PLEASE HELP WILL MARK BRAINLIST AND GIVE 20 POINTS

Answer:

[tex]\text{Perimeter: }48\:\mathrm{m},\\\text{Area: }84\:\mathrm{m^2}[/tex]

Step-by-step explanation:

The area of a triangle with side lengths [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] is given by:

[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex], where [tex]s=\frac{a+b+c}{2}[/tex]

Substituting [tex]a=21, b=17, c=10[/tex], we have:

[tex]A=\sqrt{24(24-21)(24-17)(24-10)},\\A=\sqrt{24(3)(7)(14)},\\A=\sqrt{7,084},\\A=\boxed{84\:\mathrm{m^2}}[/tex]

The perimeter of a polygon is given by the sum of its sides. Since the triangle has sides 10, 17, and 21, its perimeter is [tex]10+17+21=\boxed{48\:\mathrm{m}}[/tex].

Answer:

-14 x²

Step-by-step explanation:

10 x² - 24 x² = -14 x²

The answer is 14

if you multiply both P(x) and Q(x), the third part becomes 14x², so the coefficient of x² becomes 14.

Answered by GAUTHMATH

9514 1404 393

Answer:

  2/7

Step-by-step explanation:

Any unit fraction with a denominator between 3 and 4 will be between 1/3 and 1/4. For example, ...

  1/3.5 = 2/7 . . . . is between 1/3 and 1/4

__

You can also go at this considering decimal equivalents.

  1/4 = 0.25

  1/3 = 0.333... (repeating)

So, decimal numbers like 0.26, 0.295, 0.3330 are all values that are between 1/4 and 1/3.

Answer:

Probability of defective televisions : Now, If two televisions are randomly​ selected, then the probability that both televisions work. Hence, the probability that both televisions work is 0.5289 . Hence, the probability at least one of the two televisions does not​ work is 0.4711.

Answer:

Step-by-step explanation:

Since EF = 20 and E is at 4

F is at:

Answer:

The probability is 1/2500. (1/50)*(1/50)

Step-by-step explanation:

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Answer:

4th option

Step-by-step explanation:

tanZ = [tex]\frac{opposite}{adjacent }[/tex] = [tex]\frac{XY}{ZY}[/tex]

Answer:

D. 12/18 = 16/24

Step-by-step explanation:

The method we must go about to solve this is finding the constant. For A, we can solve it by doing 10 divided by 8 (which is 1.25) and then 40 divided by 1.25 to see if it is 36. Alternatively, we can do 10 divided by 8 and then 40 divided by 36 to see if the constant is the same. It's up to you!

My answers:

A. No (constant varies)

B. No (constant varies)

C. No (constant varies)

D. Yes! Constant is 0.75

How to solve for D:

12/16 = 0.75

18/0.75 = 24       OR          18/24 = 0.75

I hope this helps! Please don't hesitate to reach out with more questions!

Hello!

10/40 = 8/36 ?

10 × 36 = 40 × 8

360 = 40 × 8

360 ≠ 320 => 10/40 ≠ 8/36

8/18 = 6/16 ?

8 × 16 = 18 × 6

128 = 18 × 6

128 ≠ 108 => 8/18 ≠ 6/16

9/15 = 44/50 ?

9 × 50 = 15 × 44

450 = 15 × 44

450 ≠ 660 => 9/15 ≠ 44/50

12/18 = 16/24 ?

12 × 24 = 18 × 16

288 = 18 × 16

288 = 288 => 12/18 = 16/24

Good luck! :)

Answer:

10

Step-by-step explanation:

5C2 =5!

       2! (3)!

=1 x 2 x 3 x 4 x 5

(1 x 2) (1 x 2 x 3)

=4 x 5

   2

=20

  2

5C2 = 10

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

Answer:

x= -3

Step-by-step explanation:

(2x/3)-2=-4

Add 2 to both sides

2x/3=-2

multiply both sides by 3

2x=-6

divide both sides by 2

x= -3

Answer:

x = -3

Step-by-step explanation:

2x/3 - 2 = -4

Add 2 to both sides.

