Please Help! Best gets Brainlest

Answer:

There is no difference.

Step-by-step explanation:

When it comes to significant figures, they matter.

However, if you just add zeros, they essentially just become placeholders. 3 already has 0 for decimals, so it is equal to 3.0 and 3.00.

Answer:

The Brain

Step-by-step explanation:

It goes down 3 and moves to the right 2

so its -3/2 =- 1.5

you slope is -1.5❤✔ hope I helped!

Answer:

The question is not complete.

I believe this is the correct complete question:

The following sample of six measurements was randomly selected from a normally distributed population: 1, 3, -1, 5, 1, 2.

a. Test the null hypothesis that the mean of the population is 3 against the alternative hypothesis,

μ<3  Use  α=.05

b. Test the null hypothesis that the mean of the population is 3 against the alternative hypothesis,

μ≠3  Use  α=.05

c. Find the observed significance level for each test.

Step-by-step explanation:

We will first find the standard deviation (S.D) of the six measurements.

To find the S.D, we calculate the mean and variance

Mean = ∈n/n where ∈n = sum of set of numbers n

Mean = [1+3+(-1)+5+1+2] / 6 where n = 6

Mean = 11/6 = 1.8

Variance = Sum of squared deviation from mean / n-1

Variance = [(1-1.8)² + (3-1.8)² + (-1-1.8)² + (5-1.8)² + (1-1.8)² + (2-1.8)²] / 6-1

Variance = [0.64 + 1.44 + 7.84 + 10.24 + 0.64 + 0.04] / 5 = 20.84/5 = 4.168

Standard Deviation S.D = √Variance = √4.168 = 2.041

(a) [tex]H_{o}[/tex] : μ=3,  [tex]H_{a}[/tex] : μ<3

Using  α=0.05

test stat =  {mean - μ[tex]_{o}[/tex]] / S.D /[tex]\sqrt{n}[/tex] = [1.8 - 3] / [2.041/ √6

test stat = -1.2 / 0.833 = -1.44

Critical Value from Student T distribution is t[tex]_{a}[/tex] = 2.015

Therefore, the rejection value contains values < -2.015

-1.400 > -2.015. It Fails to reject [tex]H_{o}[/tex]

(b) [tex]H_{o}[/tex] : μ = 3,  [tex]H_{a}[/tex] : μ ≠ 3

Using  α=0.05

test stat =  {mean - μ[tex]_{o}[/tex]] / S.D /[tex]\sqrt{n}[/tex] = [1.8 - 3] / [2.041/ √6

test stat = -1.2 / 0.833 = -1.44

Critical Value from Student T distribution is t[tex]_{a}[/tex] = 2.571

Therefore, the rejection value contains values < -2.571 and larger value to 2.571

2.571 > -1.400 > -2.571. It Fails to reject [tex]H_{o}[/tex]

(c) Significance Value of (a) is P-value > 0.100

Significance Value of (b) is P-value > (2 x 0.100 = 0.200)

Answer:

The area of the triangle is 24 [tex]\text{cm}^{2}[/tex].

Step-by-step explanation:

We are given that the length of the base of a right-angle triangle ABC is 6 cm and the length of the hypotenuse is 10 cm.

And we have to find the area of the triangle.

As we know that the area of the triangle is given by the following formula;

Area of the triangle =  [tex]\frac{1}{2}\times \text{Base} \times \text{Height}[/tex]

Firstly, we will find the height (perpendicular) of the triangle ABC bu using the Pythagoras Theorem.

[tex]\text{Hypotenuse}^{2} =\text{Perpendicular}^{2} +\text{Base}^{2}[/tex]

[tex]\text{10}^{2} =\text{Perpendicular}^{2} +\text{6}^{2}[/tex]

[tex]100=\text{Perpendicular}^{2} +36[/tex]

[tex]\text{Perpendicular}^{2} =100-36[/tex]

[tex]\text{Perpendicular}^{2} =64[/tex]

[tex]\text{Perpendicular} =\sqrt{64}[/tex]  = 8 cm.

