Answers
1.) The potential energy of an object can be calculated using the equation: PE = mgh
Where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.
So, the potential energy of a 60 kg ball falling from a height of 20 m would be:
PE = 60 kg * 10 m/s² * 20 m = 12000 J (joules)
2.) The average power can be calculated using the equation: P = W / t
Where W is the work done and t is the time taken.
In this case, the work done can be calculated as W = mgh, where m is the mass of the girl (30 N), g is the acceleration due to gravity (10 m/s²), and h is the height of the stairs (5 m).
So, W = 30 N * 10 m/s² * 5 m = 1500 J
And the average power can be calculated as:
P = 1500 J / 6 s = 250 W (watts)
Answer:
Answer is in attached photo.
Explanation:
SolutionThe solution is in the attached photo, do take note to solve these questions, multiple formulas are needed:
Q1) Potential Energy = Mass x Gravitational Accceleration x Height
= m x g x h (SI Unit: J)
Q2) Work Done = Force x Distance
= F x d (SI Unit: J)
Average Power = [tex]\frac{Total \ Work \ Done}{Total \ Time}[/tex] (SI Unit: W)
Related Questions
Choose: The opposite figure shows a mercury barometer. If the height of the mercury column in the barometer was (h) when the atmospheric pressure was 1.01 x 105 N/m² the value of pressure at point x equals a) 1.01 x 105 N/m² b) 6.73 x 104 N/m² c) 2.52 x 104 N/m² d) 7.58 x 104 N/m² Vacuum Mercury
Answers
The pressure at the point x is atmospheric pressure was . Option A
What is the pressure in the arms of the barometer?
We know that the barometer is a kind of device that can be used in the measurement of the pressure of the substance. We have to note that the barometr does have two arms.
The image of the barometer is not shown in this question but we know that the pressure does become equilibrated between the two arms of the barometer that have been shown such that the have the same pressure.
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The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0x(t)=v0t+x0, where v0=2.5m/sv0=2.5m/s and x0=−5.0mx0=−5.0m. The polynomial relationship between position and time for the bowling ball is _______________. O cubic O inverse exponential O quadratic linear
Answers
The bowling ball's position and time are related by a linear equation.
What is linear equation?A linear equation is a mathematical formula that depicts the proportionate relationship between two or more variables, i.e., how changes in one variable cause predictable changes in the others.
The equation x(t) = v0t + x0, where v0 is the starting velocity of the ball (2.5 m/s) and x0 is the initial position of the ball, explains how the position of a bowling ball moving over a smooth surface change with time t. (-5.0 m).
In other words, the ball's position is proportional to the amount of time that has passed, with the beginning velocity, v0, serving as the proportionality constant. Since the ball's velocity is constant, its position advances linearly with time.
As a result, the bowling ball's polynomial relationship between location and time can be represented by a linear equation. Since cubic and inverse exponential equations are often non-linear and have more complicated forms, it is not one of those.
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A compass needle tends to
A. line up randomly to a magnetic field
B. line up parallel to a magnetic field
C. line up perpendicular to a magnetic field
D. line up with the geographic poles of the earth
E. None of these
Answers
The required compass needle tends to line up parallel to a magnetic field. Option B is correct.
What is a magnetic field?A magnetic field is a field that surrounds a magnetic object and exerts a force on other magnetic objects within the field. It is a type of field generated by moving electric charges or by magnetic materials.
Here,
A compass needle tends to line up parallel to a magnetic field. The compass needle is a magnet and the magnetic field from the Earth causes it to align in a north-south direction, with the North end of the needle pointing towards the magnetic North Pole.
Thus, the required compass needle tends to line up parallel to a magnetic field. Option B is correct.
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A 10 kg dog is running in a circle around a tree, trying to catch a squirrel. The dog's speed is 7 m/s and the radius of the dog’s circular path is 3 meters. What is the centripetal force acting on the dog?
A.) 163 N
B.) 16.3 N
C.) 490 N
D.) 23 N
Answers
The centripetal force acting on the dog is 245 N (The options are wrong).
