what is the best definition of an electromagnetic wave
A. An electromagnetic wave is a mechanical wave.
B. An electromagnetic wave is a longitudinal wave with electricity.
C. An electromagnetic wave is a transverse wave that has electrical and magnetic properties
Answer:
Electromagnetic waves are periodic oscillations in the intensity of an electromagnetic field. OR. An electromagnetic wave is a transverse wave that has electrical and magnetic properties
Consider a circular ring of radius r,uniformly charged with linear charge density λ. Find the electric potential at a point on the axis at a distance x from the centre of the ring. Using this expression for the potential, find the electric field at this point.
The electric potential at a point on the axis at a distance x from the centre of the ring = k (q/r). And
The electric field at a circular ring of radius r, uniformly charged with linear charge density λ = (1/ 2€⁰) (rλ /r² + x² ) ⅔
Resolution of the electric field into its vertical and horizontal components. Vertical components cancel out while horizontal components add because the ring is symmetric.
From the figure, we can determine the circumference of the ring:
L = 2πr
Hence, electric field at P:
(1/ 2€⁰) (rλ /r² + x² ) ⅔
Where,
k = 9 x 10⁹
r = radius of the ring
λ = charge density
x = distance of the point
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is a component of a network's logical topology that determines how connections are created between nodes. true or false
The statement is false Because: A network's logical topology is determined by the protocol used to create connections between nodes, such as Ethernet, optical, or wireless.
A network’s logical topology is the arrangement of the nodes, devices, and connections in a network, which defines the pattern of data transfers. It describes the way data flows between nodes and devices, and is different from the physical topology, which describes the physical wiring of a network.
A logical topology is important to characterize as it can affect the performance of the network, and can help identify issues with the network structure. Examples of logical topologies include star, ring, and mesh topologies
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The following circuit diagram is partially incomplete.
The current in Lamp 1 is 0.4 A. The potential difference across Lamp 1 is 8.0 V.
Calculate the resistance of Lamp 1.
A) 30 ohms
B) 20 ohms
C) 2 ohms
D) 3 ohms
The resistance across a device can be determined using Ohm's law if current and voltage is given. The resistance in lamp 1 is 20 ohms.
What is Ohm's law ?Ohm's law states that the voltage across a circuit is the product of the current and resistance through the circuit.
Let V be the voltage, I and R be the current and resistance respectively. Then, V= IR.
Hence, the current is inversely proportional to the resistance through the circuit. Therefore, to vary the current a variable resistor can be used in the circuit.
Given that, current in lamp 1 = 0.4 A
voltage = 8 V.
then resistance = V/I
R = 8 V/0.4 A = 20 Ω
Therefore, the resistance of the lamp L1 is 20 ohms.
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The resistance of Lamp 1 is 20 ohms.
The correct option is B.
What is Ohm's law ?Ohm’s law states that the voltage across a conductor is directly proportional to the electric current flowing through it, when all physical conditions and temperatures are constant.
Equation can be written as,
V = IR
Where, V = Voltage
I = Electric current
the constant of proportionality, R, is called Resistance
Given,
Current in Lamp 1 I = 0.4 A
Potential difference V = 8.0 volt
Resistance of Lamp R = ?
By Ohm's law
V = IR
8 = 0.4 × R
R = 8/0.4
R = 20 Ω
Hence, 20 Ω is resistance of Lamp 1
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In (Figure 1), the compact flame of a candle casts a 19-cm high shadow of a 8.2-cm tall tree cutout.
The candle is 3.2 cm from the cutout; how far is the candle from the wall?
If the candle is 3.2 cm from the cutout; then distance of the candle from the wall is, 7.41 cm
What is the similarity of triangles?Triangles with the same shape but different sizes are said to be similar triangles. Squares with any side length and all equilateral triangles are examples of related objects. In other words, if two triangles are similar, their corresponding sides are proportionately equal and their corresponding angles are congruent. Triangle resemblance is shown here by the symbol "≈"
Given that,
The compact flame of a candle casts a 19-cm high shadow of a 8.2-cm tall tree cutout,
If the candle is 3.2 cm from the cutout,
then distance of the candle from the wall = ?
Suppose, the distance of the candle from the wall = x
It can be seen the diagram,
following system is making similar triangles,
So,
Ratio of sides will be equal
height of tree/distance = height of shadow/distance
8.2/3.2 = 19/x
x = 7.41
Hence, the distance is 7.41 cm
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which one of the following sets of quantum numbers can correctly represent a 3p orbital? group of answer choices n
Example 2.2 (Lecture Notes)
Three coplanar forces of
magnitudes 80 N, 50 N and
60 N act a point O as shown
in the figure. Determine the
resultant of these force.
A
C
50 N
达
20
60⁰
80 N
60 N
Basic Mechanics Lecture Notes Prepared By E. Adaze, Lecturer, Dept. of Mech. Eng., UMAT, Tarkwa 2021
B
16
Resolution of Forces into Components
There is no consequence when a point experiences three or more coplanar forces and the vector diagram closes. The forces affecting the point are balanced.
