Not sure I would solve this problem or where to start? Can someone help me out here please?

Answer:

X⁴-7x²-8x-7

Step-by-step explanation:

Answer:

see down

Step-by-step explanation:

d is correct answer

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Explanation:

The graph of [tex]y \ge -\frac{1}{3}x+2[/tex] has the boundary y = (-1/3)x+2 which is a solid line. This line goes through (0,2) and (3,1). We shade above the boundary because of the "greater than" sign.

The graph of y < 2x+3 has a dashed boundary line of y = 2x+3, and we shade below the boundary because of the "less than" sign.

The two regions overlap in the upper right corner where it's shaded in the darkest color. The points (2,2), (3,1) and (4,2) are in this upper right corner region. If we plug the coordinates of each point into each inequality, then we'll get true statements.

For instance, let's try (x,y) = (2,2) into the first inequality

[tex]y \ge -\frac{1}{3}x+2\\\\2 \ge -\frac{1}{3}(2)+2\\\\2 \ge -\frac{2}{3}+2\\\\2 \ge -\frac{2}{3}+\frac{6}{3}\\\\2 \ge \frac{-2+6}{3}\\\\2 \ge \frac{4}{3}\\\\2 \ge 1.33\\\\[/tex]

Which is true since 2 is indeed larger than 1.33, so that confirms (2,2) is in the shaded region for [tex]y \ge -\frac{1}{3}x+2\\\\[/tex]

Let's check the other inequality as well

[tex]y < 2x+3\\\\2 < 2(2)+3\\\\2 < 4+3\\\\2 < 7\\\\[/tex]

That works too. So (2,2) is in BOTH shaded regions at the same time; hence, it's a solution to the system. You should find that (3,1) and (4,2) work for both inequalities also. This will confirm choice A is the answer.

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Extra info (optional section)

A point like (3,-1) does not work for the first inequality as shown below

[tex]y \ge -\frac{1}{3}x+2\\\\-1 \ge -\frac{1}{3}(3)+2\\\\-1 \ge -1+2\\\\-1 \ge 1\\\\[/tex]

Since -1 is neither equal to 1, nor is -1 larger than 1 either. The false statement at the end indicates (3,-1) is not a solution to that inequality.

Based on the graph, the point (3,-1) is not above the blue solid boundary line. All of this means we can rule out choice B.

You should find that (1,-2) is a similar story, so we can rule out choice C. Choice D can be ruled out because (2,0) is not a solution to the first inequality.

Answer:

0.0106 = 1.06% probability that 2 or fewer will withdraw

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they withdraw, or they do not. The probability of an student withdrawing is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

25% of its students withdraw without completing the introductory statistics course.

This means that [tex]p = 0.25[/tex]

Assume that 30 students registered for the course.

This means that [tex]n = 30[/tex]

Compute the probability that 2 or fewer will withdraw:

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{30,0}.(0.25)^{0}.(0.75)^{30} = 0.0002[/tex]

[tex]P(X = 1) = C_{30,1}.(0.25)^{1}.(0.75)^{29} = 0.0018[/tex]

[tex]P(X = 2) = C_{30,2}.(0.25)^{2}.(0.75)^{28} = 0.0086[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0002 + 0.0018 + 0.0086 = 0.0106[/tex]

0.0106 = 1.06% probability that 2 or fewer will withdraw

Answer:

y= (3/2)x - (5/2)

Step-by-step explanation:

Slope-intercept form is y=mx+b. So, 3x-2y=5 can be rearranged to slope-intercept form.

We need to isolate the y and get it by itself, so let's subtract the 3x from both sides.

-> -2y = 5 - 3x

Now we need to get rid of the -2 so that the y will be completely alone. So, divide the -2 from both sides of the equation.

-> y = (5/-2) (-3x/-2)

Now rearrange, and the negatives from the 3x and 2 cancel each other out and we are left with:

-> y = 3/2 x - 5/2

Answer:

The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 31 - 1 = 30

96% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.96}{2} = 0.98[/tex]. So we have T = 2.15

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.15\frac{15}{\sqrt{31}} = 5.8[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 105.8 - 5.8 = 105.