What is centripetal force?The formula for centripetal force is given by F = m × v² / r, where m is the mass of the object (in this case, the dog), v is the velocity of the object, and r is the radius of the circular path.
Plugging in the given values:
F = 10 kg × (7 m/s)² / 3 m = 245 N
So the centripetal force acting on the dog running around a tree is 245 N.
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true/false. a complete circuit is left on for several minutes, causing the connecting copper wire to become hot. as the temperature of the wire increases, the electrical resistance of the wire
Answers
The copper wire that connects the circuit is left on for a number of minutes before becoming heated. False, the wire becomes hotter as it gets hotter. Thus, it is false.
What is the electrical resistance of the wire?A complete circular path through which electricity flows is known as a circuit in electronics. A simple circuit consists of a current source, conductors, and a load.
The term “circuit” can broadly be used to describe any ongoing path via which electricity, data, or a signal might go.
Closed circuit, open circuit, short circuit, series circuit, and parallel circuit are the main varieties of electric circuits. The movement of electric charge or current has a conductive channel thanks to electric circuits.
Therefore, it is false that if a complete circuit is left on for a number of minutes, the copper wire that connects the devices gets warm. When the wire's temperature rises, so does its electrical resistance.
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You ride in a boat on a river flowing at 1.8 m/s. Suppose you would like the boat to move directly across the river (in the negative x direction) with a speed of 5.0 m/s. What is the corresponding speed of the boat's velocity relative to the water? What is the corresponding direction of the boat's velocity relative to the water? Express your answer to two significant figures and include appropriate units
Answers
The boat's velocity relative to the water is 6.8 m/s, in the negative y direction.
To calculate the boat's velocity relative to the water, we first need to subtract the speed of the river from the desired speed of the boat. The desired speed of the boat is 5.0 m/s, and the speed of the river is 1.8 m/s. Thus, the boat's velocity relative to the water is 5.0 m/s - 1.8 m/s = 3.2 m/s.
To determine the direction of the boat's velocity relative to the water, we need to consider the direction of the river and the desired direction of the boat.
The river is flowing in the positive x direction, while the desired direction of the boat is in the negative x direction. Therefore, the direction of the boat's velocity relative to the water is in the negative y direction.
To calculate the magnitude of the boat's velocity relative to the water, we use the Pythagorean theorem. The magnitude of the boat's velocity relative to the water is equal to the square root of the sum of the squares of its x and y components. Thus, the magnitude of the boat's velocity relative to the water is 6.8 m/s (3.2 m/s in the negative y direction).
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Part A
A sports car accelerates from rest to 94 km/h in 5.5 s.
What is its average acceleration in m/s².
Express your answer using two significant figures.
V
ΑΣΦ
?
Answers
Answer:
The average acceleration of the sports car is 16.9 m/s².
12. Consider the falling and rolling motion of the 2.0 kg ball in the following two resistance-free
situations. In one situation, the ball falls off the top of the platform to the floor. In the other situation,
the ball rolls from the top of the platform along the staircase-like pathway to the floor. Fill in answer
for each the blanks lettered A-K.
PE=100J
KE=0J
PE= F J
KE- GJ
v=__H_m/s
PE=50J
KE-A J
V= B_m/s
PE=_C_J
KE=D J
v=__E__m/s
Answer the questions using logic and a little bit of arithmetic.
Top & Bottom:
1. What is the PE of the ball at the very top of the diagram above?
2.
What is the KE of the ball at the very top of the diagram above?
3. What is the PE of the ball the location shown as I on the diagram above?
4. What is the KE of the ball the location shown as J on the diagram above?
5.
What is the velocity of the ball the location shown as K on the diagram above?
requires a little mental math - but you can use a calculator if you need it.
6. What is the PE of the ball the location shown as F on the diagram above as the ball hits the ground?
10
PE=IJ
KE J J
v=K_m/s
8. What is the velocity of the ball the location shown as H on the diagram above?
your previous answers-don't solve the velocity equation.