How do you calculate the coplanar forces' resultant force?On the other hand, the Pythagorean Theorem, F = SQRT (Fx2 + Fy2), can be used to get the consequent if the magnitude of the rectangular components is known. Knowing that the tan is equal to the opposite side of the adjacent side, one can use trigonometry to calculate the direction of the resultant.
Let us resolve each of the forces into components along the x and y axes.
For the 80 N force:
Fx = 80 N cos(60°) = 80 N x 0.5 = 40 N
Fy = 80 N sin(60°) = 80 N x 0.866 = 69.28 N
For the 50 N force:
Fx = 50 N cos(20°) = 50 N x 0.94 = 47 N
Fy = 50 N sin(20°) = 50 N x 0.342 = 17.10 N
For the 60 N force:
Fx = 60 N cos(60°) = 60 N x 0.5 = 30 N
Fy = 60 N sin(60°) = 60 N x 0.866 = 51.96 N
Resultant Force:
The resultant force is then determined by adding the components:
Fx = 40 N + 47 N + 30 N = 117 N
Fy = 69.28 N + 17.10 N + 51.96 N = 138.34 N
Therefore, the magnitude of the resultant force is:
|F| = √(Fx2 + Fy2) = √(117 x 117 + 138.34 x 138.34) = 184.2 N
The direction of the resultant force is:
θ = tan−1(Fy/Fx) = tan−1(138.34/117) = 55.7°
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the volume and pressure of a gas are 7.80 m3 and 2.10 atm, respectively. (a) if this gas expands to one and one-half its initial volume while the pressure is constant, determine the work done on the gas. j (b) on the other hand, if this gas is compressed to two-fifths its initial volume while the pressure is constant, determine the work done on the gas.
(a) The work done on the gas when it expands to one and one-half its initial volume while the pressure is constant is 2.92 x [tex]10^5[/tex] J.
(b) The work done on the gas when it is compressed to two-fifths its initial volume while the pressure is constant is 3.74 x [tex]10^5[/tex] J.
Work done on a gas can be calculated using the equation:
W = -PΔV
where P is the pressure, ΔV is the change in volume, and W is the work done.
In this case, the pressure is constant at 2.10 atm, which is equivalent to 2.10 x [tex]10^5[/tex]Pa.
For (a), the initial volume is 7.80 m^3 and the final volume is 1.5 times the initial volume, which is 11.70 m^3. The change in volume is 11.70 - 7.80 = 3.90 [tex]m^3[/tex]. So, the work done on the gas is W = -PΔV = -(2.10 x [tex]10^5[/tex]) x (3.90) = 2.92 x [tex]10^5[/tex] J.
For (b), the final volume is two-fifths the initial volume, which is 3.12 m^3. The change in volume is 7.80 - 3.12 = 4.68 [tex]m^3[/tex]. So, the work done on the gas is W = -PΔV = -(2.10 x [tex]10^5[/tex]) x (4.68) = 3.74 x [tex]10^5[/tex] J.
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The springs used in ball-point pens are some of the weaker examples found in practical applications. It usually only takes about 0.005 kilograms of mass resting on such a spring to compress it by 0.001 meters. Which of the following most closely describes the force constant of a typical ball-point pen spring?
A 0.05 N/m
B. 0.5 N/m
C. 5.0 N/m
D. 50 N/m
E. 500 N/m
The force-constant of a typical ball-point pen spring is approximately 50 N/m. Correct option is D. 50 N/m
The force constant of a spring can be calculated using Hooke's-Law, which states that the force exerted by a spring is directly proportional to its displacement.
F ∝ x ⇒ F = -kx
Here, F is the force, k is the force constant, and x is the displacement.
Here in this case, the displacement given is x = 0.001 m , the mass resting is 0.005 kg. i.e. m = 0.005 kg.
The force will be F = mg = 0.005 × 9.8 = 0.049 N
If we solve this,
0.049 N = -k × 0.001 m
k = 0.049 N / 0.001 m = 49 N/m
The approximation we get is 49 N/m and the option near this value id option D. Therefore, the force constant of a typical ball-point pen spring is approximately 50 N/m.
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If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1 thru A7)?
Answer:
A1 = 10 V
A2 = 10 V
A3 = 10 V
A4 = 0 V
A5 = 10 V
A6 = 10 V
A7 = 10 V
Explanation:
The voltage across each ammeter should be the same for each ammeter connected in parallel. Since each ammeter is connected in parallel with the power supply, the reading across each ammeter should be 100 V. Since the actual voltage inputted from the voltage source is 100 V, each ammeter should read 10 V. The only exception is the ammeter connected in series with the other ammeters (A4). Since no circuit or component is connected in series with this ammeter, the reading should be 0 V.