Plot da(t) if the output voltage of the converter pole-a is vaN(t)=Vd/2+0.85 Vd/2 sin(Ï1t), where Ï1=2Ï x 60 rad/s

Answer:

[tex]\mathbf{P_x =25 \ watts}[/tex]

[tex]\mathbf{x_{rmx} = 5 \ unit}[/tex]

Explanation:

Given that:

x(t) = 10 sin(10t) . sin (15t)

the objective is to find the power and the rms value of the following signal square.

Recall that:

sin (A + B) + sin(A - B) = 2 sin A.cos B

x(t) = 10 sin(15t) . cos (10t)

x(t) = 5(2 sin (15t). cos (10t))

x(t) = 5 × ( sin (15t + 10t) +  sin (15t-10t)

x(t) = 5sin(25 t) + 5 sin (5t)

From the knowledge of sinusoidial signal  Asin (ωt), Power can be expressed as:

[tex]P= \dfrac{A^2}{2}[/tex]

For the number of sinosoidial signals;

Power can be expressed as:

[tex]P = \dfrac{A_1^2}{2}+ \dfrac{A_2^2}{2}+ \dfrac{A_3^2}{2}+ ...[/tex]

As such,

For x(t), Power  [tex]P_x = \dfrac{5^2}{2}+ \dfrac{5^2}{2}[/tex]

[tex]P_x = \dfrac{25}{2}+ \dfrac{25}{2}[/tex]

[tex]P_x = \dfrac{50}{2}[/tex]

[tex]\mathbf{P_x =25 \ watts}[/tex]

For the number of sinosoidial signals;

[tex]RMS = \sqrt{(\dfrac{A_1}{\sqrt{2}})^2+(\dfrac{A_2}{\sqrt{2}})^2+(\dfrac{A_3}{\sqrt{2}})^2+...[/tex]

For x(t), the RMS value is as follows:

[tex]x_{rmx} =\sqrt{(\dfrac{5}{\sqrt{2}} )^2 +(\dfrac{5}{\sqrt{2}} )^2 }[/tex]

[tex]x_{rmx }=\sqrt{(\dfrac{25}{2} ) +(\dfrac{25}{2} ) }[/tex]

[tex]x_{rmx }=\sqrt{(\dfrac{50}{2} )}[/tex]

[tex]x_{rmx} =\sqrt{25}[/tex]

[tex]\mathbf{x_{rmx} = 5 \ unit}[/tex]

Answer:

Ampacity

Explanation:

Ampacity is a word used to expalin ampere capacity defined by National Electrical Codes.

Ampacity is defined as the maximum current, in amperes, that can flow in a conductor continuously under the conditions of use without exceeding the temperature rating of the conductor.

Therefore, in the National Electrical Code, the current carrying abilities of conductors are called the Ampacity.

The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.

The term contrast is known to be a word that tends to show some noticeable differences between two things.

Note that it is liken to a cause and its effect. The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.

Learn more about  contrast from

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Answer:

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

Explanation:

Power is the rate of change of work in time, since given input is average power, the total energy ([tex]\Delta E[/tex]) of the motor of the electric vehicle, measured in joules, is determined by this formula:

[tex]\Delta E = \dot W \cdot \Delta t[/tex]

Where:

[tex]\dot W[/tex] - Average power, measured in watts.

[tex]\Delta t[/tex] - Time, measured in seconds.

Now, let convert average power and time into watts and seconds, respectively:

Average Power

[tex]\dot W = (50\,hp)\times \frac{746\,W}{1\,hp}[/tex]

[tex]\dot W = 3.730\times 10^{4}\,W[/tex]

Time

[tex]\Delta t = (1\,h)\times \frac{3600\,s}{1\,h} + (25\,min)\times \frac{60\,s}{1\,min}[/tex]

[tex]\Delta t = 5.100\times 10^{3}\,s[/tex]

Then, the total energy is:

[tex]\Delta E = (3.730\times 10^{4}\,W)\cdot (5.100\times 10^{3}\,s)[/tex]

[tex]\Delta E = 1.902\times 10^{8}\,J[/tex]

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

Answer:

2.25V

Explanation:

In the above question, we are given an npn transistor.

It's VB = Biased voltage = 2.95V

We are asked to calculate the DC emitter voltage.

