Please answer i need help please i will give you brainlest please

9514 1404 393

Answer:

  x = 22, y = 123

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  (2x +13)° +57° +3x° = 180°

  5x +70 = 180 . . . . . . . . . . . . . collect terms, divde by °

  5x = 110 . . . . . . . . . . . subtract 70

  x = 22 . . . . . . . . divide by 5

__

Angles in a linear pair are supplementary.

  y° + 57° = 180°

  y = 123 . . . . . . . . divide by °, subtract 57

Answer:

[tex]h(f(4))=20[/tex]

Step-by-step explanation:

We are given the functions:

[tex]f(x)=x^2,\, g(x)=5x\text{, and } h(x)=x+4[/tex]

And we want to find

[tex]h(f(4))[/tex]

Find f(4) first:

[tex]f(4)=(4)^2=16[/tex]

Thus:

[tex]h(f(4))=h(16)[/tex]

Now, evaluate h(16):

[tex]h(16)=(16)+4=20[/tex]

Hence:

[tex]h(f(4))=20[/tex]

Answer:

108801

Step-by-step explanation:

Palindrome as defined in the given question as a number which reads the same forward and backward. Examples are: 1001, 20202, 1331 etc.

Thus, to determine the smallest 6-digit palindrome divisible by 99 without a remainder, the digits should be in the form of abccba.

Therefore, the smallest 6-digit palindrome that can be divided by 99 is 108801.

So that,

108801 ÷ 99 = 1099

Answer:

))

Step-by-step explanation:

just place your decimal once to the left I think

Answer:

[tex](a)\ P(White) = \frac{1}{2}[/tex]

(b) 10 additional white balls

(c) 10 additional black balls

Step-by-step explanation:

Given

[tex]White = 5[/tex]

[tex]Black =3[/tex]

[tex]Red = 2[/tex]

Solving (a): P(White)

This is calculated as:

[tex]P(White) = \frac{White}{Total}[/tex]

[tex]P(White) = \frac{5}{5+3+2}[/tex]

[tex]P(White) = \frac{5}{10}[/tex]

[tex]P(White) = \frac{1}{2}[/tex]

Solving (b): Additional white balls, if [tex]P(White) = \frac{3}{4}[/tex]

Let the additional white balls be x

So:

[tex]P(White) = \frac{White+x}{Total+x}[/tex]

This gives:

[tex]\frac{3}{4} = \frac{5+x}{10+x}[/tex]

Cross multiply

[tex]30+3x = 20 + 4x[/tex]

Collect like terms

[tex]4x - 3x = 30 - 20[/tex]

[tex]x = 10[/tex]

Hence, 10 additional white balls must be added

Solving (c): Additional black balls, if [tex]P(White) = \frac{1}{4}[/tex]

Let the additional black balls be x

So:

[tex]P(White) = \frac{White}{Total+x}[/tex]

So, we have:

[tex]\frac{1}{4} = \frac{5}{10+x}[/tex]

Cross multiply

[tex]10+x = 5 * 4[/tex]

[tex]10+x = 20[/tex]

Collect like terms

[tex]x = 20 -10[/tex]

[tex]x = 10[/tex]

Hence, 10 additional black balls must be added

Solution :

Given :

[tex]f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.[/tex]

1. Cumulative distribution function

[tex]$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$[/tex]

              [tex]$=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx $[/tex]

             [tex]$=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$[/tex]

             [tex]$=\frac{1}{450} \int_6^x (x^2-x) \ dx$[/tex]

             [tex]$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$[/tex]

             [tex]$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right] $[/tex]

            [tex]$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$[/tex]

2.  Mean [tex]$E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$[/tex]

                       [tex]$=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\ dx$[/tex]

                     [tex]$=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$[/tex]

                     [tex]$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$[/tex]

                     [tex]$=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) - \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right) $[/tex]

                     [tex]$=\frac{1}{450} [4608 - 252]$[/tex]

                    = 17.2857

The y-intercept is the y value where the blue line crosses the Y axis which is the vertical black line.

