prime factorization of 107

For each variable, the possible values are:

a) T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

b) X = {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

c) U = {0, 1, 2, 3, 4, 5, 6}

d) Z = {0, 1, 2}

Item a:

In total, there are 10 pumps, hence the possible values are all integers from 0 to 10, that is:

T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Item b:

In the first, there are 6 pumps, and in the second 4, hence, the difference ranges from -4 to 6, that is:

X = {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

Item c:

The maximum number in a station is 6 pumps, hence this variable ranges from 0 to 6.

U = {0, 1, 2, 3, 4, 5, 6}

Item d:

Either none of the stations has exactly two pumps in use, or one has or both, hence the variable ranges from 0 to 2.

Z = {0, 1, 2}

The question is incomplete. The complete question is:

"The number of pumps in use at both a six-pump station and a four-pump station will be determined. Give the possible values for each of the following random variables. (Enter your answers in set notation.)

a. T = the total number of pumps in use

b. X = the difference between the numbers in use at stations 1 and 2.

c. U = the maximum number of pumps in use at either station

d. Z = the number of stations having exactly two pumps in use"

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if cot(θ)<0 and cos(θ)<0, then we can conclude that θ lies in the second quadrant.

What is trigonometry functions ?

Trigonometry functions are a set of mathematical functions that relate the angles of a triangle to the lengths of its sides. The three main trigonometric functions are sine, cosine, and tangent, which are commonly abbreviated as sin, cos, and tan. These functions can be defined as ratios of the sides of a right triangle.

In a right triangle, the side opposite an acute angle is called the "opposite" side, the side adjacent to the angle is called the "adjacent" side, and the hypotenuse is the side opposite the right angle. With this terminology, we can define the following trigonometric functions:

Sine (sin): The sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse. In other words, sin(θ) = opposite/hypotenuse.

Cosine (cos): The cosine of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse. In other words, cos(θ) = adjacent/hypotenuse.

Tangent (tan): The tangent of an angle is the ratio of the length of the opposite side to the length of the adjacent side. In other words, tan(θ) = opposite/adjacent.

There are also three reciprocal trigonometric functions: cosecant (csc), secant (sec), and cotangent (cot). These functions are the reciprocals of sine, cosine, and tangent, respectively.

Trigonometric functions have many practical applications in fields such as engineering, physics, and astronomy, where they are used to solve problems involving angles and distances. They also have many applications in pure mathematics, such as in the study of periodic functions and Fourier analysis.

According to given information :

To understand why θ must be in the second quadrant, we need to recall the signs of the trigonometric functions in each quadrant.

In the first quadrant, all trigonometric functions are positive.

In the second quadrant, sine is positive and cosine is negative.

In the third quadrant, both sine and cosine are negative.

In the fourth quadrant, sine is negative and cosine is positive.

Since we know that cos(θ) is negative, we can conclude that θ lies in either the second or third quadrant. However, since cot(θ) = cos(θ)/sin(θ) and cot(θ) is negative, we know that cos(θ) and sin(θ) must have opposite signs. In the third quadrant, both cos(θ) and sin(θ) are negative, so their quotient cot(θ) would be positive, which is not the case.

Therefore, we can conclude that θ lies in the second quadrant.

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Answer:

If  cot(θ)<0 and cos(θ)<0, then we can conclude that θ lies in the second quadrant.

What are trigonometry functions ?

Trigonometry functions are a set of mathematical functions that relate the angles of a triangle to the lengths of its sides. The three main trigonometric functions are sine, cosine, and tangent, which are commonly abbreviated as sin, cos, and tan. These functions can be defined as ratios of the sides of a right triangle.

In a right triangle, the side opposite an acute angle is called the "opposite" side, the side adjacent to the angle is called the "adjacent" side, and the hypotenuse is the side opposite the right angle. With this terminology, we can define the following trigonometric functions:

Sine (sin): The sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse. In other words, sin(θ) = opposite/hypotenuse.

Cosine (cos): The cosine of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse. In other words, cos(θ) = adjacent/hypotenuse.

Tangent (tan): The tangent of an angle is the ratio of the length of the opposite side to the length of the adjacent side. In other words, tan(θ) = opposite/adjacent.

There are also three reciprocal trigonometric functions: cosecant (csc), secant (sec), and cotangent (cot). These functions are the reciprocals of sine, cosine, and tangent, respectively.

Trigonometric functions have many practical applications in fields such as engineering, physics, and astronomy, where they are used to solve problems involving angles and distances. They also have many applications in pure mathematics, such as in the study of periodic functions and Fourier analysis.