DC emitter voltage = VB - VBE

Where:

VBE = Voltage between the base and emitter of a bipolar junction transistor

VBE has a set standard voltage of 0.7V

Hence,

DC emitter voltage = 2.95V - 0.7V

= 2.25V

In this exercise we have to use the knowledge of voltage to calculate the difference, like this:

[tex]2.25V[/tex]

Knowing that the initial voltage is given by 2.95V and we want to find the voltage difference we have:

[tex]DC = VB - VBE[/tex]

Where, VBE = Voltage between the base and emitter of a bipolar junction transistor is equal to 0.7 V, this way:

[tex]DC = 2.95V - 0.7V = 2.25V[/tex]

See more about voltage at brainly.com/question/2364325

Answer:

Explanation:

The question is in complete without the diagram. please see attached the diagram

From the free body diagram of the block when it is ready to tip

∑M₀= 0.

kindly find attached the diagram of the rectangular block,

the free body diagram, and a detail solving for your reference  

Answer:

Both are right

Explanation:

It all depends on the customer. The technicians job is to inform the customer about what can be done, rest depends on the customer that what he wants to be done. If he prefers to get the parts replaced then he should do it, and he he thinks that after repair they will work well then he should go for the repair.

Answer: Neutrals

Explanation: System grounding on a power system is a term used to describe the entire processes involved when a neutral is used as the conductor to connect to the solid earth. This ensures that power is generated. This is usually done using either an inductor, an impendance or a resistor. It is very important and necessary to carry out a proper grounding of a power system in order to ensure the safety of the equipment and the personnel etc

Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

Answer: Honest

Explanation: In other to establish communication between two or more species, the sender and receiver, It is required of the sender to showcase certain behavior, sound or other demonstrations which are capable of passing a message to the receiver. These demonstrations are often reffered to as signals. Signals could be honest or dishonest. Honest signals are characterized by it's usefulness to the receiver and the conveyance of the actual or true meaning of underlying signal being transmitted. This is the opposite of dishonest signals which are often used to trick the receiving party as the information being transmitted are inaccurate and unreliable.

Answer:

the minimum volume flow rate needed to tip the block is 2.66 × 10⁻⁴ m/s

Explanation:

Given that;

diameter of the jet d = 10 mm

weight W = 6 N

Now we say

Fₓ Lfₓ - Wlw= 0

horizontal force

Fₓ = W (lw/lfₓ)

Fₓ = 6 ( 0.015/2)

Fₓ = 0.9 N

X-component of momentum

v₁p(-v₁)A₁ = - Fₓ

pA₁v₁² = Fₓ

v₁² = Fₓ / pA₁

v₁ = √( Fₓ / pA₁ )

WE SUBSTITUTE

v₁ = √ ( 0.9 / ((999)(π/4)(0.01))²

v₁ = 3.39 m/s

Now Discharge Q = A₁v₁

Q = π/4 (0.01)² (3.39)

Q = 2.66 × 10⁻⁴ m/s

therefore the minimum volume flow rate needed to tip the block is 2.66 × 10⁻⁴ m/s

Answer:

3) By forking process A again, creating another child C

Explanation:

To prevent a process B, forked from a parent process A from becoming a Zombie, you have to make sure that the parent process A calls wait for every child process that terminates. We can also fork the process A again, and have the immediate child process B exited immediately.

Correct question is;

An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 100°C. Air enters the heating section at 10°C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 20°C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.

Answer:

A) Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%

B) Q' = 420.01 KJ/min

C) m'w = 0.1472 Kg/min

Explanation:

This question depicts a steady state process and as such the mass flow rate of dry air will remain constant during the entire process.

A) Now, from the psychometric chart attached, at temperatures of T1 = 10°C & T3 = 20°C, Relative humidities; Φ2 = 70% & Φ2 = 60% and at pressure of 1 atm, we have;

Enthalpy at state 1;h1 = 23.5 Kj/kg dry air

Absolute humidity at state 1;ω1 = ω2 = 0.0053 kg of water per kg dry air

Enthalpy at state 3;h3 = 42.3 KJ/Kg dry air

Absolute humidity at state 3; ω3 = 0.0087 kg of water per Kg dry air

Specific volume at state 1;υ1 = 0.809 m³/kg

The formula for energy balance for the humidifying is given as;

h3 = h2 + hg(ω3 - ω2)

Where hg is the enthalpy of wet steam.

