nicholas wants to buy a cd for $200 that earns 3% apr and is compounded quarterly. the cd matures in 5 years. his interest earned will not be reinvested in the cd.what will nicholas total interest be at the date of maturation?

Answer:

With no digits repeated that would be 60,480

Step-by-step explanation:

9×8×7×6×5×4 = 60,480

Answer:

tell me if this right or not

Step-by-step explanation:

The largest number, which is the factor of two or more number is called the Greatest Common Factor

ex. Factors of 18 = 2×9 =2×3×3

ex.Prime factors of 24 –2×2×2×3

ex.or other factors of 14 The factors of 14 are: 1, 2, 7, 14

Answer:

B

Step-by-step explanation:

I think it's hitting a golf ball in the air, as it is a transformation, but the general shape of it is not affected.

Opening a locker, you are still affecting the general shape.

Answer:

addition=24

subtraction=6

multiplication=720

division=1.8

Answer:

6m-2m+12 and 4(m+3)

Step-by-step explanation:

4(m+12)=4m+48❎

3m-m+12=2m+12❎

6m-2m+12=4m+12✅

4(m+3)=4m+12✅

Step-by-step explanation:

If the triangle is right, we can use Pitagora

We can have 2 results

1.

[tex] \sqrt{ {6}^{2} + {8}^{2} } = \\ = \sqrt{36 + 64} = \\ = \sqrt{100} \\ = 10[/tex]

2.

[tex] \sqrt{ {8}^{2} - {6}^{2} } = \\ = \sqrt{64 - 36} = \\ = \sqrt{28 } \\ = 2 \sqrt{7} [/tex]

Answer:

The answer would be 8.1

Step-by-step explanation:

Answer:33.95 m

Step-by-step explanation:

Given

The height of the man is 2 m

Distance between man and tree is 30 m

the angle of elevation of the top from the eyes is [tex]28^{\circ}[/tex]

from the figure,

[tex]\Rightarrow \tan 28^{\circ}=\dfrac{h}{30}\\\\\Rightarrow h=30\tan 28^{\circ}=15.91\ m[/tex]

Using Pythagoras we can write

[tex]\Rightarrow AD^2=ED^2+AE^2\\\Rightarrow AD^2=30^2+15.91^2\\\Rightarrow AD=33.95\ m[/tex]

Thus the distance between the men eyes to the top of the tree is 33.95 m

Answer:

Its D

Step-by-step explanation:

I just submited that same exact test from connexus

Answer: D 500 cubic centimeters

Step-by-step explanation:

The formula of a volume is Volume = Length x Width x Height. In this case, it already gave us all of the sides that we need! So all we need to do is multiply 5 x 5 x 20 which gives us 500 cubic centimeters!

Hope this helped! ^^

Answer:

x = 8

Step-by-step explanation:

log(5x-4)-log(x+1)=log 4

log [ (5x - 4) / (x+ 1) ] = log 4

[ log (a/b) = loga - logb]

(5x - 4 ) / ( x + 1) = 4

(5x - 4) = 4x + 4

5x - 4x = 4 + 4

x = 8

Hope it will help :)❤

Answer:

its a i think

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

3x−2=2x+7

Step 1: Subtract 2x from both sides.

3x−2−2x=2x+7−2x

x−2=7

Step 2: Add 2 to both sides.

x−2+2=7+2

Answer:

x=9

Answer:

9

Step-by-step explanation:

3x-2=2x+7

3x-2x-2+2=2x-2x+7+2

x=9

3(9)-2=2(9)+7

27-2=18+7

25=25

9514 1404 393

Answer:

  b.  60

Step-by-step explanation:

We assume the percentage for the sample holds for the whole class, so the estimated number preferring November is ...

  0.248 × 230 = 57.04 ≈ 60

About 60 students prefer November.

Answer:

none of those?

Step-by-step explanation:

4(-2c) = -8c

Answer:    -9c

Step-by-step explanation:

4(-2c) - c

= -8c - c

= -9c  

-9c is the answer

Answer:

5 ounces

Step-by-step explanation:

Answer:

5 ounces .