Now, the area of the triangle =  [tex]\frac{1}{2}\times \text{Base} \times \text{Height}[/tex]

                                                =  [tex]\frac{1}{2}\times \text{6} \times \text{8}[/tex]

                                                =  24 [tex]\text{cm}^{2}[/tex]

Hence, the area of the triangle is 24 [tex]\text{cm}^{2}[/tex].

Answer:

A) 1 and -3

B) 8 and 6

C) D) 12 in.

Step-by-step explanation:

A) 1 and -3

B) x-2 = first number

x = second number

2x=5(x-2)-14

2x=5x-10-14

2x=5x-24

2x+24=5x

24=5x-2x

24=3x

8=x

So the two numbers are 8 and 6

C) width=x

length=x+8

x+x+x+8+x+8=64

4x+16=64

4x=48

x=12

Answer:

The height and  width of the interior tile =  3·x + 4 - 4 = 3·x and 2·x + 4  - 4= 2·x

Please see attached diagram

Step-by-step explanation:

The given parameters are;

The given rectangular floor tile  with width = 3·x + 4 and height = 2·x + 4

Where, x is in centimetres

The interior tile maintains a height to width ration of 2:3

The dimension of the trim border = 2 cm

Therefore;

The relationship between the width and height of the interior and exterior tiles is given as follows

Width of exterior tile = Width of interior tile + 2 × The dimension of the trim border

Which gives;

Width of exterior tile = Width of interior tile + 2 × 2 = Width of interior tile + 4

Height of exterior tile = Height of interior tile + 2 × The dimension of the trim border

Height of exterior tile = Height of interior tile + 2 × 2 = Height of interior tile + 4

Where the interior tile maintains a height to width ration of 2:3, we have;

For a unit length x, The height and the width of the interior tiles are 2·x:3·x

Therefore, for a given height 2·x, the width will be 3·x

Given the width of the exterior tile =  3·x + 4

The height of the exterior tile will then be 2·x + 4 and the width of the exterior tile will be 3·x + 4

The sides ratio of the interior tiles remain 2·x:3·x = 2/3

Answer:

12.4 pieces of ribbon

Step-by-step explanation:

When looking in the question, we can see the term "cut into equal pieces." This can insure to us that we need to divide two numbers. Since we originally have 15.5 inches long string, and we want to cut it into strings that are 1.25 inches long. We divide :

15.5 / 1.25

==> 12.4

Answer:

0

Step-by-step explanation:

We need to solve the given expression for the value of h.

- 4(-5h-4)=2(10h+8)

Opening brackets on both sides of the above equation

+20h+4=20h+16

Taking h terms on the one side and the constants on the another side

20h-20h=16-4

0=20

It means that the value of - 4(-5h-4)=2(10h+8) is equal to 0.

Answer:

The data is missing in the question, below is the complete question:

The number of credits being taken by a sample of 13​ full-time college students are listed below. Find the​ mean, median, and mode of the​ data, if possible. If any measure cannot be found or does not represent the center of the​ data, explain why. 9    9    12    12    9    10    8    8    8    8    8    8    11    Find the mean. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. The mean is nothing . ​(Type an integer or decimal rounded to one decimal place as​ needed.) B. The data set does not have a mean. Does the mean represent the center of the​ data? A. The mean represents the center. B. The mean does not represent the center because it is the smallest data value. C. The mean does not represent the center because it is not a data value. D. The mean does not represent the center because it is the largest data value. E. The data set does not have a mean. Find the median. Select the correct choice below​ and, if​necessary, fill in the answer box to complete your choice. A. The median is nothing . ​(Type an integer or decimal rounded to one decimal place as​ needed.) B. The data set does not have a median. Does the median represent the center of the​ data? A. The median represents the center. B. The median does not represent the center because it is the largest data value. C. The median does not represent the center because it is not a data value. D. The median does not represent the center because it is the smallest data value. E. The data set does not have a median. Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. The​ mode(s) is/are nothing . ​(Type an integer or decimal rounded to one decimal place as needed. Use a comma to separate answers as​ needed.) B. The data set does not have a mode. Does​ (Do) the​ mode(s) represent the center of the​ data? A. The​ mode(s) represent(s) the center. B. The​ mode(s) does​ (do) not represent the center because it​ (they) is​ (are) not a data value. C. The​ mode(s) does​ (do) not represent the center because it​ (one) is the largest data value. D. The​ mode(s) does​ (do) not represent the center because it​(one) is the smallest data value. E. The data set does not have a mode.