7. What is the KE of the ball the location shown as G on the diagram above as the ball hits the ground?
Rolling down the ramp:
9. What is the KE of the ball the location shown as A on the diagram above?
This one
Use logic &
10. What is the velocity of the ball the location shown as B on the diagram above? Use logic & your previous
answers-don't solve the velocity equation.
11. What is the PE of the ball the location shown as C on the diagram above?
12. What is the KE of the ball the location shown as D on the diagram above?
13. What is the velocity of the ball the location shown as E on the diagram above? Use logic & your previo
answers-don't solve the velocity equation.
Answers
The PE (potential energy) of the ball at the very top of the diagram is 100 J.
The KE (kinetic energy) of the ball at the very top of the diagram is 0 J.
The PE of the ball the location shown as I on the diagram is 50 J.
The KE of the ball the location shown as J on the diagram is 50 J.
What is friction?Friction is a force that acts between two objects that are in contact with each other and opposes their relative motion.
The velocity of the ball the location shown as B on the diagram can be calculated by the equation KE = 0.5 * m * v^2, where m is the mass of the ball (2 kg) and KE is the kinetic energy (50 J). Solving for velocity, we get v = sqrt(KE / (0.5 * m)) = sqrt(50 / (0.5 * 2)) = 7 m/s.
The PE of the ball the location shown as F on the diagram as the ball hits the ground is 0 J.
The KE of the ball the location shown as G on the diagram as the ball hits the ground can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball (calculated in #5 as 5 m/s). Solving for KE, we get KE = 0 + 0.5 * 2 * 5^2 = 50 J.
Using the equation KE = 0.5*m*v2, the velocity can be determined to be 7.07 m/s for B and E and 10 m/s for H and K.
The 100 J of original mechanical energy is present at each position. So the KE for A is 50 J.
The KE of the ball the location shown as A on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball. The KE at A will be 50J.
The PE of the ball the location shown as C on the diagram can be calculated by conserving energy, meaning that the initial PE at the top of the ramp plus any work done by friction must equal the final KE at this location. This can be expressed as PE + work done by friction = KE, where work done by friction is equal to friction force times distance. So, at C, PE=50J and the KE of the ball the location shown as D on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2 So, KE for D will be50J.
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at a given instant in time, a red car is traveling at twice the velocity of a blue car. which of the following statements is correct? A. The red car has a higher acceleration than the blue car
B. The blue car has a higher acceleration than the red car
C. Both cars have the same acceleration
D. There is nothing we can say about the acceleration of either car
Answers
There is nothing we can say about the acceleration of either car
How does acceleration work?
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.
The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.
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A golf ball (lighter) is fired at a bowling ball (heavier) initially at rest and bounces back elastically. Compared to the bowling ball, the golf ball after the collision has
a) less momentum but more kinetic energy
b) more momentum but less kinetic energy
c) more momentum and more kinetic energy
d) less momentum and less kinetic energy
Answers
Compared to the bowling ball, the golf ball after the collision has a) less momentum but more kinetic energy.
The bowling ball's velocity and, consequently, its kinetic energy are significantly lower than those of the golf ball because its mass is significantly greater than that of the latter.
Why is the kinetic energy of a bowling ball greater than that of a golf ball?
First off, heavier objects in motion have more kinetic energy than lighter ones. For example, a bowling ball travelling at 10 m/s (the equivalent of a very fast sprint) has a lot more kinetic energy than a golf ball travelling at the same speed.
How does a collision between a bowling ball and bowling pins alter their kinetic energy?
When two objects collide, some of the kinetic energy is converted during the collision to another form of energy, this is known as an inelastic collision. A portion of the kinetic energy from the bowling ball is transferred to the pins when it strikes them, as evidenced by the way bowling balls and pins scatter and bounce after impact.
Which ball has more inertia, a golf ball or a bowling ball?
As a result of having more mass than a golf ball, a bowling ball will have a higher moment of inertia.
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A girl tosses a stone into the air with an initial upward velocity of 8.00 meters/second and hears the splash when it hits the water 4.20 seconds later. How deep is the water level in the well below where she tossed the stone
Answers
Deep is the water level in the well below where she tossed the stone is 52.92 m.
