Answer:
x²+y²+2xy
Step-by-step explanation:
Hope it helps! If it did, please thank, rate and mark brainliest!
Answer:
O x² + 2xy + y². The result of squaring a binomial is the sum of the square of the first term in the binomial, the product of twice the first term and the second term and the square of the second term: (x + y)² = x² + 2xy + y².
what is the surface area
The surface area of the cube of side length 0.125 inches is given as follows:
S = 0.09375 in².
How to obtain the surface area?The surface area for a cube of side length a is given by the equation presented as follows:
S = 6a².
The side length in this problem has the value given as follows:
a = 1/8 = 0.125 in.
Hence the surface area of the cube is calculated as follows:
S = 6(0.125)²
S = 0.09375 in².
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Find the Domain, Range, rel. Max and minimum, end behavior, and thr increasing and decreasing intervals.
EQUATION: f(x)=-x^3+8x^2-15x
Step-by-step explanation:
Domain: The domain of the function is all real numbers.
Range: The range of the function is all real numbers less than or equal to 8. To see this, note that the leading coefficient of the polynomial is negative (-x^3), so the function approaches negative infinity as x approaches positive or negative infinity. The largest y-value the function can attain is 8, which occurs at x = 2.
Relative maxima and minima: To find the relative maxima and minima, we find the critical points of the function, which are the values of x that satisfy f'(x) = 0 or f'(x) does not exist. The first derivative of the function f(x) is given by:
f'(x) = -3x^2 + 16x - 15
Solving f'(x) = 0, we get:
-3x^2 + 16x - 15 = 0
x = 1, 5
We also need to determine the concavity of the function near each critical point to determine whether each is a relative maximum or minimum. To do this, we find the second derivative of the function and evaluate its sign at each critical point. The second derivative of f(x) is given by:
f''(x) = -6x + 16
Since f''(x) is always negative, the function is concave down and therefore has a relative maximum at x = 1 and a relative minimum at x = 5.
End behavior: The leading term of the function is -x^3, which means the function approaches negative infinity as x approaches negative infinity and positive infinity as x approaches positive infinity. The end behavior of the function is therefore negative infinity as x approaches negative infinity and positive infinity as x approaches positive infinity.
Increasing and decreasing intervals: To find the increasing and decreasing intervals of the function, we find the critical points and the sign of f'(x) in the intervals between the critical points.
f'(x) = -3x^2 + 16x - 15
Since f'(x) is negative for x < 1 and positive for x > 1, the function is decreasing for x < 1 and increasing for x > 1. Similarly, since f'(x) is positive for x < 5 and negative for x > 5, the function is increasing for x < 5 and decreasing for x > 5. So, the increasing intervals are (negative infinity, 1) and (1, 5) and the decreasing intervals are (5, positive infinity).
the value of the optimal solution is 28.5. suppose that the right-hand side for constraint 1 is increased from 10 to 11. (a) use the graphical solution procedure to find the new optimal solution. what is the value of the objective function at the optimal solution?
The linear program has an optimal solution of 28.5 at (A, B) = (2, 5) when the right-hand side for constraint 1 is 10. If the right-hand side is increased to 11, the optimal solution remains 28.5 at the same point.
The dual value for constraint 1 stays the same as long as the right-hand side stays within the range 8.4 to 11. The value of the optimal solution will increase by 0.5 for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is within the range 23 to 27.
a) To find the new optimal solution, we need to graph the feasible region and find the new corner points. After the change, the first constraint becomes 1A + 1B ≤ 11. The other two constraints remain the same. The corner points can be found by substituting the bounds of each variable into the constraints and solving for the other variable. The feasible region can then be graphed, and the maximum of the objective function can be found at one of the corner points.