According to given information :

To understand why θ must be in the second quadrant, we need to recall the signs of the trigonometric functions in each quadrant.

In the first quadrant, all trigonometric functions are positive.

In the second quadrant, sine is positive and cosine is negative.

In the third quadrant, both sine and cosine are negative.

In the fourth quadrant, sine is negative and cosine is positive.

Since we know that cos(θ) is negative, we can conclude that θ lies in either the second or third quadrant. However, since cot(θ) = cos(θ)/sin(θ) and cot(θ) is negative, we know that cos(θ) and sin(θ) must have opposite signs. In the third quadrant, both cos(θ) and sin(θ) are negative, so their quotient cot(θ) would be positive, which is not the case.

Therefore, we can conclude that θ lies in the second quadrant.

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The lateral area and the surface area of the right prism are 540 square yards and 1152 square yards, respectively.

Herein we find the case of a right prism with a triangular base, whose lateral area (A) and surface area (A'), both in square yards, must be determined.

The lateral area is the sum of the areas of three rectangular faces and the surface area is the sum of the lateral area and the area of the two triangles. Area formulas for rectangles and triangles are shown below:

Rectangle

A = w · l

Triangle

A = 0.5 · w · l

Where:

Now we determine the lateral area and the surface area of the prism:

Lateral area

A = (37 yd) · (5 yd) + (20 yd) · (5 yd) + (51 yd) · (5 yd)

A = 540 yd²

Surface area

A' = 540 yd² + 2 · 0.5 · (51 yd) · (12 yd)

A' = 1152 yd²

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The Price for one slice pizza is $1.25 and for one drink is $2.25.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

Jim ordered a sports drink and three slices of pizza for $8.50.

His friend ordered two sports drinks and two slices of pizza for $8.00.

let the price for pizza be $ and for one drink is $y.

So, the system of equation is

x + 3y = 8.5....(1)

2x+ 2y= 8......(2)

Solving above two equations we get

2(8.5- 3y) + 2y= 8

17 - 6y + 2y= 8

-4y = -9

y= 9/4

y= 2.25

and, x= 8.5- 3(2.25)= 8.5- 6.75 = $1.25

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The zeroes of the polynomials will be x = (-1 ± 7) / 4.

A polynomial in mathematics is an expression made up of coefficients and indeterminates and involves only the operations of multiplication, addition, subtraction, and non-negative integer exponentiation of variables.

To represent the quadratic polynomial 2x²+ x - 6 using algebra tiles, we can use the following tiles:

Two squares with side length x, representing 2x²

One rectangle with length x and width 1, representing x

Six small squares, representing -6

We can arrange these tiles to form a rectangle as shown below:

A rectangle made of algebra tiles with 2x² squares, x rectangle, and -6 small squares]

The area of this rectangle is the same as the value of the polynomial, which is 2x²+ x - 6.

To determine the equivalent factored form of this polynomial, we need to find two binomials that, when multiplied together, give us the original polynomial. We can start by using the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a = 2, b = 1, and c = -6, since our polynomial is 2x^2 + x - 6.

Plugging in these values, we get:

x = (-1 ± √(1² - 4(2)(-6))) / 2(2)

x = (-1 ± √(49)) / 4

x = (-1 ± 7) / 4

So, the two roots of the quadratic polynomial are x = 3/2 and x = -2.

Therefore, we can write the factored form of the quadratic polynomial as:

2x² + x - 6 = 2(x - 3/2)(x + 2)

To determine the number of zero pairs needed to model this polynomial, we can count the number of negative tiles (small squares) left after forming the rectangle. In this case, we have six negative tiles, which means we need six zero pairs to model this polynomial.

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Answer:

Step-by-step explanation:

A basis for R3 that includes vectors in the set is {[1 0 -2], [3 2 -4], [0 0 1]}. This is achieved by removing the linearly dependent vector [1 0 -2] and adding the vector [0 0 1] to the set to obtain a set that spans R3.

A basis for R3 that includes vectors in the set can be found by removing vectors from a linearly dependent set and/or adding vectors to a set that does not span R3.

The set given is {[1 0 -2], [3 2 -4]}.

To check if the set spans R3, we need to calculate the determinant of the matrix created by the two vectors. The determinant of the matrix is 0, which tells us that the set does not span R3. To create a basis for R3, we need to add a third vector that is not linearly dependent on the other two. We can add the vector [0 1 1] to the set, creating the following set:

{[1 0 -2], [3 2 -4], [0 1 1]}

To check if this set spans R3, we calculate the determinant of the matrix created by the three vectors. The determinant of the matrix is -6, which is not 0.

