Pedro buys lunch at school every day. He always gets pizza when it is
available. The cafeteria has pizza about 80% of the time.
Pedro runs a simulation to model this using a random number generator. He
assigns these digits to the possible outcomes for each day of the week:
• Let 0 and 1 = no pizza available
Let 2, 3, 4, 5, 6, 7, 8, and 9 = pizza available
The table shows the results of the simulation.
95032 4715071709 3888994007
350135789072924 19365 47879
What is the estimated probability that Pedro will eat pizza for lunch every day
next week?
O A. 0.0
B. 0.3
OC. 0.4
D. 0.7

Answer is B: 0.3

Reason: in each box, there are 5 digits to represent the 5 days in a week. There’s 10 boxes to represents 10 weeks. In each box there’s a chance out of 5 for Pedro to get pizza. You multiply each days possibly of Pedro getting pizza by each other n get about .26 & round it to .3 - hope that helps! ((:

Answer:0.3 is also 30%

Step-by-step explanation:

Answer:

0.3 is correct, from your screen and mine :)

Step-by-step explanation:

Factor the expression below.
9x2-1
O A. (x - 1)(9x + 1)
O B. (3x - 1)(3x - 1)
O C. (x - 1)(9x-1)
O D. (3x - 1)(3x + 1)

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