The new corner points are (0,0), (0,9), (6,0), and (2,5). The feasible region can be graphed as a triangle with these corner points. The maximum of the objective function 3A + 2B occurs at the point (2,5), where the value of the objective function is 28.5.
b) The value of the objective function at the optimal solution is 28.5, at (A, B) = (2, 5).
c) The right-hand side range information for constraint 1 tells us that if the right-hand side is increased from 10 to 11, the dual value will remain the same (since the allowable increase is 2.6 and the right-hand side only increases by 1). The range for constraint 1 is 8.4 to 11. As long as the right-hand side stays within this range, the dual value of 2.6 is applicable.
d) The dual value for constraint 2 is 0.5. Using this dual value and the right-hand side range information, we can conclude that the value of the optimal solution will increase by 0.5 for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is within the range 23 to 27.
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Complete question:
Consider the following linear program.
Max 3A + 2B s.t.
1A + 1B ≤ 10
3A + 1B ≤ 27
1A + 2B ≤ 18
A, B ≥ 0
The value of the optimal solution is 28.5. Suppose that the right-hand side for constraint 1 is increased from 10 to 11.
(a) Use the graphical solution procedure to find the new optimal solution.
What is the value of the objective function at the optimal solution?
(blank) at (A, B) =
Use the solution to part (a) to determine the dual value for constraint 1.
(c) The computer solution for the linear program provides the following right-hand side range information
. Constraint RHS Value Allowable Increase Allowable Decrease
1 10.00000 2.60000 1.00000
2 27.00000 3.00000 13.00000
3 18.00000 Infinite 6.50000
What does the right-hand side range information for constraint 1 tell you about the dual value for constraint 1?
The range for constraint 1 is (blank) to (blank) . As long as the right-hand side stays (within/outside) this range, the dual value of (blank) is applicable.
(d) The dual value for constraint 2 is 0.5. Using this dual value and the right-hand side range information in part (c), what conclusion can be drawn about the effect of changes to the right-hand side of constraint 2?
The value of the optimal solution will increase by (blank) for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is (within/outside) the range (blank) to (blank).
GUYS HELP ME WITH THESE PLEASE (emergency)
Answer:LxW
Step-by-step explanation:
Length x width
Nicole was looking for a job for winter break. In winter she charges $10 per hour.
1) Write an equation for babysitting. Y=10x
2) What is the slope
3) What is the y-intercept?
, what does the slope represent?
what does the y-intercept represent?
A rectangular garden has a walkway around it. The area of the garden is 4(6.5x+2.5). The combined area of the garden and the walkway is 4.5(8x+4). Find the area of the walkway around the garden as the sum of two terms.
Answer:
see below
Step-by-step explanation:
area of the garden is 4(6.5x+2.5).
combined area of the garden and the walkway is 4.5(8x+4).
so area of the walkway = 4.5(8x+4) -4(6.5x+2.5)
=36x+18 -26x-10
=10x+8
The question is asking what the fraction would be, I find it difficult to figure the answer out. I added some pictures, there are actually 6 stages but I can only add 5 attachments.
The fraction of the area of the triangle that would be shaded in stage 7 is equal to 2,187/16,384.
No, there isn't a stage when the fraction of area shaded would be equal to 0.
What is a fraction?In Mathematics, a fraction simply refers to a numerical quantity which is not expressed as a whole number. This ultimately implies that, a fraction is simply a part of a whole number.
Next, we would determine the area of the triangle that would be shaded in stage 2 is as follows;
Fraction of the area = 3/4 × 3/4 = 9/16.
The area of the triangle that would be shaded in stage 3 is as follows;
Fraction of the area = 3/4 × 3/4 × 3/4 = 27/64.
The area of the triangle that would be shaded in stage 4 is as follows;
Fraction of the area = 3/4 × 3/4 × 3/4 × 3/4 = 81/256.
Therefore, the area of the triangle that would be shaded in stage 7 is as follows;
Fraction of the area = 3/4 × 3/4 × 3/4 × 3/4 × 3/4 × 3/4 × 3/4 = 2,187/16,384.
In this context, we can reasonably infer and logically deduce that there isn't a stage when the fraction of area shaded in this triangle would be equal to zero (0) because there is a linear relationship between the shaded and unshaded area.