Therefore, the set {[1 0 -2], [3 2 -4], [0 1 1]} is a basis for R3.

The complete question: For the matrix below. Find a basis for R3 that includes vectors in the set by removing vectors from a linearly dependent set and/or adding vectors to a set that does not span R3.

( matrix attached below )

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Answer: Here you go.

Step-by-step explanation:

The worker makes 4 ornaments every 15 minutes, which is equivalent to 16 ornaments per hour (since 60 minutes / 15 minutes = 4, and 4 x 4 = 16).

Therefore, the worker can make 48 ornaments in 3 hours (since 3 hours x 16 ornaments per hour = 48 ornaments).

If he is paid $1.15 for each ornament he makes, then he earns $55.20 for making 48 ornaments (since 48 ornaments x $1.15 per ornament = $55.20).

Therefore, if the worker works for 3 hours making ornaments, he would earn $55.20.

Answer:

960 miles

Step-by-step explanation:

just multiply by 48x20=960

Answer:

We have to find co-ordinates of the fourth vertex.

Let fourth vertex be D(x,y)

Since, ABCD is a parallelogram, the diagonals bisect each other.

Si, co-ordinate of mid-point of AC= Co-ordinate of mid-point of BD.

∴ The fourth vertex is D(−b,b)

Step-by-step explanation:

The number is the sample deviation, on average 5.5 units from the mean.

The two key areas in statistics are variance and standard deviation. It is a metric for statistical data dispersion. The degree to which values in a distribution deviate from the distribution's average is known as dispersion. The following measurements can be used to determine the extent of the variation:

Range

Quartile Deviation

Mean Deviation

Standard Deviation

Suppose we compute and find that it is equal to 5.5. How do we interpret this number

The number is the sample deviation, on average 5.5 units from the mean.

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The area of the composite figure consists in the sum of the areas of two rectangles, two triangles and a semicircle.

In this problem we find the representation of a composite figure HJKLMNOP, whose area can be determined as the sum of area of different figures. We find the areas of the following figures herein:

Triangle

A = 0.5 · w · l

Rectangle

A = w · l

Semicircle

A = 0.5π · r²

Where:

The composite figure is the result of summing the areas of two rectangles, two triangles and a semicircle.

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Answer: If each drink is 8.64 fluid ounces and Gwen is pouring 48 drinks, then the total amount of fluid ounces she poured is 8.64 fluid ounces * 48 drinks = 413.12 fluid ounces.

Step-by-step explanation:

Answer:

A, C, E

Step-by-step explanation:

TAN = sin / cos

now use algrebra tonsolve the other equations.

B is the value for CoTangent. not tangent.

C is true. multiply both sides by cos

D is false.

E is true. dividing by sin then requires the inverse ratio. which flips fractions on both sides.

Answer:

M--------------N

S---------------T

Step-by-step explanation:

Parallel means that no matter how far they extend they will never touch

Answer:5/4

Step-by-step explanation:

2/3k=8/15

then,

2*15=8*3k

30=24k

k=30/24=15/12=5/4

Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = π, Frequency = 1/π,  equation -4cos(2x) + 1:

Sinusoidal Functions

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

y = (1-3)/2

y = -1

Amplitude is the difference between the maximum and minimum values

A =4

The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at  x = π

Thus the period is

T = π

The frequency is the reciprocal of the period:

f = 1/T = 1/π

The angular frequency is

ω = 2πf

ω = 2

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

f(x) = -4cos(2x) + 1

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Assuming that the coefficient of restitution follows a normal distribution, we can use the z-score associated with a 95% confidence level, which is approximately 1.96.

to find the margin of error for the sample mean. Since we want to find an interval that contains 99% of the values, we need to include ±2.5% on both sides of the mean. Thus, the interval can be calculated as follows:

Interval = sample mean ± z-score * (standard deviation / square root of sample size)

Since we do not have information about the mean or standard deviation of the coefficient of restitution, we cannot provide a specific interval. However, if we assume that the standard deviation is 0.1, we can use a rule of thumb that a sample size of at least 30 is required to use the central limit theorem and assume normality. Then, the interval would be:

Interval = sample mean ± 1.96 * (0.1 / square root of 30)

Note that this is just an example, and the interval will depend on the actual sample mean and standard deviation of the coefficient of restitution.

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Step-by-step explanation:

27cups of flour got to multiple

Answer:

$84.00

Step-by-step explanation:

$80.00 x .05 = $4.00

$80.00 + $4.00 = $84.00

Answer:

the cost is $84.00

Step-by-step explanation:

you take 80.00 x 5% tax that gives you $4.00 so the total is $84.00

The range of flight time is 22 minutes, and the sample standard deviation is 8.24 minutes.

To compute the range, we simply subtract the smallest value from the largest value: Range = 282 - 260 = 22.

To compute the sample standard deviation, we first calculate the mean flight time by summing the values and dividing by the sample size:

Mean = (282 + 270 + 260 + 266 + 260 + 267) / 6 = 266.17

Then we subtract the mean from each flight time, square the differences, sum the squared differences, divide by the sample size minus one, and take the square root of the result:

Standard Deviation = √((1/5) * [(282-266.17)² + (270-266.17)² +

(260-266.17)² + (266-266.17)² + (260-266.17)² + (267-266.17)²]) = 8.24.

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Complete Question:

The following data represent the flight time (in minutes) of a random sample of six flights from Las Vegas, Nevada, to Newark, New Jersey, on United Airlines. 282, 270, 260, 266, 260, 267 Compute the range and sample standard deviation of flight time. The range of flight time is minutes.

The solution of the system is equal to u, u is in the plane [tex]R^3[/tex].

Augmented matrix for Exercise 11:

[1 2 4 -2 0 1 5 9 -3]

The solution is: x = 2, y = -3, z = 1

Augmented matrix for Exercise 12:

[1 2 1 0 -3 -1 5 -1 3]

The solution is: x = -1, y = 6, z = -2

To determine if u = [0 4 4] is in the plane [tex]R^3[/tex], we need to find the solution of the system of linear equations formed by the augmented matrix:

[3 -5 -2 0 6 1 4 1 1]

Solving this system, we find that x = 0, y = 4, z = 4. Since the solution of the system is equal to u, u is in the plane [tex]R^3[/tex].

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Answer:

$25.08

Step-by-step explanation:

7.6% = 0.076

We take

330 times 0.076 = $25.08

You will pay $25.08 sale tax.

Answer:

<1=26

<2=154

<3=26

<4=26

<5=154

<6=154

<7=26

The correct option for the percent of the unshaded area of the circle is (3). 64%.

The area of a circle is π multiplied by the square of the radius. The area of a circle(A) when the radius 'r' is given is πr².

A = πr²

π = 3.14

Area of the bigger circle = 3.14 × 5 × 5

Area of the bigger circle = 78.5

Area of the smaller circle = 3.14 × 3 × 3

Area of the smaller circle = 28.26

Area of the unshaded region of the circle = 78.5 - 28.26

Area of the unshaded region of the circle = 50.24

percent of the unshaded region = (50.24 × 100)/78.5

percent of the unshaded region = 64%

Therefore, the percent of the unshaded area of the circle is equal to 64%.

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Answer: See attached.

Step-by-step explanation:

   We will input the given x-values and solve for y by substituting x for the values in the original function, h(x)=2x-2.

h(-5) = 2(-5)-2 = -12

h(-1) = 2(-1)-2 = -4

h(1) = 2(1)-2 = 0

h(2) = 2(2)-2 = 2

The value of the composition function ( f + g ) ( x ) = x²³ - 3x + 2

Evaluation of a function at the value of another function is known as Composition of function. A function composition is a process in which two functions, f and g, form a new function, h, in such a way that h(x) = g(f(x)). This signifies that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

Given data ,

Let the first function be represented as f ( x )

Now , the value of f ( x ) = -3x + 2

Let the second function be represented as g ( x )

Now , the value of g ( x ) = x²³

On simplifying , we get

The value of ( f + g ) ( x ) = f ( x ) + g ( x )

Substituting the values of f ( x ) and g ( x ) , we get

( f + g ) ( x ) = x²³ - 3x + 2

Hence , the composition function is ( f + g ) ( x ) = x²³ - 3x + 2

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Answer: Since IK and LN are parallel lines, then mIJM and mNMJ are supplementary, meaning that they add up to 180 degrees. Therefore, mIJM = 180° - mNMJ = 180° - 116° = 64°.

Step-by-step explanation:

2.4 cups of milk were used.

A fraction represents a part of a whole.

Let's start by figuring out how much of a gallon was used for coffee:

1/4 of a gallon = (1/4) x 1 gallon = 0.25 gallons

2/5 of a gallon = (2/5) x 1 gallon = 0.4 gallons

So, 0.25 gallons of the 0.4 gallons were used for coffee

Remaining amount of the 0.4 gallons was used for milk:

0.4 - 0.25 = 0.15 gallons

Now, we need to convert 0.15 gallons to cups.

One gallon is equal to 16 cups

0.15 gallons = 0.15 x 16 cups/gallon = 2.4 cups

Therefore, 2.4 cups of milk were used.

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