2x/3 = -2

Multiply both sides by 3/2.

x = -2 * 3/2

x = -3

Answer:

66

Step-by-step explanation:

Add both of the angles given together

43 + 23

Given:

Net income = $19,090

Assets at the beginning of the year = $209,000.

Assets at the end of the year total = $264,000.

To find:

The return on assets.

Solution:

Formula used:

[tex]\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}[/tex]

Using the above formula, we get

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{236500}[/tex]

[tex]\text{Return of assets}\approx 0.0807[/tex]

The percentage form of 0.0807 is 8.07%.

Therefore, the return on assets is 8.07%.

Answer:

A

Step-by-step explanation:

since it's negative so it will get smaller

Answer:

Hence the answers are,

a) Probability that in the past 12 months the car had more than one problem = P(X > 1) is 0.2716.

b) The Probability that in the past 12 months the car had almost two problems = P( X < 2) is 0.9160.

c) The Probability that in the past 12 months the car had zero problems = P(X= 0 ) is 0.3606.

Step-by-step explanation:

Let's take X to be the number of problems per car.

By considering the given statement, X follows a Poisson Distribution with Mean (X) = 1.02.

The Poisson probability formula is :

e Pr( X = k) = e- k! k= 0,1,2...

a)

The Probability that in the past 12 months the car had more than one problem = P(X > 1)

[tex]P(X > 1) =1- P(X < 1) \\\\=1- (P(X = 0) + P(X = 1)-1.021.02 e + 1.021.02 =1-6 0!\\= 1-0.3606 + 0.3678\\= 1-0.7284\\= 0.2716[/tex]

b)

The Probability that in the past 12 months the car had almost two problems = PX < 2)

[tex]Pr(X < 2) = Pr(X = i) = Pr(X = 0) + Pr(X = 1) + Pr(X = 2)\\-1.021.020 -1.021.02 -1.021.02 e e + e + 0! 1! 2!\\= 0.3606 + 0.3678 + 0.1876\\= 0.9160[/tex]

c)

The Probability that in the past 12 months the car had zero problems = P(X= 0 )

[tex]- 1.021.02 e 0!\\= 0.3606[/tex]

Answer:

The width is 10 feet.

Step-by-step explanation:

We know that the area of a rectangle is given by the formula:

[tex]\displaystyle A=L\cdot W[/tex]

Where L is the length and W is the width.

We are given that the length of the rectangle is three times the width. In other words:

[tex]L=3W[/tex]

The total area is 300 square feet. And we want to determine the width of the rectangle.

So, substitute 300 for A and 3W for L:

[tex](300)=(3W)\cdot W[/tex]

Multiply:

[tex]300=3W^2[/tex]

Divide both sides by three:

[tex]W^2=100[/tex]

And take the principal square root of both sides. So:

[tex]W=10[/tex]

Thus, the width of the rectangle is 10 feet.

Answer:

[tex]8 \ feet[/tex]

Step-by-step explanation:

In this situation, one is given the following information. A ladder is leaning against a wall and has a measure of (17) feet. The bottom of the ladder is (15) feet away from the wall. One can infer that the wall forms a right angle with the ground. Thus, the triangle formed between the ground, ladder, and wall is a right triangle. Therefore, one can use the Pythagorean theorem. The Pythagorean theorem states the following,

[tex]a^2+b^2=c^2[/tex]

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle. The parameter (c) represents the hypotenuse or the side opposite the right angle. In this case, the legs are the ground and wall, and the hypotenuse is the ladder. Substitute this into the formula a solve for the height of the wall.

