Please help Find the missing area.

Answer:

4/9

Step-by-step explanation:

Answer:

4/9 and 4/7

Step-by-step explanation:

Answer:

Letter c is correct

Step-by-step explanation:

I solved each problem and Cleos was right

Answer:

40%

Step-by-step explanation:

In month of April, the percent of raining will be 40 %.

Given that, In the month of April, it rains 2 days for every 3 days that it does not rain.

It means that in 5 days, 2 days raining and 3 days  does not raining.

Number of days raining in 5 days = 2 days

Percent of raining is, [tex]=\frac{2}{5}*100 =40[/tex]

Hence, In month of April, the percent of raining will be 40 %.

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Step-by-step explanation:

not wrong that is super right

Answer:

2x + 8.7 = 64.9

Step-by-step explanation:

Answer:

13.25

Step-by-step explanation:

Answer:

2.39%

Step-by-step explanation:

Maxwell bought $15,000 worth of 52-week T-bills for $14,650

Therefore the rate of return on investment can be calculated as follows

= 15,000-14,650/14,650× 100

= 350/14,650 × 100

= 0.02389 × 100

= 2.39%

Hence the rate of return on this investment is 2.39%

Answer:

285, 7392, 15708, are divisible by 3 but not by 9

Step-by-step explanation:

it's because of we add the sun of the digits, 285, 7392, 15708, they are divisible by 3. actually, except for 629, all of them are divisible by 3, but 5490 and 43695 are both divisible by 3 and 9

Answer:

Step-by-step explanation:

Put these numbers into their prime factors.

18: 2 * 3 * 3

27: 3 * 3 * 3

12: 2 * 2 * 3

The LCM must have

two 2s

Three 3s

That's it

2*2 * 3 * 3 * 3

LCM = 108

648 might be a multiple of the three, but it's not the smallest one.

108 = 27 * 4

108 = 18 * 6

108 = 12 * 9

Answer: 10:1

Step-by-step explanation:

I don’t know. I took my math exam and got the wrong answer, this is the correct one. i hope i helped someone :)

2/3 : 1/15 as a unit rate is  [tex]10:1[/tex] .

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate.

According to the question

[tex]\frac{2}{3} : \frac{1}{15}[/tex] as a unit rate

As, unit rate is having denominator = 1

So,

[tex]\frac{2}{3} : \frac{1}{15}[/tex]

= [tex]\frac{2}{1} : \frac{1}{5}[/tex]

= [tex]10:1[/tex]

Hence,  2/3 : 1/15 as a unit rate is  [tex]10:1[/tex] .

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Answer:

-0.60

why? because the percentages match.

Answer:

7/10

Step-by-step explanation:

solve 5 divide by 7 =0.714

solve 7 divided by 8 = 0.875

11 divided by 15 = 0.73333

7 divided by 10= .70

Answer:

16.00

Step-by-step explanation:

19.99 - 25% + 6% = 15.89 =16.00

Answer:

Step-by-step explanation:

b

Answer:

12

Step-by-step explanation:

AB + BC = AC

(2x - 8) + (x + 17) = 39

3x + 9 = 39

x = 10

AB = 2(10) - 8 = 12

Answer:

64.00 was incressed

Step-by-step explanation:

Answer:

about 51-52 percent should be the answer

Step-by-step explanation:

please mark brainlyiest

sorry if this isn't right

Answer:

8.3, 7, 6.4 which is $21.07

Step-by-step explanation:

Answer:

8.333333333333 but round it to 8.3

Step-by-step explanation:

all u have to do it divide 25 and 3 and get 8.3333333 so then u round it to 8.3

Answer:

were is the line graphed?

Step-by-step explanation:

But I will help?

Answer:

I can't see the line but if you start at a point where the line crosses over an intersecting corner and find the next nearest corner where it intersects the slope will be however many up(or down - if its down its negative) you have to go/ how many sideways you have to go

ex:

so in example A the slope would be 2/1 which simplifies to 2 and in example B the slope would be -3/2

Answer:

f(g(2))=7

Step-by-step explanation:

The Composite Function

Given f(x) and g(x) as real functions, the composite function [tex](f\circ g)(x)[/tex] is defined as:

[tex](f\circ g)(x)=f(g(x))[/tex]

It can be found by substituting g into f.

