Answer:
A money market account paying 3.5% interest, renewable for three-month commitments.
Need help please I don’t get it
the e-function stuff can be confusing sometimes, but notices that g(x) / the blue line, is just somewhat lower, rest is the same.
how much lower? look at the y-intercepts
f(0)= "about 5"
g(0)= "about -3"
with this y-intercept only option c can work
There are 100 sheets of paper on table. It takes 10 seconds to count 10 sheets. How many seconds will you need to count 80 sheets?
Answer:
80 seconds
Step-by-step explanation:
10/10 = 1
now it takes 1 seconds to count 1 sheet
80 x 1 = 80 seconds to count 80 sheets
Step-by-step explanation:
10sheets=10seconds
1sheet=1sheet÷10sheets x 10seconds
=1second
80sheets=80sheets÷1sheet x 1second
80seconds
hope this is helpful
i’ll give brainliest to right answer please hurry
Answer:
Scientific notation uses exponential notation. When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.
Answer:
Look at the exponitial factor. If it is like 10^2 or like 10^10 the number is very big because it is raised to a very big power. Oppisitely, when it is rasied to a negative number, the number producted will have many decimal places. For example 10^-1 is literaly 0.1.
Step-by-step explanation:
Yes I got u
Some number times 7 is equal to the number increased by 9
Answer:
.
Step-by-step explanation:
.
A's salary is 50% more than B's. How
much percent is B's salary less than A's?
a. 33(1/4)% b. 33(1/3)% c. 33(1/2)% d. 33%
Answer:
The correct answer is B. 33 1/3%.
Step-by-step explanation:
Given that A's salary is 50% more than B's, to determine how much percent is B's salary less than A's, the following calculation must be performed:
Salary A = B + 50
Salary B = 100
Salary A = 100 + 50 = 150
150 = 100
100 = X
100 x 100/150 = X
10,000 / 150 = X
66.666 = X
100 - 66,666 = 33,333
Answer:
B. 33 1/3%.
Step-by-step explanation:
Hope this helps
Can someone help me with this question an my other work?
The quadratic function f(x) = -x2 - 6x - 8 is graphed.
What are the solutions of the quadratic equation 0 =
x2 - 6x - 8?
Ту
2
O 2 and 4
0-2 and 4
0-2 and 4
O: 2 and 4
6 5 A
-3
-1
X
-2
ون
Answer:
-2 and -4
Step-by-step explanation:
When the quadratic equation equals 0, that means when y = 0.
By looking at the graph, whenever y = 0 is when the graph crosses the x-axis.
The graph crosses the x-axis at only two points:
(-4, 0) and (-2, 0)
So the solutions to the graph when -x^2 - 6x - 8 equals 0 is -2 & -4.
Hope it helps (●'◡'●)
Answer:
-2 and -4
Step-by-step explanation:
if you'll notice the function goes through the x axis at -2 and -4
Which of the following is an acute triangle?
70
30*
24°
45
126
132
36°
90°
45
559 55°
Triangle A
Triangle B
Triangle C
Triangle D
A. Triangle B
B. Triangle A
O
C. Triangle C
O.
D. Triangle D
The correct answer will be option (B) Triangle A
Acute triangleAn acute-angled triangle is a type of in which all the three internal angles of the triangle are acute, that is, they measure less than 90°
How to solve this problem?
The steps are as follow:
In acute triangle the the internal angle should not or greater than 90 degreeIn triangle B one of internal angle is 126 degree which is greater than 90 degree so it is not acute triangleOne internal angle of triangle C is 90 degree so it is also not acute triangleFor triangle D one angle is 132 degree which is greater than 90 degree so it also not acute triangleIn triangle A all the internal angle is less than 90 degree so it is acute triangleSo the triangle A is acute triangle
Learn more about Acute triangle here:
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Simplify by expressing fractional exponents instead of radicals.
The number of users of a certain website (in millions) from 2004 through 2011 follows:
Year Period Users (Millions)
2004 1 1
2005 2 5
2006 3 11
2007 4 58
2008 5 145
2009 6 359
2010 7 607
2011 8 846
Using Minitab or Excel, develop a quadratic trend equation that can be used to forecast users (in millions). (Round your numerical values to one decimal place.)