From second table attached, hg at 100°C is 2675.6 KJ/kg

Thus;

Making h2 the subject, we have;

h2 = h3 + hg(ω2 - ω3)

Plugging in the relevant values we have;

h2 = 42.3 + 2675.6(0.0053 - 0.0087)

h2 = 33.2 KJ/kg

Still using the psychrometric chart attached at ω2 = 0.0053 and h2 = 33.2 KJ/kg, we have;

Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%

B) to determine the rate of heat transfer, let's first find the mass flow rate first;

m' = V1'/υ1

Thus, m' = 35/0.809

m' = 43.3 kg/min

Thus, rate of heat transfer is given by;

Q' = m'(h2 - h1)

Plugging in the relevant values, gives;

Q' = 43.3(33.2 - 23.5)

Q' = 420.01 KJ/min

C) the rate at which water is added to the air in the humidifying section is given by;

m'w = m'( ω3 - ω2)

m'w = 43.3(0.0087 - 0.0053)

m'w = 0.1472 Kg/min

Answer:

T₂ = 19.5 °C

∅₂ = 37.8%

Q = 420.01 kJ/min

m[tex]_{w}[/tex] = 0.015 kg/min

Explanation:

Given:

total pressure = p = 1 atm

Temperatures:

T₁ = 10°C

T₃ = 20°C

Relative Humidity:

∅₁ = 70%

∅₃ = 60%

Volume = V₁ = 35 m³/min

Solution:

a) Use psychometric chart to determine the enthalpies by using the given values of temperatures and relative humidity:

h₁ = 23.5 kJ/kg

w₁ = 0.0053

w₁ = w₂

h₃ = 42.3 kJ/kg

w₃ = 0.0087

v₁ = 0.809 m³/kg

When the airs flows through the heating section, the amount of moisture in it remains constant. So

w₁ = w₂

When the airs flows through the humidifying section, the amount of moisture in it increases. So

w₃ > w₂

Compute enthalpy h₂

h₂ = h₃ - ( w₃ - w₂) hs

where hs is the enthalpy of wet steam at 100°C from steam table

hs = 2676 kJ/kg

h₂ = 42.3 - ( 0.0087  - 0.0053 ) 2676

    = 42.3 -  (0.0034) 2676

    = 42.3 - 9.0984

    = 33.2016

h₂ = 33.2 kJ/kg

Compute T₂ and ∅₂

Using h₂ = 33.2 kJ/kg and w₂ = 0.0053 and psychometric chart:

T₂ = 19.5 °C

∅₂ = 37.8%

Compute mass flow rate:

mass flow rate = m = V₁ /v₁

                                = 35/0.809

                                = 43.26 kg/min

     m = 43.3 kg/min

b) Compute heat transfer in the heating section:

Q = m x (h₂  - h₁)

   = 43.3 kg/min ( 33.2 kJ/kg - 23.5 kJ/kg )

   = 43.3  ( 9.7 )

Q = 420.01 kJ/min

c) Compute rate at which water is added to the air in the humidifying section

Let m[tex]_{w}[/tex] be the mass flow rate equation of water in  humidifying section is:

m[tex]_{w}[/tex]  = m(w₃ - w₂)

      = 43.3 ( 0.0087  - 0.0053 )

      =  43.3(0.0034)

      = 0.14722

      = 0.147 kg/min

m[tex]_{w}[/tex] = 0.015 kg/min

Answer:

b

Explanation: because it says input file.read

Answer:

Steady flow

Explanation:

Flows in fluids can be categorized into different classes depending on the type of flow and the variations in their characteristics such as velocity, pressure, density, temperature, e.t.c

When these characteristics do not change when measured over time at a single point, then the flow is said to be steady. For a steady flow, the mathematical expression, amidst other conditions, is given as follows;

[tex]\frac{dV}{dt} = 0, \frac{dP}{dt} = 0, \frac{dT}{dt} = 0[/tex]

Where;

V, P and T are the velocity, pressure and temperature of the fluid.

PS:

Other types of flows include:

i. Unsteady flow

ii. Laminar flow

iii. Turbulent flow

iv. Uniform flow

v Non-uniform flow

vi. Rotational flow

vii. Irrotational flow

Answer:

Correct question is;

An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 100°C. Air enters the heating section at 10°C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 20°C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.

Answer:

A) Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%

B) Q' = 420.01 KJ/min

C) m'w = 0.1472 Kg/min

Explanation:

This question depicts a steady state process and as such the mass flow rate of dry air will remain constant during the entire process.

A) Now, from the psychometric chart attached, at temperatures of T1 = 10°C & T3 = 20°C, Relative humidities; Φ2 = 70% & Φ2 = 60% and at pressure of 1 atm, we have;

Enthalpy at state 1;h1 = 23.5 Kj/kg dry air

Absolute humidity at state 1;ω1 = ω2 = 0.0053 kg of water per kg dry air

Enthalpy at state 3;h3 = 42.3 KJ/Kg dry air

Absolute humidity at state 3; ω3 = 0.0087 kg of water per Kg dry air

Specific volume at state 1;υ1 = 0.809 m³/kg

The formula for energy balance for the humidifying is given as;

h3 = h2 + hg(ω3 - ω2)

Where hg is the enthalpy of wet steam.

From second table attached, hg at 100°C is 2675.6 KJ/kg

Thus;

Making h2 the subject, we have;

h2 = h3 + hg(ω2 - ω3)

Plugging in the relevant values we have;

h2 = 42.3 + 2675.6(0.0053 - 0.0087)

h2 = 33.2 KJ/kg

Still using the psychrometric chart attached at ω2 = 0.0053 and h2 = 33.2 KJ/kg, we have;

Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%

B) to determine the rate of heat transfer, let's first find the mass flow rate first;

m' = V1'/υ1

Thus, m' = 35/0.809

m' = 43.3 kg/min

Thus, rate of heat transfer is given by;

Q' = m'(h2 - h1)

Plugging in the relevant values, gives;

Q' = 43.3(33.2 - 23.5)

Q' = 420.01 KJ/min

C) the rate at which water is added to the air in the humidifying section is given by;

m'w = m'( ω3 - ω2)

m'w = 43.3(0.0087 - 0.0053)

m'w = 0.1472 Kg/min

Answer:

Go, but only if the intersection is clear.

Explanation:

Traffic at intersection can be complicated at times. If the green light comes on after a red light, you have the right of way to go, but you should be careful to only go when the intersection is clear to avoid an accident. Once using the road, a good driver should be conscious of the other road users, as accidents might happen from you claiming your-right of-way

Answer:

they could add a play structure, with the stream they can put ducks and fish in it and picnic places

brainliest plz

Explanation:

Answer:

just took the quiz (k12) answer is...

Ask questions to identify a problem, develop a model, and carry out the plan/desgn.

Explanation:

Answer:

Cite two important additional refinements that resulted from the Wave-mechanical

atomic model.

Answer:

Explanation:

Brittle material are materials that don not undergo plastic deformation, they have very low plasticity that is while cracks can form without plastic deformation

The major/ common examples are glass, ceramics, graphite

In other words brittle materials break instead of bending, they have very low energy absorption as they don not undergo plastic deformation

Answer:

Both B and G ( Hexagonal and Tetragonal )

Explanation:

The crystals system listed below has the following relationship for the unit cell edge lengths; a = b ≠ c ( hexagonal and Tetragonal )

hexagonal ; represents  a crystal system  which has three equal axes that have an angle of 60⁰ between them while Tetragonal denotes crystals that have  three axes which have only two of its axes equal in length.

The option B and G that is Hexagonal and the Tetragonal are correct.

These both represent the crystal system that follows the relationships for the units of the cell edge lengths as a = b  not equal to c.

The hexagonal shows the crustal system having equal access of the 60-degree angle in them. While the tetragonal shows the crystal that has three axes having two equal lengths.

Find out more information about the crystal systems.

brainly.com/question/8590454

Explanation:

From the table of conduction shape factor and dimensionless conduction rates for selected systems, for vertical cylinder in a semi-infinite medium

[tex]S=& \frac{2 \pi L}{\ln \left(\frac{4 L}{D}\right)}[/tex]

[tex]S=& \frac{2 \pi L}{\ln \left(\frac{4 L}{D}\right)}[/tex]

[tex]\frac{2 \pi \times 0.1}{\ln \left(\frac{4 \times 0.1}{0.005}\right)}[/tex]

[tex]=0.1433 \mathrm{m}[/tex]

Answer:

External diameter = 158.15 mm mm

Internal diameter = 59.31 mm

Explanation:

We are given;

Diameter ratio; d_i = ⅜d_o

Where d_i is internal diameter and d_o is external diameter

Power;P = 375 KW = 375000 W

Rotational speed;N = 100 rpm

Max torque is 20% greater than mean torque; T_max = 1.2T_avg

Shear stress;τ = 60 N/mm²

Length; L = 4m = 4000 mm

Angle of twist; θ = 2° = 2π/180 radians

Modulus of rigidity;G = 0.85 X 10^(5) N/mm²

Formula for the power transmitted by the shaft is;

P = 2πNT_avg/60

Plugging in the relevant values, we have ;

375000 = 2π × 100T_avg/60

T_avg = (375000 × 60)/(2π × 100) = 35809.862 N.m = 35809862 N.mm

Since T_max = 1.20T_avg

Thus, T_max = 1.20(35809862) = 42971834.4 N.mm

Checking for strength, we'll use;