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PLEASE HELP LOOK AT THE PICTURE ATTACHED
Answer:
600
Step-by-step explanation:
She had -350 then ended with 250
First you get -350 to 0... that's by adding 350.
Then getting from 0 to 250, you add 250
Now we add 350 and 250 to get a total of 600
In a sale, a clothes shop reduces its prices by 15%. A shirt usually costs $37. How much is it in the sale? How do I work this out?
Answer:
$ 31.45
Step-by-step explanation:
15% = 0.15 x 37 = 5.55$ off the original price so 31.45$ is the final price for the tee shirt. Give brainlist please
Sale price for the given shirt will be $32.
According to question given are-
Percentage of the reduction rate of the shirt is = 15%
Reduction Percentage refers to the percentage rate at which the Initial Per Certificate Entitlement will diminish daily, assuming that the daily rate will be calculated as the annual rate given in the Final Terms divided by 365 and applied as necessary.
Actual cost of the shirt is = $37.
decreased rate "Reduced rate" refers to a contribution rate that is lower than the standard rate required by State law, while "standard rate" refers to the rate used to compute variances from that rate.
So, accordingly Reduction rate = (Actual rate X Reduction Percentage)/100
Reduction = (37×15)/100 = Rs 5.55$ ≅ 5$
So the sale price = 37−5 = 32$
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Is 6xy2 is the greatest common factor of 12xy2, 36x2y2, and 42xy4
Yes, 6xy² is the greatest common factor of 12xy², 36x²y², and 42 xy⁴. The Greatest common factor is the highest common factor of all the given numbers.
We can find the greatest common factor by applying the prime factorization method. There are two steps involved to find the highest common factor.
Find the factors 12, 36, and 42.Find the common factor for the variables i.e. xy², x²y², and xy⁴Step 1
The factors of the numbers are
Factors of 12 are 1,2,3,4,6,12
Factors of 36 are 1,2,3,4,6,9,12,18,36
Factors of 42 are 1,2,3,6,7,14,21,42
The common factor for 12,36,42 are 1,2,3,6
Therefore, the greatest common factor for 12,36,42 is 6.
Step 2
We have to find the common factors for the variable parts x¹,y²,x²,y²,x¹,y⁴
The factor for x¹ is x itself.
The factors for y² is y⋅y
The factors for x² are x⋅x
The factors for y² are y⋅y
The factor for x¹ is x itself.
The factors for y⁴ are y⋅y⋅y⋅y
Hence, the common factors for the variables
x¹,y²,x²,y²,x¹,y⁴ are x⋅y⋅y
The GCF for the variable part is xy².
Now, multiply the GCF of the numerical part i.e.6 and the GCF of the variable part i.e. xy².
Therefore, it comes out to be 6xy².
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a decimal number lies between 0.7 and 0.8 . it has three digits to the right of the decimal point. thus, it is of the following format: it is the largest number between 0.7 and 0.8 .the sum of the digits of this decimal number is 24 . find the decimal number.
The decimal number that lies between 0.7 and 0.8, has three digits to the right of the decimal point, and whose sum of the digits is 24 is 7.98.
A decimal number is a number that has a fractional part represented by a decimal point. The digits to the right of the decimal point represent values that are smaller than 1.
In this problem, we are given that the decimal number has three digits to the right of the decimal point and that its sum of the digits is 24. Let's call the decimal number x. We can write an equation to represent the sum of the digits:
x = a + b/10 + c/100
Where a, b, and c are the digits of x.
We know that 0.7 < x < 0.8 and that the sum of the digits of x is 24, so we can write two more equations:
0.7 < a + b/10 + c/100 < 0.8
a + b + c = 24
By solving these three equations, we can find the decimal number x.
We know that a must be 7 because 0.7 < x < 0.8, so a = 7. We also know that b + c = 24 - 7 = 17. Now we need to find two digits b and c such that b + c = 17 and b/10 + c/100 is between 0 and 0.1.