Consider the equation of motion s = ut + 0.5 at²
Take the upward direction as positive,
Initial velocity, u = 8 m/s
Acceleration, a = -9.81 m/s²
Time, t = 4.20 s
Substituting
s = ut + 0.5 at²
s = 8 x 4.20 + 0.5 (-9.81) x 4.20²
s = -52.92 m
Depth of well = 52.92 m
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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A bubble of air of volume 3.0 mm3 is under water. The bubble is at a depth where the pressure of the air inside the bubble is four times atmospheric pressure. The temperature of the air in the bubble stays the same as it rises to the surface. What is the volume of the air in the bubble as it reaches the surface?
Answers
The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.
How the volume was calculatedThe volume of an ideal gas is proportional to its temperature and inversely proportional to its pressure. Since the temperature of the air in the bubble stays the same, the ratio of the initial pressure to the final pressure is equal to the ratio of the final volume to the initial volume.
Since the pressure inside the bubble at a depth of 4 times atmospheric pressure is 4 times atmospheric pressure, the pressure inside the bubble at the surface is equal to atmospheric pressure.
The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.
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2. A person standing at the edge of a cliff throws one ball straight up and another ball
straight down, each at the same initial speed. Neglecting air resistance, which ball hits the
ground below the cliff with the greater speed?
Answers
Answer:
the ball that is thrown down
Explanation:
due to force
A friend of yours is loudly singing a single note at 400 Hz while racing toward you at 23.0 m/s on a day when the speed of sound is 342 m/s.Part A: What frequency do you hear?Part B:What frequency does your friend hear if you suddenly start singing at 400 ?
Answers
You heard a frequency of 428.8 Hz, and your companion heard a frequency of 426.8 Hz.
What is a simple definition of frequency?The quantity of oscillations that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the amplitude is 2 per moment. This same frequency is 100 times per hour if it consumes 1/100 of an hour.
Where is the use of frequency?The frequency of oscillation and granular phenomenon, such as mechanical energy, speech recordings (sound), electromagnetic radiation, and light, is a crucial parameter in science and engineering.
The frequency you heard,
f = f(s) / [1 - (v(s)/v) ]
f = 400 / [1 - 23/342]
f = 400 / (1 - 0.0672)
f = 400 / 0.9328
f = 428.8 Hz
The frequency your friend hearing,
f = f(s) * [1 + (v(s)/v) ]
f = 400 * [1 + 23/342]
f = 400 * (1 + 0.0672)
f = 400 * 1.0672
f = 426.8 Hz
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HELP ME QUICKLYYYYY!!! TYYY
Listed in the Item Bank are some important labels for sections of the image below. Drag and drop each label to the corresponding area it identifies in the image.
1: cell membrane
2: nucleus
3: DNA
4: cytoplasm
5: ribosome
Answers
Answer:
vamos tú puedes
Explanation:
The equation of a wave traveling in a horizontal direction is expressed as y = 5sin(60t - x)
What's the phase angle
(a)90° (b)180° (c)270° (d)360° (e)0°
Answers
Answer:
The equation of a transverse wave traveling along a very long string is y=6.0sin(0.020πx+4.0πt), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave, and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x=3.5 cm when t=0.26s?/(a) The amplitude is y
m
=6.0 cm.
(b) We find λ from 2π/λ=0.020π⋅λ=1.0×10
2
cm.
(c) Solving 2πf=ω4.0π, we obtain f=2.0 Hz.
(d) The wave speed is v=λf=(100 cm)(2.0 Hz)=2.0×10
2
cm/.s
(e) The wave propagates in the −x direction, since the argument of the trig function is kx+ωt instead of kx−ωt
(f) The maximum transverse speed (found from the time derivative of y) is
u
max
=2πfy
m
=(4.0πs
−1
)(6.0 cm)=75 cm/s
(g) y(3.5 cm,0.26 s)=(6.0 cm)sin[0.020π(3.5)+4.0π(0.26)]=2.0 cm.