Answer:
y = 26.3x² - 116.9x + 109.6
Step-by-step explanation:
Given the data ;
Year Period Users (Millions)
2004 1 1
2005 2 5
2006 3 11
2007 4 58
2008 5 145
2009 6 359
2010 7 607
2011 8 846
A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :
y = Ax² + Bx + C
y = 26.3x² - 116.9x + 109.6
which of these statements is true for f(x) =3x2x
Step-by-step explanation:
which of these statements is true for f(x) =3x2xsorry i think u got yr question incomplete ...stay safe healthy and happy........Problem: The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72
inches and standard deviation 3.17 inches. Compute the probability that a simple random sample of size n=
10 results in a sample mean greater than 40 inches. That is, compute P(mean >40).
Gestation period The length of human pregnancies is approximately normally distributed with mean u = 266
days and standard deviation o = 16 days.
Tagged
Math
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days
or less?
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days
or less?
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of
the mean?
Know
Learn
Booste
V See
Answer:
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.
Step-by-step explanation:
To solve these questions, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.
This means that [tex]\mu = 38.72, \sigma = 3.17[/tex]
Sample of 10:
This means that [tex]n = 10, s = \frac{3.17}{\sqrt{10}}[/tex]
Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
This is 1 subtracted by the p-value of Z when X = 40. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997
1 - 0.8997 = 0.1003
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
[tex]\mu = 266, \sigma = 16[/tex]
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
This is the p-value of Z when X = 260. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{260 - 266}{16}[/tex]
[tex]Z = -0.375[/tex]
[tex]Z = -0.375[/tex] has a p-value of 0.3539.
0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 20[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}[/tex]
[tex]Z = -1.68[/tex]
[tex]Z = -1.68[/tex] has a p-value of 0.0465.
0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 50[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}[/tex]
[tex]Z = -2.65[/tex]
[tex]Z = -2.65[/tex] has a p-value of 0.0040.
0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?
Sample of size 15 means that [tex]n = 15[/tex]. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.
X = 276
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = 2.42[/tex]
[tex]Z = 2.42[/tex] has a p-value of 0.9922.
X = 256
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = -2.42[/tex]
[tex]Z = -2.42[/tex] has a p-value of 0.0078.
0.9922 - 0.0078 = 0.9844
0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.
An angle with measure of 71° is bisect at what angle?
Answer:
A
Step-by-step explanation: just divide 71 into 2 which gives you 35.5 making a your answer.
In 2019, 15.9% of Broadway actors were acting in their first role on Broadway. Suppose we took a survey of 38 Broadway actors and found that 18.4% of the actors we surveyed were first-timers. What are the mean and standard deviation for the sampling distribution of pÌ p^? 1. Mean: 0.159, Standard Deviation: 0.0592. Mean: 0.159, Standard Deviation: 0.36573. Mean: 0.184, Standard Deviation: 0.0634. Mean: 0.184, Standard Deviation: 0.0595. Mean: 0.159, Standard Deviation: 0.063In 2019 the CDC reported that 14.0% of US adults are smokers. Suppose you take a random sample of 30 smokers and find that the proportion of them who are current smokers is 16.7%.What is the mean and the standard deviation of the sampling distribution of pÌ p^ ?1. mean = 0.140, standard deviation = 0.0682. mean = 0.167, standard deviation = 0.0633. mean = 0.140, standard deviation = 0.0634. mean = 0.167, standard deviation = 0.068
Answer:
For the Broadway actors acting in their first role on Broadway, mean: 0.184, Standard Deviation: 0.063.
For the proportion of smokers, mean = 0.167, standard deviation = 0.068
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Suppose we took a survey of 38 Broadway actors and found that 18.4% of the actors we surveyed were first-timers.
This means that [tex]p = 0.184, n = 38[/tex]
What are the mean and standard deviation for the sampling distribution of p^?
Mean:
[tex]\mu = p = 0.184[/tex]
Standard deviation:
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.184*0.816}{38}} = 0.063[/tex]
Suppose you take a random sample of 30 smokers and find that the proportion of them who are current smokers is 16.7%.
This means that [tex]n = 30, p = 0.167[/tex]
What is the mean and the standard deviation of the sampling distribution of p^ ?