The largest value of b that still satisfies this condition is 9. This means that
=> c = 17 - 9 = 8.
Therefore, the decimal number
=> x = 7 + 9/10 + 8/100 = 7.98.
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Alan is 77 inches tall. He casts a shadow 14 feet long. His dad casts a 12-foot shadow at the
same time. How much shorter is Alan's dad than Alan? Draw a picture before you begin!
Answer:
66 inches
Step-by-step explanation:
77→ 14
X→12
In the proportion
a/b=c/d
the product of the means equals the product of the extremes. That is,
ad=bc.
So,
77 * 12 = X * 14
x = (77 X 12) / 14 = 66
2. Explain how to find the surface area of any prism.
THIS IS TIMED!
A rectangle has vertices at (Negative1, 6), (Negative1, Negative2), (3, 6), and (3, Negative 2). Sara says the area of the rectangle is 16 square units and her work is shown below.
Steps
Sara’s Work
Step 1
Base: StartAbsoluteValue negative 1 EndAbsoluteValue + StartAbsoluteValue 3 EndAbsoluteValue = 4
Step 2
Height: StartAbsoluteValue 6 EndAbsoluteValue + StartAbsoluteValue negative 2 EndAbsoluteValue = 4
Step 3
Area: 4 times 4 = 16 square units
Where, if at all, did Sara first make a mistake in finding the area of the rectangle?
Step 1
Step 2
Step 3
no mistake
Answer:
Step 2
Step-by-step explanation:
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/\ Explantion hope it help...
- The weight of an object having mass 5kg is 450 N weight of another object having mass 50kg is 147N. Check weather the mass and we weight are proportional What is the constant of proportionality
Answer:
see below
Step-by-step explanation:
We are here given that weight of an object having mass of 5kg is 450N .
As we know that,
Weight = mass * acceleration due to gravity (g)
So that ,
450N = g * 5kg
g = 450/5 m/s²
g = 90m/s²
Again in second case,
147N = g' * 50kg
g' = 147/50 m/s²
g' = 29.4 m/s²
since here g ≠ g'
Therefore,
mass and weight are not promotional in this case. This may be due to the fact that the acceleration due to gravitational force of each celestial object is different and weights may have been measured on different planets.
And the constant of proportionality is g ( acceleration due to the gravitational force) .
And we are done!
I need help with this. A is wrong
Answer:
I think BC
Step-by-step explanation:
Chef Ramsy used 1/4 of a bag of flour to make some muffins and twice as many cupcakes.The amount of flour he used for each muffins was 3 times as much as each cupcake.Chef Ramsy used 5/6 of the remaining bag of flour on a cake.He used 256.5g more flour on the cake than the muffins.
What friction of the bag of flour was used on the muffins?
How much flour was there in the bag at first?
1/4 of the flour was used for the muffins and 5/6 of the remaining flour was used for the cake.
How did we get the values?Let's call the total amount of flour in the bag "x".
The amount used for the muffins is 1/4 of the total bag, or x/4.
The amount used for the cupcakes is twice as much as for the muffins, or 2 * x/4 = x/2.
The amount used for the muffins was 3 times as much as for the cupcakes, so 3 * x/2 = 3x/2 grams of flour were used for muffins.
The amount used for the cake was 256.5 grams more than the muffins, so x/4 + 256.5 = 3x/2.
Solving for x, we find that x = 2048 grams.
So, 1/4 of the flour was used for the muffins, or 2048 * 1/4 = 512 grams.
And 5/6 of the remaining flour was used for the cake, or (2048 - 512) * 5/6 = 1024 grams.
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Name the place value to the immediate right of the ones place.
A) tens
B) hundredths
decimal point
D) tenths
In the diagram, AC is a diameter of circle O. If the slope of Bis-
B
1
what is the slope of AB?
A. 1/2
B. -1/-4
C. 2
D. -2
E. -4
In the diagram, AC is a diameter of circle O. If the slope of BC is -1/2, then the slope of AB is 2.