The line crosses at the number 4, so the y-intercept is 4

Answer: D. 4

Answer: just had this problem! X = 11

Answer:

C: 44

Step-by-step explanation:

Answer:

D. <S, <R, <T

Step-by-step explanation:

Recall: On a triangle, the bigger an angle measure the longer the side opposite it and vice versa.

In ∆RST,

The longest side, SR = 22, is opposite to <T

Therefore, <T is the biggest angle.

Medium side, ST = 21, is opposite to <R, therefore,

<R is the medium angle measure

The smallest angle measure <S is opposite to the shortest side, RT.

Angels I'm order form the smallest to largest will be:

<S, <R, <T

Answer:

gradient = 2

line: y = 2x - 4

Step-by-step explanation:

Find the slope from the slope intercept formula

y = mx + b

b is the y intercept

b = -4 and the point is (0,-4)

So far the equation looks like this.

y = mx - 4

Use the other intercept (x intercept) to find m

x = 2

y = 0

0 = m*2 - 4                Add 4 to both sides

4 = 2m                      Divide by 2

4/2 = m

m = 2

So the gradient or slope is 2

Answer:

B

Step-by-step explanation:

Exclude C:

[tex] |x| [/tex]

is not curved

To shift right, minus inside the

[tex] |?| [/tex]

Thus

[tex] |x - 4| [/tex]

To shift up, add outside the

[tex] |?| [/tex]

Thus:

[tex] |x +4| + 2[/tex]

B

Brainliest please~

Answer:

$23.3

Step-by-step explanation:

you can use ratios to solve this:

$6.99/x=0.30/0.100 then cross multiply to get 0.3x=6.99

So, 6.99 divided by 0.3 = 23.3

so the original price is $23.3

Answer:

0，0

Step-by-step explanation:

n=2，

[tex] {2}^{2} - 2 - 2 = 0 [/tex]

[tex] {2}^{2} - 5 \times 2 + 6 = 0[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

There are a couple of relations that are applicable to these questions.

__

The segment lengths relation tells us ...

  10x = 8×7 . . . . . . products of segment lengths are equal

  x = 56/10 = 5.6 . . . . divide by 10

__

The value of y° is the average of the intercepted arcs:

  y° = (85° +45°)/2 = 65°

_____

Additional comment

This diagram does not have enough information to allow computation of z. We would need to know the intercepted arc, or the length of the secant that meets tangent z.

Answer:

Step-by-step explanation:

The solution triangle attached below :

Since we have a right angled triangle, we can make use of Pythagoras rule to obtain the vertical distance, x

Recall :

Hypotenus² = opposite² + adjacent²

Hence,

x² = 61² - 60²

x² = 3721 - 3600

x² = 121

x = √121

x = 11

Vertical distance equals 11 inches

Answer:

50% i believe

Step-by-step explanation:

because in every scenario theres 2 teams and if they are well matched it be half and half on every game assuming they're the same level of comp

Answer:

x = 3

Step-by-step explanation:

A midsegment in a trapezoid is formed when one connects the midpoints of the two legs (non-parallel sides) in a trapezoid. The midsegment theorem states that the length of the midsegment is equal to the average of the two bases (that is the parallel sides).

One can apply the midsegment theorem here by stating the following;

[tex]\frac{(YZ)+(TM)}{2}=PW[/tex]

Substitute,

[tex]\frac{23+11x+2}{2}=29[/tex]

Simplify,

[tex]\frac{25+11x}{2}=29[/tex]

Inverse operations,

[tex]\frac{25+11x}{2}=29[/tex]

[tex]25+11x=58\\\\11x = 33\\\\x = 3[/tex]

Answer:

6, 15, 24, 33

Step-by-step explanation:

Basically, the number on top of the sigma represents the number of terms total in that sequence, and on the right you have the equation in which you can plug in whichever value that falls into what the top number says to find the output. In other words, just plug in 1 for k to find a1, 2 for k to find a2, etc.