Step-by-step explanation:

Answer:

[tex]P(X \le 4) = 0.7373[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

[tex]P(x > 20) = 0.4207[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

[tex]P(x = 24) = 0.0236[/tex]

[tex]P(x = 15) = 1.18\%[/tex]

Step-by-step explanation:

Given

[tex]p = 80\% = 0.8[/tex]

The question illustrates binomial distribution and will be solved using:

[tex]P(X = x) = ^nC_xp^x(1 - p)^{n-x}[/tex]

Solving (a):

Given

[tex]n =5[/tex]

Required

[tex]P(X\ge 4)[/tex]

This is calculated using

[tex]P(X \le 4) = P(x = 4) +P(x=5)[/tex]

This gives:

[tex]P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}[/tex]

[tex]P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0[/tex]

[tex]P(X \le 4) = 0.4096 + 0.32768[/tex]

[tex]P(X \le 4) = 0.73728[/tex]

[tex]P(X \le 4) = 0.7373[/tex] --- approximated

Solving (b):

Given

[tex]n =25[/tex]

i)

Required

[tex]P(X\le 15)[/tex]

This is calculated as:

[tex]P(X\le 15) = 1 - P(x>15)[/tex] --- Complement rule

[tex]P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}[/tex]

[tex]P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]  

[tex]P(x > 15) = 0.98266813045[/tex]

So:

[tex]P(X\le 15) = 1 - P(x>15)[/tex]

[tex]P(x \le 15) = 1 - 0.98266813045[/tex]

[tex]P(x \le 15) = 0.01733186955[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

ii)

[tex]P(x>20)[/tex]

This is calculated as:

[tex]P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]

[tex]P(x > 20) = 0.42067430925[/tex]

[tex]P(x > 20) = 0.4207[/tex]

iii)

[tex]P(20\ge x \le 24)[/tex]

This is calculated as:

[tex]P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)[/tex]

[tex]P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1[/tex]

[tex]P(20\ge x \le 24)= 0.61291151859[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

iv)

[tex]P(x = 24)[/tex]

This is calculated as:

[tex]P(x = 24) = 25* 0.8^{24}*0.2^1[/tex]

[tex]P(x = 24) = 0.0236[/tex]

Solving (c):

[tex]P(x = 15)[/tex]

This is calculated as:

[tex]P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 0.01177694905[/tex]

[tex]P(x = 15) = 0.0118[/tex]

Express as percentage

[tex]P(x = 15) = 1.18\%[/tex]

The calculated probability (1.18%) is way less than the advocate's claim.

Hence, we do not believe the claim.

its $1.07 my bad XD :P

Step-by-step explanation:

Answer:

[tex]64[/tex]cm³

Step-by-step explanation:

[tex]8 \times 2 \times 4 \\ = 64[/tex]

Answer:

64

Step-by-step explanation:

Hello There!

The formula for volume of a rectangular prism is

[tex]V=lwh[/tex]

where w = width

l = length

h = height

They give us the following dimensions

height = 4

width = 2

length = 8

all we have to do is plug in the values

[tex]V=2(4)8\\2*4=8\\8*8=64\\V=64[/tex]

Thus the answer is 64

Answer:

Step-by-step explanation:

Answer:

See Below.

Step-by-step explanation:

We want to verify the trigonometric identity:

[tex]\cos^2(5x)-\sin^2(5x)=\cos(10x)[/tex]

For simplicity, we can let u = 5x. Therefore, by substitution, we acquire:

[tex]\cos^2(u)-\sin^2(u)[/tex]

Recall the double-angle identity formula(s) for cosine:

[tex]\displaystyle \begin{aligned} \cos(2x)&=\cos^2(x)-\sin^2(x)\\&=2\cos^2(x)-1\\&=1-2\sin^2(x)\end{aligned}[/tex]

Therefore, our identity becomes:

[tex]=\cos(2u)[/tex]

Back-substitute:

[tex]=\cos(2(5x))=\cos(10x)\stackrel{\checkmark}{=}\cos(10x)[/tex]

Hence proven.

cos²A - sin²A = cos2A, this is a general indentity where A can have any random value x/2, y/3, 1/8, 8, 9 etc.

Replacing A with 5x:

=> cos²(5x) - sin²(5x) = cos²(10x)

Moreover,

cos(A + B) = cosAcosB - sinAsinB.