[tex]a^2+b^2=c^2[/tex]

Substitute,

[tex](ground)^2+(wall)^2=(ladder)^2\\\\(15)^2+(wall)^2=(17)^2\\[/tex]

Simplify,

[tex](15)^2+(wall)^2=(17)^2\\\\225+(wall)^2=289[/tex]

Inverse operations,

[tex]225+(wall)^2=289\\\\(wall)^2=64\\\\wall=8[/tex]

9514 1404 393

Answer:

  x = 30°

Step-by-step explanation:

The lines will be parallel if and only if the sum of the marked angles is 180°:

  4x +2x = 180°

  6x = 180° . . . . . collect terms

  x = 30° . . . . . . . divide by 6

Answer:

The length is of 59 cm.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle with width w and length l is given by:

[tex]P = 2(w + l)[/tex]

Width of 49 centimeters and a perimeter of 216 centimeters:

This means that [tex]w = 49, P = 216[/tex]

The length is cm.

We have to solve the equation for l. So

[tex]P = 2(w + l)[/tex]

[tex]216 = 2(49 + l)[/tex]

[tex]216 = 98 + 2l[/tex]

[tex]2l = 118[/tex]

[tex]l = \frac{118}{2}[/tex]

[tex]l = 59[/tex]

The length is of 59 cm.

Answer:

Step-by-step explanation:

a.) it's just mean, variance

so here it's just 12,6.25

b.) For the x bar thing just divide the variance by the number of people (mean stay the same)

the variance is then (2.5²/34)= .1838

which makes it (12,.1838)

c.) here we don't use x bar (and so it's normal (12,2.5²))

p(11.6) = (11.6-12)/(2.5)= -.16 = .4364

p(12.4)= (12.4-12)/2.5 = .16= .5636

.5636-.4364= .1272

d.) here we use x bar because it's asking for an average so it's normal (12, .1838)

same deal

p(11.6)=(11.6-12)/√.1838= -.93295= .1762

p(12.4)= (12.4-12)/√.1838= .93295= .8238

.8238-.1762= .6476

d.) no because they're probably IID

f.) It's average so here we use x bar

q1 is just the 25th percentile

the 25th percentile is -.6745

-.6745=(x-12)/(√.1838)= 11.711

q3 is the 75th percentile

.6745=(x-12)/√.1838

x=12.289

The interquartile range is just the difference between the two

12.289-11.711= .5784

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that [tex]p = \frac{231}{361} = 0.6399[/tex]

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095[/tex]

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

[tex]E = -31*0.4095 + 21*0.5905 = -0.29[/tex]

The expected value of the proposition is of -0.29.

Answer:

Step-by-step explanation:

I'm sure he was making a joke at the expense of people who rely on mathematics rather than common sense. It is funny, but then Twain was a remarkably funny author..

The problem is that the comparison is apt using some sort of proportion, but it is absurd to think that the land holding the river would also shrink a proportional amount.  

The river reached a minimum (presumably) in 1875 by cutting out all the loops that were there in 1700. The Mississippi was then a straight line from it's beginning to its delta on the gulf of Mexico. It could not get any shorter. Still, Twain managed to get laughs with his whimsical humor.

Thanks for posting. This made my evening.

Answer:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Step-by-step explanation:

Given

[tex]\triangle ABD \cong \triangle CBD[/tex]

Required

The congruent segments by CPCTC

From the question, we have:

[tex]\angle ADB \cong \angle CDB[/tex] --- given

[tex]\angle DBA \cong \angle DBC[/tex] --- given

Both triangles share a common side (length BD);

So, we have:

[tex]BD = BD[/tex]

Hence, the congruent segments are:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Answer:

c) tan

Step-by-step explanation:

tan = Opposite side / close side

When close side = v         and     Opposite side = 2,8m

Answer:

38.74%

Step-by-step explanation:

Given the data:

21 21 22 22 23 23 23 24 24 24 24 24 25 25 25 26 26 27 27

We obtain the beginner running population and standard deviation

Population mean, μ = Σx/n = 456/19 = 24

Standard deviation, σ = 1.747 (using calculator)

Friend's Runtime, x = 23.5 minutes

Obtaining the friend's Zscore :

Z = (x - μ) / σ

Z = (23.5 - 24) / 1.747

Z = - 0.286

Obtaining the Pvalue :

Using a standard normal distribution table :

P(Z < - 0.286) = 0.38744

Hence. Percentage of population that has lesser time :

0.38744 * 100% = 38.74%