Answer:
animal
Explanation:
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As student used a pen to draw a line across a piece of chromatography paper. he then placed a sample of dye on the drawn line for analysis . is the student doing the right thing? why?
Answer is in the photo. I can only upload it to a file hosting service. link below!
tinyurl.com/wpazsebu
Ca3(PO4)2 + 3H2SO4 3CaSO4 + 2H3PO4.
What mass of concentrated H2SO4 (98% by mass) must be used to react completely
with 100.00 g of calcium phosphate?
100g
H2SO4 = 3x98x100/310 = 94.84g
used mass of h2so4x100/all mass of H2so4 = 98%
yx100/98=94.84x100/98 = 96.81.
Check the attached photo for clear answer.
What is the use of calcium phosphate?It may be used to treat conditions caused by low calcium levels such as bone loss (osteoporosis), weak bones (osteomalacia/rickets), decreased activity of the parathyroid gland (hypoparathyroidism), and certain muscle diseases (latent tetany).
Is calcium phosphate good for health?About Calcium Phosphate Supplements
It aids in healthy bone development and is crucial from infancy to adulthood. But, calcium does more than build strong bones. It's also very important for healthy digestion. Calcium aids in bile acid metabolism, excretion of fatty acids, and healthy gut microbiota.
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The fizz in the soda that we drink is carbonic acid. Leaving the soda can open to the environment separates the carbonic acid into water and carbon dioxide. What type of reaction is this and what is the resulting product?
Answer:
The reactionnis known as a decomposition reaction
The equation of the reaction is given below as:
H₂CO₃ -----> H₂O + CO₂
Explanation:
A reaction in which a single compound is split into two or more simpler substances is known as a decomposition reaction.
In the reaction in which when a soda can is opened and left to the environment, the fizz in the soda, carbonic acid, separates into water and carbon dioxide is an example of a decomposition reaction.
The equation of the reaction is given below:
H₂CO₃ -----> H₂O + CO₂
In the reaction above, a larger molecular weight compound, carbonic acid with the molecular, H₂CO₃ is splits into two simpler substances of smaller molecular weight, water, H₂O and carbon dioxide, CO₂.
This reaction rate is made faster by an increase in temperature and by a decrease in pressure of the soda.
Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equation)
Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
Solid Iron = FeCopper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)Metal Copper = CuWriting the equation using symbols leaves us with:
Fe + CuNO₃ → Fe(NO₃)₃ + CuIt is not balanced yet. Now we balance the NO₃ species on the left side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + CuFinally we balance the Cu species on the right side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3CuThe frequency of a wave can be calculated by dividing the speed of a wave by its wavelength. Calculate the frequency of a radio wave having a speed of 300,000,000 m/s and a wavelength of 0.00056 m.
Answer:
snovd vosb r
Explanation:
What’a the answer!!?
Answer:
2,1,2
1,2,1,1
the answer
calculate the percentage mass of potassium in potassium chloride, KCI
Consider a different situation. An ice cube is placed in a cup, and the cup is filled to the brim with mineral oil, which has a density of 0.8 g/cm3. The density of ice is about 9% less than the density of liquid water, which is about 1 g/cm3. After the ice melts, what will happen to the level of the water/oil mixture in the cup
Name each of the following molecular binary compounds:
01. CaCl2 01. hydroiodic acid
02. HI (g) 02. hydrogen monoiodide gas
03. HI (aq) 03. diiodine tetraoxide
04. BH3 04. bromine monofluoride
05. Cl2O6 05. silicon tetrahydride
06. ClF 06. tetraphosphorus hexaoxide
07. P2Cl4 07. disulfur monoxide
08. I2O5 08. carbon monooxide
09. BrF5 09. hydrogen monochloride gas
10. HBr (aq) 10. tetraphosphorus decaoxide
11. IF7 11. dibromine monoxide
12. NF3 12. dinitrogen tetrafluoride
13. H2Se (aq) 13. disilicon hexahydride
14. BrCl 14. tetraarsenic hexaoxide
15. H2Se (g) 15. hydrochloric acid
16. SnO2 16. arsenic trihydride
17. HBr (g) 17. iodine heptafluoride
18. AsF3 18. bromine dioxide
19. N2O3 19. disulfur decafluoride
20. IF5 20. dichlorine heptaoxide
Answer:
Explanation:
From the given information; we are to assign the correct naming for the molecular binary compounds.