The given functions are:

[tex]f(x)=4x+3[/tex]

[tex]g(x)=x^2-3[/tex]

It's required to find f( g( 2 ) )

Find g(2):

[tex]g(2)=2^2-3[/tex]

Operating:

[tex]g(2)=4-3 =1[/tex]

g(2)=1

Now find f(1):

[tex]f(1)=4(1)+3[/tex]

[tex]f(1)=4+3 =7[/tex]

Thus:

f( g( 2 ) )=7

Answer:

B and C

Step-by-step explanation:

60-25= 35

So you have to pick the numbers between 30 and 35, but not 30 I believe.

The numbers greater than 30 and less than the difference between 60 and 26 were 32 & 34.

Step-by-step explanation:

Given:

Numbers : 30, 32, 34,36,38

To find:

The numbers greater than 30 and less than the difference between 60 and 25.

Solution:

30<N<(60-25)

30<N<35

Where:

N = Number greater than 30 and less than 45

30<30<35 ( not valid, 30 is equal to 30)

30<32<35 ( valid)

30<34<35 ( valid)

30<36<35 ( not valid, 36 is greater than 35)

30<38<35 (not valid,38 is greater than 35)

The numbers greater than 30 and less than the difference between 60 and 26 were 32 & 34.

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Answer:

Constant rate of change. The rate of change is the same on the entire graph.

Step-by-step explanation:

Answer:

List all of the solutions.

50 k m =

9 m i n u t e s =

14 k m =

Step-by-step explanation:

Answer:

y = -4x + 50

Step-by-step explanation:

To write the function we'll use y = mx + b, where y is the distance the boat is away from shore, m is how many km/minute the boat moves at, x is how many minutes it's been, and b is how many km away from shore the boat was at the start. We already know the value of b is 50, so we can put that into the equation:

y = mx + 50

To find how many km the boat moves per minute, let's use the given amount of minutes and km (9, 14) and put them into the equation:

14 = m(9) + 50

Now let's solve for m:

14 = 9m + 50

Subtract 50 from both sides to isolate the 9m:

14 - 50 = 9m + 50 - 50

- 36 = 9m

divide both sides by 9 to isolate the m:

-36/9 = 9m/9

-4 = m

The boat moves at -4 km/minute, which is the same thing as saying that  after 1 minute passes, the boat gets 4km closer to the shore. Now we can input this value into the equation and we have our answer:

y = -4x + 50

Answer: 3s-139

Step-by-step explanation: (2s+5 - 3s)+4(s-6^2)

Collect like terms and evaluate

(-s+5) +4 (s-36)

Rewrite and remove the parentheses

-S+5 +4s -144

Collect like terms and calculate and you get

3s-149

playing with blocks??

Answer:

25 days

Step-by-step explanation:

Assuming that the farmer waits for n days to get get the maximum profit.

Given that the total number of cows the farmer has, = 100

Currect weight of one cow = 125 kg.

Weight gain rate for one cow = 3 kg/day

So, weight gained by one cow in n days = 3n kg

Therefore, the weight of one cow after n days [tex]= 125 + 3n \;\;kg \cdots(i)[/tex]

Cost for keeping one cow = $5/day.

Cost for keeping one cow for n days = $ 5n

So, Cost for keeping 100 cows for n days [tex]= \$ 5n \times 100 =\$500n \cdots(ii)[/tex]

Current market price = 25 pesos / kg = 125 cents / kg [ as 1 peso = 5 cents]

The falling rate of market price = 1 cent /day.

Fall in price in n days [tex]= 1\times n = n[/tex] cents.

So, market price after n days [tex]= 125-n cent/kg\cdots(iii)[/tex]

By using equations (i) and (iii),

The selling price of one cow after n days [tex]= (125+3n) \times (125-n)[/tex] cents.

So, the selling price of 100 cows after n days [tex]= (125+3n) \times (125-n)\times 100[/tex] cents.