6. The resistance of a platinum coil of platinum resistance thermometer at 0 °C is 5 Ohms and at 100 C is 5.39 Ohms. When this thermometer is put in a hot bath, the resistance of platinum wire is found to be 5.795 Ohms. The temperature of the bath is? A. 345.652 K B.400 °C C. 345.652 C D. 400 K
Answers
The temperature of the hot bath is approximately 400 °C. (Option B).
How is the Temperature Calculated?To find the temperature of the hot bath, we need to use the temperature coefficient of resistance (α) of platinum and the resistance at 0°C and 100°C as a reference.
The equation to find the temperature is given by:
T = (R/R0 - 1) / α + T0
Where R is the resistance at the hot bath temperature, R0 is the resistance at 0°C, T0 is 0°C, and α is the temperature coefficient of resistance of platinum.
Using this equation and the given values, we can calculate T as:
T = (5.795/5 - 1) / (5.39/5 - 1) * (100 - 0) + 0 = approximately 400 °C
So the temperature of the hot bath is approximately 400 °C .
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The melting point of MgO is higher than that of NaF. Explanations for this observation include which of the following?I. Mg2+ is more positively charged than Na+.II. O2- is more negatively charged than F-.III. The O2- ion is smaller than the F- ion.Pilihan jawabanI and II onlyII onlyI and III onlyII and III onlyI, II , and III
Answers
Because Mg2+ is more positively charged than Na+, MgO has a higher melting point than NaF. Moreover, O2 has a stronger negative charge than F (I & II only, option A)
Ionic solids MgO and Naf both exist. MgO has a higher melting point than NaF because it takes more energy to break the bonds in MgO since it contains higher-charged ions than NaF (Na+ and F).
While Naf (Na+ and F) has a monovalent nature, MgO (Mg2+ and O2) has both divalent (Mg2+ and O2) ions. In the crystal lattice of MgO, the electrostatic forces between the ions are higher than in the case of Naf. As a result, MgO's melting point (2642⁰ C) is greater than NaF's (992⁰ C).
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NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude: The result at certain altitude is: R-0.0533 kPa:km Convert R to J cm Lo
Answers
After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.
What is joule?
In both electromagnetic and mechanical applications, the joule was specifically meant to be the unit of energy.The use of the calorie was formally discouraged with the adoption of the definition at the ninth General Conference on Weights and Measures in 1948, which alsoalso added the specification that the joule was to be preferred as the unit of heat in the context of calorimetry.The joule as it appeared in the present International System of Units in 1960 was directly related to this definition.To convert R to J, convert their units,
1 kPa·km = 1.0 × 10⁻⁸ J(cm⁻⁴)
0.0533 kPa·km = -0.0533 × 1.0 × 10⁻⁸ J(cm⁻⁴)
= 5.33 × 10⁻¹⁰ J·cm⁻⁴
Thus, After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.
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In which circumstance would hypnosis be most effective and appropriate?
Answers
Hope this helps have an excellent day!
ITS DUE IN 5 MINSSSSSSs Through his investigation, Nathanial identified when equal forces are applied to an object, the motion of the object does not change. He started a data table to record the evidence from his investigation. Which further evidence can Nathanial use to support his findings? (ANSWER RIGHT NOW, ITS DUE LITERALLY IN 10 MINS)
67 N in row one and 110 N in row two
120 N in row one and 67 N in row two
115 N in row one and 65 N in row two
100 N in row one and 65 N in row two
Answers
Answer:
Explanation:
2nd choice: 120 N in row one and 67 N in row two
Applied forces have to be equal in magnitude and opposite in direction to cancel each other out and result in no change to the object's motion
2) Three positive charges are located as shown in the diagram below q1 1cm q3 q1 1cm q2 find the size of electrostatic force exerted by charge q3.
