Please can you help me from 1 to 6

Answer:

(a) The slope of distance-time graph gives the speed of the objects.

           As the slope of object  (B) is the greatest among all, thus  B has the largest speed and hence it is the fastest among all the objects.

(b)  :      As the curve of the objects do not intersect with each other even once, hence they cannot be at the same point on the road at the same time.

(c)   :      On the y axis  (i.e.  distance line), 7 small represents 4 km

      ∴  1 small line  =  

7

4

​  

=0.57 km

           Position of C at the instant B passes A is  8 km

(d)   ;     Position of B at the instant it passes C is 2nd small line above 4 km i.e. 4+2×0.57=5.14 km  

       ∴ Distance traveled by B   =5.14−0=5.14 kmV

Explanation:

Answer:

D

Explanation:

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Answer:

C. the ice cube and the glass of water have higher heat capacity than the swimming pool

Answer:

It's D.

Explanation:

When the egg is not fertilized, the thick uterus lining breaks down and the blood, tissues, and the unfertilized egg come out of the vagina commonly known as menstruation. When the egg is not fertilized the menstrual cycle takes place as the egg is shredded off from the body.

Answer:

Mass = 96g

Explanation:

Molarity = number of moles/volume of solvent

According to the provided information, volume = 1.55L, Molarity = 1.55M

number of moles (n) = molarity × volume

n = 1.55 × 1.55

n = 2.4025

n = 2.40mol

For NaOH, molar mass = 23 + 16 + 1 = 40g/mol

mole = mass/molar mass

Mass = molar mass × mole

Mass = 40 × 2.40

Mass = 96g

Answer:

A. carbon dioxide

Explanation:

Answer:

ω∉1

Explanation:

TB solution = 100.3315 °C

T freezing solution = -1.209 °C

Given

1.2 g glycerol

20 g water

Required

the boiling point

the freezing point

Solution

ΔTB = KB . m

ΔTF = KF . m

mass water = 20 g = 0.02 kg

Kb water = 0.51 °C/m

KF water = 1.86 °C/m

mol glycerol :

= 1.2 g : 92,09382 g/mol

= 0.013

molal  : the number of moles of solute in 1 kg of solvent  

molal of solution :

= 0.013 : 0.02

= 0.65 m

ΔTB = KB . m

ΔTB = TB solution - TB solvent  

TB solution - 100 = 0.51 x 0.65

TB solution - 100 = 0.3315

TB solution = 100.3315 °C

ΔTF = KF . m

ΔT = KF . m

ΔTF = 1.86 x 0.65

ΔTF = 1.209

T_f  = -1.209 °C

Answer:like my photo bc i like it

Explanation:

omg i look .........................................  

Answer: Thus 44 g of [tex]CO_2[/tex] will be produced  if 30 g of [tex]C_6H_{12}O_6[/tex] were reacted with an excess of oxygen

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} C_6H_{12}O_6 =\frac{30g}{180g/mol}=0.17moles[/tex]

The balanced chemical equation is:  

[tex]C_6H_{12}O_6 +6O_2(g)\rightarrow 6CO_2+6H_2O(g)[/tex]

As [tex]C_6H_{12}O_6[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

According to stoichiometry :

1 mole of [tex]C_6H_{12}O_6[/tex] produce =  6 moles of [tex]CO_2[/tex]

Thus 0.17 moles of [tex]C_6H_{12}O_6[/tex] will produce=[tex]\frac{6}{1}\times 0.17=1.0mole[/tex]  of [tex]CO_2[/tex]

 Mass of [tex]CO_2=moles\times {\text {Molar mass}}=1.0moles\times 44g/mol=44g[/tex]

Thus 44 g of [tex]CO_2[/tex] will be produced  if 30 g of [tex]C_6H_{12}O_6[/tex] were reacted with an excess of oxygen.

Pretty sure it’s gypsum.

Answer:

Explanation:

Acid rain that seeps into the ground can dissolve nutrients, such as magnesium and calcium, that trees need to be healthy. Acid rain also causes aluminum to be released into the soil, which makes it difficult for trees to take up water. ... The acidic clouds and fog strip important nutrients from their leaves and needles.