The upper end of the interval is the sample mean added to M. So it is 105.8 + 5.8 = 111.6

The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).

Answer:

a) The reorder point necessary to provide a 95 percent service probability is 1557 units.

b) The Z value of 0.74 corresponds to 77% service probability.

Step-by-step explanation:  

Average weekly demand (d) = 315 units  

The standard deviation of weekly demand (\sigmad) = 90 units  

Lead time (L) = 4 weeks  

At 95% service level value of Z = 1.65  

Reorder point = d x L + safety stock  

[tex]= d \times L + (Z \times \sigma d \times \sqrt L)\\\\= 315 x 4 + (1.65 x 90 x \sqrt 4)\\\\= 1260 +(1.65 x 90 x 2)\\\\= 1260 + 297\\\\= 1557 units[/tex]

b) Earlier the safety stock was 297 units(calculated in part a)

Now the safety stock is reduced to 55%.so,55% of 297 = 163.35 units  

So the new safety stock = 297 - 163.35 = 133.65  

[tex]Safety stock = Z \times \sigma d \times \sqrt L\\133.65 = Z x 90 x 2\\133.65 = 180Z\\ Z = 133.65/180\\Z = 0.74[/tex]  

The Z value of 0.74 corresponds to 77% service probability.

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Answer:

  6.5 cm

Step-by-step explanation:

The length of the rhombus is the length of the long diagonal: 12 cm.

Perhaps you want the length of one side. We recognize the given lengths as the legs of a 5-12-13 right triangle. Since each side is the hypotenuse of a right triangle whose legs are half the diagonals, the side length of the rhombus will be half of 13 cm.

The side lengths of the rhombus are 6.5 cm.

Answer:

To create the graph of k(x) , the graph of f(x)   undergoes  a vertical stretching  by a factor of 9.

Step-by-step explanation:

We are given that

[tex]k(x)=9f(x)[/tex]

We have to Identify the transformation that occurs to create the graph of k(x).

To create the graph of k(x) we will multiply the function f(x) value by 9.

Let f(x) be any function

[tex]g(x)=a f(x)[/tex]

Where a>1

It means to obtain the graph  of g(x) the graph f(x)  has  undergone a vertical stretching  by a factor of a.

We have k=9>1

Therefore, to create the graph of k(x) , the graph of f(x) undergoes a vertical stretching  by a factor of 9.

Answer:

0.1636 = 16.36% probability that Kobe makes his 10th free throw on his 14th shot

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either he makes it, or he misses. The probability of making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

He is able to make a free throw 70% of the time.

This means that [tex]p = 0.7[/tex]

What is the probability that Kobe makes his 10th free throw on his 14th shot?

9 of his first 13(P(X = 9) when n = 13), and then the 10th with 0.7 probability.

Thus

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{13,9}.(0.7)^{9}.(0.3)^{3} = 0.2337[/tex]

0.7*0.2337 = 0.1636

0.1636 = 16.36% probability that Kobe makes his 10th free throw on his 14th shot

Answer:

 $10,000

Step-by-step explanation:

.05 x = 500

x = 500/.05

x = $10,000

Answer:

90

Step-by-step explanation:

360 ÷ 4 = 90

Answer:

x = 20

Step-by-step explanation:

 3x -10 = 2x +10

x = 20

Answer:

B

Step-by-step explanation:

The coeffecients (I totally didn't spell that right) and variables match up.

Answer:

yeah u forgot to add the picture ig

Answer:

A is the equation in standard form

Step-by-step explanation:

Given :-

To Find :-

Solution :-

We know that the circumference of the Circle with radius r is given by ,

=> C = 2πr .

=> C = 2 × 3.14 × 50 cm

=> C = 314 cm .

Hence the required answer is 314 cm .

Answer:

Step-by-step explanation:

b 75

Answer:

19.80

Step-by-step explanation:

Given the equation :

y = a (e)^kt

If a = 100, y = 50, and k = -0.035, find t.