Answers
F = k * (q1 * q3) / r^2
where:
k is Coulomb's constant (8.99 x 10^9 N * m^2 / C^2)
q1 and q3 are the magnitudes of charges 1 and 3 (assumed to be in Coulombs)
r is the distance between the charges (1 cm in this case)
So the force can be calculated as:
F = 8.99 x 10^9 N * m^2 / C^2 * (q1 * q3) / (1 cm)^2
Plugging in the numbers, assuming q1 and q3 are both 1 Coulomb each:
F = 8.99 x 10^9 N * m^2 / C^2 * (1 Coulomb * 1 Coulomb) / (1 cm)^2
= 8.99 x 10^9 N
The electrostatic force between the two charges is 8.99 x 10^9 N.
A microwave oven emits radiation at a wavelength of 0.500 cm What is the frequency of this radiation? a.) 6.67 x 10-7 Hz b.) 6.00 x 1010 Hz c.) 1.50 x 106 Hz d.) 2.00 Hz
Answers
The frequency of a microwave oven that emits radiation at a wavelength of 500 cm would be 6.00 × 10¹⁰ Hz (B)
The frequency of a radiation in physics is the quantity of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time. Heinrich Rudolf's name was given to the SI unit that measures frequency known as the hertz. Additionally, 1 Hz means one cycle per second.
The distance between the two closest points that are in phase with one another is known as a wavelength. As a result, a single full wavelength separates two nearby peaks or troughs on a wave. Typically, the wavelength of a wave is denoted by the letter lambda (λ).
The following formula gives the relationship between wavelength and frequency:
V = f × λ
Where:
V = wave speed
= 3 × 10⁸ m/s (speed of light)
F = frequency
λ = wavelength
= 0.005 m
Thus, the frequency of the microwave would be:
3 × 10⁸ m/s = f × 0.005 m
f = ( 3 × 10⁸ m/s) ÷ (0.005 m)
f = 6 × 10¹⁰ Hz
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If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7)?
a. 3 A, 1A, 2A, 1A, 2A, 1A, 3A
b. 3 A, 2A, 1A, 1A. 1A, 1A, 2A
c. 3 A, 2A, 1A, 1A. 1A, 1A, 2 A
d. 3 A, 2A, 1A, 1A, 1A, 1A, 3A
Answers
If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7), 3 A, 1A, 2A, 1A, 2A, 1A, 3A. so, option (a) is correct.
What is ammeter ?
A shunt and a gadget known as a galvanometer are parallelly linked within the ammeter. Shunts are resistances that let measured current flow through an ammeter and provide a complete readout. A sensitive current detector is the galvanometer.
What is power ?
Work is done at a certain rate according to power. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit of power. Power is the rate at which energy is used up since power is the transfer of energy. For instance, a 60-W light bulb uses about 60 J of energy every second.
Therefore, If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7), 3 A, 1A, 2A, 1A, 2A, 1A, 3A. (a).
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a direct expansion-type evaporator is also called a . flooded evaporator dry-type evaporator multi-circuit evaporator stamped evaporator
Answers
A dry-type evaporator is another name for a direct expansion evaporator. An evaporator seems to be a container or platform that converts liquid into vapor.
Evaporator, what is it?In contrast to the condenser, the evaporator absorbs heat from the compartment's air while converting refrigerant liquid to gas. Due to the reduced pressure and heat dissipation, the liquid refrigerant is much cooler than for the fan air surrounding it when it reaches the evaporator.
What sort of evaporator is employed?One of the popular evaporators is the LTV. Basically, it is a liquid separator coupled to a shell and tube heat exchanger. The climbing film evaporator and the descending film evaporator are quite similar. It is the total opposite of something like a falling movie.
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A merry-go-round is spinning in a circle at a constant speed. A child is 4 meters away from the center of the merry-go-round and experiences a centripetal acceleration of 6 m/s^2. What is the tangential velocity of the child?
A.) 1.5 m/s
B.) 24.0 m/s
C.) 9.1 m/s
D.) 4.9 m/s
Answers
The velocity is 4.9 m/s.
What is the centripetal acceleration?Centripetal acceleration is the acceleration that acts towards the center of a circular path and is required to maintain an object in circular motion. It is defined as the rate of change of velocity of an object moving in a circular path.
