tex]P(Z<2.05)-P(Z<-2.05)[/tex]
= [tex]0.9798-0.0202[/tex]
= [tex]0.9596[/tex]
(d)
= [tex]P(Z>0.55)[/tex]
= [tex]1-P(Z<0.55)[/tex]
= [tex]1-0.7088[/tex]
= [tex]0.2912[/tex]
3. Of 1000 randomly selected cases of lung cancer, 450 resulted in death within 5 years. Calculate a 96% CI on the death rate from lung cancer.
Answer:
The 96% CI on the death rate from lung cancer is (0.4177, 0.4823).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
Of 1000 randomly selected cases of lung cancer, 450 resulted in death within 5 years.
This means that [tex]n = 1000, \pi = \frac{450}{1000} = 0.45[/tex]
96% confidence level
So [tex]\alpha = 0.04[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.04}{2} = 0.98[/tex], so [tex]Z = 2.054[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 - 2.054\sqrt{\frac{0.45*0.55}{1000}} = 0.4177[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 + 2.054\sqrt{\frac{0.45*0.55}{1000}} = 0.4823[/tex]
The 96% CI on the death rate from lung cancer is (0.4177, 0.4823).
Factor 2x2+25x+50. Rewrite the trinomial with the x-term expanded, using the two factors.
9514 1404 393
Answer:
rewrite: 2x^2 +5x +20x +50factored: (x +10)(2x +5)Step-by-step explanation:
I find this approach the most straightforward of the various ways that trinomial factoring is explained or diagramed.
You want two factors of "ac" that have a total of "b". Here, that means you want factors of 2·50 = 100 that have a total of 25. It is helpful to know your times tables.
100 = 1·100 = 2·50 = 4·25 = 5·20 = 10·10
The sums of these factor pairs are 101, 52, 29, 25, and 20. We want the pair with a sum of 25, so that's 5 and 20.
The trinomial can be rewritten using these factors as ...
2x^2 +5x +20x +50
Then it can be factored by grouping consecutive pairs:
(2x^2 +5x) +(20x +50) = x(2x +5) +10(2x +5) = (x +10)(2x +5)
_____
Additional comment
It doesn't matter which of the factors of the pair you write first. If our rewrite were ...
2x^2 +20x +5x +50
Then the grouping and factoring would be (2x^2 +20x) +(5x +50)
= 2x(x +10) +5(x +10) = (2x +5)(x +10) . . . . . same factoring
HELPPP
3p-4-8p<-19
i need the steps as well
9514 1404 393
Answer:
p > 3
Step-by-step explanation:
3p -4 -8p < -19 . . . . . . given
-5p -4 < - 19 . . . . . . . . collect terms
-5p < -15 . . . . . . . . . . . add 4
p > 3 . . . . . . . . . . . . . . divide by -5 (reverses the inequality symbol)
the cost of 10 oranges is $6. what is the cost of an orange ?
Answer Choices:
$0.40
$0.60
$4
$6
Answer:
$0.60
Step-by-step explanation:
To find the cost of 1 orange, divide the $6 by 10:
6/10 = 0.6
Hope it helps (●'◡'●)
The mean age of 5 people in a room is 27 years.
A person enters the room.
The mean age is now 35.
What is the age of the person who entered the room?
Answer:
main age = total age/total people
if Main age is = 27
[tex]27 = \frac{ \times }{5} [/tex]
and x = 135
Total age is = 135
then main age is 35
[tex][35 = \frac{y}{6} [/tex]
and y = 210
first main age - second main age = age of the person participating
210 - 135 = 75
the age is = 75HAVE A NİCE DAY
Step-by-step explanation:
GREETINGS FROM TURKEY
I WILL MARK BRAINLIEST PLEASE HELP! This graph represents f(x), and g(x) = -7x + 8.
Which statement about these functions is true?
A.
Function f(x) is increasing, and g(x) is decreasing.
B.
Function f(x) is decreasing, and g(x) is increasing.
C.
Functions f(x) and g(x) are both decreasing.
D.
Functions f(x) and g(x) are both increasing.
Answer:
A
Step-by-step explanation:
ITS OPTION (A)
PLZ MARK ME BRAINLIEST..