01. CaCl2 → Calcium CHloride
02. HI (g) → Hydrogen mono iodide gas
03. HI (aq) → Hydroiodic acid
04. BH3 → Borontrihydride
05. Cl2O6 → Dichlorine hexoxide
06. ClF → Chlorine monoflouride
07. P2Cl4 → Phosphorus tetrachloride
08. I2O5 → Diiodine pentaoxide
09. BrF5 → Bromine pentaflouride
10. HBr(aq) → Hydrobromic acid
11. IF7 → Iodine heptaflouride
12. NF3 → nitrogen triflouride
13. H2Se(aq) → hydroselenic acid
14. BrCl → Bromine monochloride
15. H2Se(g) → Hydrogen Selenide
16. SnO2 → Tindeoxide
17. HBr(g) → Hydrogenbromide gas
18. AsF3 → Arsenic triflouride
19. N2O3 → Dinitrogentrioxide
20. IF4 → Iodine pentafluoride
01. hydroiodic acid → HI (aq)
02. hydrogen monoiodide gas → HI (g)
03. diiodine tetraoxide → I2O4
04. bromine monofluoride → BrF
05. silicon tetrahydride → SiH4
06. tetraphosphorus hexaoxide → P4O6
07. disulfur monoxide → S2O
08. carbon monooxide → CO
09. hydrogen monochloride gas → Hcl
10. tetraphosphorus decaoxide → P4O10
11. dibromine monoxide → Br2O
12. dinitrogen tetrafluoride → N2F4
13. disilicon hexahydride → SiH6
14. tetraarsenic hexaoxide → As4O6
15. hydrochloric acid → HCl (aq)
16. arsenic trihydride → AsH3
17. iodine heptafluoride → IF7
18. bromine dioxide → BrO2
19. disulfur decafluoride → S2F10
20. dichlorine heptaoxide → Cl2O7
Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which this transition belongs?
Answer:
The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.
Explanation
lets calculate -
Rydberg equation- [tex]\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})[/tex]
where ,[tex]\pi[/tex] is wavelength , R is Rydberg constant ( [tex]1.097\times10^7[/tex]), [tex]n_1[/tex] and [tex]n_2[/tex]are the quantum numbers of the energy levels. (where [tex]n_1=2 , n_2=4[/tex])
Now putting the given values in the equation,
[tex]\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )[/tex][tex]=2056875m^-^1[/tex]
Wavelength [tex]\pi =\frac{1}{2056875}[/tex]
=[tex]4.86\times10^-^7[/tex] = 486nm
Therefore , the wavelength is 486nm and it belongs to The Balmer series.
POS MOLECULES SPEED UP WHEN ENERGY IS CREATED AND SLOW DOWN WHEN ENERGY IS DESTROYED True False? explain why
Answer: Scientists use the term bioenergetics to describe the concept of energy flow (Figure 4.2) through living systems, such as cells. Cellular processes such as the building and breaking down of complex molecules occur through stepwise chemical reactions. Some of these chemical reactions are spontaneous and release energy, whereas others require energy to proceed. Just as living things must continually consume food to replenish their energy supplies, cells must continually produce more energy to replenish that used by the many energy-requiring chemical reactions that constantly take place. Together, all of the chemical reactions that take place inside cells, including those that consume or generate energy, are referred to as the cell’s metabolism.
1. Chlorofluorocarbons (CFCs) are of interest because of their ability to destroy ozone molecules. A carbon-chlorine bon din the CFC molecule can be broken by sunlight, leaving a highly reactive free radical which then goes on to destroy the surrounding ozone molecules. The energy of a C-Cl bond is 328 kJ/mole. Calculate the wavelength of light needed to break a bond in a single molecule. In which region of the spectrum (infrared, visible, UV) does this wavelength fall
Answer:
See explanation
Explanation:
Energy of the photon (E) = 328 * 10^3/6.02 * 10^23 = 5.45 * 10^-19 J
Recall that E = hc/λ
h = Plank's constant = 6.36 * 10^-34 Js
c = speed of light = 3 * 10^8 m/s
λ = ??
λ = hc/E
λ = 6.36 * 10^-34 * 3 * 10^8/5.45 * 10^-19
λ = 3.5 * 10^-7 m
This falls into the UV region of the spectrum
Question 18 of 20
Which statement explains why a chemical equation must be balanced?
A. It must show how each chemical formula is written to accurately
represent each substance.
B. It must show that coefficients and subscripts can be used in
chemical formulas.
O C. It must show that the mass of each element involved is conserved
by a chemical reaction.
O D. It must show the reactants and products on the correct sides of
the reaction arrow.