The formula for centripetal acceleration can be expressed as:
a_c = v^2 / r
Given that;
a = v^2/r
a = acceleration
v = tangential velocity
r = radius
Thus;
v = √ar
v = (6 * 4)^1/2
v = 4.9 m/s
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Suppose a car's velocity is to the left, and its acceleration is to the right. Which of the following describes this car's motion? A) The car is speeding up. B) The car is slowing down. C) The car is moving at a constant speed.
Answers
The correct answer is B) The car is slowing down.
What is velocity?Velocity is a vector quantity that measure the rate and direction of the change. Velocity is an object position it is equal to distance traveled devide by time.
This is because when the velocity is to the left and the acceleration is to the right, the acceleration is in the opposite direction of the velocity.
This means that the car is experiencing a deceleration, or a slowing down of its velocity. Since the acceleration is to the right, the car is slowing down with respect to the right.
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list two characteristics sound that are affected by the medium through which the sound passes and two characteristics that are not affected
Answers
The frequency of a sound wave remains constant when it moves through one medium to another, whereas the wave's temperature, velocity, and wavelength all change.
A frequency is defined.Frequency is the number of waves that pass through a specific spot in a defined amount of time. A wave has a frequency of 2 per second if it goes though within less than one second. if the time required becomes a hundredth of either an hour.
What does the frequency of a wave mean?The frequency of a recurrent occurrence, such as a wave, over a given time period is measured using this unit. A cycle is a single instance of the regular pattern. only waves that are moving and have different positions.
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At highway speeds, a particular automobile is capable of an acceleration of about 2.0 m/s At this rate, how long does it take to accelerate from 70km/hto 120km/h? Express your answer to two significant figures and include the appropriate units. .
Answers
Answer:
It takes approximately 10.3 seconds to accelerate from 70km/h to 120km/h, when the acceleration is 2.0m/s.
(D) A water tank located at a depth of 8 m from ground level is half full of water. This water is pumped up by a water pump in the basement and drilled at 2 mis' access. 10 minutes until the water in the tank is finished 0: The power of the motor is 1 kW and the cross-sectional area of the tank is 2m. ii) Determine the useful work (output) done by the equation/x, (ii) Find the energy required for friction, (iii) Find the efficiency of the pump. (iv) Suggest a way to increase the value of (iii) above. (Density of water = 1000 kgm ]
Answers
The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.
What should be the method to calculate the output, friction and efficiency?The weight of the water pushed and the height it is lifted can be multiplied to determine the beneficial work done by the pump. The volume of water in the tank multiplied by its density yields the weight of the water therein. The tank's total volume, which can be determined by multiplying the tank's cross-sectional area by its height, is equal to half of the amount of water in the tank (8 m). The water therefore weighs:
Volume is calculated as cross-sectional area times height (2 m x 8 m = 16 m3).
Weight is equal to volume times density, or 16 m3 times a density of 1000 kg/m3 equals 16,000 kg.
Useful work=Weight x Height = 16,000 kg x 10 m = 160,000 J for useful work.
A proportion of the useful work can be used to estimate the amount of energy needed for friction. This proportion is influenced by the pump's design, the water's viscosity, and other elements. The energy needed for friction can be computed using a 10% friction loss as follows:
Frictional energy equals 0.1 x 160,000 J, or 16,000 J.
The ratio of the pump's useful work to its energy input can be used to calculate the pump's efficiency. The energy input can be estimated as the motor's power (1 kW) times how long it runs for (10 minutes, or 600 seconds). So, the efficiency can be determined as follows: Energy input is calculated as follows: 1 kW x 600 sec = 600,000
Efficiency is calculated as follows: 160,000 J of useful work per 600,000 J of energy input, or 26.7%.
The friction loss can be decreased, the pump's design can be improved to reduce energy losses, or the motor's power can be increased to increase the pump's efficiency. As the beneficial work performed by the pump is directly proportional to the height the water is lifted, increasing the height the water is lifted is another alternative.
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