Answer:

a.) mean = 9.23

ii) The mean represents the centre (A)

b) Median = 9

ii) The median represents the centre (A)

c) Mode = 8

ii)  The​ mode(s) does​ (do) not represent the center because it​(one) is the smallest data value. (D)

Step-by-step explanation:

Arranging the data in ascending order:

8 8 8 8 8 8 9 9 9 10 11 12 12

a) calculating for mean

[tex]\bar x = \frac{sum\ of\ data}{number\ of\ data}\\ \bar x = \frac{8+8+8+8+8+8+9+9+9+10+11+12+12}{13} \\\bar x =\frac{120}{13} \\\bar x = 9.23[/tex]

ii) does the mean represent the centre of the data?

The measure of central tendency/location is a statistical tool used to accurately depict values that are at the central location of the data set

Yes, the mean represents the centre of the data, because there are no outliers in the data set. Outliers are unusual values compared to the rest of the values in the dataset.

b) calculating the median (M)

[tex]M =( \frac{n\ +\ 1}{2})th\ term\\ \\where:\\n = number\ of\ data\ in\ the\ dataset = 13\\\\\therefore M = \frac{13+1}{2}\\ M = \frac{14}{2} \\M= 7th\ term[/tex]

The 7th term after arranging in ascending or descening order, is the median term

8 8 8 8 8 8 9 9 9 10 11 12 12

∴ Median = 9

ii) Yes, the Median represents the center of the data, because it litterally tells the data at the middle of the distribution  

c) The mode is the data with the highest number of occurrence in the dataset (highest frequency);  8 8 8 8 8 8 9 9 9 10 11 12 12

The data with the highest number of occurrence is 8, which occurred 6 times.

Mode = 8

ii) The mode does not represent the centre of the data because it is the smallest value in the dataset, hence it doesn't tell the value that is the middle term.

Answer:

y = (1/2n) + (9/4)

Step-by-step explanation:

4y - 2n = 9

add 2n to both sides

4y = 9 + 2n

divide both sides by 4

y = (9/4) + (2/4n)

simplify

y = (9/4) + (1/2n)

put in standard form

y = (1/2n) + (9/4)

Answer:

y=9+2n/4

Step-by-step explanation:

4y-2n=9

   +2n

4y=9+2n

÷4     ÷4

y=9+2n/4

Answer:

d) $146.15

Step-by-step explanation:

From the above Question, we are given the following values:

The annual dividend per share of a perpetual preferred stock = $9.50

The required return rate on this preferred stock = 6.5% = 0.06

The selling price of the stock = ??

The formula to calculate the Selling price of the stock =

Annual dividend per share / Required return rate

= $9.5/ 0.065

= $146.15384615

Approximately $146.15

Therefore, the price at which the stock should sell is $146.15.

Answer:

(-4,-1)

Step-by-step explanation:

If a line must be parallel, then its slope must be the same.

Their points can be different, the slope should be same.

So, y = 1/3x - 4

=> We find the slope of the equation:

=> Slope = the number with which "x" is multiplied

=> Slope of this equation = 1/3

So, we need to find the point that makes a slope of 1/3 from (-3, 2)

=> Slope = y/x - y1/x1

=> 1/3 = -3/2 - y1/x1

=> y1/x1 = -3/2 - 1/3

=> y1/x1 = -3-1 / 2-3

=> y1/x1 = -4/-1

So, the point is (-4,-1)

a

n

​

=−0,06n+24

mark me a brainlist

Answer:

4 ounces

Step-by-step explanation:

If you divide the 164 ounces by the 8 ounces per glass, you get 20.5 glasses filled. So, half of the last glass would be 4.

Answer:

4 ounces

Step-by-step explanation:

We're looking for the remainder of ounces.

To find how many FULL glasses will be made, we divide 8 by 164 and look at the integer part of the number.

[tex]164\div8=20.5[/tex]

So 2 full glasses were made.

To find the remainder, we multiply 20 by 8 and subtract from 164.