When A = B,

cos(A + A) = cosAcosA - sinAsinA

cos2A = cos²A - sin²A

You can do the same with 5x.

cos(10x) = cos(5x + 5x)

cos(10x) = cos(5x)cos(5x) - sin(5x)sin(5x)

cos(10x) = cos²(5x) - sin²(5x)

Answer:

a,b,c,d and e

Step-by-step explanation:

a circle can be rotated any degree an be symmetrical therefore it has a infinite order of rotational symmetry

thus meaning that the answers are a , b , c, d and e

Answer:

11.26

Step-by-step explanation: The easy way to . complete this is to get the 22.52 split it in half to get your answer. Because they asked for the price of 2 and 2 is half of 4.

since 4 bags of bananas costs $22.52, you would just divide by 2 to find out how much 2 bags of bananas costs.

22.52/2=$11.26

It costs $11.26 for 2 bags of bananas.

Answer:

The pvalue of the test is 0.0178 < 0.1, which means that there is evidence at the .10 level to suggest that the mean IQ score for Lower Arlington residents differs from the national average

Step-by-step explanation:

Previous analyses have determined that national average adult IQ score is 100.

This means that the null hypothesis is: [tex]H_0: \mu = 100[/tex]

Is there any evidence at the .10 level to suggest that the mean IQ score for Lower Arlington residents differs from the national average.

This means that the alternate hypothesis that will be tested is:

[tex]H_a: \mu \neq 100[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

100 is tested at the null hypothesis:

This means that [tex]\mu = 100[/tex]

Standard deviation of 15.

This means that [tex]\sigma = 15[/tex]

A random sample of 35 adults from Lower Arlington, yields an average score of 106.

This means that [tex]n = 35, X = 106[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{106 - 100}{\frac{15}{\sqrt{35}}}[/tex]

[tex]z = 2.37[/tex]

Pvalue of the test:

Since z is positive, and we are testing if the mean is different from a value, the pvalue of the test is 2 multiplied by 1 subtracted by the pvalue of z = 2.37.

Looking at the z-table, z = 2.37 has a pvalue of 0.9911

1 - 0.9911 = 0.0089

2*0.0089 = 0.0178

Is there any evidence at the .10 level to suggest that the mean IQ score for Lower Arlington residents differs from the national average

The pvalue of the test is 0.0178 < 0.1, which means that there is evidence at the .10 level to suggest that the mean IQ score for Lower Arlington residents differs from the national average

It should be in Quadrant II! <3

Answer:

Quadrant II

Step-by-step explanation:

Answer:

[tex]\sqrt{65}[/tex] is the closest to 8

Step-by-step explanation:

[tex]\sqrt{61}=7.81 \\\sqrt{66}=8.12 \\\sqrt{65} =8.06\\\sqrt{62} =7.87[/tex]

Answer:

D

Step-by-step explanation:

Examples

-10 +9 = -1

-8 +9 = 1

-9+9=0

9514 1404 393

Answer:

  a) left curve: f(x); right curve: g(x)

  b) the functions are inverses of each other

Step-by-step explanation:

(a) An exponential function with a base greater than 1 has increasing slope. A log function has decreasing slope. The exponential function is on the left.

__

(b) The base of the exponential is the same as the base of the logarithm, so these functions are inverses of each other. This can be seen in the fact that each is a reflection of the other in the line y=x.

Answer:

(31.919,42.881)

Step-by-step explanation:

Using the t-distribution, it is found that the 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant is (31.92, 42.88). It means that we are 95% that the true mean number of pepperonis for all large pizzas at the restaurant is within this interval.

In this problem, we will find the standard deviation for the sample, hence the t-distribution will be used.

The confidence interval is given by:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which:

For this problem:

The lower bound of the interval is:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 37.4 - 2.2622\frac{7.66}{\sqrt{10}} = 31.92[/tex]

The upper bound of the interval is:

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 37.4 + 2.2622\frac{7.66}{\sqrt{10}} = 42.88[/tex]

The 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant is (31.92, 42.88). It means that we are 95% that the true mean number of pepperonis for all large pizzas at the restaurant is within this interval.

More can be learned about the t-distribution at https://brainly.com/question/16162795