Question A cotton farmer produced 390 pounds per acre after 4 years of operating. After 9 years, he was producing 460 pounds per acre. Assuming that the production amount has been increasing linearly, estimate the production per acre 7 years after he started farming. Your answer should just be a numerical value. Do not include units in your answer. Provide your answer below:
can someone tell me if why these triangles are similar
Answer:
Step-by-step explanation:
If the triangles given in the picture are similar,
ΔVUT ~ ΔVLM
By the property of similarity of two triangles, their corresponding sides will be proportional.
[tex]\frac{TV}{VM}= \frac{VL}{VU}[/tex]
[tex]\frac{49}{14}=\frac{28}{8}[/tex]
[tex]\frac{7}{2}=\frac{7}{2}[/tex]
True.
Therefore, ΔVUT and ΔVLM will be similar.
The height and base radius of a cone are increased by a factor of 2 to create a similar cone. How is the slant height of the cone affected? The slant height of the larger cone is equal to the slant height of the smaller cone. The slant height of the larger cone is double the slant height of the smaller cone. The slant height of the larger cone is 4 times the slant height of the smaller cone. The slant height of the larger cone is 8 times the slant height of the smaller cone.
Answer:
The slant height of the cone affected is two times the slant height of original cone
Step-by-step explanation:
we know that
If the height and base radius of a cone are increased by a factor of to create a similar cone
then
the scale factor is equal to
therefore
the slant height of the cone affected is equal to the slant height of the original cone multiplied by the scale factor
Find the slant height of the original cone
Let
l-----> slant height of original cone
la-----> slant height of the cone affected
Applying the Pythagoras theorem
so
The slant height of the cone affected is two times the slant height of original cone
(I GOT THIS FROM SOMEONE ELSES ANSWER IN 2017 SO I HOPE THIS HELPS)
The slant height of the larger cone is double the slant height of the smaller cone.
Option B is the correct answer.
What is a cone?It is a shape of a Christmas tree where there is a base of radius r and a top point called the apex.
The volume of a cone is 1/3 πr²h
We have,
The slant height of the cone is affected by a factor of 2.
When the height and base radius of a cone are multiplied by 2, the dimensions of the new cone are doubled.
Therefore,
The slant height of the larger cone is double the slant height of the smaller cone.
Learn more about cones here:
https://brainly.com/question/13798146
#SPJ5
Nine children are to be divided into an A team, a B team and a C team of 3 each. The A team will play in one league, the B team in another, the C team in a third league. How many different divisions are possible
Answer:
The answer is "840".
Step-by-step explanation:
Following are the number of ways in which selecting a team A by 9 children:
[tex]= ^{9_{C_{3}}\\\\\\[/tex]
[tex]=\frac{9!}{3! \times 6!} \\\\=\frac{9\times 8\times 7\times 6!}{3 \times 2\times 1\times 6!}\\\\=\frac{9\times 8\times 7}{3 \times 2\times 1}\\\\=\frac{3\times 4\times 7}{1}\\\\=\frac{84}{1}\\\\=84[/tex]
Following are the number of ways in which selecting a team B by remaining 6 children:
[tex]= ^{6}_{C_{3}}[/tex]
[tex]= \frac{6!}{(3! \times 3!)}\\\\= \frac{6!}{(3\times 2\times 1 \times 3!)}\\\\= \frac{6\times 5 \times 4 \times 3!}{(3\times 2\times 1 \times 3!)}\\\\= \frac{ 5 \times 4 \times 3!}{3!}\\\\= 5 \times 4 \\\\=20[/tex]
Following are the number of ways in which selecting a team C by remaining 3 children:
[tex]= ^{3}_{C_{3}}\\\\=\frac{3!}{3!}\\\\= 1[/tex]
Following are the number of ways in which making 3 teams by 9 children:
[tex]= \frac{(84 \times 20 \times 1)}{3!}\\\\= \frac{(84 \times 20 )}{6}\\\\= 14 \times 20\\\\= 280\\\\[/tex]
(Note: we've split by 3! Because it also is necessary to implement three teams between themselves)
Now 3 leagues have to be played. One is going to be run by each team.
That is the way it is
Different possible divisions
[tex]= 280 \times 3!\\\\= 280 \times (3 \times 2 \times 1)\\\\= 840[/tex]