What is the diameter of the circle?
The diameter of a circle is the length of the line starting from one point on a circle to another point and passing through the center of the circle. It is equal to twice the radius of the circle.
We have that,
ABC is a right triangle
so,
AB is perpendicular to BC
we know that
If two lines are perpendicular, then the product of their slopes is equal to -1.
so,
m1 * m2 = -1
in this problem
mAB * mBC =-1
solve for mAB
mAB = -1 / mBC
mAB = -1 / -1/2
mAB = 2
therefore, In the diagram, AC is a diameter of circle O. If the slope of BC is -1/2, then the slope of AB is 2.
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Complete Question:
In the diagram, AC is the diameter of circle O. If the slope of BC is -1/2, what is the slope of AB?
Convert 9.335 • 10^5 to standard form.
Answer:
933500
Step-by-step explanation:
You move the decimal over 5 spaces to the right
how do you break apart the factor 42 using place values
The number can be broken apart from the factor 42 using the place value as 40 + 2 here 4 is in the tens place and 4 is in the one's place.
What is the number?A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
It is given that:
The number is 42.
As we know,
The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
So, We get;
⇒ 42 = 40 + 2
⇒ 42 = 4 × 10 + 2 × 1
Thus, The number can be broken apart from the factor 42 using the place value as 40 + 2 here 4 is in the tens place and 4 is in the one's place.
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Jim has the following grades: homework average is 88%, quiz average is 76%, Exam One grade was 64%, Exam Two grade was 85%, Exam Three grade was 92% and Exam Four grade was 94%. (6 pts) a) Find Jim's exam average for his four exams. b) Find Jim's weighted average if homework counts as 15% of his grade, quiz average counts as 10% of his grade, and the exam average is 75% of the grade. Show all your work.
Answer:
a) 83.75% or 84% rounded to the nearest percent.
b) 84%
Step-by-step explanation:
[tex]\frac{64+85+92+94}{4}[/tex] = 83.75 changed to a percent and rounded to the nearest percent would be 84%
.15(.88) + .10(.76) + .75(.84) = .838 changed to a percent and rounded to the nearest percent would be 84%
Please help me solve
The area of rectangle from the given vertices is 90 squared units
What is the area of the rectangleThe area of a rectangle is the product of its length and width. If a rectangle has length "l" and width "w", its area can be calculated as:
A = l * w
where A is the area and l and w are the length and width of the rectangle, respectively.
The area of a rectangle can be calculated as the product of its length and width. Given the vertices, the length of the rectangle is 14 - 4 = 10 units, and its width is 2 - (-7) = 9 units. Hence, the area of the rectangle is 10 * 9 = 90 square units.
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A sandwich store charges $20 to have 3 subs delivered and $26 to have 4 subs delivered. If the total charge is $56, how many subs are in the order?
The number of subs in the order is 8 or 9
how many subs are in the order?Let's call the number of subs in the order "x".
Since the cost of 3 subs is $20, the cost per sub is $20 / 3 = $6.67.
And since the cost of 4 subs is $26, the cost per sub is $26 / 4 = $6.50.
So the cost per sub is between $6.50 and $6.67.
If the total cost is $56, then the cost per sub must be $56 / x.
So:
x = 56/6.5 or x = 56/6.67
Evalutate
x = 8.6 or x = 8.4
Approximate
x = 9 or 8
Hence, the subs is 8 to 9
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You may have polarized sunglasses that eliminate glare by polarizing the light. When light is polarized, all of the waves are traveling in parallel planes. Suppose vertically polarized light with intensity strikes a polarized filter with its axis at an angle. Of with the vertical. The intensity of the transmitted light and are related by the equation write as a function
The intensity of the transmitted light, [tex]I_{t}[/tex], is equal to half of the original intensity, [tex]I_{0}[/tex].