τ = Tr/J_p

Or since r = d/2

It can be written as;

τ = T(d_o)/2J_p - - - (1)

Where T is T_max

But Polar moment of inertia of hollow shaft is;

J_p = [π(d_o)⁴ - π(d_i)⁴]/32

Now, we are told that d_i = ⅜d_o

Thus;

J_p = [π(d_o)⁴ - π(⅜d_o)⁴]/32

J_p = (π/32) × d_o⁴(1 - 3⁴/8⁴)

J_p = 0.0926 d_o⁴

Plugging this for J_p in eq 1,we have;

τ = T(d_o)/2(0.0926d_o⁴)

Making d_o the subject gives;

d_o³ = T/(2 × 0.0926τ)

Plugging in the relevant values to give;

d_o³ = 42971834.4/(2 × 0.0926 × 60)

d_o³ = 3867155.7235421166

d_o = ∛3867155.7235421166

d_o = 156.96 mm

Thus, d_i = ⅜ × 156.96 = 58.86 mm

Checking for stiffness, we'll use;

T/J_p = Gθ/L

Again T is T_max

Plugging in the relevant values, we have;

42971834.4/0.0926 d_o⁴ = (0.85 × 10^(5) × 2π/180)/4000

464058686.825054/d_o⁴ = 0.7417649321

d_o⁴ = 464058686.825054/0.7417649321

d_o⁴ = 625614216.5028806

d_o = ∜625614216.5028806

d_o = 158.15 mm

d_i = ⅜ × 158.15 = 59.31 mm

So we will pick the highest values.

Thus;

d_o = 158.15 mm

d_i = 59.31 mm

Answer:

D

Explanation:

Confidential data is not supposed to be shared amongst others.

Answer:

D.

Explanation:

Revealing confidential data is illegal first of all. And second business isn't allowed to share info due to the confidentiality law.  All the others aren't unethical, they are just precautions for the safety of other employees.

Answer: total heat dissipated from the array is 0.60 Watt

Explanation:

No. of fins 8

Given that:

Wdth (b) = 3 mm = 0.003 m

thickness (t) = 0.4 mm = 0.0004 m

length (L) = 40 mm

combined convection and radiation heat transfer coefficient to be = 8.0 W/m² K.

Tb = 340 K, Tw = 300 K

First we compute for area of  fins A = 0.003 m × 0.00004 = 1.2 × 10⁻⁶ m²

Perimeter of Fin P = 2( 0.003 m + 0.00004 m ) = 0.0068 = 6.8 × 10⁻³  

for 2024 T6 aluminium alloy K = 151 W/m-k from table

Now

m = √ ( hp/ka) = √[( 8 × 6.8 × 10⁻³  ) / (151 × 1.2 × 10⁻⁶ m²)] = 17.327

Lc = L + t/2 = 40 + 0.4/2 = 40.2 mm = 40.2 × 10⁻³

Now heat transfer from on fin :

Q = √( hpKA) × (Tb-Tw) × Tanh(mLc)

= √( 8×6.8 × 10⁻³×151×1.2 × 10⁻⁶) × (340-300) × tanh (0.6965)

= 3.13963 × 40 × 0.602144

= 0.075620 Watt

So total heat dissipated from array of 8 fins = 8 ×0.075620 = 0.60 Watt

Answer:

Technician A

Explanation:

Technician A is correct. Technician B is incorrect, as the brake booster aids in the drivers ability to depress the brake pedal, but the force applied is the same if the booster was absent.

Answer:

Increases

Explanation:

By inhibiting the motion of dislocations by impurities in a solid solutions, is a strengthening mechanism. In solid solutions it is atomic level strengthening resulting from resistance to dislocation motion. Hence, the strength of the alloys can differ with respect to the precipitate's property. Example, the precipitate is stronger (ability to an obstacle to the dislocation motion) than the matrix and it shows an improvement of strength.

Answer:

Because the shunt winding consist of a large number of turns,

Explanation:

It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due  to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly

Answer:

36V, 100A-hr

Explanation:

Since the batteries are connected in series;

i. the output voltage will be the sum of the individual voltages

ii. the current rating (A-hr) will be the same as their individual current rating (A-hr). And this is because the same current flows through the batteries.

From i,

The output voltage, V, is given by the sum of the voltages of the three batteries;

V = 12V + 12V + 12V

V = 36V

From ii,

The A-hr capacity of the connection is the same as that of the individual batteries;

100 A-hr

Therefore, the output voltage and A-hr capacity of this connection is:

36V, 100A-hr