[tex]20\cdot8=160\\\\164-160=4[/tex]

Hope this helped!

Answer:

C 2

Step-by-step explanation:

-3 doubled = -6

-6 +8 = 2 so C 2

Answer:

C. 2

Step-by-step explanation:

-3(2) = -6

-6+8 = 2

Answer:

Had Picked

Step-by-step explanation:

Answer:

90*12=1080

1080*13.2=14256

14256:100=142,56pounds

Answer:

Question 1

a) Range

= $2962

b) Variance

= $680557.4954

c) Standard Deviation

= $824.9590871

Question 2

Are there any​ outliers, and are they likely to have much of an effect on the measures of​ variation?

Yes, there are outliers present I the given sample data.

These outliers are the larger cost for marriage proposals which are: 1750, 3000

These largest costs are much bigger than the rest of the​ sample data, and they would likely have much of an effect on the measures of​ variation

Step-by-step explanation:

We are given the following sample data in dollars

38, 50, 50, 55, 55, 95, 95, 130, 180, 213, 250, 350, 450, 1750, 3000

Question 1

a) Range

This is the difference between the maximum cost and the minimum cost

The minimum cost = $38

The maximum cost = $3000

Range = $3000 - $38

= $2962

b) Variance

Reading the question, we are given sample data.

Hence, we use the formula for Variance of a sample

= (Mean - x)²/N - 1

Step 1

We find the Mean

Mean = Sum of terms/Number of terms

Number of terms = 15

Mean = 38 + 50 + 50 + 55 + 55 + 95 + 95 + 130 + 180 + 213 + 250 + 350 + 450+ 1750 + 3000/15

= $6761/15

= $450.7333333

Step 2

(x - Mean)²/N - 1

N = 15

= $[(38 - 450.7333333)²+ (50 + 450.7333333)²+( 50 +450.7333333)² + (55 +450.7333333)² + (55 +450.7333333)² + (95 + 450.7333333)²+ (95 +450.7333333)²+ (130 +450.7333333)²+ (180 +450.7333333)² + (213 + 450.7333333)²+ (250 +450.7333333)² + (350 + 450.7333333)² + (450 +450.7333333)²+ (1750 +450.7333333)² + (3000 +450.7333333)²]/15 - 1

=$ (- 412.7333333² + -400.7333333² + -400.7333333² + -395.7333333² + -395.7333333² + -355.7333333² + -355.7333333² + -320.7333333² + -270.7333333² + -237.7333333² + -200.7333333² + -100.7333333² + -0.7333333333² + 1299.266667² + 2549.266667²)/15 - 1

= $( 170348.8044+ 160587.2044, 160587.2044+ 156604.8711, 156604.8711+ 126546.2044, 126546.2044+ 102869.8711, 73296.53776+ 56517.13776, 40293.8711+ 10147.20444+ 0.5377777777+ 1688093.872, 6498760.539)/14

= $9527804.935/14

Variance = $680557.4954

c) Standard deviation = √Variance

Standard deviation = √$680557.4954

= $824.9590871

Question 2

Are there any​ outliers, and are they likely to have much of an effect on the measures of​ variation?

Yes, there are outliers present in the given sample data.

These outliers are the largest cost for marriage proposals which are: $1750 and $3000

These largest costs are much bigger than the rest of the​ sample data, and they would likely have much of an effect on the measures of​ variation.

Answer:

13.9 miles

Step-by-step explanation:

If we draw out the way he drove, the drive from his home to the intersection represents the long leg of a right triangle and the short leg can be represented by his drive from the intersection to the workplace.

A road from his home to work would represent the hypotenuse.

Since we know the distances of the legs, we can use the pythagorean theorem to find the hypotenuse, or the distance of the new road.

Plug in the values:

a² + b² = c²

12² + 7² = c²

193 = c²

13.9 = c

= 13.9 miles

The measure of the angle y is 120°.

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

The Sum of the three angles is 180 degrees.

33 + 87 + x = 180

x = 180 - 120

x = 60

Now,

x + y = 180

60 + y = 180

y = 180 - 60

y = 120

Thus,

The value of y is 120°.