Mean:
[tex]\mu = p = 0.167[/tex]
Standard deviation:
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.167*0.833}{30}} = 0.068[/tex]
help me please ineed your help
√(9+ √32)
Please simplify
Answer:
3.82
Step-by-step explanation:
[tex]\sqrt{(9+\sqrt{32}) }[/tex] Do not confirm the answer unless your equation looks like that?
[tex]\sqrt{(9+\sqrt{32}) }[/tex] Start by the [tex]\sqrt{32}[/tex]
[tex]\sqrt{(9+5.65) }[/tex] Now add (9 + 5.65)
[tex]\sqrt{14.65}[/tex] Finally Simplify
[tex]3.82[/tex] Final answer
A sports company has the following production function for a certain product, where p is the number of units produced with x units of labor and y units of capital.
p(x,y)=2500x1/5y1/5
Find:
1. Number of units produced with 26 units of labor and 1333 units of capital.
2. Marginal productivities.
3. Evaluate the marginal productivities at x=25, and y=1333
Answer:
(a) 20226 units
(b) Marginal productivities
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
(c) Evaluation of the marginal productivities
[tex]P_x =803[/tex]
[tex]P_y = 15[/tex]
Step-by-step explanation:
Given
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex]
Solving (a): P(x,y) when x = 26 and y = 1333
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P(26,1333) = 2500*26^\frac{1}{5}*1333^\frac{1}{5}[/tex]
[tex]P(26,1333) = 20226[/tex] --- approximated
Solving (b): The marginal productivities
To do this, we simply calculate Px and Py
Differentiate x to give Px, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * x^{\frac{1}{5}-1} & y^\frac{1}{5}[/tex]
[tex]P_x =2500 * x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
Differentiate y to give Py, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_y =2500 * x^\frac{1}{5} & y^{\frac{1}{5}-1}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
Solving (c): Px and Py when x = 25 and y = 1333
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * 25^{-\frac{4}{5}} * 1333^\frac{1}{5}[/tex]
[tex]P_x =803[/tex] --- approximated
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex] becomes
[tex]P_y =2500 * 25^\frac{1}{5} * 1333^\frac{-4}{5}[/tex]
[tex]P_y = 15[/tex]
A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. Select the correct description of the population in this study.
Complete Question
A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. What is the numerical value of the sample mean?
Answer:
Sample Mean [tex]\=x=80[/tex]
Step-by-step explanation:
From the question we are told that:
Population Mean [tex]\mu=78[/tex]
Standard deviation [tex]\sigma=90[/tex]
Sample size [tex]n=120[/tex]
Sample Mean [tex]\=x=80[/tex]
Therefore
The numerical value of the sample mean is
Sample Mean [tex]\=x=80[/tex]
Solve using the elimination method
x + 5y = 26
- X+ 7y = 22
Answer:
[tex]x=6\\y=4[/tex]
Step-by-step explanation:
Elimination method:
[tex]x+5y=26[/tex]
[tex]-x+7y=22[/tex]
Add these equations to eliminate x:
[tex]12y=48[/tex]
Then solve [tex]12y=48[/tex] for y:
[tex]12y=48[/tex]
[tex]y=48/12[/tex]
[tex]y=4[/tex]
Write down an original equation:
[tex]x+5y=26[/tex]
Substitute 4 for y in [tex]x+5y=26[/tex]:
[tex]x+5(4)=26[/tex]
[tex]x+20=26[/tex]
[tex]x=26-20[/tex]
[tex]x=6[/tex]
{ [tex]x=6[/tex] and [tex]y=4[/tex] } ⇒ [tex](6,4)[/tex]
hope this helps...
Answer:
x = 6, y = 4
Step-by-step explanation:
x + 5y = 26
- x + 7y = 22
_________
0 + 12y = 48
12y = 48
y = 48 / 12
y = 4
Substitute y = 4 in eq. x + 5y = 26,
x + 5 ( 4 ) = 26
x + 20 = 26
x = 26 - 20
x = 6
Find the expected value of the winnings
from a game that has the following
payout probability distribution:
Payout($) 2 46 8 10
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]
The expected payout is
2 × 0.5 + 4 × 0.2 + 6 × 0.15 + 8 × 0.1 + 10 × 0.05
= 1 + 0.8 + 0.9 + 0.8 + 0.5
= 4
The expected value of the winnings from this game is $3.90.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
Example:
The probability of getting a head in tossing a coin.