SUBMIT
Answer:
d.It must show the reactants and products on the correct sides of
the reaction arrow
Explanation:
hope it helps
pleaaaaase helppppppppppppp ASAP
Answer:
Explanation:
a) The forward reaction is exothermic, hence when temperature is increased the equilibrium shift towards the reactants side to get rid of the excess energy. This will mean that more reactants are produced decreasing yield
b) There are a fewer number of moles of gas on the right side compared to the left side (Just count the coefficients before each compound) so a higher pressure will mean that the equilibrium will shift towards the products side in order to decrease the pressure. This will mean that more products are formed increasing yield
c) When something is powdered it's surface area to volume ratio increases. A higher surface area means that the particles around it have more area to work on so the frequency of collisions will increase increasing the rate of reaction. This is why iron is powdered.
A characteristic used to describe something is called a
If only one sperm cell is needed to fertilize an egg, why are males capable of producing so many sperm cells?
The empirical formula for compound is P2O5. The molar mass of the compound is 283.89g. What is the molecular formula?
Answer:
P4O10
Explanation:
(P2O5)n=283.89
62+80=283.89
142n=283.89
n=2
P2O10
The empirical and molecular formula are related by the formula, molecular formula=2×empirical formula ,meaning double the atoms present in empirical formula,hence molecular formula is P₄O₁₀.
What is empirical formula?Empirical formula of a compound is defined as the simplest whole number ratio of atoms which are present in a compound.It does not make any mention of the arrangement of atoms or the number of atoms. The empirical formula gives information about the ratio of number of atoms which are present in a compound.
Molecular formula is determined from the empirical formula by dividing the molar mass of a compound by the empirical formula mass. The resultant which should be a whole number or very close to the whole number , then the subscripts are multiplied by the whole number to get the molecular formula.
For the compound P₂O₅ the subscripts of phosphorous and oxygen are multiplied by 2 and hence the molecular formula P₄O₁₀.
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Consider the fatty acid. A carboxylate salt is attached to a 19 carbon chain, where double bonds are present between carbons 5 and 6, between carbons 8 and 9, between carbons 11 and 12, and between 14 and 15. The carboxylate carbon is carbon 1. All double bonds are cis. Which of the designations are accurate for the fatty acid
Answer:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
Explanation:
From the image attached below:
We can see the structure of the delta nomenclature showing the numbers of carbons, numbers of double bonds, and the locations of the double bonds in the structure of the carboxylate salt.
Also, we can see the structure of the fatty acid where; the location of the first double bond from the methyl end is shown.
Hence, the designation which are accurate for these structures are:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
Why it is true to say that calcium carbonate has both ionic and covalent bonds?
Answer:
Calcium carbonate is an ionically bonded compound.
Covalent Bond: This bond is formed because atoms share a pair of electrons through an orbital.
Please if you just want point TELL ME I can’t fail this.
Match the environmental stresses to what would happen in the chemical reaction. Think through the path from the carbon cycle - how CO2
CO2is removed from the atmosphere and stored in sinks and then how CO2
CO2is released from sinks and/or produced. Loss of carbon sinks, like trees
Decrease in shellfish due to overfishing
Decrease the number of farms
Increase in Earth's temperature
Decrease in number of cars burning gas
Answer:
here you go. I took the test :)
Explanation:
Calculate the pH and percent ionization of a HC2H3O2 solution with a concentration of 0.500 M. (Ka = 1.8 x10-5)
Answer:
I can not see the file
Explanation:
Express
as
ordinary numbers.
3 x 10^0=
What do scientist use to classify organisms?
Answer:
a Binomial Naming System
Explanation:
When one gram of liquid water at its boiling point is changed into water vapor
1.
334 J/g is gained from the surrounding environment
2.
334 J/g is released into the surrounding environment
3
2260 J/g is gained from the surrounding environment
4
2260 J/g is released into the surrounding environment
Answer: 2260 J/g is gained from the surrounding environment
When one gram of liquid water at its boiling point is changed into water vapor, 2260 J/g of energy is gained from the surrounding environment.
What is heat of vaporization?Heat of vaporization is the amount of heat that is required by any body during their transition process from liquid state to vapor state, at a particular temperature i.e. no change in temperature during whole process.
During the transition of one gram of liquid water into water vapor at its boiling point of 100°C, 2260 J/g energy is absorbed by the water for the formation of vapor.
Hence, option (3) is correct.
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What are the two products of an acid base neutralization reaction?
Answer:
Neutralization reactions occur when two reactants, an acid and a base, combine to form the products salt and water.