As 1 $ = 100 cents. so

The selling price of 100 cows after n days [tex]=\$ 5(125+3n) (125-n)\cdots(iv)[/tex].

Now, from equations (ii) and (iv)

Net profit, [tex]P = 5(125+3n) (125-n) - 500n\cdots(v)[/tex]

To get the maximum profit, differentiate the profit function in equation (v) with respect to n and equate it to zero to get the value of n, i.e

[tex]\frac {dP}{dn}=0 \\\\\Rightarrow \frac {d}{dn}(5(125+3n) (125-n) - 500n)=0 \\\\\Rightarrow  5[ (125+3n)(-1)+(125-n)(3)]-500=0 \\\\\Rightarrow 5[ -125-3n+375-3n]-500 =0 \\\\\Rightarrow 5[ -125-3n+375-3n]=500\\\\\Rightarrow 250-6n=500/5=100 \\\\\Rightarrow 6n = 250-100=150 \\\\\Rightarrow n= 150/6 = 25.[/tex]

Hence, the farmer has to wait for 25 days to get the maximum profit.

El granjero puede obtener ganancias máximas en el día 229.

En este problema debemos construir una función de ganancia ([tex]G[/tex]), en pesos, igual a la ganancia neta por venta de la carne de vacuno ([tex]N[/tex]) menos los costes de mantenimiento ([tex]M[/tex]). Cada una de las variables ha de considerar el cambio de los indicadores en función del tiempo, entonces:

Función de ganancia

[tex]G = N - M[/tex] (1)

Función de ganancia neta

[tex]N = (125+3\cdot t)\cdot 100\cdot (5-0.01\cdot t)[/tex] (2)

Función de mantenimiento

[tex]M = 5[/tex] (3)

Al aplicar (2) y (3) en (1) tenemos la siguiente fórmula:

[tex]G = (125 + 3\cdot t) \cdot 100 \cdot (5 - 0.01\cdot t) - 5[/tex]

[tex]G = (125 + 3\cdot t) \cdot (500-t) - 5[/tex]

[tex]G = 62500+1500\cdot t -125\cdot t -3\cdot t^{2}-5[/tex]

[tex]G = -3\cdot t^{2}+1375\cdot t +62495[/tex]

El día correspondiente a la máxima ganancia es el valor [tex]t[/tex] del vértice de la parábola. Una forma rápida es mediante herramientas gráficas. Aquí encontramos que el granjero puede obtener ganancias máximas en el día 229.

Para aprender más sobre funciones cuadráticas, invitamos a ver esta pregunta verificada: https://brainly.com/question/8495268

Answer:

A. 1

Step-by-step explanation:

The value of any real number raised to 0 is 1.

Answer:

SHe put the decimal point in the wrong spot, it's suppose to be 43.89

Step-by-step explanation:

Answer:

no because 438.9 divided by seven is 62.7

Step-by-step ex

Answer:

The range is 3.6

Step-by-step explanation

The range is equal to the largest # - the smallest #

Which mean: 11.8 - 8.2= 3.6

Step-by-step explanation:

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Answer:

137 minutes

Step-by-step explanation:

Answer:

[tex]x = \frac{3}{4} + \frac{ \sqrt{105} }{4} \: \: , \: \: \: x = \frac{3}{4} - \frac{ \sqrt{105} }{4} \\ [/tex]

Step-by-step explanation:

2x² - 3x - 12 = 0

Using the quadratic formula which is

[tex]x = \frac{ - b \pm\sqrt{ {b}^{2} - 4ac} }{2a} \\ [/tex]

From the question

a = 2 , b = - 3 , c = - 12

So we have

[tex]x = \frac{ - - 3\pm \sqrt{ ({ - 3})^{2} - 4(2)( - 12)} }{2(2)} \\ = \frac{3\pm \sqrt{9 + 96} }{4} \\ = \frac{3\pm \sqrt{105} }{4} \: \: \: \: \: \: [/tex]

Separate the solutions

We have the final answer as

[tex]x = \frac{3}{4} + \frac{ \sqrt{105} }{4} \: \: , \: \: \: x = \frac{3}{4} - \frac{ \sqrt{105} }{4} \\ [/tex]

Hope this helps you