P(H) = 1/2
We have,
To find the expected value of the winnings, we multiply each possible payout by its probability and then sum these products.
So,
Expected Value = (2 x 0.5) + (4 x 0.2) + (6 x 0.15) + (8 x 0.1) + (10 x 0.05)
Expected Value = 1 + 0.8 + 0.9 + 0.8 + 0.5
Expected Value = 3.9
Therefore,
The expected value of the winnings from this game is $3.90.
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Which division problem does the diagram below best illustrate?
A diagram with 8 ovals containing 4 squares each.
O 16 divided by 4 = 4
O 32 divided by 4 = 8
O 36 divided by 4 = 9
O 8 divided by 2 = 4
Answer:
The answer is 32 divided by 4
Step-by-step explanation:
Because in each box there is 4. There are 8 ovals all together. So 8×4, you get 32 and divide it by the number of squares in an oval which is 4
Answer:
the answer is 32 divided by 4=8
Step-by-step explanation:
because when you look at the ovals there's eight ovals and in side there's four squares..
HOPE THIS HELPS!!!!!
This Bar Chart shows the number of DVDs sold at a local music store during one week.
Which measure(s) of central tendency can be used to determine the average number of DVDs sold each day?
A. the median
B. the mean
C. the mean and the median
D. the mode
Answer:
B. the mean
Step-by-step explanation:
According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.
Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.
This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.
Answer:
The Mean
Step-by-step explanation:
I took the test
Could you help me and answer a couple questions for me?
Answer:
I think no. D is the answer
help I don't get it, help
Answer:
No, it is not possible.
Step-by-step explanation:
AB // CD and BC is transversal.
∠ABC = ∠BCD ---> Alternate interior angles are equal.
Here, it is different which is not possible.
Why is underfind the square root of a negative number?
Answer:
The square root of a negative number is undefined, because anything times itself will give a positive (or zero) result. Note: Zero has only one square root (itself). Zero is considered neither positive nor negative
Answer:
sjshzhshshdhdgdgdhdhdgshshshshshwywhwhw
Find the quotient of the following
Answer:
you simply have to do ide the coefficients and subtract the power
The principal P is borrowed at a simple interest rate are for a period of time T. Find the loans future value A, or the total amount due at time T
Answer:
The total amount due after five years is $57,000.
Step-by-step explanation:
Recall that simple interest is given by the formula:
[tex]\displaystyle A=P(1+rt)[/tex]
Where A is the final amount, P is the principal amount, r is the rate, and t is the time (in years).
Since we are investing a principal amount of $38,000 at a rate of 10.0% for five years, P = 38000, r = 0.1, and t = 5. Substitute:
[tex]\displaystyle A=38000(1+(0.1)(5))[/tex]
Evaluate. Hence:
[tex]\displaystyle A=\$ 57,000[/tex]
The total amount due after five years is $57,000.
SCALCET8 3.8.001.MI. A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population consists of two members. Find the population size after seven days. (Round your answer to the nearest whole number.) P(7)
Answer:
A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population · Q: For this discussion, you will work in groups to find the area and answer questions.
Step-by-step explanation:
The marked price of a bicycle is Rs 2000. If the shopkeeper allows some discount and a customer
bought it for Rs 1921 including 13% VAT, how much amount was given as the discount?
Answer:
Discount amount = $328.73
Step-by-step explanation:
Below is the calculation for the discount amount:
The marked price of bicycle = 2000
Purchase price = Rs 1921
VAT = 13%
First find the purchase price excluding VAT = 1921 - (13% of 1921) = 1671.27
Discount amount = 2000 - 1671.27
Discount amount = $328.73
Convert the following 11110011.001 to decimal
Answer:
243.125
Step-by-step explanation:
First do the integral part
11110011
1. From left to right, starting with a zero,
2. add the digit, double, move on to the next digit and repeat step 2 until digits are exhausted.
The successive results are
1
3
7
15
30
60
121
243
For the decimal part, we proceed similarly but
1. From the right-most digit proceed to the left, start with a zero.
2. Add the digit, halve, move on to the next digit and repeat step 2 until the decimal is reached.
Successive results are:
0.5
.25
.125
So the final result is 11110011.001 binary is 243.125 decimal