50 = 100(e)^(-0.035t)

50/100 = e^(-0.035t)

0.5 = e^-0.035t

Take the In

In(0.5) = - 0.035t

-0.693147 = - 0.035t

-0.693147 / - 0.035 = t

19.8042 = t

Hence, t = 19.80

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Answer:

  (8a -a²)/(a +2)

Step-by-step explanation:

Cancel common factors from numerator and denominator.

  [tex]\dfrac{-56+15a-a^2}{a^2+2a}\div\dfrac{a-7}{a^2}=-\dfrac{(a-7)(a-8)(a^2)}{a(a+2)(a-7)}\\\\=-\dfrac{a(a-8)}{a+2}=\boxed{\dfrac{8a-a^2}{a+2}}[/tex]

Answer:

m=5

n=-3

Step-by-step explanation:

3m+2m=9

3m-3n=24

3(5)+2(-3)=9

15-6=9 correct

Answer:

D

Step-by-step explanation:

Answer:

[tex]P = (7, -\frac{3}{5})[/tex]

Step-by-step explanation:

Given

[tex]A = (-9,5)[/tex]

[tex]B = (11,-2)[/tex]

[tex]m : n = 4 : 1[/tex]

Required

Point P

This is calculated as:

[tex]P = (\frac{m * x_2 + n * x_1}{m + n}, \frac{m * y_2 + n * y_1}{m + n})[/tex]

So, we have:

[tex]P = (\frac{4 * 11 + 1 * -9}{4 + 1}, \frac{4 * -2 + 1 * 5}{4+1})[/tex]

[tex]P = (\frac{35}{5}, \frac{-3}{5})[/tex]

[tex]P = (7, -\frac{3}{5})[/tex]

Answer:

1) has bigger answer

Step-by-step explanation:

1)

solving parenthesis first we get

5 × 10

so, the answer = 50

2)

solving 3 × 5 first as we have to see multiplication first then addition

2 + 15 + 5

22

comparing both

50 > 22

so problem 1 has a bigger answer

Answer:

Correct option is

C

10

5

10P

5

Total ways in which one passenger can stop =10

Total ways in which 5 passengers can stop =10∗10∗10∗10∗10

=10

5

We will select 5 floors from 10 floors and assign each individual to each floor to keep everyone isolated from each other

No. of ways in which no two persons stop at the same floor =10C

5

∗5!

=10P

5

⇒P(E)=10P

5

/10

5

here you go it's too easy

Step-by-step explanation:

Explanation is in the attachment .

Hope it is helpful to you ❣️☪️❇️

Step-by-step explanation:

If the price is below the equilibrium level, then the quantity demanded will exceed the quantity supplied. Excess demand or a shortage will exist. If the price is above the equilibrium level, then the quantity supplied will exceed the quantity demanded. Excess supply or a surplus will exist.Whenever markets experience imbalances—creating disequilibrium prices, surpluses, and shortages—market forces drive prices toward equilibrium. A surplus exists when the price is above equilibrium, which encourages sellers to lower their prices to eliminate the surplus.

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Answer:

  x = -5  or  x = -2

Step-by-step explanation:

Factoring, we have ...

  ((x +3 +2)((x +3) -1)) = 0

  (x +5)(x +2) = 0

  x = -5  or  x = -2 . . . . . . . . values that make the factors zero

Answer:

[tex]P(Negative | Yes) = 0.0486[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {Yes} & {No} & {Positive} & {137} & {24} & {Negative} & {7} & {132} \ \end{array}[/tex]

Required

[tex]P(Negative | Yes)[/tex]

This is calculated as:

[tex]P(Negative | Yes) = \frac{n(Negative\ n\ Yes)}{n(Yes)}[/tex]

So, we have:

[tex]P(Negative | Yes) = \frac{7}{137+7}[/tex]

[tex]P(Negative | Yes) = \frac{7}{144}[/tex]

[tex]P(Negative | Yes) = 0.0486[/tex]