Learn more about triangles here:

https://brainly.com/question/25950519

#SPJ2

Answer:

[tex]P(X\leq 1) = 0.331[/tex]

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

[tex]P(X = x) = \frac{y^xe^{-y}}{x!}[/tex]

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

[tex]P(X\leq 1) = P(X=0) + P(X =1)[/tex]

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

[tex]P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}[/tex]

[tex]P(X = 0) = \frac{1 * e^{-2.3}}{1}[/tex]

[tex]P(X = 0) = e^{-2.3}[/tex]

[tex]P(X = 0) = 0.10025884372[/tex]

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

[tex]P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}[/tex]

[tex]P(X = 1) = \frac{2.3 * e^{-2.3}}{1}[/tex]

[tex]P(X = 1) =2.3 * e^{-2.3}[/tex]

[tex]P(X = 1) = 2.3 * 0.10025884372[/tex]

[tex]P(X = 1) = 0.23059534055[/tex]

[tex]P(X\leq 1) = P(X=0) + P(X =1)[/tex]

[tex]P(X\leq 1) = 0.10025884372 + 0.23059534055[/tex]

[tex]P(X\leq 1) = 0.33085418427[/tex]

[tex]P(X\leq 1) = 0.331[/tex]

Hence, the required probability is 0.331

Answer:

Step-by-step explanation:

9k + 3 > 6k - 18

To solve the inequality shown first group like terms.

That's send the constants to the right side of the inequality and those with variables to the left side.

We have

9k - 6k > - 18 - 3

Simplify

3k > - 21

Divide both sides by 3

We have the final answer as

Hope this helps you

Answer:

A. 0.78 and 1.255.

B.  0.095

C. -0.475

Step-by-step explanation:

The given regression line is

y=-0.17+0.095x

A.

The true average flow rate for a pressure drop of 10 inch can be computed by putting x=10 in above equation.

y=-0.17+0.095*10

y=-0.17+0.95

y=0.78

The true average flow rate for a pressure drop of 10 inch is 0.78.

The true average flow rate for a pressure drop of 15 inch can be computed by putting x=15 in above equation.

y=-0.17+0.095*15

y=-0.17+1.425

y=1.255

The true average flow rate for a pressure drop of 15 inch is 1.255.

B.

The slope represents average change in y due to unit change in x.

So, the true average change in flow rate associated with a 1 inch increase in pressure drop is 0.095(1)= 0.095.

C.

When pressure drops decreases by 5 in. then the average change in flow rate is 0.095(-5)=-0.475.

The flow rate in the device is an illustration of average rates.

The function is given as:

[tex]\mathbf{y = -0.17 + 0.095x}[/tex]

(a) The true average flow rate when pressure drops 10 and 15 in

When x = 10, we have:

[tex]\mathbf{y = -0.17 + 0.095 \times 10}[/tex]

[tex]\mathbf{y = 0.78}[/tex]

When x = 15, we have:

[tex]\mathbf{y = -0.17 + 0.095 \times 15}[/tex]

[tex]\mathbf{y = 1.255}[/tex]

Hence, the true average flow rates when pressure drops 10 and 15 in are 0.78 and 1.255 respectively

(b) The true average flow rate when pressure increases by 1 in

This simply represents the slope of the function.

The function is given as:

[tex]\mathbf{y = -0.17 + 0.095x}[/tex]

A linear regression equation is represented as:

[tex]\mathbf{y = b + mx}[/tex]

Where m represents the slope

By comparison:

[tex]\mathbf{m = 0.095}[/tex]

Hence, the true average flow rates associated to a 1 in pressure increment is 0.095

(c) The average change in flow rate when pressure drops decreases by 5 in

The domain of the function is given as:

[tex]\mathbf{x = 5\ to\ 20}[/tex]

A decrement of -5 in means: x = -5

This is out of the domain of the function

Hence, the average change at a decrement of 5 in cannot be calculated

Read more about average change at:

https://brainly.com/question/23483858

Answer:

slope of F(X) = to the slope of G(X)

Step-by-step explanation:

your answer should be: letter C

No lies, I just did the exam and I've got it right, gook luck, guys.

please let me know if it worked, and also please don't forget to make brainly, give a rate, and add the heart ;) I will do the same on you.