Hope that helps!

Answer:

(d) 7

Step-by-step explanation:

The total number of subsets that can be derived from a set with n elements is given by;

2ⁿ

Out of these subsets, there is one empty set. Therefore, the total number of non-empty subsets is given by;

2ⁿ - 1

Given:

A = {x, y, z}

Set A has 3 elements. This means that n = 3

Therefore, the total number of subsets that can be derived from set A is

2ⁿ = 2³ = 8

One of these 8 subsets is an empty set, therefore, the total number of non-empty subsets of A is;

2ⁿ - 1 = 2³ - 1

8 - 1 = 7

This can be checked by writing all the possible subsets of A as follows;

∅

{x}

{y}

{z}

{x, y}

{y, z}

{x, z}

{x, y, z}

Removing the empty set ∅, the non-empty subsets of A are;

{x}

{y}

{z}

{x, y}

{y, z}

{x, z}

{x, y, z}

Answer:

C

Step-by-step explanation:

Start by simplifying what you can in each radicalfor example, the

∛(xy⁵)= y∛(xy²)

and

∛(x⁷y¹⁷)=x²y⁵∛(xy²)

So know our equation looks like

y∛(xy²)*x²y⁵∛(xy²)

Now because what's inside the radical is the same we can combine them

y⁶x²∛(xy²)²

distribute the square

so

∛(xy²)²=  ∛(x²y⁴)= y∛(x²y)

and finally,

y⁶x²*y∛(x²y)= y⁷x²∛(x²y)

this is equal to option C

Answer:

x < -10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

x/-2 > 5

Step 2: Solve for x

[tex]\large {\mathsf {\red{\underbrace {\overbrace{\blue{ {\pink}{Answєr}}}}}}} \: [/tex]

x > - 10

[tex] \large \mathtt \green{Step-by-step \: explanation : }[/tex]

[tex] \small \sf \frac{x}{ - 2} > 5 \\ [/tex]

Solve for x

[tex] \small \sf \frac{x}{ - 2} > 5 \\ [/tex]

common denominator is 2

[tex]\small \sf ➪ \frac{2x}{ - 2} >2 \times 5 \\ [/tex]

[tex]\small \sf ➪ \frac{ \cancel{2}x}{ - \cancel{ 2}} >2 \times 5 \\ [/tex]

➪ - x > 2 × 5

➪ - x > 10

multiply by - 1

➪ - x × - 1 > 10 × - 1

x > - 10

Answer:

The answer should be (7, 5)

Answer: -9x-1y-9/

Step-by-step explanation:

Answer: b

Step-by-step explanation:

I really dont like edge

[tex]V = 864\pi[/tex]

Step-by-step explanation:

Since one of the boundaries is y = 0, we need to find the roots of the function [tex]f(x)=-2x^2+6x+36[/tex]. Using the quadratic equation, we get

[tex]x = \dfrac{-6 \pm \sqrt{36 - (4)(-2)(36)}}{-4}= -3,\:6[/tex]

But since the region is also bounded by [tex]x = 0[/tex], that means that our limits of integration are from [tex]x=0[/tex] (instead of -3) to [tex]x=6[/tex].

Now let's find the volume using the cylindrical shells method. The volume of rotation of the region is given by

[tex]\displaystyle V = \int f(x)2\pi xdx[/tex]

[tex]\:\:\:\:\:\:\:= \displaystyle \int_0^6 (-2x^2+6x+36)(2 \pi x)dx[/tex]

[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \int_0^6 (-2x^3+6x^2+36x)dx[/tex]

[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \left(-\frac{1}{2}x^4+2x^3+18x^2 \right)_0^6[/tex]

[tex]\:\:\:\:\:\:\:= 864\pi [/tex]