Answer:

b i think im sorry if im wrong

Explanation:

Answer:

the mass of the copper piece is 110.2976 grams

Answer:

1. Renewable Resource

2. Carbonate

3. Fossil Fuel

4. Nonrenewable Resource

5. Carbon Cycle

Answer:

1. Renewable Resource

2. Carbonate

3. Fossil Fuels

4. Non-renewable Resource

5. Carbon Cycle

Answer:

equal to ​

Explanation:

This question is depicting the LAW OF CONSERVATION OF MASS/MATTER, which states that matter can neither be created nor destroyed. Hence, in an isolated system, the original mass of the reactants must be EQUAL TO the final mass of the products formed.

In other words, the law states that no matter the change in chemical composition of the reactants in a chemical process, the mass does not change or it remains constant.

Answer:

the called potential energy because the potential energy is the latentenergy in an object at rest

Answer:

Given

[HONH2] = 0.45M

[OH-] = 5.26 x 10-6 M

                                           HONH2 + H2O -------------> HONH3+ + OH-

Initial                                     0.45           55                         0             0

at equilibrium                        0.45-x        55-x                      x             x

Given

[OH-] = x =  5.26 x 10-6 M

Therefore [HONH3+] = x =  5.26 x 10-6 M

pOH = -log[OH-] = -log(5.26 x 10-6) = 5.279

=> pH = 14- pOH = 8.72

From hendersen-hasselbach equaiton

8.72 = pKa + log(0.45/5.26 x 10-6)

=> pKa = 3.788

=> pKb = 14-3.788 = 10.21

percent of ionization = 5.26 x 10-6 * 100/0.45 = 1.17 x 10-3 %

concentration of NaOH required to make the same pH= [OH-] = 5.26 x 10-6 M

Percent of ionization of NaOH = [OH-]*100/NaOH = 5.26 x 10-6 *100/5.26 x 10-6 = 100%

The gravitational potential energy of a basketball  : PE = 18.375 J

Given

height = h = 3 m

mass = 0.625 kg

Required

The potential energy

Solution

The energy produced from its position is called potential energy (PE)  

which can be formulated as:  

PE = m. g. h (g = 9.8 m/s²)

Input the value :

PE = 0.625 x 9.8 x 3

PE = 18.375 J

Answer:

D.

Explanation:

Because force and energy are used to move.

Answer:

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Explanation:

Answer:

It will have 5 valence electrons as its in group 5.

The atom will gain as its closer to the full configuration 8.

The charge will be 3- as it will gain 3 electrons.

Explanation:

you can watch this video and understand

Answer:

not chemical only that's classifying reactions

and figures equations

Explanation:

that may answer

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The reaction of the different metals together to form a new compound is called a chemical reaction.

According to the question, we have to color the region which shows the behavior of the reaction.

Hence, these are the answer to the question.

For more information, refer to the link:-

https://brainly.com/question/15804584

as it breaks down the surface , it reshapes it

Answer:

That is extremely confusing. Try contacting your prof.

Explanation:

The noble gas that precedes a given partial electron configuration must itself have an electron configuration that is complete up to the partial electron configuration. The noble gas's electron configuration should, when fully written out right before the partial electron configuration, give us a valid electron configuration for some element.

For the first series, the highest principal energy level has the number 4, so our noble gas should at least be one that is in the third period (numerically, the energy level is the same as the period number). That noble gas would be argon. The partial electron configuration given is not that of a noble gas (note: all noble gases have an electron configuration that contains Np⁶, where N = the highest principal energy level). So, the noble gas that appropriately precedes our first partial electron configuration is [Ar].

Argon's electron configuration is 1s²2s²2p⁶3s²3p⁶. Using the Aufbau Principle, 4s² would correctly follow 3p⁶. [Ar]4s²3d¹⁰4p² is equivalent to writing out 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p²; either way, this would happen to be the electron configuration of germanium.

Now that we hopefully have our fundamentals down, we can apply them to figure out the noble gases that precede the remaining partial electron configurations.

[Kr]5s²4d¹⁰5p⁵: This is the electron configuration of iodine.

[He]2s²2p⁵: This is the electron configuration of fluorine.

[Xe]6s²4f¹⁴5d¹⁰6p²: This is the electron configuration of lead.

[Ne]3s²2: This is the electron configuration of magnesium.