Given θ = 45° and cosθ = [tex]\sqrt\frac{I_{t} }{I_{0} }[/tex]
When polarized light with intensity [tex]I_{0}[/tex] strikes a polarized filter with its axis at an angle θ with the vertical, the intensity of the transmitted light, [tex]I_{t}[/tex], depends on the angle θ and the original intensity [tex]I_{0}[/tex]. The relationship between [tex]I_{t}[/tex] and [tex]I_{0}[/tex] is described by the equation cosθ = [tex]\sqrt\frac{I_{t} }{I_{0} }[/tex].
If θ = 45°, then the equation θ can be simplified to cos 45° =[tex]\sqrt\frac{I_{t} }{I_{0} }[/tex].
The cosine of 45° is equal to [tex]\frac{1}{\sqrt{2} }[/tex], so we have:
[tex]\frac{1}{\sqrt{2} }=\sqrt\frac{I_{t} }{I_{0} }[/tex]
On Squaring both sides, we have:
[tex]\frac{1}{{2} }=\frac{I_{t} }{I_{0} }[/tex]
Multiplying both sides by [tex]I_{0}[/tex], we have:
[tex]I_{t}=\frac{I_{0} }{2}[/tex]
Therefore, if θ = 45°, the intensity of the transmitted light, [tex]I_{t}[/tex], is equal to half of the original intensity, [tex]I_{0}[/tex].
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Write an expression for the volume of a rectangular prism with length 7. 5 ft, width w ft, and height 4. 2 ft. Enter the smaller number first
An expression for the volume of a rectangular prism with length 7.5 ft, width w ft, and height 4.2 ft is 31.5w ft³.
Therefore the answer is 31.5 ft³.
The volume of a rectangular prism can be found by multiplying its length, width, and height. So, for a rectangular prism with length 7.5 ft, width w ft, and height 4.2 ft, the volume can be expressed as:
V = 7.5 * w * 4.2
V = 31.5 w ft³
So, the expression for the volume of this rectangular prism is 7.5 * w * 4.2, that is 31.5 w cubic feet.
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Solve for x.
A) x = 4tan56°
B) x = 4sin34°
C) x = 4tan34°
D) x = 4sin56°
E) x = 4cos34°
The correct Option for this question is option C i.e. x= 4tan34°. The other options which are given in the question are incorrect.
The Right angled triangle along with the base angle of 34°. The base is equal to 4.
θ= 34°
To find the value of x which is equal to the perpendicular of the right-angled triangle
According to the trigonometric ratio
tanθ = Perpendicular ÷ base
According to the above formula
tan 34 = x ÷ 4
Now, we have to multiply each side by 4.
x= 4× tan34° which means x= 4tan34°
tan 34° = 0.6745
x= 4× 0.6745
X=2.70
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Solve the polynomial (preferably with the X or Box method) g^2+9g+18=0
Answer:
To solve the polynomial (g^2 + 9g + 18 = 0) using the X or Box method, you need to factor the polynomial into two binomials. To do this, you need to find two numbers that multiply to 18 and add up to 9. The two numbers are 6 and 3, so the polynomial can be factored as:
g^2 + 9g + 18 = (g + 6)(g + 3) = 0
To find the solutions, you set each factor equal to 0 and solve for g:
g + 6 = 0, so g = -6
g + 3 = 0, so g = -3
The solutions to the polynomial are g = -6 and g = -3.
Step-by-step explanation:
find a geometric mean between 16 and 36
Answer:
5.196103885259%
Step-by-step explanation:
Negative values detected. All input values threated as percentages (e.g. an input of 0.1 is threated as 0.1%, -10 is threated as -10%).
Justin has two craft sticks that are 14 inches long and 11 inches long. Which ratio compares the length of the shorter stick to the length of the longer stick?
Answer: To find the ratio of the length of the shorter stick to the length of the longer stick, we need to divide the length of the shorter stick by the length of the longer stick:
11 inches ÷ 14 inches = 11/14
So, the ratio of the length of the shorter stick to the length of the longer stick is 11/14.
Step-by-step explanation: