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Answer:

1196 g

Explanation:

N= 14 O= 16

every 3 moles of NO2 gives one mole of NO

So, 3[14 + (2×16)] = 138 grams of NO2

gives : 14+16 = 30 grams of NO

NO2 NO

138 30

? 260

Therefore, 260 × 138 ÷ 30 = 1196 g of NO2 are required

for many reasons fluorine is mor reactive than nitrogen

1: F is more electronegative atom than N

2: F just needs an electron and N needs 3 electrons to reach noble gases electron configuration

4: F2 bond is weaker than N2 bond

Answer:

Pka of formic acid (HCOOH)= 3.75

pH= PKa +log [ Sodium formate/ formic acid] = 3.75

NaOH reacts with HCOOH as HCOOH (aq) + NaOH(aq) --> NaCHO2 (aq) and H2O (l)

Moles of HCOOH= 0.1*1= 0.1 moles

Moles of NaOH= 5*1/1000= 0.005 moles

HCOOH is in excess and the excess is = 0.1 - 0.005 = 0.095

Moles of sodium formate = 0.005 + 0.1 = 0.105 moles of HCOOH= 0.095

volume after mixing = 1 + 5 /1 000=1.005

Concentrations : HCOOH= 0.095/1.005 sodium formate= 0.105/1.005

pH= 3.75+log (0.105/0.095)=3.85

When NaOH is added, molarity is , 1*5= 1000*M

M= 5/1000=0.005

The pH remains the same. Only the molarity of NaOH changes.

The equilibrium concentration of N₂O₄, given that the concentration of NO₂ is 1.78×10⁻² is 5.42×10⁻²

Keq = [Product] / [Reactant]

Keq = [NO₂]² / [N₂O₄]

5.85×10⁻³ = [1.78×10⁻²]² / [N₂O₄]

Cross multiply

5.85×10⁻³ × [N₂O₄] = [1.78×10⁻²]²

Divide both sides by 5.85×10⁻³

[N₂O₄] = [1.78×10⁻²]² / 5.85×10⁻³

[N₂O₄] = 5.42×10⁻²

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Answer:

First answer is "The equilibrium lies to the left", and the second one is 5.42 x 10^-2 M.

Explanation:

Hope i helped yall :D

Answer:

The correct answer is - directly; Avogadro’s.

Explanation:

At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.

Thus, the correct answer is - directly; Avogadro’s.

Answer:

Download Ptable, it will show all of the elements, and you can click on them, and it will show all the information you need about them!

Explanation:

I hope this helps!!!!!

Answer:

The peritoneum

Explanation:

The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.

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Answer:

1896 mmHg

Explanation:

P1/T1 = P2/T2

P1 = 2065 mmHg

T1 = 416 K

P2 = ?

T2 = 382 K

Solve for P2 --> P2 = P1T2/T1

P2 = (2065 mmHg)(382 K) / (416 K) = 1896 mmHg

Answer:

Explanation:

Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)  

Mass of uncreystaliized product = 109.03 gm - 105.98 gm

Mass of uncrystaliized product = 3.05 gm

For methyl benzoate;

mass = 3.08 g

no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole

It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.

moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles

∴

mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol

mass of nitro methyl benzoate = 4.098 gm

For HNO_3 solution:

mass = 1.42 gm/ml × 2.0 ml

mass = 2.84 gm

Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]

= 1.9596 gm

Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]

= 0.0311 mole

1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate

Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole

The mass for nitro methyl benzoate can now be determined as:

= 0.0311 mole × 181.5 gm/mole

= 5.634 gm

Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.

The mass obtainable from the LR = 4.098 gm

Answer:

the independent variable (sometimes known as the manipulated variable )

Explanation:

is the variable whose change isn't affected by any other variable in the experiment

Answer:

I think it the carbon 14 which is a half life of 5730 because in 4.5billion years ago I don't think any human being existed on earth I'm not sure I hope that I helped you and good luck .

Carbon-14 dating will be used to find a numerical date for some hominid artifacts found buried by ash from a volcanic eruption.

What is carbon dating?

Radiocarbon dating also known as carbon dating or carbon-14 dating.

It is a method for establishing the age of an organic thing using the properties of radiocarbon, a radioactive carbon isotope.

Willard Libby created the approach in the late 1940s.

Thus, Carbon -14 dating will give your friend the most accurate numerical age.

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Explanation:

the soap is the product made from a detergent

Answer:

2,1,2

1,2,1,1

the answer

Answer: 2260 J/g is gained from the surrounding environment

When one gram of liquid water at its boiling point is changed into water vapor, 2260 J/g of energy is gained from the surrounding environment.

Heat of vaporization is the amount of heat that is required by any body during their transition process from liquid state to vapor state, at a particular temperature i.e. no change in temperature during whole process.

During the transition of one gram of liquid water into water vapor at its boiling point of 100°C, 2260 J/g energy is absorbed by the water for the formation of vapor.

Hence, option (3) is correct.

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Answer:

d

Explanation:

answer d makes the equation balance

Answer:

animal

Explanation:

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Answer:

Explanation:

When two non-miscible liquids are put together, the one with the higher density will be on the bottom, while the one with the lower density will be on top.

Meaning that in this problem's case toluene would be on the top layer and water in the bottom layer.

Answer:

According to the Brønsted definition, an acid is a substance capable of donating a proton, and a base is a substance capable of accepting a proton. ... The species giving up the proton is HCl, an acid. The species accepting the proton is water, the base. The species Cl- is the conjugate base of HCl.

Answer:

It depends. what hot spot are you looking for?

Answer:

A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.

Explanation:

Hope this is what you mean be hot spot!