The slope of a line f(x) is greater than the slope of a line g(x). Therefore, option A is the correct answer.

The coordinate points on equation of line g(x) are (0, 2), (5, 4) and (10, 6) and f(x) are (3, 1) and (0, -1).

The slope or gradient of a line is a number that describes both the direction and the steepness of the line. The slope can be determined using the formula, slope = (y2-y1)/(x2-x1).

Now, slope of a line g(x) is (4-2)/(5-0)

=2/5

Slope of a line f(x) is (-1-1)/(0-3)

=2/3

The slope of a line f(x) is greater than the slope of a line g(x). Therefore, option A is the correct answer.

To learn more about the slope of a line visit:

https://brainly.com/question/16180119.

#SPJ2

Answer:

Step-by-step explanation:

From the given information:

the null hypothesis and the alternative hypothesis can be computed as follows:

[tex]\mathbf{H_o:}[/tex] The sample have a distribution that agrees with the distribution of state populations.

[tex]\mathbf{H_1:}[/tex] The sample have a distribution that does not agrees with the distribution of state populations.

The Chi-Square test statistics [tex]\mathbf{X^2 = \dfrac{(Observed \ value - Expected \ value )}{(Expected \ value ) ^2 }}[/tex]

Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8%. A market researcher selects a sample of 1000 subjects, with 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana.

The observed and the expected value can be computed as follows:

States           Observed           Expected                        [tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

Washington     450             0.51 × 1000 = 510

Oregon            340              0.30 × 1000 = 300

Idaho                150               0.11  × 1000 = 110

Montana             60              0.08 × 1000 = 80

Total                 1000                                1000

For washington :

[tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

[tex]X^2 = \dfrac{(450 -510)^2}{510}[/tex]

[tex]X^2 = \dfrac{3600}{510}[/tex]

[tex]X^{2}=[/tex] 7.06

For Oregon

[tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

[tex]X^2 = \dfrac{(340- 300)^2}{300}[/tex]

[tex]X^2 = \dfrac{1600}{300}[/tex]

[tex]X^{2}=[/tex] 5.33

For Idaho

[tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

[tex]X^2 = \dfrac{(150- 110)^2}{110}[/tex]

[tex]X^2 = \dfrac{1600}{110}[/tex]

[tex]X^2 =14.55[/tex]

For Montana

[tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

[tex]X^2 = \dfrac{(60- 80)^2}{80}[/tex]

[tex]X^2 = \dfrac{400}{80}[/tex]

[tex]X^2 = 5[/tex].00

The Chi-square test statistics for the observed and the expected value can be computed as follows:

States           Observed           Expected                        [tex]X^2 = \dfrac{(O- E)^2}{E}[/tex]

Washington     450             0.51 × 1000 = 510                  7.06

Oregon            340              0.30 × 1000 = 300                5.33

Idaho                150               0.11  × 1000 = 110                 14.55

Montana             60              0.08 × 1000 = 80                  5.00

Total                 1000                                1000                 31.94

The Chi-square Statistics Test [tex]\mathbf{X^2 = 31.94}[/tex]

Degree of freedom = n -  1

Degree of freedom = 4 - 1

Degree of freedom = 3

At 0.05 level of significance, the critical value of :

[tex]X^2_{(df, \alpha) }=X^2_{(3, 0.05)[/tex] = 7.815

Decision Rule: To reject null hypothesis if the test statistics is greater than the critical value

Conclusion: We reject the null hypothesis since test statistics is greater than critical value, therefore, we conclude that there is sufficient information to say that the sample has a distribution that does not agrees with the distribution of state populations.

Answer:  4.

Step-by-step explanation:

As you can see from the table in you input 0 into the function your output will be 4.

Answer:  $0.27

Step-by-step explanation:

7a + 11b = 1.47

        7a = 1.47 - 11b

          [tex]a=\dfrac{1.47-11b}{7}[/tex]

Make a table. Choose values for b starting at $0.01 and solve for "a".

The value of "a" must terminate at the hundredths place since we are working with money.

You will discover that a = 0.10 and b = 0.07

The cost of 2 apples and 1 banana is:

  2a + b

= 2(0.10) + (0.07)

=    0.20 + 0.07

=          0.27