Explanation:
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Answer: Water and NaCl is always formed
Explanation:
I hope this helped!
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1) This rock is made out of cooled magma.
A) Igneous
B) Sedimentary
C) Metamorphic
D) Sandstone
2) This type of rock is made through the processes of heat and pressure.
A) Igneous
B) Sedimentary
C) Metamorphic
D) Sand
3) Sandstone is a sedimentary rock. How does sandstone form?
A) It melted and cooled.
B) It broke into sediment and then compacted.
C) It was heated and put under pressure.
D) Rocks don’t form; they stay as they are.
4) What type of rock can be broken down into sediment through weathering?
A) Igneous
B) Sedimentary
C) Metamorphic
D) All types of rocks
5) How does rock from a mountain turn into small pieces of rock?
A) Wind and rain break the rock into small pieces.
B) Earthquakes and natural disasters break the rock.
C) The sun's rays break the rock.
D) Everything breaks into pieces if you leave it out.
6) Can igneous rock underneath Earth’s outer layer change into sedimentary rock?
A) Yes, but it must be subducted first.
B) Yes, but it must be weathered first.
C) Yes, but it must be uplifted first.
D) No, igneous rock can never become sedimentary.
7) This energy source creates magma, which is melted rock that will turn into igneous rock.
A) Sun
B) Air
C) Earth's Interior
D) Water
8) This energy source helps create weather, which creates sediment to form sedimentary rocks.
A) Air
B) Sun
C) Water
D) Earth's Interior
9) What is the difference between magma and lava?
A) Magma is very hot, lava is cool.
B) Magma is molten rock within the earth; lava is molten rock on the earth's surface.
C) Magma is molten rock on the earth's surface; lava is molten rock within the earth.
D) Magma is cool, lava is very hot.
1. a) Igneous.
2. c) Metamorphic.
3. b) It broke into sediment and then compacted.
4. d) All types of rocks.
5. a) Wind and rain break down the rock into small pieces.
6. a) Yes, but it should be subtuced first.
7. c) Earth's interior.
8. c) Water.
9. b) Magma is molten rock within the Earth; lava is molten rock on the Earth's surface.
At what temperature (in K) does NH₃ have a density of 0.812 g/L at 1.17 atm?
Answer:
The temperature is "298.51 K".
Explanation:
The given values are:
Density of ammonia,
d = 0.812 g/L
Pressure,
P = 1.17 atm
Mass:
M = [tex]NH_3[/tex]
= [tex]14+ 1\times 3[/tex]
= [tex]17[/tex]
As we know,
⇒ [tex]PV=nRT[/tex]
∴ [tex]T=\frac{PV}{nR}[/tex]
[tex]=\frac{PV}{\frac{W}{M}\times R }[/tex]
[tex]=\frac{PVM}{W\times R}[/tex]
By putting the value of "W", get
[tex]=\frac{PVM}{V\times d\times R}[/tex]
[tex]=\frac{P\times M}{d\times R}[/tex]
On substituting the values in the above equation, we get
[tex]=\frac{1.17\times 17}{0.812\times 0.08205}[/tex]
[tex]=\frac{19.89}{0.06699}[/tex]
[tex]=298.51 \ K[/tex]
Answer:
299
Explanation:
Or 298.51 to be exact!
What is the formula for Dicarbon trioxide
Answer:
diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2
Explanation:
hope that helps you╰(*°▽°*)╯Amanda inserted the gel tray with the well towards the red ( ) end of the chamber during gel electrophoresis and carefully pipetted her samples into the wells as indicated in the lab directions. After viewing her gel under UV light, she did not find bands in the regions that she was expecting. What did she most likely see in her gel results and why
Answer:
hello the options related to your question is missing attached below is the complete question with the options
answer:
Any visible bands were found in the small area above the wells instead in the expected large bottom area of the gel, because Amanda should have placed the wells into the black (-) end of the chamber for DNA to move towards the opposite red (+) end of the gel. ( 2 )
Explanation:
Why Amanda did not see any bands in the region that she was expecting is because during electrophoresis ( which allows the distinguishing of various lengths of DNA fragments on a gel ) the DNA been negative will migrate to the positively charged electrodes and The shorter brands will move faster through the gel, providing DNA fragments arrangements on the gel according to size.
Balance C3H8 + O2 + CO2 + H2O
Assuming the second plus sign is a typo and was meant to be a reaction arrow, this would be the balanced equation:
C3H8 + 5O2 —> 3CO2 + 4H2O