I hope this helps you!  

Answer: frequency is 8.57 ·10^14 Hz

Explanation: lambda = 3500 A = 0,000 000 350 m

Wave number is 1/ lambda = 2857142.857 1/m

Wave equation c = frequency · lambda and f = c / lambda

Frequency = 300 000 000 m/s / 0,000 000350 m

The wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].

Explanation:

Given that,

The wavelength of violet radiation,

[tex]\lambda=3500\ A\\\\=3500\times 10^{-10}\ m\\\\=3.5\times 10^{-7}\ m[/tex]

To find,

The wave number and frequency of violet radiation.

Solution,

Wavelength, [tex]\lambda=3.5\times 10^{-7}\ m[/tex]

Wave number is the reciprocal of the wavelength,

[tex]\overline{\lambda}=\dfrac{1}{\lambda}[/tex]

Put all the values,

[tex]\overline{\lambda}=\dfrac{1}{3.5\times 10^{-7}}\\\\\overline{\lambda}=2.85\times 10^{6}\ m^{-1}[/tex]

The relation between the wavelength, frequency and speed of wave is given by :

[tex]f=\dfrac{c}{\lambda}[/tex]

Where

c is the speed of light

Put all the values,

[tex]f=\dfrac{3\times 10^8}{3.5\times 10^{-7}}\\\\f=8.57\times 10^{14}\ Hz[/tex]

So, the wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].

Reference,

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Answer:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Explanation:

Hello there!

In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Best regards!

Answer:

write the balanced chemical equation of the reaction between strong acid and weak base also mention the types of salt obtained in the reaction

Explanation:

HCl → H+(aq) + Cl−(aq) (100%)

Any acid that dissociates 100% into ions is called a strong acid. If it does not dissociate 100%, it is a weak acid. HC2H3O2 is an example of a weak acid:

HC2H3O2→ H+(aq) + C2H3O2−(aq) (~5%)

Because this reaction does not go 100% to completion, it is more appropriate to write it as an equilibrium:

HC2H3O2 ⇄ H+(aq) + C2H3O2−(aq)

As it turns out, there are very few strong acids, which are given in Table 12.2 “Strong Acids and Bases”. If an acid is not listed here, it is a weak acid. It may be 1% ionized or 99% ionized, but it is still classified as a weak acid.

Answer:

P4O10

Explanation:

(P2O5)n=283.89

62+80=283.89

142n=283.89

n=2

P2O10

The empirical and molecular formula are related by the formula, molecular formula=2×empirical formula ,meaning double the atoms present in empirical formula,hence molecular formula is P₄O₁₀.

Empirical formula of a compound is defined as the simplest whole number ratio of atoms which are present in a compound.It does not make any mention of the arrangement of atoms or the number of atoms. The empirical formula gives information about the ratio of number of atoms which are present in a compound.

Molecular formula is determined from the empirical formula by dividing the molar mass of a compound by the empirical formula mass. The resultant which should be a whole number or very close to the whole number , then the subscripts are multiplied by the whole number to get the molecular formula.

For the compound P₂O₅ the subscripts of phosphorous and oxygen are multiplied by 2 and hence the molecular formula P₄O₁₀.

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Answer:

2Zn2+3O2 ----> 2ZnO+2SO2

Explanation:

Answer:

Explanation:

In electrophilic aromatic substitution, the substituent(s) that favors electrophilic attack is said to be ortho or para to the substituent. Meta directors are deactivators. Altogether, these directors have an integral role to play in the success and regioselectivity of electrophilic aromatic substitution reactions.

From the information given: The;

Strongly deactivating meta- director  ⇒ NO₂ (nitro group)

Moderately deactivating meta- director  ⇒ CN (cyano group)

Strongly activating ortho-/para- director ⇒ OH (hydroxy; group)

Weakly deactivating ortho-/para- director ⇒ -X (halide group)

Weakly activating ortho-/para- director ⇒ - Ph  (phenyl group)

Ortho and para substituents favors the electrophilic substitution reaction and meta substituents are deactivators.

Regioselectivity of any reaction tells about the preferred side over another side of the reaction to success.

Ortho or para substituents on the benzene ring will increase the chances of electrophilic aromatic substitution by increase the s electrons on the ring. While the meta directors are deactivators, they have an integral role to play in the success and regioselectivity of electrophilic aromatic substitution reactions.

Strongly deactivating meta director nitro group.

Moderately deactivating meta director cyano group.

Strongly activating ortho/para director hydroxy group.

Weakly deactivating ortho/para director halide group.

Weakly activating ortho/para director phenyl group.

Hence, from the above discussion it is clear that Ortho and para substituents favors the electrophilic substitution reaction and meta substituents are deactivators.

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Answer:

[tex]\Large \boxed{\sf -6000 \ J}[/tex]

Explanation:

Use formula

[tex]\displaystyle \sf Heat \ (J)=mass \ (kg) \times specific \ heat \ capacity \ (Jkg^{-1}\°C^{-1}) \times change \ in \ temperature \ (\°C)[/tex]

Specific heat capacity of ice is 2,000 J/(kg °C)

Substitute the values in formula and evaluate

[tex]\displaystyle \sf Heat \ (J)=0.05 \ kg \times 2000 \ Jkg^{-1}\°C^{-1} \times (-100\°C-(-40 \°C))[/tex]

[tex]Q=0.05 \times 2000 \times (-100-(-40)) =-6000[/tex]

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1) 2KCIO3=2kci+3o2

2)CH4 + 2O2 → CO2 + 2H2O

3)  2HCl + Ca(OH)2 → CaCl2 + 2H2O

I hope this helped!

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